Answer: 100k Joules
Explanation:
Think about what you observed in the Sim and the information the lead chemist sent you about the soda can. Which substance in the Sim best represents water (substance B or C)? Explain your answer in the space below.
Answer:
Substance C.
Explanation:
Substance C changed phase by condense and melted faster than substance B, which best represents liquid.
How are deceleration and acceleration related?
Answer:
Deceleration is reverse of acceleration
DUE TONIGHT 50 POINTS
An applied force of 13 N east acts on a 6.5-kg block that is moving east at 2.5 m/s on a level, frictionless surface. What is the final speed
of the block if the force is applied for 2.1 s?
A. 1.7 m/s
B. 4.2 m/s
C. 6.7 m/s
D. 7.2 m/s
9. A 12 v battery is connected to four 5 ohm light bulbs. What is the equivalent
resistance for the bulbs in series? In parallel?
10. What would be the current through each light of problem 9?
For parallel circuit?
For series circuit?
-no bs answers
What is a real world example of the Law of Conservation of Momentum?
Answer:
The thrust that you feel at the time of firing is one of the real-life example of the conseriation nomentum
does this man look okay? hes all pink and stuff O_O hes teaching me frickin science
Answer:
He is pink panther. How nerdy does he sound?
Explanation:
CO + 7H2 - C3Hg + 3H20
Answer:
Espanol 7h2 that's c coupon
A 1.5 kg block moves at 4 m/s
Answer:
12 joules
Explanation:
I'm assuming you're looking for kinetic energy?? Kinetic energy is 1/2 mv^2. 4 squared is 16, 16 times 1.5 = 24. 24/2 = 12.
Force (N) = 250
Mass (kg) = 221
Acceleration (m/s^2) = ?
Answer:
The required acceleration is [tex]a=1.1[/tex] m/s²
Explanation:
Given
Force F = 250 NMass m = 221 kgTo determine
Acceleration a = ?
We know that acceleration is produced when a force is applied to a body.
The acceleration can be determined using the formula
[tex]F = ma[/tex]
where
F is the force m is the mass a is the accelerationnow substituting F = 250 , and m = 221 in the formula
[tex]F = ma[/tex]
[tex]250 = 221 (a)[/tex]
switch the equation
[tex]221(a) = 250[/tex]
Divide both sides by 221
[tex]\frac{221a}{221}=\frac{250}{221}[/tex]
simplify
[tex]a=\frac{250}{221}[/tex]
[tex]a=1.1[/tex] m/s²
Therefore, the required acceleration is [tex]a=1.1[/tex] m/s²
True or False Heat is the measure of the flow of thermal energy. *
True
False
Answer:
True
Explanation:
Answer:
that is very much true im pretty sure
(edit I was wrong its false)
How do simple
machines magnify
forces?
Answer:
Motion at one end of the beam results in motion at the other end in the opposite direction.
Explanation:
The location of the fulcrum can magnify (or reduce) the force applied at one end at the expense (or advantage) of the distance over which the other end travels. Sorry if I get this wrong! I am in 5th grade. ♥
all energy,potential kinetic within a specific system
a)joule
b) total energy
c) potential energy
Answer:
C
Explanation:
The potential and kinetic energy within a specific system is called the total energy of the system.
Option B is the correct answer.
Potential and Kinetic EnergyThe energy of the specific system due to its steady position is defined as the potential energy of the system.
The energy of the system which is stored due to the motion of the system is called the kinetic energy of the system.
The mechanical energy of the system is the total energy within the system including its kinetic and potential energy.
The sum of kinetic and potential energy is known as mechanical energy. An object's mechanical energy is defined as the total energy which is stored during its steady position and stored during the motion of the object.
Hence we can conclude that option B represents the correct answer for the given statement.
To know more about the potential and kinetic energy, follow the link given below.
https://brainly.com/question/21288807.
The electric force between two charged balloons is 0.12 newtons. If the distance between the two balloons is halved, what will be the new force?
A.
0.03 newtons
B.
0.06 newtons
C.
0.36 newtons
D.
0.48 newtons
Answer:
d. 0.48
Explanation:
What conditions would you expect to find during an effusive eruption?
Answer:
Effusive eruptions occur when hot, (1200oC) runny basalt magmas reach the surface. Dissolved gases escape easily as the magma erupts, forming lava that flows downhill quite easily. Effusive eruptions build up gently-sloping Shield Volcanoes like Hawaii.
1)Describe the difference between an
energy transfer and energy store.
2)Give 3 examples of an energy transfer.
3)Give 3 examples of an energy store.
Answer:
1) Energy transfer is the movement of energy from one location to another. ... Energy transformation is when energy changes from one form to another – like in a hydroelectric dam that transforms the kinetic energy of water into electrical energy.
2)A swinging pirate ship ride at a theme park. Kinetic energy is transferred into gravitational potential energy.
A boat being accelerated by the force of the engine. ...
Bringing water to the boil in an electric kettle.
3)Common examples of energy storage are the rechargeable battery, which stores chemical energy readily convertible to electricity to operate a mobile phone, the hydroelectric dam, which stores energy in a reservoir as gravitational potential energy, and ice storage tanks, which store ice frozen by cheaper energy at night
Explanation:
PLEASE MARK ME AS BRAINLIEST
An object is placed 1.0 cm from a convex mirror with a focal length of 4.0 cm.
Answer:
image distanc=-0.8cm
Explanation:
.8 is the answer, sorry I do not have the proof.
But the other guy DOES NOT know how to write.
Zad. 2 W marszobiegu chłopiec przebiegł 900 m w ciągu 205 min, a następnie przeszedł 300m w tym danym czasie. Jaka była średnia prędkość chłopca podczas marszobiegu?
Odpowiedź:
0,049 m / s
Wyjaśnienie:
Biorąc pod uwagę, że:
Dystans biegu = 900m
Czas trwania = 205 minut
Długość przejścia = 300 m
Zajęty czas = 205 minut
Średnia prędkość :
(Przebieg + pokonany dystans) / całkowity czas
Średnia prędkość :
(900 m +. 300 m) / 205 + 205
1200 m / 410 minut
Minuty do sekund
1200 / (410 * 60)
1200/24600
= 0,0487804
= 0,049 m / s
A tennis ball covers a distance of 12 meters in 0.4 seconds what is the velocity of the tennis ball?
Answer:
30m/s
Explanation:
Given parameters:
Distance = 12m
Time taken = 0.4s
Unknown:
Velocity of the tennis ball = ?
Solution:
Velocity of a body is the displacement per unit of time.
Velocity = [tex]\frac{displacement}{time}[/tex]
So;
Velocity = [tex]\frac{12}{0.4}[/tex] = 30m/s
A toy car is allowed to roll down a ramp during an experiment. While it is on the ramp, gravity acts on the car as an unbalanced force. Which of the following graphs best illustrates the car’s velocity as a function of time while it is on the ramp?
Answer:
When an unbalanced force acts on an object, the motion of the object is changed. If the object is at rest, the force makes it move. If the object is in motion, the force changes its velocity. Any change in velocity is acceleration
Explanation:
jayfeather friend me
Potential energy = 0 J Kinetic energy =
Answer:drfdcfrfvgtgy6hbhhbhyg vcfrfr5tgvcfrtg vcdftghegthetrgbdgtthethe3thet
Explanation:
Sdwerftyrujtnyhbvcrdefgswthyujdehrtgfyhrjfuygtdhjueyrtgehwu3y4tgrehjwheyrgdhbnsjhfgvbdnhgfdhjsdehbrvbdensdvfgreyhsdgrftyhedggrfdhsgfv
why malleability is a useful property
Please help with these questions!!!!!
Answer:
4.c
5.d
6.c
Explanation:
A young man exerted a force of 9,000 N on a stalled car but was unable to move it. How much work was done?
The whale shark the largest of fish and can have the mass of three adult elephants. Suppose that a crane is whale shark into a tank for delivery to an aquariumThe crane must exert an unbalanced force of 2.5 * 10 ^ 4 to lift the shark from rest. If the shark's acceleration equals 1.25 m/s ^ 2 , what is the shark's mass?
Answer:
Mass, m = 20000 kg
Explanation:
The force acting on the shark, [tex]F=2.5\times 10^4\ N[/tex]
Acceleration of the shark, a = 1.25 m/s²
We need to find the mass of the Shark. The force acting on an object is given by :
F = ma
m is the shark's mass
So,
[tex]m=\dfrac{F}{a}\\\\m=\dfrac{2.5\times 10^4}{1.25}\\\\m=20000\ kg[/tex]
So, the mass of the Shark is 20000 kg.
A book is resting on a table. The table is raised on one end to an angle of 15° to the floor. If the book remains at rest, what keeps the book from sliding?
A. rolling friction
B. static friction
C. sliding friction
D. fluid friction
Answer: Static Friction
Explanation: As you tilt the book you know that it will stay fixed to start with, but eventually, once the angle is large enough, the book will start to slide. It is the static friction force that holds the book in place at small angles of tilt.
The book remains at rest if A book is resting on a table. The table is raised on one end to an angle of 15° to the floor due to static friction, so option C is correct.
What is static friction?An item is kept at rest by the force of static friction. The phrase "static friction" can be defined as "the friction people perceive when they attempt to move a stationary object on a surface, but without actually causing any relative motion between the body and the surface it is on."
You can predict that the book will initially remain fixed when you tilt it, but once the angle is sufficiently large, it will finally begin to slide. The book is held in place at slight tilt angles by static friction force.
The formula for the coefficient of static friction is μ = tan θ, here θ is the angle of inclination if the angle is bigger the friction force is more but at 90° when the book is vertical then the friction force will not work on the book
Therefore, the book remains at rest if A book is resting on a table. The table is raised on one end to an angle of 15° to the floor due to static friction.
To know more about static friction:
https://brainly.com/question/17237604
#SPJ2
how many electrons does a neutral atom of the element iron (fe) have?
Answer:
26 electrons
A neutral iron atom contains 26 protons and 30 neutrons plus 26 electrons in four different shells around the nucleus. As with other transition metals, a variable number of electrons from iron's two outermost shells are available to combine with other elements
Explanation:
hope this helps have a good rest of your night :) ❤
Free fall acceleration
I need help?!!
Explanation:
if g is 10ms^-1
answers are
1-10
2-20
3-30
4-40
5-50ms^-1
If the half-life of tritium (hydrogen-3) is 12.3 years, how much of
a 10 g sample of tritium is present after 250.0 years?
Answer:
0.0000076 grams
Explanation:
We're given the half life of Tritium to be 12.3 years. In order to find out the amount of substabce remaining:
Let's first find how many 'half lives' are in 250 years.
[tex]n = \frac{250}{12.3} = 20.325[/tex]
Now what is half life? It means the time taken for a given quantity of an element to lose half it's mass.
So in 12.3 years we can find that The amount of 250 g of Tritium will be 250/2 = 125 g. In 24.6 years we'll have 125/2 = 62.5 g
So now we can devise a formula:
[tex]m = \frac{original \: amount}{ {2}^{n} } [/tex]
Where m is the remaining amount and n is th number of half lives in the time given.
Using this formula we can calculate:
[tex]m = \frac{10}{ {2}^{20.325} } [/tex]
Doing this calculation we get:
[tex]m = 0.0000076 \: g[/tex]
As we can see a very small value remains.
Two charges separated by one meter exert a 9 N force on each other. If the charges are pushed to a 3 meter separation, the force on each charge will be 3 N.
True or False?
Answer:
False
Explanation:
The formula of force that exists between two charges is expressed as;
F = kq1q2/r²
If two charges separated by one meter exert a 9 N force on each other, the;
9 = kq1q2/1²
9 = kq1q2 ..... 1
If the charges are pushed to a 3 meter separation, then;
F = kq1q2/3²
F = kq1q2/9 .... 2
Divide both equations;
9/F = (kq1q2)/ kq1q2/9
9/F = kq1q2 * 9/ kq1q2
9/F = 9
F = 9/9
F = 1N
Hence if the charges are pushed to a 3 meter separation, then the force on EACH charge will be 1N. Hence the answer is False
A 136 kg defensive lineman is about to tackle a 100 kg quarterback. Right before
impact, the lineman is moving north at 6.0 m/s and the quarterback is moving
north at 1.0 m/s. Determine the speed and direction of the two players
immediately after the tackle.
Answer:
3.88 m/s North
Explanation:
We are given that
[tex]m_1=136kg[/tex]
[tex]m_2=100 kg[/tex]
[tex]v_1=6 m/s[/tex]
[tex]v_2=1m/s[/tex]
We have to find the speed and direction of the two players
immediately after the tackle.
Using linear conservation of momentum
[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]
Substitute the values
[tex]136\times 6+100\times 1=(136+100)v[/tex]
[tex]916=236v[/tex]
[tex]v=\frac{916}{236}[/tex]
[tex]v=3.88m/s[/tex]
Direction of the two players immediately after the tackle is North.
