A pilot is traveling at a height of 30,000 feet above level ground. She looks down at
an angle of depression of 6° and spots the runway. As measured along the ground, how
many miles away is she from the runway? Round to the nearest tenth of a mile.

Answer:

540.6 mi

Step-by-step explanation:

The angle of depression = angle of elevation = 6°

Let x = the distance to the runway.

tan 6 = 30000/x

xtan 6 = 30000

x = 30000/tan 6 =285430.9 ft

285430.9336.../5280 = 540.6 mi

A pilot is flying 30,000 feet above the surface of the earth. She notices the runway when she looks down at a 6° depression then she is 540.6 miles away from the runway.

A depression angle is formed when the viewer is higher than the object they are looking at. When a viewer looks at an object at a closer distance than themselves, an angle is formed under the horizontal line drawn at the viewer's eye level and the line connecting the object to the viewer's eye.

Elevation angle is the angle formed when a person stands on the ground and looks at an object above the ground at a height above the person's height. This is the basic difference between the two angles. Both angles are calculated using trigonometry concepts.

The angle of depression is defined as the angle formed by the horizon and the line connecting the object to the viewer's eye. This angle depends on two factors: altitude and distance.

Given: A pilot is flying 30,000 feet above the surface of the earth. She notices the runway when she looks down at a 6° depression.

The angle of depression = angle of elevation = 6°

Let x be the distance to the runway.

tan 6 = 30000/x

simplifying the above equation, we get

x tan 6 = 30000

x = 30000/tan 6 = 285430.9 ft

285430.9336/5280 = 540.6 mi

She is 540.6 mi away from the runway.

To learn more about angle of depression, refer to:

brainly.com/question/27865363

#SPJ2

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