Before working this problem, review Conceptual Example 14. A pellet gun is fired straight downward from the edge of a cliff that is 14.7 m above the ground. The pellet strikes the ground with a speed of 27.2 m/s. How far above the cliff edge would the pellet have gone had the gun been fired straight upward
Answer:
23.04 m
Explanation:
We'll begin by calculating the initial velocity of the pellet. This can be obtained as follow:
Height (h) of cliff = 14.7 m
Final velocity (v) = 27.2 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) =?
v² = u² + 2gh
27.2² = u² + (2 × 9.8 × 14.7)
739.84 = u² + 288.12
Collect like terms
u² = 739.84 – 288.12
u² = 451.72
Take the square root of both side
u = √451.72
u = 21.25 m/s
Thus, the initial velocity of the pellet is 21.25 m/s.
Finally, we shall determine the maximum height to which the pellet would have gone assuming the gun was fired straight upward. This can be obtained as follow:
Initial velocity (u) = 21.25 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 m/s (at maximum height)
Maximum height (h) =?
v² = u² – 2gh (since the pellet is going against gravity.
0² = 21.25² – (2 × 9.8 × h)
0 = 451.5625 – 19.6h
Collect like terms
0 – 451.5625 = –19.6h
–451.5625 = –19.6h
Divide both side by –19.6
h = –451.5625 / –19.6
h = 23.04 m
Therefore, the pellet will reach a maximum height of 23.04 m above the cliff.
From the Water in each of the next move
A 10,000 g body falls from a height of 20 m. Calculate the potential energy when it is at a height of 10 m
Answer:
Ep = 980 J
Explanation:
First, grams must be converted to kilograms. So, we must divide the value of the mass, by 1000.
[tex]\boxed{\frac{10000}{1000}=\boxed{10kg}}[/tex] ---------- Converted to kg.==================================================================
Data:
Mass (m) = 10 kgGravity (g) = 9.8 m/s²Height (h) = 10 mPotential Energy (Ep) = ?Use formula:
Ep = m * g * hReplace:
Ep = 10 kg * 9.8 m/s² * 10 mMultiply operations, with units:
Ep = 980 JWhat is the potential energy?
The potential energy is 980 Joules.
A clump of soft clay is thrown horizontally from 9.80 m above the ground with a speed of 20.0 m/s. Assume it sticks in place when it hits the ground At what time will the clay hit the ground
Answer:
Explanation:
The time to hit the ground will be same as time taken to fall from the height of 9.8 m with initial vertical velocity of zero .
Considering vertical displacement
initial velocity u = 0
displacement s = 9.8 m
acceleration a = g = 9.8 m /s²
time t = ?
s = ut + 1/2 g t²
9.8 = 0 + .5 x 9.8 x t²
t² = 2
t = √2 = 1.4 s
Heart Disease is the number one cause of preventable death in the United States
A True
B False
Heart disease is the leading cause of death for both men and women. This is the case in the U.S. and worldwide. More than half of all people who die due to heart disease are men.
TRUE
The planet Mars is host to five functioning spacecraft, three in orbit about the planet and two on the surface of the planet. Thanks to those spacecraft, we know that the planet Mars has a mass that is 0.11 times that of Earth and a radius that is 0.53 times that of Earth. The acceleration of an object in free-fall near the surface of Mars is most nearly what in terms of the local value of g on Earth
Answer:
0.392
Explanation:
Mm = 0.11Me
Rm = 0.53Re
g = GM / r^2
G = 6.67 * 10^-11
gmars = (G * 0.11Me) / (0.53Re)^2
Recall:
gearth = GMe /Re^2
Hence, gmars in terms of gearth equals
gmars = gearth * (0.11 / 0.53^2)
gmars = gearth * 0.3915984
gmars = 0.392gearth
formula for percentage error
Answer:
PE = (|accepted value – experimental value| \ accepted value) x 100%
Explanation:
Pulling a rubber band back and then letting it fly across the room is an example of
A. converting energy to work
B. converting elastic energy to gravitational
C. converting kinetic energy to potential
Answer:
b
Explanation:
because a elastic band uses elastic energy
Each tire on a car has a radius of 0.330 m and is rotating with an angular speed of 15.6 revolutions/s. Find the linear speed v of the car, assuming that the tires are not slipping against the ground.
