10 + 25
The expression represents a quadraticy polynomial with
terms. The constant
term is
the leading term is
and the leading coefficient is

Answer:

shape name is it square or rectangle is needed to be told

Step-by-step explanation:

if it's square then area is 9cm^2

Answer:

66ft^2

Step-by-step explanation:

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

[tex]Event\ 1 = \{1,2,3,4,5,6\}[/tex]

Next, we list out the sample space of F

[tex]Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\[/tex]

[tex]6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}[/tex]

In (1): the sample space of E is:

[tex]E = \{1\}[/tex]

So:

[tex]P(E) = \frac{n(E)}{n(Event\ 1)}[/tex]

[tex]P(E) = \frac{1}{6}[/tex]

In (2): the sample space of F is:

[tex]F = \{5,5,5,5\}[/tex]

So:

[tex]P(F) = \frac{n(F)}{n(Event\ 2)}[/tex]

[tex]P(F) =\frac{4}{36}[/tex]

[tex]P(F) =\frac{1}{9}[/tex]

For E and F to be independent:

[tex]P(E\ and\ F) = P(E) * P(F)[/tex]

Substitute values for P(E) and P(F)

This gives:

[tex]P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}[/tex]

[tex]P(E\ and\ F) = \frac{1}{54}[/tex]

However, the actual value of P(E and F) is 0.

This is so because [tex]E = \{1\}[/tex] and [tex]F = \{5,5,5,5\}[/tex] have 0 common elements:

So:

[tex]P(E\ and\ F) = 0[/tex]

Compare [tex]P(E\ and\ F) = \frac{1}{54}[/tex] and [tex]P(E\ and\ F) = 0[/tex].

These values are not equal.

Hence: the two events are not independent

Answer:

80 +30h

Step-by-step explanation:

Answer:

80 + 30h

Step-by-step explanation:

Distribute the 10 over the (8 + 3h). This means: multiply 10 by 8 and by 3h.

10 x 8 = 80

10 x 3h = 30h

10(8 + 3h) = 80 + 30h

Answer:

30

Step-by-step explanation:

If CUB is 78 and that’s the full angle just to 48 minus 78 and you get your answer.

Hi there! :)

[tex]\large\boxed{\text{ x = 0, or (0, 2)}}[/tex]

The solution of g(x) = 3x + 2 and f(x) = |x - 1| + 1 is where the two lines intersect.

According to the graph, the functions intersect at the point (0, 2), or x = 0. This is the solution to the system of equations.

We could also prove this algebraically by setting the two equations equal to each other:

3x + 2 = | x - 1 | + 1

Assume the absolute value function is negative:

3x + 2 = -(x - 1) + 1

Simplify:

3x + 2 = -x + 2

Add x to both sides:

4x + 2 = 2

Subtract 2 from both sides:

4x = 0

x = 0. This is the solution to the system.

Answer:

0.0625 should be the answer of .5 to the fourth power.

Answer:

20.5

Step-by-step explanation:

Answer:

n =1.78

Step-by-step explanation:

2(5n-6)

2(n+1)

10n-12+4n+2=15

14n-10=15

subtract both sides by 10

14n=25

25/14

n=n =1.78571428571

[tex]\huge{\mathfrak{\purple{Answer}}}[/tex]

Equation: x² - 15x = 16

Factors: x = -16 and x = 1

[tex]\huge{\mathfrak{\purple{Explanation}}}[/tex]

Given

A number squared minus fifteen times the number is equal to 16.

Equation: x² - 15x = 16

Factors:

x² - 15x - 16 = 0

So,

(x - 16) (x + 1)

=> x - 16 = 0, x + 1 = 0

= x = -16 and x = 1

#HopeItHelps

Answer:

Step-by-step explanation:

2 to 5 or 2:5

      or

2 to 3 or 2:3

Answer:

124

Step-by-step explanation:

You can find this answer by simply multiplying 62 by 2. lol

Answer:

a. [tex]m(t) = 26.67 - 26.67e^{-0.03t}[/tex] b. 7.44 s

Step-by-step explanation:

a. If the concentration of salt in the brine entering the tank is 0.2 kg/L, determine the mass of salt in the tank after t min.

Let m(t) be the mass of salt in the tank at any time, t.

Now, since a brine solution flows in at a rate of 4 L/min and has a concentration of 0.2 kg/L, the mass flowing in per minute is m' = 4 L/min × 0.2 kg/L = 0.8 kg/min

Now, the concentration in the tank of volume 100 L at any time, t is m(t)/100 L. Since water flows out at a rate of 3 L/min, the mass flowing out per minute is

m(t)/100 × 3 L/min = 3m(t)/100 kg/min

Now the net rate of change of mass of salt in the tank per minute dm/dt = mass flowing in -mass flowing out

dm/dt = 0.8 kg/min - 3m(t)/100 kg/min

So, dm/dt = 0.8 - 0.03m(t)

