(1) When the driver is at rest, the restoring force exerted by spring is equal in magnitude to the driver's weight, so that
∑ F = s - mg = 0 ==> s = mg = 617.4 N
If the spring is compressed 0.015 m, then the spring constant k is such that
617.4 N = k (0.015 m) ==> k = 41,160 N/m ≈ 41 kN/m
(2) The total mass of the passengers is
24 (68 kg) + 3 (15 kg) + 5 (3 kg) + 25 kg = 1717 kg
so that if everyone is at rest, the spring is compressed a distance x such that
kx = (1717 kg) g ==> x ≈ 0.41 m
The diagram shows the velocity-time graph for a car travelling in a straight line along a road. Calculate the acceleration between t = 2.0 s and t = 5.0 s.
Answer:
a = Δv/Δt = (0 - 20) / (5 - 2) = -6⅔ m/s²
An object of mass 6.36 kg is released from rest and drops 2.05 m to the floor. The collision is completely inelastic. How much kinetic energy is lost during the collision
Answer:
Essentially all of it
Explanation:
The potential energy was
PE = mgh = 6.36(9.81)(2.05) = 127.90278 = 128 J
ignoring air resistance, this PE converts to KE
With no rebound final velocity is zero, so Kinetic energy lost = 128 J
The fastest possible rate of rotation of a planet is that for which the gravitational force on material at the equator just barely provides the centripetal force needed for the rotation. Calculate the minimum rotation period assuming a density of 3.70 g/cm3.
Answer:
m ω^2 R = centripetal force
G M m / R^2 = gravitational force
ω^2 = G M / R^3 for the forces to be equal
d (density) = M / V = M / (4/3 R^3) = 3/4 M / R^3
or M / R^3 = 4 d / 3
Then
ω^2 = G 4 d / 3
d = 3.7 g/cm^2 = 3700 kg/m*3 converting
ω^2 = 6.67E-11 * 3700 * 4 / 3 = 32.9E-8
ω = 5.74E-4
P = 1 / f = 2 pi / ω = 6.28 / 5.74E-4 = 1.09E4 sec
10900 / 3600 = 3.04 hrs for the minimum rotation period
Marks: 1
What is the power of a light that uses 300 joules of energy in 60
seconds?
18,000 W
50 W
5 W
0.2 W
Answer:
W = 5W
Explanation:
1W = 1J/s
W = Watts
J = Joules
s = seconds
W = J/s
W = 300J/60s
W = 5W
Motion Velocity
Reference point Speed
1. An object is in __________ when its distance from a(n) ________ is changing.
2. Speed is given direction is called _______________
3. ____________ can be calculated if you know the distance that an object travels in one unit of time.
Answer:
1. An object is in motion when its distance from another object is changing.
2.Speed is given direction is called velocity.
Speed can be calculated.......
What are the three major types of severe weather? Describe at least two characteristics of each type
Answer:
High winds, hail, excessive precipitation, and wildfires are forms and effects of severe weather, as are thunderstorms, downbursts, tornadoes, waterspouts, tropical cyclones, and extratropical cyclones. Regional and seasonal severe weather phenomena include blizzards (snowstorms), ice storms, and duststorms.
Explanation:High winds- wind speeds as low as 23 knots (43 km/h) may lead to power outages when tree branches fall and disrupt power lines. Once wind exceed 135 knots (250 km/h) within strong tropical cyclones and tornadoes, homes completely collapse, and significant damage is done to larger buildings. Total disruption occurs once wind exceeds 175 knots (324 km/h)
Tornado- Typically look like a narrow funnel reaching from the clouds to the ground. Their wind speed goes from 65 to 250 miles per hour.
"An extreme weather condition in which we face the high speed wind in combination with heavy snow."
As for any blizzard has the normal wind speed of about 40 mph, and the visibility range reduces to less then 500 ft.
Answer: High winds, hail, excessive precipitation, and wildfires are forms and effects of severe weather, as are thunderstorms, downbursts, tornadoes, waterspouts, tropical cyclones, and extratropical cyclones. Regional and seasonal severe weather phenomena include blizzards (snowstorms), ice storms, and duststorms.
Explanation:
True or False If the mass of the object increases, then the potential energy of the object decreases.
I can learn new things but I cannot change how good I am at math. A strongly agree B. agree C disagree D. strongly disagree
Mathematics is a broad subject that anyone who constantly practices by learning from first principle and from example will grow in perfection of the subject as time goes by. Hence, I strongly disagree
During my schools days, I struggled learning mathematics, at the time it was difficult, I began practising and learning from text examples, with time I got a hang of it and my grade and confidence level in the subject increased.
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A mass of 0.01 kg of steam at a quality of 0.9 is contained in the cylinder as shown in Figure 1 below. The spring just touches the top of the piston. Heat is then added until the air expanded, and the spring is compressed by 15.7 cm. Calculate the final temperature of the steam in this cylinder. Sketch the process on a P-y and T-v diagrams with respect to saturation lines.
Which statement about cultural differences in reinforcement is TRUE?
A. People from individualistic cultures may find the ability to get relatives jobs more reinforcing than people from
collectivistic cultures.
B. People from individualistic cultures may find awards that single them out as more reinforcing than people from
collectivistic cultures.
C. Women from individualistic cultures may place more importance on convenient working hours than women from
collectivistic cultures.
D. People from individualistic cultures find higher pay more reinforcing than people from collectivistic cultures.
People often wants to be recognized for their achievement. The true statement is that People from individualistic cultures may find awards that single them out as more reinforcing than people from
collectivistic cultures.
Individualism is simply known as a type of cultural system that place huge emphasis on the needs of the individual self more than those of the group/society.It is often based on the individual self and its specific qualities that distinguishes one from others.
Collectivism is simply known as a cultural system that place emphasis on the needs of the group/society more than our self need self.
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Find the net torque .
Answer:
Explanation:
I will ASSUME this means torque about the dot.
3) 20(3) + 10(6) - 30(4) = 0 N•m
4) 10(0.5) - 6sin45(1) = -0.7573593... or about 0.76 N•m CCW
5) 25(3) - 40sin30(4) = -5 N•m or 5 N•m CCW
6) 15(3) - 12(2) - 10sin45(6) = -21.4264068... or about 21 N•m CCW
A tightly sealed house has a large ceiling fan that blows air out of the house and into the attic. The owners turn the fan on and forget to open any windows or doors. What happens to the air pressure in the house after the fan has been on for a while, and does it become easier or harder for the fan to do its job
Answer:
Assuming the attic is ventilated to the open air the air pressure inside the house gets lower and the fan job becomes easier. It will speed up because while the pressure differential across the fan is increased, the mass of air being moved has decreased.
This can be verified by running a household vacuum cleaner in hose mode. With the hose open and air moving through it, the motor speed will be at a certain level producing a certain noise pitch . Placing your hand over the hose end will decrease the pressure in the hose, reduce the volume of air moving and you will hear an increase in motor pitch as it speeds up under lower load conditions.
The area inside the vacuum hose is akin to the inside of a well sealed house with an attic fan running.
In the physical sciences, pressure is compressive stress at quite a point within a confined fluid or the perpendicular force per unit area.
What is Pressure?The force exerted perpendicularly to an object's surface per unit area across which that force is dispersed is termed as pressure. In relation to the surrounding pressure, gauge pressure is the pressure.
The air pressure within the house decreases and the fan's task gets simpler if the attic is aired to the outside air. It will increase because the amount of air being moved is much less, while the pressure difference across the fan is greater.
Running a home vacuum in hose mode will demonstrate this. The motor speed will be maintained at a set level, producing a specific noise pitch, with the duct open and air flowing through it. You will notice an increase in motor pitch when it speeds up under reduced load situations by placing your finger over the hose end, which will also lower the pressure in the hose and limit the amount of air moving.
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True or False If the mass of the object increases, then the potential energy of the object decreases.
Answer:
The amount of gravitational potential energy an object has depends on its height and mass. The heavier the object and the higher it is above the ground, the more gravitational potential energy it holds. Gravitational potential energy increases as weight and height increases.
Explanation:
Answer:
Explanation:
It depends on where your reference frame for potential energy is chosen.
If a mass is above the reference origin and mass increases, potential energy will increase so the statement is FALSE
If the mass is at the reference origin and the mass increases, the potential energy stays constant at zero so the statement is FALSE
If the mass is below the reference origin and the mass increases, then the potential energy goes from a negative value to an even lower negative value so the statement in this case is TRUE
A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:
The wavelengths of the constituent travelling waves CANNOT be 400 cm.
The given parameters:
Length of the string, L = 100 cmThe wavelengths of the constituent travelling waves is calculated as follows;
[tex]L = \frac{n \lambda}{2} \\\\n\lambda = 2L\\\\\lambda = \frac{2L}{n}[/tex]
for first mode: n = 1
[tex]\lambda = \frac{2\times 100 \ cm}{1} \\\\\lambda = 200 \ cm[/tex]
for second mode: n = 2
[tex]\lambda = \frac{2L}{2} = L = 100 \ cm[/tex]
For the third mode: n = 3
[tex]\lambda = \frac{2L}{3} \\\\\lambda = \frac{2 \times 100}{3} = 67 \ cm[/tex]
For fourth mode: n = 4
[tex]\lambda = \frac{2L}{4} \\\\\lambda = \frac{2 \times 100}{4} = 50 \ cm[/tex]
Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.
The complete question is below:
A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:
A. 400 cm
B. 200 cm
C. 100 cm
D. 67 cm
E. 50 cm
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A disgruntled physics student, frustrated with
finals, releases his tensions by bombarding the
adjacent building, 13.5 m away, with water
balloons. He fires one at 38◦
from the horizontal with an initial speed of 23.6 m/s.
The acceleration of gravity is 9.8 m/s
2
.
For how long is the balloon in the air?
Answer:
Explanation:
The balloon would require a time of
t = d/v = 13.5/ (23.6cos38) = 0.7259...s
to travel the horizontal distance.
the vertical position relative to the throw point at that time is
h = 0 + (23.6sin38)(0.7259) + ½(-9.8)(0.7259²)
h = 7.9652...
so as long as the adjacent building is at least 8.0 m higher than the student position, the balloon is in the air for 0.726 s.
If the building is shorter than 8.0 m above the student, the balloon will land on the building roof and will be in the air for a longer period of time
a 0.015 kg bullet traveling at 500 m/s strikes a 1.0 kg block of wood that is balanced on a table edge 0.92 m above the ground as shown to the right. the bullet buries itself in the block. calculate the horizontal distance, dx where the block hits the floor.
The horizontal distance where the block hits the floor is 3.2 m.
The given parameters:
mass of the bullet, m₁ = 0.015 kgspeed of the bullet, u₁ = 500 m/smass of block wood, m₂ = 1.0 kgheight of the table, h = 0.92 mThe final velocity of the bullet-block system after the collision is calculated by applying the principle of conservation of linear momentum;
[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\0.015(500) + 1(0) =v(0.015 + 1)\\\\7.5 = 1.015v\\\\v = \frac{7.5}{1.015} \\\\v = 7.39 \ m/s[/tex]
The time taken for the bullet-block system to fall to the floor after collision is calculated as follows;
[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.92}{9.8} }\\\\t = 0.43 \ s[/tex]
The horizontal distance where the block hits the floor is calculated as follows;
[tex]X = v_x t\\\\X = 7.39 \times 0.43\\\\X = 3.2 \ m[/tex]
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A body is moving along a circular path with variable speed, it has both radial and tangential acceleration.
Select one:
True
False
Answer:
True; ar = v^2 / R Radial acceleration because it moves in a circular path
at = α R = tangential acceleration because its speed changes
a = at + ar total acceleration equals sum of radial and tangential
Can someone help me with this problem?
Answer:
no
Explanation:
u flipped it i cant see
Which of these do not affect fluid friction?
The surface of an object
The viscosity (thickness) of fluid an object is in
The shape of an object
The weight of an object
A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. The total mechanical energy is 25 J. The maximum speed of the block is:
Answer:
Explanation:
easy way
when system is all kinetic energy, velocity is at a maximum
E = ½mv²
v = √(2E/m) = √(2(25)/0.5) = √100 = 10 m/s
harder way
ω = √(k/m) = √(80/0.5) = √160 rad/s
When the system is entirely spring potential, the amplitude A is
E = ½kA²
A = √(2E/k) = √(2(25)/80) = 0.790569... = 0.79 m
maximum velocity is ωΑ = 0.79√160 = 10 m/s
A 2-kg object moving at 10 m/s has a 4-N force applied to it. Can you predict how the force will affect the object? A) yes, it will slow it down at a rate of 2 m/s2. B) yes, it will speed it up at a rate of 2 m/s2. yes, it will speed it up at a rate of 4 m/s2. D) It cannot be determined without more information.
Answer:
D) It cannot be determined without more information.
Explanation:
Velocity is a vector meaning it has both magnitude and direction.
Force and acceleration are also vectors.
Without knowing the directions of each, we cannot know if the mass has a speed (scalar value) change.
We can know that the mass will have a velocity change at the rate of 2 m/s² in the direction of the applied force.
If that force is applied in the direction of initial velocity, the velocity (and speed) will increase in magnitude in the same direction.
If that force is applied opposite of the initial velocity, the the velocity (and speed) will decrease in magnitude in the same direction. If the acceleration lasts long enough, velocity will eventually become zero and then become negative. At the same time, speed will become zero, and then increase again as speed is the absolute value of the magnitude of velocity.
If the force is applied at any other angle, both the velocity and the speed will change in both magnitude and direction.
The number of wavelengths that pass a fixed point on a wave is called ______?
Explanation:
it's called a wave frequency
im pretty sure but than again I'm in Middle School but just trust me
Answer:
wave frequency i think. hope its helps
Colloid - well ______ together but not ______________
Answer:Colloid - well compacted together but not one
Which of the following waves DO NOT require a medium to travel?
Answer:
hey man, think you forgot to put the questions
Answer This!!!!!!
I'll give brainliest to whoever gets it right.
And 100 Points!
Answer: Time (days) = 88, the (mass) = 0.2180
Explanation:
Time (days) = 88, the (mass) = 0.2180
How might "Roller Coaster Physics" have been different if the author's purpose had been to warn
readers of the dangers of roller coasters?
Use at least two details from the passage to support your answer.
Answer: The answer is hupa loopa
Explanation:
3. A car travelling at 12 m/s into a stationary truck of about 10 times the cars mass. a. If the collision was completely inelastic, what velocity would the two travel at if the stuck together? b. If the collision was completely elastic, what would be the velocities of the car and truck after the collision? c. In order to exert a force of only 3500N on the truck during the collision, how much time would the collision have to take?
(a) The final velocity of the two vehicles if the collision was inelastic is 1.1 m/s.
(b) For the elastic collision, the final velocity of the car is 9.81 m/s backwards and the final velocity of the truck is 2.19 m/s forward.
(c) The time taken to exert the given force is 0.00625 m (s).
The given parameters;
Initial velocity of the car, u₁ = 12 m/sInitial velocity of the truck, u₂ = 0Mass of the car, = mMass of the truck, = 10m(a) The final velocity of the two vehicles if the collision was inelastic is calculated as follows;
[tex]m_1 u_1 + m_2u_2 = v(m_1+ m_2)\\\\12m + 10m(0) = v(m + 10m)\\\\12m = v(11m)\\\\v = \frac{12m}{11m} \\\\v = 1.1 \ m/s[/tex]
(b) The final velocity of the two vehicles if the collision was elastic is calculated as follows;
[tex]m_1 u_1 + m_2u_2 = m_1v_1 + m_2v_2\\\\\12m \ + \ 10m(0) = mv_1 + 10mv_2\\\\12m = m(v_1 + 10v_2)\\\\12 = v_1 + 10 v_2\ \ - --(1)[/tex]
Apply one-directional velocity equation:
[tex]u_1 +v_1 = u_2 + v_2\\\\12 + v_1 = 0 + v_2\\\\12+ v_1 = v_2 \ \ --- (2)[/tex]
Substitute the value of [tex]v_2[/tex] into equation (1);
[tex]12 = v_1 + 10(12 + v_1)\\\\12= v_1 + 120 + 10v_1\\\\12- 120 = 11v_1\\\\-108 = 11v_1\\\\v_1 = \frac{-108}{11} \\\\v_1 = -9.81 \ m/s\\\\[/tex]
Solve for [tex]v_2[/tex];
[tex]v_2 = 12 + v_1\\\\v_2 = 12 - 9.81\\\\v_2 = 2.19 \ m/s[/tex]
Thus, for the elastic collision, the final velocity of the car is 9.81 m/s backwards and the final velocity of the truck is 2.19 m/s forward.
(c)
The change in the momentum of the truck is calculated as;
[tex]\Delta P = m_2(v_2 - u_2)\\\\\Delta P = 10m(2.19)\\\\\Delta P = 21.9m[/tex]
The time taken to exert the given force is calculated as follows;
[tex]Ft = \Delta P\\\\t = \frac{\Delta P}{F} \\\\t = \frac{21.9 \ m}{3500} \\\\t = 0.00625 \ m (seconds)[/tex]
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An object accelerates at a rate of -3.2 m/s^2 to a velocity of 8 m/s over a time of 14 s. What was its initial velocity?
[tex]\text{Given that,}\\\\\text{Acceleration, a = -3.2 m s}^{-2}\\\\\text{Time, t = 14 sec}\\\\\text{Velocity, v = 8 m s}^{-1}\\\\\text{Initial velocity, v}_0 = ?\\\\\\v = v_0 +at\\\\\implies v_0 = v -at = 8 -(-3.2)(14) = 8 + 44.8 =52.8~ \text{m s}^{-1}[/tex]
How much potential energy does an 8 kg flower pot hanging 5 m above the ground have
Answer:
Explanation:
Relative to ground level it has
PE = mgh = 8(10)(5) = 400 J
A student catches a can of soda dropped from some unknown height by Mr. Fineman. If
the can was dropped from rest, and it is traveling at 8.9 m/s before it arrives in the
student's hand...
Answer:
v² = u² + 2gh
8.9² = 0² + 2(9.8)h
h = 4.0 m
v = at
t = 8.9/9.8
t = 0.91 s