Answer:
v = 32.345 m/s
Explanation:
given data
radius r = 0.330 m
angular speed = 15.6 revolutions/s
solution
we will get here linear speed v, that is express as
v = r × w .....................1
here w = 17.5 × 2 × π radians
so now put value in eq1
v = 0.330 × 15.6× 2 × π
v = 32.345 m/s
How does earths magnetic field work
Answer: On Earth, flowing of liquid metal in the outer core of the planet generates electric currents. The rotation of Earth on its axis causes these electric currents to form a magnetic field which extends around the planet.
Explanation:
Answer:
the rotation of earth on its axis causes electric currents to form a magnetic field which extends around the planet
Your favorite golfer taps the golf ball with just enough force that it rolls into the ninth hole is an example of what law of motion???
Answer:
mass and on the net force acting on it. ... Tap again to see term ... Newton's second law of motion states that an object's acceleration depends on its ... You hit a ping-pong ball & a tennis ball with a tennis rack
Answer this and you get 100 points
You better answer it quick though
Answer what? Apologies, but I don't see anything. (。>︿<)
A 97.1 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.63 rad/s . A monkey drops a 8.97 kg bunch of bananas vertically onto the platform. They hit the platform at 45 of its radius from the center, adhere to it there, and continue to rotate with it. Then the monkey, with a mass of 22.1 kg , drops vertically to the edge of the platform, grasps it, and continues to rotate with the platform. Find the angular velocity of the platform with its load. Model the platform as a disk of radius 1.73 m .
Answer:
the final angular velocity of the platform with its load is 1.0356 rad/s
Explanation:
Given that;
mass of circular platform m = 97.1 kg
Initial angular velocity of platform ω₀ = 1.63 rad/s
mass of banana [tex]m_{b}[/tex] = 8.97 kg
at distance r = 4/5 { radius of platform }
mass of monkey [tex]m_{m}[/tex] = 22.1 kg
at edge = R
R = 1.73 m
now since there is No external Torque
Angular momentum will be conserved, so;
mR²/2 × ω₀ = [ mR²/2 + [tex]m_{b}[/tex] ([tex]\frac{4}{5}[/tex] R)² + [tex]m_{m}[/tex]R² ]w
m/2 × ω₀ = [ m/2 + [tex]m_{b}[/tex] ([tex]\frac{4}{5}[/tex] )² + [tex]m_{m}[/tex] ]w
we substitute
w = 97.1/2 × 1.63 / ( 97.1/2 + 8.97(16/25) + 22.1
w = 48.55 × [ 1.63 / ( 48.55 + 5.7408 + 22.1 )
w = 48.55 × [ 1.63 / ( 76.3908 ) ]
w = 48.55 × 0.02133
w = 1.0356 rad/s
Therefore; the final angular velocity of the platform with its load is 1.0356 rad/s
Problem 6: A bullet in a gun is accelerated from rest from the firing chamber to the end of the barrel at an average rate of 6.3 × 105 m/s2 for 8.2 × 10-4 s.Ball,removedc795646bb4371e1754411a7dadf94458c503446af1b6450bb3269c1f97e8ef53removedremoved58b1e9a401041b69266daacea519e828d050d14013adc67f8c64697e40f2ef89removedtheexpertta - tracking id: 0W86-2A-6A-4E-962A-28979. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account.show answer No Attempt What is the gun’s muzzle velocity (that is, the bullet’s final speed), in meters per second
Answer:
v = 5.166 10² m / s
Explanation:
We can solve this exercise using the kinematics equations
v = v₀ + at
as the bullet starts from rest its initial velocity is zero
v = a t
let's calculate
v = 6.3 10⁵ 8.2 10⁻⁴
v = 5.166 10² m / s
What term is used to describe DNA Replication?
