A business woman bought a stove for $1209.calculate the selling price of the stove if she made a profit of 11%. (B) the stove was damage in transporting it to the customer . determine the selling price of the stove if she incurred a loss of 8% on the cost price​

Answer:

A(9,3)

B(9,0)

C(5,1)

Step-by-step explanation:

Answer:

D. Five pounds of oats are divided equally among eight horses.

Step-by-step explanation:

A scenario representing 5/8 has to involve a quantity of 5 being divided by 8.

The situation with the oats and horses represents 5/8, because the 5 pounds of oats are being equally divided among the 8 horses.

The other answer choices are incorrect because they are dividing 8 by 5 instead, which is 8/5 instead of 5/8.

So, the correct answer is D. Five pounds of oats are divided equally among eight horses.

Answer:

2x-4(x+7)=2

Step-by-step explanation:

Peter's age:x.... twice age:2x

Phil's age:x+7...4times age:4(x+7)

Difference if ages is 2

Hence; 2x-4(x+7)=2

Answer:

Answer

4.9/5

38

loitzl9006

Ambitious

54 answers

6.5K people helped

Answer:

x=25

Step-by-step explanation:

we know that "x" is Peter's age

assume that "y" is Phil's age

In the sentence "Phil's age is 7 years more than 1/5 times than Peter's age" are two things: "Phil's age": y and "1/5 times Peter's age": 1/5 x

create equation with these two things

y = 1/5 x

including "7 years more"

many people make a lot of errors with it, they dont know: y+7 = 1/5 x or y=1/5 x + 7 ?

in order to avoid mistakes

read the sentence and point, which: y or 1/5 x is greater and smaller

"Phil's age is 7 years more than ..."

so y is greater, and 1/5 x smaller

y = 1/5 x

greater = smaller

we must add 7 to smaller number to make an equality

greater = smaller + 7

y = 1/5 x + 7

Second sentence:

"4 times Phil's age is 2 years less than twice Peter's age."

Two things: "4 times Phil's age": 4y and "twice Peter's age": 2x

4y = 2x

read the sentence once again

"4 times Phil's age is 2 years less than (...)" , so 4y - smaller, 2x - greater

4y = 2x

smaller = greater

including "2 years less" we add 2 to a smaller number

smaller + 2 = greater

4y + 2 = 2x

Substitute y=1/5 x + 7 to the equation 4y+2 = 2x

Step-by-step explanation:

Answer:

$5.00

Step-by-step explanation:

$3.50+$1.50=$5.00

Answer:

0

Step-by-step explanation:

Replace q with 7 .

[tex]7 + ( - 7) = 0[/tex]

[tex] \sf \: q + ( - 7) \\ \sf \: q = 7 \\ \\ \sf \: q + ( - 7) \\ \sf= 7 + ( - 7) \\ \sf= 7 - 7 \\ \sf= \boxed{\bf \: 0}[/tex]

Hope it helps.

RainbowSalt2222

Answer:

y=(4-2x)/3

Step-by-step explanation:

3y= 4-2x

y= (4-2x)/3

Answer:

0.5

Step-by-step explanation:

k = y/x

k = 0.5/1

k = 0.5

Answer:

0.1667 = 16.67% probability that they are both black.

Step-by-step explanation:

The balls are drawn without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

5 + 4 = 9 balls, which means that [tex]N = 9[/tex]

4 are black, which means that [tex]k = 4[/tex]

2 are chosen, which means that [tex]n = 2[/tex]

What is the probability that they are both black?

This is P(X = 2). So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 2) = h(2,9,2,4) = \frac{C_{4,2}*C_{5,0}}{C_{9,2}} = 0.1667[/tex]

0.1667 = 16.67% probability that they are both black.

Answer:

Đổi 60% = 3/5

a) Số học sinh trung bình là:  40 * 1/4 = 10 (hsinh)

Tổng số hsk và hsg là:  40 - 10 = 30 (hsinh)

Số học sinh khá bằng 60% số học sinh còn lại nên số hsk là:

             30 * 60% = 18 (hsinh)

Số học sinh giỏi là:  30 - 18 = 12 (hsinh)

b) Tổng số hs khá và giỏi chiếm số phần trăm trong lớp là:

             30 : 40 * 100 = 75%

(5,-8) after a 180 degree counterclockwise rotation about the origin is (-5,8)

Answer:

-3x(3x+5)(3x-4)

= -(9x²+15x)(3x-4)

= -27x³-9x²+60x

Answered by GAUTHMATH

Answer:

x=9 ⇒AC=24

Step-by-step explanation:

vì DE//B C⇒ΔABC  Tương ung ti tỉ lệ vớiv  ΔADE

⇒DB/AB=EC/AC

⇒AC=(EC.AB)/DB

⇒AC=24

Answer:

Step-by-step explanation:

The dimensions as a pair, appear twice for each combination.

