A student increases the temperature of a 300 cm3 balloon from 40 °C to 110 °C.
What will the new volume of the balloon be? Round your answer to one decimal point.
(To convert, add 273.15)

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A Student Increases The Temperature Of A 300 Cm3 Balloon From 40 C To 110 C. What Will The New Volume

Answers

Answer 1

Answer:

367.1 cm³

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 300 cm³

Initial temperature (T₁) = 40 °C

Final temperature (T₂) = 110 °C

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273.15

Initial temperature (T₁) = 40 °C

Initial temperature (T₁) = 40 °C + 273.15

Initial temperature (T₁) = 313.15 K

Final temperature (T₂) = 110 °C

Final temperature (T₂) = 110 °C + 273.15

Final temperature (T₂) = 383.15 K

Finally, we shall determine the final volume (i.e the new volume) of the balloon. This can be obtained by using the Charles' law equation as illustrated below:

Initial volume (V₁) = 300 cm³

Initial temperature (T₁) = 313.15 K

Final temperature (T₂) = 383.15 K

Final volume (V₂) =?

V₁/T₁ = V₂/T₂

300 / 313.15 = V₂ / 383.15

Cross multiply

313.15 × V₂ = 300 × 383.15

313.15 × V₂ = 114945

Divide both side by 313.15

V₂ = 114945 / 313.15

V₂ = 367.1 cm³

Therefore, the new volume of the balloon is 367.1 cm³


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Answers

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Answers

Your answer and workings are all mentioned in the picture below.

Taking into account the reaction stoichiometry, 56.42 grams of N₂ are formed when 4 moles of NH₃ react.

Reaction stoichiometry

In first place, the balanced reaction is:

4 NH₃ + 3 O₂  → 2 N₂+ 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

NH₃: 4 molesO₂: 3 molesN₂: 2 molesH₂O: 6 moles

The molar mass of the compounds is:

NH₃: 17 g/moleO₂: 32 g/moleN₂: 28 g/moleH₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

NH₃: 4 moles ×17 g/mole= 68 gramsO₂: 3 moles ×32 g/mole= 96 gramsN₂: 2 moles ×28 g/mole= 56 gramsH₂O: 6 moles ×18 g/mole= 108 grams

Mass of N₂ formed

The following rule of three can be applied: if by reaction stoichiometry 4 moles of NH₃ form 56 grams of N₂, 4.03 moles of NH₃ form how much mass of N₂?

[tex]mass of N_{2} =\frac{4.03 moles NH_{3} x56 grams of N_{2} }{4 moles NH_{3}}[/tex]

mass of N₂= 56.42 grams

Then, 56.42 grams of N₂ are formed when 4 moles of NH₃ react.

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Answers

Answer:

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PLEASE MARK ME AS BRAINLIEST

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Answers

Answer:

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2. Polar Covalent: electronegativity difference between 0.4 and 1.8

3. Ionic: electronegativity difference > 1.8

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-Cl2 has a electronegativity difference of 3.0 - 3.0 = 0 (nonpolar covalent bond)

However, we still have two more options, A and B, but they are not diatomic for us to use the electronegativity differences with.

We must now consult their geometries. Because CO2 has a linear geometry (O=C=O), the two sides will cancel each other out, resulting in a nonpolar covalent bond. At this point, by process of elimination, we can already determine the answer to be A. H2O. We can verify this by looking at the geometry of H2O, which is bent (H-O-H; imagine the O is above the H's, I cannot draw it in this response). H2O's bent geometry classifies it as polar covalent; the electrons are slightly more attracted towards the O, the more electronegative element. Side note: this makes the O slightly more negative in charge, whilst the H's are slightly more positive in charge.

P.S. I apologize for not being able to draw and demonstrate that last paragraph, but I hope you get a general idea. You can search up the "H2O geometry" and "CO2 geometry" to get a better idea! :)

H₂O represents a nonpolar molecule containing polar covalent bonds. Hence Option (A) is correct

What is Polar Covalent Bond ?

A polar covalent bond exists when atoms with different electronegativities share electrons in a covalent bond.

Consider the hydrogen chloride (HCl) molecule. Each atom in HCl requires one more electron to form an inert gas electron configuration.

Water (H₂O), like hydrogen Chloride (HCl), is a polar covalent molecule. When we look at a diagram of water , we can see that the two hydrogen atoms are not evenly distributed around the oxygen atom

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