Conservative
Un-conservative
Non-conservative
Semi-conservative
Answer:
Semi-conservative
Explanation:
Each strand of the original DNA molecule serves as a template for the production of its counterpart
What is the potential energy of an object 20 m in the air with a
mass of 600 kg?
Answer:
Ep = 117600 J
Explanation:
Data:
Mass (m) = 600 kgHeight (h) = 20 mGravity (g) = 9.8 m/s²Potential Energy (Ep) = ?Use formula:
Ep = m * g * hReplace:
Ep = 600 kg * 9.8 m/s² * 20 mMultiply operations, and units:
Ep = 117600 JWhat is the potential energy?
The potential energy is 117600 Joules.
Explain two reasons why astronomers are continually building larger and larger telescopes. Explain two reasons why astronomers are continually building larger and larger telescopes. Larger telescope mirrors have a larger surface area and can therefore collect more light, which makes faint objects bright enough to detect. Also, larger telescope mirrors produce more scattering of light due to diffraction, which contributes to better angular resolution. Larger telescope mirrors have a larger surface area and can therefore collect more light, which contributes to better angular resolution. Also, larger telescope mirrors produce more scattering of light due to diffraction, which makes faint objects bright enough to detect. Larger telescope mirrors have a larger surface area and can therefore collect more light, which contributes to better angular resolution. Also, larger telescope mirrors produce less scattering of light due to diffraction, which makes faint objects bright enough to detect. Larger telescope mirrors have a larger surface area and can therefore collect more light, which makes faint objects bright enough to detect. Also, larger telescope mirrors produce less scattering of light due to diffraction, which contributes to better angular resolution.
Answer:
* Larger mirrors collect more light and therefore fainter and more distant objects can have enough intensity to be detected
* arger mirrors decreases the angle of dispersion giving a better resolution of the bodies
Explanation:
Refracting telescopes get bigger every day for two main reasons.
* Larger mirrors collect more light and therefore fainter and more distant objects can have enough intensity to be detected
* the diffraction process for circular apertures is given by
θ = 1.22 λ / D
where d is the diameter of the mirror, therefore having larger mirrors decreases the angle of dispersion giving a better resolution of the bodies
A laser positioned on a ship is used to communicate with a small two man research submarine resting on the bottom of a lake. The laser is positioned 12 m above the surface of the water, and it strikes the water 20 m from the side of the ship. The water is 76 m deep and has an index of refraction of 1.33. How far is the submarine from the side of the ship
Answer:
84.1 m
Explanation:
Given :
The distance from the ship to submarine :
20 + y
Using Pythagoras :
Tan θ = opposite / Adjacent
Tan θ = 20 / 12
12 tan θ = 20
θ = tan^-1(20/12)
20
θ = 59.036°
The angle phi;
n1sinθ1 = n2sin θ
Sin 59.036 = 1.33 * sin phi
Sin phi = sinsin(59.04) ÷1.33
0.8574907 = 1.33 * sin phi
Sin phi = 0.8574907 / 1.33
Sin phi = 0.6447298
phi = sin(0.6447298
Phi = 40.15°
From Pythagoras :
y = 76tan40.15°
y = 76 * 0.8435707
y = 64.11
20 + y
20 + 64.11 = 84.11
Explain why your PE and KE are usually not both high at the same time (If PE is high then usually KE is low)
Orion, also called the Hunter, has three stars that make up Orion's belt.
Which star is at the tip of the arrow? PLEASE HELP I NEED THIS FAST
A. Sirius
B. Betelgeuse
C. Rigel
D. Polaris
Answer - B. Betelguese.
I really hope this helps!!
A hiker walks 7.7 miles to the east in 3.6 hours, then turns around and walks 2.1 miles to the west in 2.4 hours. What was the magnitude of her average velocity during the trip?
Answer:
2.18 miles per hour
Explanation:
Given:
A hiker walks 7.7 miles to the east in 3.6 hours.