SA = 2* 16 * 8 + 2 * 16 * 6 + 2*8* 6

That's because when you look at the figure, there are 2 places each face is positioned.

SA = 256 + 192 + 96

SA = 544

Answer:

125 sweets

Step-by-step explanation:

Let the total # of sweets the teacher bought be the variable, x.

We can set up this equation to find the # of sweets she bought:

40 · 3 + 5 = x

Because she gave 3 sweets each to her 40 students, we have to multiply these two numbers to get the # of sweets the teacher gave out.

120 + 5 = x

Then, since there's 5 extra sweets left, we can add it to the # of sweets the teacher gave out to get the total amount of sweets she bought.

125 = x

x = 125

125 sweets

Answer:

Total sweets = 125

Step-by-step explanation:

Number of sweets given to each student = 3

Number of sweets given to 40 students = 40*3 = 120

Number of sweets left with the teacher = 5

Total sweets = 120 + 5 = 125

Answer:

10 or -2 (Both work)

Step-by-step explanation:

Solve the equation |x - 4| = 6:

|x - 4| = 6

Now do the inverse operation of negative 4 to get positive 4.

|x - 4| = 6

  + 4  + 4

|x| = |10|

x = 10

Step-by-step explanation:

1. 22/60

2. LCM..of 3,9 is 9

So, 3+2/9 ( made the denominators equal)

5/9 Answer

Answer:

which of these fraction is not equivalent to 2/5 is 22/60

b) work out 1/2 + 2/9 = 5/9

Answer:

2.21

Step-by-step explanation:

Answer:

a + b = 5.30

a + b = 7

No

Step-by-step explanation:

Expressing the information as system of linear equation :

Let apples = a, oranges = b

If $5.30 is charged for one apple and one orange, then we have ;

a + b = 5.30 - - - (1)

If $14 is charged for 2 apples and 2 oranges, then we have ;

2a + 2b = 14 - - - - (2)

a + b = 7

Since both equations gives varying combined cost for equal amount of the fruit, then a unique cost cannot be obtained for each fruit from the systems of equation using simultaneous equation process.

From (1)

a = 5.30 - b

Put a = 5.30 - b in (2)

2(5.30 - b) + 2b = 14

10.6 - 2b + 2b = 14

10.6 = 14 - - - - - (variables cancels out).

Answer:No the System has no solution

Step-by-step explanation:

Answer: 5

Step-by-step explanation:

⇒ (x - 4) = 1

⇒ x = 1 + 4

⇒ x = 5

Therefore value of x = 5

Answered by Gauthmath must click thanks and mark brainliest

cosec(2t)=1/sin(2t) ==> 1/(2×cos(t)×sin(t))

cos(2t)= 1-2sin²t

or 2cos²t-1

or cos²t - sin²t

after we knew this informations we have to write it in the question

1/2×sint×cost-1/1/2×sint×cost=cos2t

-2×sint×cost+1/2sint×cost/1/2sint×cost=cos2t

the 2sint×cost will gone

-2×sint×cost+1=cos2t

lets take cos2t =1-2sin²t

-2×sint×cost+1=1-2sin²t

-2sint×cost=-2sin²t

cost=sint

that means the t is equal to 45 because sin45 and cos45 equal to √2/2

hopefully i didn't waste your time by reading and not understanding my English is not that good sorry

Answer:

see explanation

Step-by-step explanation:

Using the identities

cosec x = [tex]\frac{1}{sinx}[/tex]  , 1 - sin²θ = 1

Consider the left side

[tex]\frac{cosec^20-1}{cosec^20}[/tex]

= [tex]\frac{\frac{1}{sin^20}-\frac{sin^20}{sin^20} }{\frac{1}{sin^20} }[/tex]

= ( [tex]\frac{1}{sin^20}-\frac{sin^20}{sin^20}[/tex] ) × [tex]\frac{sin^20}{1}[/tex] ← distribute parenthesis by sin²θ

= 1 - sin²θ

= cos²θ

= right side, thus proven

Let

ATQ

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 40x+50x=45000[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 90x=45000[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow x=\dfrac{45000}{90}[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow x=500[/tex]

Now

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow Rita=50x=50(500)=25000[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow Mina=40x=40(500)=20000[/tex]

Answer:

Step-by-step explanation:

a.)

