A television camera is positioned 4000 ft from the base of a rocket launching pad. The angle of elevation of the camera has to change at the correct rate in order to keep the rocket in sight. Also, the mechanism for focusing the camera has to take into account the increasing distance from the camera to the rising rocket. Let's assume the rocket rises vertically and its speed is 800 ft/s when it has risen 3000 ft. (Round your answers to three decimal places.)
(a) How fast is the distance from the television camera to the rocket changing at that moment?
ft/s
(b) If the television camera is always kept aimed at the rocket, how fast is the camera's angle of elevation changing at that same moment?
rad/s
Answers
============================================
Explanation for part (a)
t = time in secondsx = horizontal distance from the camera to the launch pady = vertical distance from the launch pad to the rocket's locationz = distance from camera to the rocket at time tAll distances mentioned are in feet.
We'll have a right triangle which allows us to apply the pythagorean theorem. Refer to the diagram below.
a^2+b^2 = c^2
x^2+y^2 = z^2
Apply the derivative to both sides with respect to t. We'll use implicit differentiation and the chain rule.
[tex]x^2+y^2 = z^2\\\\\frac{d}{dt}[x^2+y^2] = \frac{d}{dt}[z^2]\\\\\frac{d}{dt}[x^2]+\frac{d}{dt}[y^2] = \frac{d}{dt}[z^2]\\\\2x*\frac{dx}{dt}+2y*\frac{dy}{dt}=2z*\frac{dz}{dt}\\\\x*\frac{dx}{dt}+y*\frac{dy}{dt}=z*\frac{dz}{dt}\\\\[/tex]
Now we'll plug in (x,y,z) = (4000,3000,5000). The x and y values are given. The z value is found by use of the pythagorean theorem. Ie, you solve 4000^2+3000^2 = z^2 to get z = 5000. Or you could note that this is a scaled copy of the 3-4-5 right triangle.
We know that dx/dt = 0 because the horizontal distance, the x distance, is not changing. The rocket is only changing in the y direction. Or you could say that the horizontal speed is zero.
The vertical speed is dy/dt = 800 ft/s and it's when y = 3000. It's likely that dy/dt isn't the same value through the rocket's journey; however, all we care about is the instant when y = 3000.
Let's plug all that in and isolate dz/dt
[tex]4000*0+3000*800=5000*\frac{dz}{dt}\\\\2,400,000=5000*\frac{dz}{dt}\\\\\frac{dz}{dt} = \frac{2,400,000}{5000}\\\\\frac{dz}{dt} = 480\\\\[/tex]
At the exact instant that the rocket is 3000 ft in the air, the distance between the camera and the rocket is changing by an instantaneous speed of 480 ft/s.
-----------------------------------------------------------------------
Explanation for part (b)
Again, refer to the diagram below.
We have theta (symbol [tex]\theta[/tex]) as the angle of elevation. As the rocket's height increases, so does the angle theta.
We can tie together the opposite side y with the adjacent side x with the tangent function of this angle.
[tex]\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(\theta) = \frac{y}{x}[/tex]
Like before, we'll apply implicit differentiation. This time we'll use the quotient rule as well.
[tex]\tan(\theta) = \frac{y}{x}\\\\\frac{d}{dt}[\tan(\theta)] = \frac{d}{dt}\left[\frac{y}{x}\right]\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{\frac{dy}{dt}*x - y*\frac{dx}{dt}}{x^2}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{800*4000 - 3000*0}{4000^2}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{3,200,000}{16,000,000}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{32}{160}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{1}{5}\\\\[/tex]
Let's take a brief detour. We'll return to this later. Recall earlier that [tex]\tan(\theta) = \frac{y}{x}\\\\[/tex]
If we plug in y = 3000 and x = 4000, then we end up with [tex]\tan(\theta) = \frac{3}{4}\\\\[/tex] which becomes [tex]\tan^2(\theta) = \frac{9}{16}[/tex]
Apply this trig identity
[tex]\sec^2(\theta) = 1 + \tan^2(\theta)[/tex]
and you should end up with [tex]\sec^2(\theta) = 1+\frac{9}{16} = \frac{25}{16}[/tex]
So we can now return to the equation we want to solve
[tex]\sec^2(\theta)*\frac{d\theta}{dt} = \frac{1}{5}\\\\\frac{25}{16}*\frac{d\theta}{dt} = \frac{1}{5}\\\\\frac{d\theta}{dt} = \frac{1}{5}*\frac{16}{25}\\\\\frac{d\theta}{dt} = \frac{16}{125}\\\\\frac{d\theta}{dt} = 0.128\\\\[/tex]
This means that at the instant the rocket is 3000 ft in the air, the angle of elevation theta is increasing by 0.128 radians per second.
This is approximately 7.334 degrees per second.
The distance from the television camera to the rocket is changing at 480 ft/s while the camera's angle of elevation is changing at 0.128 rad/s
Let x represent the distance from the camera to the rocket and let h represent the height of the rocket.
a)
[tex]x^2=h^2+4000^2\\\\2x\frac{dx}{dt}=2h\frac{dh}{dt} \\\\x\frac{dx}{dt}=h\frac{dh}{dt} \\\\At \ h=3000\ ft, \frac{dh}{dt}=800\ ft/s;\\x^2=3000^{2} +4000^2\\x=5000\\\\\\x\frac{dx}{dt}=h\frac{dh}{dt} \\\\5000\frac{dx}{dt}=3000*800\\\\\frac{dx}{dt}=480\ ft/s[/tex]
b)
[tex]tan(\theta)=\frac{h}{4000} \\\\h=4000tan(\theta)\\\\\frac{dh}{dt}=4000sec^2(\theta)\frac{d\theta}{dt} \\\\\\At\ h=3000\ ft;\\\\tan\theta = \frac{3000}{4000}=\frac{3}{4} \\\\sec^2(\theta)=1+tan^2(\theta)=1+(\frac{3}{4})^2=\frac{25}{16} \\\\\\\frac{dh}{dt}=4000sec^2(\theta)\frac{d\theta}{dt}\\\\800=4000*\frac{25}{16}* \frac{d\theta}{dt}\\\\\frac{d\theta}{dt}=0.128\ rad/s[/tex]
Hence, The distance from the television camera to the rocket is changing at 480 ft/s while the camera's angle of elevation is changing at 0.128 rad/s
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Sin A = 15 / 17
Step-by-step explanation:
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Dưới đây là bảng CĐKT gần đây nhất của VNA:
ĐVT: tỷ đồng
TÀI SẢN
NGUỒN VỐN
Tài sản lưu động
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Tổng tài sản
11.30
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32.65
Nợ ngắn hạn (NH)
Nợ dài hạn
Vốn cổ phần ưu đãi
Vốn cổ phần thường
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10.69
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32.65
Biết: Nợ NH không chịu bất kỳ khoản phí nào, chi phí trung bình nợ NH sau thuế là 5.5%;
Chi phí nợ dài hạn trước thuế là 11.5%;
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Thuế TNDN là 32%.
Yêu cầu:
Tính chi phí vốn của mỗi nguồn nợ ngắn hạn, nợ dài hạn, vốn cổ phần ưu đãi, vốn cổ phần phổ thông?
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If sin(x) = 1 and cos(x) = 0, what is cot(x)?
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1
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Answer:
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Edge said it's 0
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Trigonometric ratios are mathematical functions that relate the angles of a right triangle to the ratios of the lengths of its sides. These ratios are fundamental in trigonometry and have applications in various fields, such as physics, engineering, and navigation.
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The value of the sin(x) is 1. The value of cos(x) is 0.
The formula for the cot(x) is written below:
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cot(x) = 0 / 1
cot(x) = 0
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Answer:
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Answers
Answer:
Step-by-step explanation:
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What is remainder theorem for polynomials?If there is a polynomial p(x), and a constant number 'a', then
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So, Let p(x) = x + 3
p(x) = 0
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x = -3
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[tex]f(x) = -2x^3 + x^2 - 4x + 1\\\\f(-3) = -2(-3)^3 + (-3)^2 - 4(-3) + 1\\\\f(-3) = 54 + 9 + 12 + 1\\\\f(-3) = 76[/tex]
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Answer:
(1). A = 18 cm² ; (2). TR = 18 units
Step-by-step explanation:
an international company has 27,100 employees in one country. if this represents 18.4% of the company's employees, how many employees does it have in total? round to nearest whole number
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Answer:
(a) 218.6 N
(b) 97.14 N
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Answer:
B, D, F
Step-by-step explanation:
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5.(06.02 MC)
Line BC contains points B (4, -5) and C (3, 2). Line DE contains points D (2,0) and E (9, 1). Lines BC and DE are (1 point)
parallel
perpendicular
neither
Answers
Answer:
Answer: Option A.
Step-by-step explanation:
Hey there!
Given; The Line BC contains points B (4, -5) and C (3, 2).
And the Line DE contains points D (2,0) and E (9, 1)
Note: Use double point formula for finding the equation and then find slopes of both then put the condition for perpendicular lines and parallel lines.
From line BC;
The points are B (4, -5) and C (3, 2).
Using double point formula;
[tex](y - y1) = \frac{y2 - y1}{x2 - x1}(x - x1) [/tex]
Keep all the value;
[tex](y + 5) = \frac{2 + 5}{3 - 4} (x - 4)[/tex]
Simplify it;
[tex]y + 5 = - 7x + 28[/tex]
Therefore, the equation is y = -7x+23........(I)And slope(m1) is -7 {comparing the equation (I) with y=Mx+c}
Again;
The points D (2,0) and E (9, 1)
Using double point formula;
[tex](y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)[/tex]
Keep all values;
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Answer:
y = 3x - 5
Step-by-step explanation:
Slope = 3
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Answer:
y = 3x - 5
Step-by-step explanation:
Find the slope of the line between (0,−5)(0,-5) and (3,4)(3,4) using m=y2−y1x2−x1m=y2-y1x2-x1, which is the change of yy over the change of xx.
m=3m=3
Use the slope 33 and a given point (0,−5)(0,-5) to substitute for x1x1 and y1y1 in the point-slope form y−y1=m(x−x1)y-y1=m(x-x1), which is derived from the slope equation m=y2−y1x2−x1m=y2-y1x2-x1.
y−(−5)=3⋅(x−(0))y-(-5)=3⋅(x-(0))
Simplify the equation and keep it in point-slope form.
y+5=3⋅(x+0)
Add xx and 00.
y+5=3xy+5=3x
Subtract 55 from both sides of the equation.
y=3x−5
what expression is equivalent to (-7²-x-5)-(3x²+x)
Answers
Answer:
-3x² - 2x - 54
Step-by-step explanation:
(-7²-x-5)-(3x²+x)
-7² - x - 5 - 3x² - x
-49 - x - 5 - 3x² - x
-3x² - x - x - 49 - 5
-3x² - 2x - 54
A manufacturer knows that their items have a normally distributed length, with a mean of 18.2 inches, and standard deviation of 3.9 inches. If 2 items are chosen at random, what is the probability that their mean length is less than 21.9 inches
Answers
Answer:
0.9099 = 90.99% probability that their mean length is less than 21.9 inches.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean of 18.2 inches, and standard deviation of 3.9 inches.
This means that [tex]\mu = 18.2, \sigma = 3.9[/tex]
2 itens:
This means that [tex]n = 2, s = \frac{3.9}{\sqrt{2}}[/tex]
What is the probability that their mean length is less than 21.9 inches?
This is the p-value of Z when X = 21.9. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{21.9 - 18.2}{\frac{3.9}{\sqrt{2}}}[/tex]
[tex]Z = 1.34[/tex]
[tex]Z = 1.34[/tex] has a p-value of 0.9099.
0.9099 = 90.99% probability that their mean length is less than 21.9 inches.
A person on the top of a tall building looks through his binoculars at his friend that is 300 ft away from the building on the ground. If the angle of depression from the person on the building is 30°, how tall is the building?
Answers
Answer:
520 feets
Step-by-step explanation:
The height of the building, h can be obtuined using trigonometry ;
From the attached diagram, opposite side = 300 feets ; height, h = adjacent side
Hence,
Tan θ = opposite / Adjacent
Tan 30° = 300 / height
0.5773502 = 300 / height
Height = 300 / 0.5773502
Height = 519.615
Height = 520 feets
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Answers
Answer:
Step-by-step explanation:
Our friend asking what the actual function is has a point. I completed this under the assumption that what we have is:
[tex]f(x)=\frac{e^{3x}}{5x-2}[/tex] and used the quotient rule to find the derivative, as follows:
[tex]f'(x)=\frac{e^{3x}(5)-[(5x-2)(3e^{3x})]}{(5x-2)^2}[/tex] and simplifying a bit:
[tex]f'(x)=\frac{5e^{3x}-[15xe^{3x}-6e^{3x}]}{(5x-2)^2}[/tex]and a bit more to:
[tex]f'(x)=\frac{5e^{3x}-15xe^{3x}+6e^{3x}}{(5x-2)^2}[/tex] and combining like terms:
[tex]f'(x)=\frac{11e^{3x}-15xe^{3x}}{(5x-2)^2}[/tex] and factor out the GFC in the numerator to get:
[tex]f'(x)=\frac{e^{3x}(11-15x)}{(5x-2)^2}[/tex] That's the derivative simplified. If we want f'(0), we sub in 0's for the x's in there and get the value of the derivative at x = 0:
[tex]f'(0)=\frac{e^0(11-15(0))}{(5(0)-2)^2}[/tex] which simplifies to
[tex]f'(0)=\frac{11}{4}[/tex] which translates to
The slope of the function is 11/4 at the point (0, -1/2)
Four spinners are spun. Spinner 1 has outcomes Spinner 2 has outcomes Spinner 3 has outcomes Spinner 4 has outcomes The outcomes for each spinner are equally likely. is the sum of the numbers that come up on the spinners. What is the expected value of
Answers
Complete Question
Four spinners are spun. Spinner 1 has outcomes {1,2,3,4,5,6,7,8} Spinner 2 has outcomes {1,2,3,4,5,6} Spinner 3 has outcomes {1,2,3,4,5,6} Spinner 4 has outcomes {1,2,3,4,5} The outcomes for each spinner are equally likely. S is the sum of the numbers that come up on the spinners. What is the expected value of S?
Answer:
[tex]E(s)=14.5[/tex]
Step-by-step explanation:
From the question we are told that:
Spinner 1 ={1,2,3,4,5,6,7,8}
Spinner 2= {1,2,3,4,5,6}
Spinner 3 = {1,2,3,4,5,6}
Spinner 4 {1,2,3,4,5}
Generally the equation for expected outcome is mathematically given by
[tex]E(s)=\sum P(x).x[/tex]
Where
[tex]x=\frac{n(n+1)}{2}[/tex]
For Spinner 1
[tex]E(s_1)=\sum \frac{1}{8}*\frac{8(8+1)}{2}[/tex]
[tex]E(s_1)=4.5[/tex]
For Spinner 2
[tex]E(s_2)=\sum \frac{1}{6}*\frac{6(6+1)}{2}[/tex]
[tex]E(s_2)=3.5[/tex]
For Spinner 3
[tex]E(s_2)=E(s_3)[/tex]
For Spinner 3
[tex]E(s_4)=\sum \frac{1}{6}*\frac{6(6+1)}{2}[/tex]
[tex]E(s_4)=3[/tex]
Therefore The Expected Value
[tex]E(s)=\sum E(s 1..4)[/tex]
[tex]E(s)=4.5+2(3.5)+3[/tex]
[tex]E(s)=14.5[/tex]
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Step-by-step explanation:
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Answer:
A
Step-by-step explanation:
Write a quadratic equation with integer coefficients having the given numbers as solutions.
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Answer:
x² -22 = 0
Step-by-step explanation:
The roots are opposites, so the equation is pretty simple.
x = ±√22
x² = 22 . . . . . square both sides
x² -22 = 0 . . . . your quadratic equation in standard form
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Answer:
(-5, 4)
Step-by-step explanation:
The inside corner moves from (2, -2) to (-3, 2). That is 5 is subtracted from the x-coordinate, and 4 is added to the y-coordinate. (x, y) ⇒ (x -5, y +4)
The translation vector can be written horizontally as (-5, 4), or vertically as ...
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The average mileage per gallon for cars built since 1940 approximates to the following curve 0.0075*t^2-.2672*t+14.8 where t is year -1940.
Answer the following questions:
What is the expected MPG in 2025?
How about 2050?
Is this a valid function?
Is there a top end to MPG?
Answers
9514 1404 393
Answer:
46.3 in 202576.2 in 2050Step-by-step explanation:
The attached shows the predicted mileage for cars built in 2025 to be 46.3 mpg, 76.2 mpg for cars built in 2050.
__
No doubt, the function is valid over the time period used to derive it. It may or may not be valid for predicting MPG beyond that period.
Virtually any function that predicts future increases without bound will turn out to be unreliable at some point. In this universe, there are always limits to growth.
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Answer:
B
Step-by-step explanation:
5³.5^×
simply means
5³×5^×
using indices rule,
multiplication is addition
5 is common
so 5(³+×)
hence 5^3+×
In an experiment, you choose to have two randomly assigned groups. In one, you take measurements both pretest and posttest; with the second, a posttest-only measure. This describes which task of conducting an experiment
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Answer:
The answer is "Specific treatment levels".
Step-by-step explanation:
When we experimenting with 'level' which is related to the quantity or magnitude of treatment. For this part of an experiment or study, a group or individual is exposed to a specified set of circumstances. For example: If four categories are exposed to different doses of a given drug, then each dose reflects a level of a treatment factor in the model.
Solve 3 - 5(a - 4) any one who can answer in the next 3 mins plz answer
Answers
Answer:
[tex]3-5\left(a-4\right)[/tex]
[tex]-5(a-4)=-5a+20[/tex]
[tex]=3-5a+20[/tex]
[tex]=-5a+23[/tex]
OAmalOHopeO
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\text{3 - 5(a - 4)}\\\\\huge\text{\underline{\underline{DISTRUBUTE -5 within the parentheses}}}\\\\\large\text{3 - 5(a) - 5(-4)}\\\large\text{= 3 - 5a + 20}\\\\\huge\text{\underline{\underline{COMBINE the LIKE TERMS}}}\\\large\text{-5a + (3 + 20)}\\\large\text{= \bf -5a + 23}\\\\\\\boxed{\boxed{\huge\text{Therefore, your answer is: \bf -5a + 23}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!} \\\\\\\frak{Amphitrite1040:)}[/tex]
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Answer: [tex](\frac{2}{5},0) ; (0,2)[/tex]
Step-by-step explanation:
(to find the x-intercept, plug in 0 for y)
(to find the y-intercept, plug in 0 for x)
[tex]0=-5x+2\\5x=2\\x=\frac{2}{5}\\(\frac{2}{5},0)\\y=-5(0)+2\\y=2 \\(0,2)[/tex]
find the missing side lengths
Answers
this is a special triangle so v = 17
u = 17√2
Answer:
v = 17
u = 17[tex]\sqrt{2}[/tex]
Step-by-step explanation:
If v = 17 (it is because it is a right triangle, so the pythagorean theorum works, and triangles are 180 degrees, so 180 - 90 = 90, so the other two angles are 45 degrees, meaning that v is the same length as 17.) then
17 ^ 2 = u ^2
289 = u^2
17 root to 2
Find the measure of x. X=8, x=7, x=9, x=11
Answers
Answer:
[tex]\frac{135}{15} =\frac{15(x+2)}{15}[/tex]
[tex]9=x+2[/tex]
[tex]x=7[/tex]
OAmalOHopeO
According to government data, the probability than an adult never had the flu is 19%. You randomly select 70 adults and ask if he or she ever had the flu. Decide whether you can use the normal distribution to approximate the binomial distribution, If so, find the mean and standard deviation, If not, explain why. Round to the nearest hundredth when necessary.
Answers
Answer:
Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.
The mean is 13.3 and the standard deviation is 3.28.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].
The probability than an adult never had the flu is 19%.
This means that [tex]p = 0.19[/tex]
You randomly select 70 adults and ask if he or she ever had the flu.
This means that [tex]n = 70[/tex]
Decide whether you can use the normal distribution to approximate the binomial distribution
[tex]np = 70*0.19 = 13.3 \geq 10[/tex]
[tex]n(1-p) = 70*0.81 = 56.7 \geq 10[/tex]
Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.
Mean:
[tex]\mu = E(X) = np = 70*0.19 = 13.3[/tex]
Standard deviation:
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{70*0.19*0.81} = 3.28[/tex]
The mean is 13.3 and the standard deviation is 3.28.
