Answer:
0.0015 = 0.15% probability that if the motel books 150 guests, not enough seats will be available.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].
150 guests booked:
This means that [tex]n = 150[/tex]
85% of booked guests show up for their room.
This means that [tex]p = 0.85[/tex]
Is the normal approximation suitable:
[tex]np = 150(0.85) = 127.5[/tex]
[tex]n(1-p) = 150(0.15) = 22.5[/tex]
Both greater than 10, so yes.
Mean and standard deviation:
[tex]\mu = E(X) = np = 150*0.85 = 127.5[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{150*0.85*0.15} = 4.3732[/tex]
Find the probability that if the motel books 150 guests, not enough seats will be available.
More than 140 show up, which, using continuity correction, is [tex]P(X > 140 + 0.5) = P(X > 140.5)[/tex], which is 1 subtracted by the p-value of Z when X = 140.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{140.5 - 127.5}{4.3732}[/tex]
[tex]Z = 2.97[/tex]
[tex]Z = 2.97[/tex] has a p-value of 0.9985.
1 - 0.9985 = 0.0015.
0.0015 = 0.15% probability that if the motel books 150 guests, not enough seats will be available.
Find the first five terms to an=2an-1+3, a1=6
Answer:
a1=6 a2=15 a3=33 a4=69 a5=141
Step-by-step explanation:
an=2an-1+3
We should attempt n=2 to find the second term
a2=2a1+3= 2*6+3=15
n=3 to find the third term
a3=2a2+3= 2*15+3=33
n=4 to find the fourth term
a4=2a3+3=2*33+3=69
n=5 to find the fifth term
a5= 2a4+3=2*69+3= 141
If 2x - 5y – 7 = 0 is perpendicular to the line ax - y - 3 = 0 what is the value of a ?
A) a =2/3
B) a =5/2
C) a = -2/3
D) a = -5/2
Answer:
D) a = - 5/2
Step-by-step explanation:
2x -5y - 7 = 0
5y = 2x - 7
y = 2/5 x - 7
the slope of this line is therefore 2/5 (factor of x).
the perpendicular slope is then (exchange y and x and flip the sign) -5/2, which is then a and the factor of x.
Write the inequality shown in this graph.
Answer:
y > -1/2 x + 4
Step-by-step explanation:
Equation of a line : (y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-4)/(2-4)= (x-0)/(4-0)
(y-4)/-2 = x/4
(-y+4)/2 = x/4
-y+4 = 1/2 x
-y = 1/2 x - 4
y = -1/2 x + 4
the solutions of the inequality are the points above this line, so
y > -1/2 x + 4
Diego Company manufactures one product that is sold for $75 per unit in two geographic regions—the East and West regions. The following information pertains to the company’s first year of operations in which it produced 57,000 units and sold 52,000 units. Variable costs per unit: Manufacturing: Direct materials $25 Direct labor $18 Variable manufacturing overhead $3 Variable selling and administrative $5 Fixed costs per year: Fixed manufacturing overhead $627,000 Fixed selling and administrative expenses $645,000 The company sold 36,000 units in the East region and 16,000 units in the West region. It determined that $310,000 of its fixed selling and administrative expense is traceable to the West region, $260,000 is traceable to the East region, and the remaining $75,000 is a common fixed expense. The company will continue to incur the total amount of its fixed manufacturing overhead costs as long as it continues to produce any amount of its only product. Required: What is the company’s net operating income (loss) under absorption costing?
Answer:
626949
Step-by-step explanation:
Find the dimensions of the rectangle of largest area that can be inscribed in an equilateral triangle of side L if one side of the rectangle lies on the base of the triangle.
base=
height=
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Answer:
base: L/2height: L√3/2Step-by-step explanation:
Let x represent the ratio of the rectangle base to the triangle side length. Then the height of the small triangle above the rectangle will be x times the height of the equilateral triangle. Then the height of the rectangle is (1-x) times the height of the equilateral triangle. The rectangle's area will be ...
A = bh
A = (xL)(1-x)(L·√3/2) = (L²√3/2)(x)(1-x)
This graphs as parabola opening downward with x-intercepts at x=0 and x=1. The vertex is on the line of symmetry, halfway between these zeros, at x = 1/2.