[tex]14*2^x[/tex]

b.)

[tex]14*2^7=1792[/tex]

Answer:

Step-by-step explanation:

a1=-8

a2=3

D=11

n=-8+11(n-1)

Answer:

pandn

Step-by-step explanation:

jsubeuodoqok1kwnebhxhhw

emdndiiwjwkd

d

ddnjd

Answer:

28.3

Step-by-step explanation:

A = [tex]\pi r^{2}[/tex]

Plug in:

A = [tex]\pi 3^{2}[/tex]

A = [tex]9 \pi[/tex]

A = 9 × 3.14 = 28.26 = 28.3

The answer is 28.3

Hope this helped.

Answer:

3/10

Step-by-step explanation:

3 red, 4 green, and 3 yellow balls = 10 balls

P(red) = number of red balls / total balls

           = 3/10

Answer:

It already shows the answers.

Step-by-step explanation:

I'm pretty sure you already submitted. The ones with check marks are correct and the ones with x marks are incorrect.

Answer:

(k) cos(θ)·√(1 + cot²θ) = √(cosec²θ - 1)

From trigonometric identities, we have;

1 + cot²θ = cosec²θ

On the Left Hand Side of the equation, we get;

cos(θ)·√(1 + cot²θ) = cos(θ) × cosec(θ) = cot(θ)

On the Right Hand Side of the equation, we have;

√(cosec²(θ) - 1) = √(1 + cot²(θ) - 1) = √(cot²(θ)) = cot(θ)

∴ √(cosec²θ - 1) = cot(θ)

By transitive property of equality, therefore;

cos(θ)·√(1 + cot²θ) = √(cosec²θ - 1)

(l) sin⁶A + cos⁶A = 1 - 3·sin²A·cos²A

sin⁶A + cos⁶A = (sin²A)³ + (cos²A)³

(sin²A)³ + (cos²A)³ = ((sin²A) + (cos²A))³ - 3·((sin²A)·(cos²A))·((sin²A) + (cos²A))

∴ (sin²A)³ + (cos²A)³ = (1)³ - 3·((sin²A)·(cos²A))·(1) = 1 - 3·((sin²A)·(cos²A))

sin⁶A + cos⁶A = (sin²A)³ + (cos²A)³ = 1 - 3·((sin²A)·(cos²A))

sin⁶A + cos⁶A = 1 - 3·((sin²A)·(cos²A))

(m) (sinA - cosecA)² + (cosA - secA)² = cot²A + tan²A - 1

(sinA - cosecA)²  = sin²A - 2×sinA×cosecA + cosec²A = sin²A - 2 + cosec²A

(cosA - secA)² = cos²A - 2×cosA×secA + sec²A = cos²A - 2 + sec²A

∴ (sinA - cosecA)² + (cosA - secA)² = sin²A - 2 + cosec²A + cos²A - 2 + sec²A

Where;

sin²A - 2 + cosec²A + cos²A - 2 + sec²A = sin²A + cos²A  - 2  - 2 + cosec²A + sec²A

sin²A + cos²A  - 2  - 2 + cosec²A + sec²A = 1 - 4 + cosec²A + sec²A

1 - 4 + cosec²A + sec²A = cosec²A + sec²A - 3

Where;

cosec²A = cot²A + 1

sec²A = tan²A + 1

∴ cosec²A + sec²A - 3 = cot²A + 1 + tan²A + 1 - 3 = cot²A + tan²A - 1 = The Right Hand Side of the equation

∴ (sinA - cosecA)² + (cosA - secA)² = cot²A + tan²A - 1

(n) [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex] = sinA - cosA

Squaring the Right Hand Side of the equation, we get;

(sinA - cosA)² = sin²A -2·sinA·cosA + cos²A = sin²A + cos²A -2·sinA·cosA

sin²A + cos²A -2·sinA·cosA = 1 - 2·sinA·cosA

∴ (sinA - cosA)² =  1 - 2·sinA·cosA

Taking the square root of both sides gives;

√((sinA - cosA)²) = [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex]

∴ sinA - cosA = [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex]

By symmetric property of equality, we have;

[tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex] = sinA - cosA

Step-by-step explanation: