A ​17-foot ladder is placed against a vertical wall of a​ building, with the bottom of the ladder standing on level ground feet from the base of the building. How high up the wall does the ladder​ reach?

Answers

Answer 1

Answer:

15 feet..

taking base as 8m

Given: ladder = 17 m and base = 8 m

The ladder forms a right triangle with the base of 8 m, the wall will be 15 m and the ladder (hypotenuse) is 17 m.

Let’s say you did not know that this was a standard 8–15–17 right triangle.

This is how you can figure it out:

hypotenuse(h)22 = side2112 + side2222

Let side11 = base and side22 = wall

1722 = 822 + wall22

wall = 172−82−−−−−−−√172−82

wall = 289−64−−−−−−−√289−64

wall = 225−−−√225

wall = 15 feet

Answer 2

Height of wall is 15 feet

Given:

Length of ladder = 17 feet

Base distance from ladder = 8 feet (Missing information)

Find:

Height of wall

Computation:

Length of ladder = hypotenuse

Base distance from ladder = Base

Height of wall = Perpendicular

Using Pythagorean theorem

[tex]Perpendicular = \sqrt{Hypotenuse^2 - Base^2}[/tex]

By putting values

[tex]Perpendicular = \sqrt{17^2 - 8^2}[/tex]

[tex]Perpendicular = \sqrt{289 - 64} \\\\Perpendicular = \sqrt{225} \\\\Perpendicular = 15[/tex]

Height of wall = 15 feet

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A 17-foot Ladder Is Placed Against A Vertical Wall Of A Building, With The Bottom Of The Ladder Standing

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