The base of the rectangle is L/2.
The height of the rectangle is L√3/2.
_____
The general solution to this sort of problem is that one side of the rectangle is the midsegment of the triangle.
At a university of 25,000 students, 18% are older than 25. The registrar will draw a simple random sample of 242 of the students. The percentage of students older than 25 in the sample has an expected value of 18% and a standard error of:______.
Answer:
Standard error of: 2.47%
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
18% are older than 25.
This means that [tex]p = 0.18[/tex]
Simple random sample of 242 of the students.
This means that [tex]n = 242[/tex]
Standard error:
By the Central Limit Theorem:
[tex]s = \sqrt{\frac{0.18*0.82}{242}} = 0.0247[/tex]
0.0247*100% = 2.47%
Standard error of: 2.47%
plz help with this:)
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Answer:
-4
Step-by-step explanation:
The point (x, y) = (0, 0) is on the line, so it represents a proportional relation. Any ratio of y to x will be the slope. The choice that makes this computation easiest is ...
x = 1, y = -4
y/x = -4/1 = -4
The slope of the line is -4.
WILL GIVE BRAINIEST PLEASE WRITE IN ''f(x) = a(b)^x'' ORDERAn industrial copy machine has the ability to reduce image dimensions by a certain percentage each time it copies. A design began with a length of 16 inches, represented by the point (0,16). After going through the copy machine once, the length is 12, represented by the point (1,12).
Answer:
f(x) = 16*0.75^x
Step-by-step explanation:
first off let's use this coordinate (the one given) :
(0,16)
let's substitute this into the equation with x being 0 and f(x) being 16
16 = a*b^0
*anything to the power of 0 is 1*
so:
a = 16
now use the second coordinate :
(1,12)
and do the same by substituting 1 for x and 12 for f(x), we also know what 'a' is:
12 = 16*b^1
12 = 16 * b
b = 3/4
so :
f(x) = 16*0.75^x
Answer:
f(x) = 16(.75)^x
Step-by-step explanation:
How to multiply
(c+7)(3x-2)
Answer:
3cx - 2c + 21x - 14
Step-by-step explanation:
( c + 7 ) ( 3x - 2 )
= c ( 3x - 2 ) + 7 ( 3x - 2 )
= c ( 3x ) - c ( 2 ) + 7 ( 3x ) - 7 ( 2 )
= 3cx - 2c + 21x - 14
Answer:
3cx-2c+21x-14
Step-by-step explanation:
try to expand it by multiplying everything in the first brackets by every thing in the second brackets.
c(3x-2)+7(3x-2)
3cx-2c+21x-14
I hope this helps
I need help ASAP please
Answer:
yes how can I help you???
please help me with geometry
Answer:
∠ DBC = 60°
Step-by-step explanation:
BD is an angle bisector , so
∠ DBC = ∠ ABD = 60°
angel ABD =60°
BD line is bisector
angel DBC=60° because both the angel are similar
There is a path of width 2.5 m inside around a square garden of length 45m.
(a) Find the area of the path.
(b) How many tiles will be required to pave in the path by the square tiles of length 0.5m? Find it.
Help ! 도와주세요, 제발 :(
Answer:
2.5+2.5+45+45
=95.0m
therefore area of the square= 95.0m
45m×0.5=45.5÷95=
Step-by-step explanation:
2.5m
2.5 m tiles are required
[tex]area = 2.5 \times 45 = 192.5 \: squared \: cenimetre \\ \\ no \: of \: tiles = 0.5 \times 0.5 = 0.25 \\ 192.5 \div 0.25 = 770tiles[/tex]
True or False: A line perpendicular to x=7 has a slope of 0
Answer:
True, I believe
Step-by-step explanation:
Answer:
The answer is yes because its horizontal
If two resistors with resistances R1 and R2 are connected in parallel, as in the figure below, then the total resistance R, measured in ohms (Ω), is given by 1/R = 1/R1 + 1/R2 . If R1 and R2 are increasing at rates of 0.3 Ω/s and 0.2 Ω/s, respectively, how fast is R changing when R1 = 60 Ω and R2 = 80 Ω? (Round your answer to three decimal places.)
The rate of change of R with time in the given equation is 0.004 ohm/s
Given parameters:
[tex]\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} \\\\\frac{dR_1}{dt} = 0.3 \ ohm/s\\\\\frac{dR_2}{dt} = 0.2 \ ohm/s\\\\R_1 = 60 \ ohms\\\\R_2 = 80 \ ohms[/tex]
To find:
The rate of change of R with time in the given equation.First determine the value of R from the given equation;
[tex]\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} \\\\\frac{1}{R} = \frac{1}{60} + \frac{1}{80} \\\\\frac{1}{R} = \frac{4 + 3}{240} \\\\\frac{1}{R} = \frac{7}{240} \\\\R = \frac{240}{7} = 34.286 \ ohms[/tex]
Finally, to determine the rate of change of R, differentiate the given equation.
[tex]\frac{-1}{R^2} \frac{dR}{dt} = \frac{-1}{R_1^2} \frac{dR_1}{dt} - \frac{1}{R_2^2} \frac{dR_2}{dt} \\\\\frac{1}{R^2} \frac{dR}{dt} = \frac{1}{R_1^2} \frac{dR_1}{dt} + \frac{1}{R_2^2} \frac{dR_2}{dt}\\\\\frac{dR}{dt} = R^2(\frac{1}{R_1^2} \frac{dR_1}{dt} + \frac{1}{R_2^2} \frac{dR_2}{dt})[/tex]
[tex]\frac{dR}{dt} = 34.286(\frac{1}{(60)^2} \times 0.3 \ \ \ + \ \ \ \frac{1}{(80)^2} \times 0.2)\\\\\frac{dR}{dt} = 34.286(8.333 \times 10^{-5} \ \ \ + \ \ \ 3.125 \times 10^{-5})\\\\\frac{dR}{dt} = 34.286(11.458 \times 10^{-5})\\\\\frac{dR}{dt} = 0.00393\\\\\frac{dR}{dt} \approx 0.004 \ ohm/s[/tex]
Thus, from the given equation the rate of change of R with time is 0.004 ohm/s
Learn more here: https://brainly.com/question/14796851
Answer:
the verified answer is wrong.
Step-by-step explanation:
OP forgot to square R (34.286)
write your answer as an integer or as a decimal rounded to the nearest tenth
Answer:
8.6
Step-by-step explanation:
VW = WX / cos (36°)
= 7 / 0.81
= 8.6
Answer:
8.65
Step-by-step explanation:
cos 36° = 7 / VW
VW = 7 / cos 36°
VW = 8.65
Find the area of the shaded regions
Sector area
Area of whole = 51.313
Area of unshaded = 9.424
Area of shaded = 41.8886
Answer:
40π/3Step-by-step explanation:
Find the area of the bigger circle:
A = πr² = π(4 + 3)² = 49πFind the area of 120° sector AOC:
A = 120°/360°*A = 1/3*49π = 49π/3Find the area of smaller circle:
A = π(3²) = 9πFind the area of 120° sector of DOB:
A = 120°/360°*9π = 3πNow find the shaded area, the difference of areas of sectors:
49π/3 - 3π = 40π/3Make x the subject
y = 4(3x-5)/9
Answer:
3/4y +5/3 = x
Step-by-step explanation:
y = 4(3x-5)/9
Multiply each side by 9
9y = 4(3x-5)/9*9
9y = 4(3x-5)
Divide each side by 4
9/4 y = 4/4 (3x-5)
9/4y = 3x-5
Add 5 to each side
9/4y +5 = 3x-5+5
9/4y +5 = 3x
Divide by 3
9/4 y *1/3 +5/3 = 3x/3
3/4y +5/3 = x
The amount of money invested in a retirement fund is an example of which of the following?
a.
investment asset
b.
liquid asset
c.
long term asset
d.
use asset
Please select the best answer from the choices provided
Answer:
the answer is A
okay that it have a nice day
Answer:
the answer above me is correct!
Step-by-step explanation:
Edge 2021
If a seed is planted, it has a 90% chance of growing into a healthy plant.
If 6 seeds are planted, what is the probability that exactly 2 don't grow?
Answer:
[tex]\displaystyle\frac{19,683}{200,000}\text{ or }\approx 9.84\%[/tex]
Step-by-step explanation:
For each planted seed, there is a 90% chance that it grows into a healthy plant, which means that there is a [tex]100\%-90\%=10\%[/tex] chance it does not grow into a healthy plant.
Since we are planting 6 seeds, we want to choose 2 that do not grow and 4 that do grow:
[tex]\displaystyle \frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}[/tex]
However, this is only one case that meets the conditions. We can choose any 2 out of the 6 seeds to be the ones that don't grow into a healthy plant, not just the first and second ones. Therefore, we need to multiply this by number of ways we can choose 2 things from 6 (6 choose 2):
[tex]\displaystyle \binom{6}{2}=\frac{6\cdot 5}{2!}=\frac{30}{2}=15[/tex]
Therefore, we have:
[tex]\displaystyle\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \binom{6}{2},\\\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot 15,\\\\P(\text{exactly 2 don't grow})=\boxed{\frac{19,683}{200,000}}\approx 9.84\%[/tex]
Answer:
[tex] {?}^{?} However, this is only one case that meets the conditions. We can choose any 2 out of the 6 seeds to be the ones that don't grow into a healthy plant, not just the first and second ones. Therefore, we need to multiply this by number of ways we can choose 2 things from 6 (6 choose 2):
\displaystyle \binom{6}{2}=\frac{6\cdot 5}{2!}=\frac{30}{2}=15(26)=2!6⋅5=230=15
Therefore, we have:
\begin{gathered}\displaystyle\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \binom{6}{2},\\\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot 15,\\\\P(\text{exactly 2 don't grow})=\boxed{\frac{19,683}{200,000}}\approx 9.84\%\end{gathered}P(exactly 2 don’t grow)=101⋅101⋅109⋅109⋅109⋅109⋅(26),P(exactly 2 don’t grow)=101⋅101⋅109⋅109⋅109⋅109⋅15,P(exactly 2 don’t grow)=200,00019,683≈9.84%
[/tex]
Name
MATH 1342
Lab 12 - Ch.10 - Hypothesis Testing
Critical Thinking, Communication Skills, Empirical/Quantitative Skills
2. A machine is designed to fill jars with 16 ounces of coffee. A quality control inspector
suspects that the machine is not filling the jar with the full 16 ounces. A sample of 20 jars has
a mean of 15.8 ounces and a standard deviation of 0.32 ounce. Is there enough evidence to
support the inspector's claim that the mean number of ounces of coffee in the jars is less than
16? Use a = .05.
1.
Hand H
2.
3.
Critical value(s)
4.
Graph
5.
Test Statistic
6.
P-value
7.
Reject H. or Do Not Reject H.
8.
Conclusion
1 & 2:The null and alternate hypotheses are
H0 : u = 16 vs Ha: u < 16
The null hypothesis is that the mean is 16 ounces against the claim that it is less than 16 ounces.
3:The significance level is 0.05
4. Critical Value:
The critical region for significance level = 0.05 for one tailed test is z< ± 1.645
5.The test statistic
The test statistic to be used is
z= x- μ/σ/√n
z= 15.8-16/0.32/√20
z= -0.2/ 0.071556
z= -2.7950
6. The p-value ≈ 0.00259 for one tailed test.
7. Reject H0
Since the calculated value of z= -2.7950 is less than z∝= -1.645 we reject the null hypothesis.
8. Conclusion:
There is enough evidence to support the inspector's claim that the mean number of ounces of coffee in the jars.
https://brainly.com/question/15980493
Graph
A coffee pot holds 3 3/4 quarts of coffee. How much is this in cups.
Answer: 15 cups
Step-by-step explanation:
7 root 3 by 3 minus 3 root 2 by root 15 minus 3 root 2 minus 2 root 5 by root 6 + root 5
Answer:
Hill doctoral tricot trivial paint Tahiti he who Olney of Accokeek if Dogtown k park pectin rabbit tabernacle numbed.
Let f(x,y) =2x^3 y-xy find the domain
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Answer:
x, y ∈ all real numbers
Step-by-step explanation:
For your function ...
f(x, y) = 2x^3·y -xy
there appear to be no values of x or y for which the function is undefined. The domain for both x and y is "all real numbers."
Charlie has an annual salary of $75,000.00. He is paid every two weeks. What is the gross income amount for each paycheck?
Answer:
$2884.62
Step-by-step explanation:
A year has 52 weeks
The number of times Charlie will receive a paycheck will be 52w ÷ 2w = 26 times
Charlie's gross income each paycheck will be 7500÷26 = $2884.62 every two weeks
75000 ÷ (52 ÷2)
7500 ÷ 26
$2884.62
If each face on a standard die shows a number,1,2,3,4, 5 or 6.If the die is tossed 30 times, how many times would you expect to get 3.
Answer:
We should get a 3 about 5 times
Step-by-step explanation:
Possible outcomes 1,2,3,4,5,6
P(3) = number of 3's / total = 1/6
Expect a 3 = number of rolls * probability of a three
= 30 * 1/6
=5
morgan got 17/20 of the questions on a science test correct. what percent of the questions did she get correct?
Answer:
85%
Step-by-step explanation:
100% = 20
1% = 100%/100 = 20/100 = 0.2
now, how often does 1% fit into the actual result of 17 ? and that tells us how many %.
17/0.2 = 17/ 1/5 = 17/1 / 1/5 = 5×17 / 1 = 5×17 = 85%
Answer:
17/20×100=
85%
=85%
hope this helps
- 2/3 (2 - 1/5) use distributive property
Answer:
-6/5
Step-by-step explanation:
- 2/3 (2 - 1/5)
Distribute
-2/3 *2 -2/3 *(-1/5)
-4/3 + 2/15
Get a common denominator
-4/3 *5/5 +2/15
-20/15 +2/15
-18/15
Simplify
-6/5
Carol is having a hard time understanding the central limit theorem, so she decides to do her own experiment using the class data survey collected at the beginning of class on the number of hours a student takes during her Spring 2019 BUSI 2305 course. The data file has a total number of 54 students where the average is 10.8 with a standard deviation of 3.15. She sets out to collect the mean on 8 samples of 6 students. Based on this what are the total possible samples that could occur based on the population
Answer:
25827165
Step-by-step explanation:
from the question that we have here
the total population = 54 students
the sample size = 6 students
So given this information carol has to pick the total samples from the 54 students that we have here
the total ways that she has to do this
= 54 combination 6
= 54C6
= [tex]\frac{54!}{(54-6)!6!}[/tex]
= 25827165
this is the total number of possible samples that could occur given the total population of 54 students.
Of all the people applying for a certain job 75% are qualified and 25% are not. The personnel manager claims that she approves qualified people 80% of the time, she approves unqualified people 30% of the time. Find the probability that a person is qualified if he or she was approved by the manager The probability is:_______.
Type an integer or decimal rounded to four decimal places as needed)
Answer:
The probability is: 0.8889.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Approved
Event B: Qualified
Probability of a person being approved:
80% of 75%(qualified)
30% of 25%(not qualified). So
[tex]P(A) = 0.8*0.75 + 0.3*0.25 = 0.675[/tex]
Probability of a person being approved and being qualified:
80% of 75%, so:
[tex]P(A \cap B) = 0.8*0.75[/tex]
Find the probability that a person is qualified if he or she was approved by the manager.
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.8*0.75}{0.675} = 0.8889[/tex]
The probability is: 0.8889.
Help please this is due today
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Answer:
the correct choice is marked
Step-by-step explanation:
The end behavior matches that of an odd-degree polynomial. The only function shown that has that behavior is the one marked:
[tex]f(x)=\dfrac{x^2-36}{x-6}=\dfrac{(x+6)(x-6)}{(x-6)}=x+6\qquad x\ne6[/tex]
__
Additional comment
The other functions have horizontal (not slant) asymptotes, so do not have the described end behavior.
B: y=0
C, D: y=1