The initial mass of salt entering m(0) = 0 kg

dm/dt = 0.8 - 0.03m(t)

separating the variables, we have

dm/[0.8 - 0.03m(t)] = dt

Integrating, we have

∫dm/[0.8 - 0.03m(t)] = ∫dt

-0.03/-0.03 × ∫dm/[0.8 - 0.03m(t)] = ∫dt

1/(-0.03)∫-0.03dm/[0.8 - 0.03m(t)] = ∫dt

-1/0.03㏑[0.8 - 0.03m(t)] = t + C

㏑[0.8 - 0.03m(t)] = -0.03t - 0.03C

㏑[0.8 - 0.03m(t)] = -0.03t + C'  (C'= -0.03C)

taking exponents of both sides, we have

[tex]0.8 - 0.03m(t) = e^{-0.03t + C'} \\0.8 - 0.03m(t) = e^{-0.03t}e^{C'}\\0.8 - 0.03m(t) = Ae^{-0.03t} A = e^{C'}\\0.03m(t) = 0.8 - Ae^{-0.03t}\\m(t) = 26.67 - \frac{A}{0.03} e^{-0.03t}\\when t = 0 \\m(0) = 0\\m(0) = 26.67 - \frac{A}{0.03} e^{-0.03(0)}\\\\0 = 26.67 - \frac{A}{0.03} e^{0}\\26.67 = \frac{A}{0.03} \\\frac{A}{0.03} = 26.67\\\frac{A}{0.03} = 6.67\\A = 26.67 X 0.03\\A = 0.8\\m(t) = 26.67 - \frac{A}{0.03} e^{-0.03t}\\\\m(t) = 26.67 - \frac{0.8}{0.03} e^{-0.03t}\\[/tex]

So, the mass of the salt after t min is

[tex]m(t) = 26.67 - 26.67e^{-0.03t}[/tex]

b. When will the concentration of salt in the tank reach 0.1 kg/L?

When the concentration of the salt reaches 0.1 kg/L, m(t) = 0.1 kg/L

Solving the equation for t,

[tex]m(t) = 26.67 - 6.67e^{-0.03t}\\0.1 = 26.67 - 26.67e^{-0.03t}\\26.67e^{-0.03t} = 26.67 - 0.1\\26.67e^{-0.03t} = 26.57\\e^{-0.03t} = 26.56/26.67\\e^{-0.03t} = 0.9963\\[/tex]

taking natural logarithm of both sides, we have

-0.03t = ㏑0.9963

-0.03t = -0.0038

t = -0.0038/-0.03

t = 0.124 min

t = 0.124 × 60 s

t = 7.44 s

Answer:

1300

Step-by-step explanation:

Answer:x=11/2+y/2

Step-by-step explanation:

The solution of the given system of equation would be (6, 2)

Two or more equations to be solved together, i.e., the solution must satisfy all the equations in the system.

We have Given the equations, 3x + 2y = 22

-x + 4y = 2

Solving by elimination, Multiplying the second equation by 3,

3x+2y = 22

-3x + 12y = 6

Adding the equation, we get;

2y+12y = 22+6

24y = 28

y = 2

Putting y=2 we get;

3x+2*2=22

3x+4 = 22

3x = 18

x = 6

Hence, The solution is (6, 2)

For more references on system of equations, click;

brainly.com/question/24065247

#SPJ2

Answer:

First blank: Divide

Second blank: Multiply

Third blank: 25

Step-by-step explanation:

For the first part, you would divide to get X as itself

For the second part, you would multiple to cancel out the fraction and be left with whole numbers, which is much easier to work with

1.3 x 25 = 32.5, so that would be that answer

Answer:

Correct Answer - It shows the unit rate of the graph in miles per hour.

Step-by-step explanation:

hope this helps

Answer:

$80.99

Step-by-step explanation:

Turn the percentage into a decimal.

19% -> 0.19

Multiply.

99.99 * 0.19 ≈ 19

Subtract.

99.99 - 19 = 80.99

Best of Luck!

Answer:

7.48

Step-by-step explanation:

find what 6% of 7.95 is and then subtrct that from 7.95 which gives u ur answer

Answer:

The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A study suggested that children between the ages of 6 and 11 in the US have an average weightof 74 lbs, with a standard deviation of 2.7 lbs.

This means that [tex]\mu = 74, \sigma = 2.7[/tex]

What proportion of childrenin this age range between 70 lbs and 85 lbs.

This is the pvalue of Z when X = 85 subtracted by the pvalue of Z when X = 70. So

X = 85

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{85 - 74}{2.7}[/tex]

[tex]Z = 4.07[/tex]

[tex]Z = 4.07[/tex] has a pvalue of 1

X = 70

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{70 - 74}{2.7}[/tex]

[tex]Z = -1.48[/tex]

[tex]Z = -1.48[/tex] has a pvalue of 0.0694

1 - 0.0694 = 0.9306

The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

Answer:

[tex]n + 4.4 = 8.1[/tex]

Step-by-step explanation:

We know we have to write an algebraic equation for the sentence - so "translate" the phrases of the sentence step-by-step. Let the unknown number be represented by the variable n, as the question states.

Start with the phrase "the sum of a number and 4.4." A sum comes as a result of adding numbers together - therefore the first part of the equation must be [tex]n + 4.4[/tex].

Next, the sentence says "is 8.1." The "is" indicates that the expression we just wrote equals something, so that number must be 8.1. Therefore, the whole equation must be [tex]n + 4.4 = 8.1[/tex].

Answer:

Angles and sides are the main differences! In a rectangle, all angles will be 90 degrees. In a rhombus, opposite angles will always be congruent. And, all sides in a rhombus are congruent, while in a rectangle, opposite sides are congruent

Step-by-step explanation:

here

work=force* distance

=100*5

=500 joules

=500/15

=33.33 Watts.

Answer:

40%

Step-by-step explanation:

Answer:

If you need help on further questions like this, divide what he has to what he needs or his goal

in order to get 37.5% you have to divide 75/ 200

You will get 0.357 and that is 37.5% this is ABOUT 40% but I reccomend putting 37.5% to be safe.