A hiker walks 2.1 miles to the west in 2.4 hours
To find: magnitude of average velocity during the trip
Solution:
Total distance = 7.7 + 2.1 = 9.8 miles
Total Time = 2.1 + 2.4 = 4.5 hours
Average velocity = Total distance ÷ Total Time =[tex]\frac{9.8}{4.5}=2.18[/tex] miles per hour
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Answer:
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Answer:
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A swimmer pushing off from the wall of a pool exerts a force of 1 newton on the wall. What is the reaction force of the wall on the swimmer?
Answer: 1 Newton
Explanation:
"Every action has an equal and opposite reaction."
Please mark as Brainliest if it is correct.
Force is an action-reaction principle. It stated that the force always exists in a pair. The reaction force of the wall on the swimmer will be 1N.
What is Newton's third law of motion?Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.
Both occur in an action-reaction form. Hence for every action, there is an equal and opposite reaction.
[tex]\rm F_{action}=F_{reaction} \\\\ \rm F_{action= 1N[/tex]
[tex]\rm F_{reaction} = 1N[/tex]
Hence the reaction force of the wall on the swimmer will be 1N.
To learn more about Newton's third law refer to the link;
https://brainly.com/question/1077877
Suppose a car is traveling at 22.8 m/s, and the driver sees a traffic light turn red. After 0.404 s has elapsed (the reaction time), the driver applies the brakes, and the car decelerates at 9.00 m/s2. What is the stopping distance of the car, as measured from the point where the driver first notices the red light?
Answer:
38.09 m
Explanation:
We'll begin by calculating the distance travelled by the car during the reaction time. This can be obtained as follow:
Reaction time (tᵣ) = 0.404 s
Initial velocity (u) = 22.8 m/s,
Distance travelled during the reaction time (sᵣ) =?
sᵣ = utᵣ
sᵣ = 22.8 × 0.404
sᵣ = 9.21 m
Next, we shall determine the distance travelled by the car when the brake was applied. This can be obtained as follow:
Initial velocity (u) = 22.8 m/s
Acceleration (a) = –9 m/s² (since the car is decelerating)
Final velocity (v) = 0 m/s
Distance travelled when the brake was applied (s₆) =?
v² = u² + 2as₆
0² = 22.8² + (2 × –9 × s₆)
0 = 519.84 – 18s₆
Collect like terms
0 – 519.84 = –18s₆
–519.84 = –18s₆
Divide both side by –18
s₆ = –519.84 / –18
s₆ = 28.88 m
Finally, we shall determine the stopping distance of the car, as measured from the point where the driver first notices the red light. This can be obtained as follow:
Distance travelled during the reaction time (sᵣ) = 9.21 m
Distance travelled when the brake was applied (s₆) = 28.88 m
Stopping distance =?
Stopping distance = sᵣ + s₆
Stopping distance = 9.21 + 28.88
Stopping distance = 38.09 m
Which is an advantage of storing data digitally?
A. It is easy to change the data if you have the right computer
programs.
B. It is easy to copy a computer virus to a device along with the data.
C. The quality of copies decrease as more copies are made.
D. Other people can access personal data from unsecured devices.
Answer:
A
Explanation:
Because I said so
Answer:
A
Explanation:
i took the test and got it right please mark me ❤️
6. The petrol in a petrol can weighs 2000g. The density of petrol is 0.8g/cm3.
What is the volume of the petrol in the can in a) cm3 b)litres (1000cm3=1 litre)
Pls help :((
Answer:
a. 2500 cm³.
b. 2.5 litres.
Explanation:
Given the following data:
Density = 0.8g/cm³
Mass = 2000g
To find the volume of the petrol;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
[tex]Density = \frac{mass}{volume}[/tex]
Making volume the subject of formula, we have;
[tex]Volume = \frac{mass}{density}[/tex]
Substituting into the equation, we have:
[tex]Volume = \frac{2000}{0.8}[/tex]
Volume = 2500 cm³
a. The volume of the petrol in the can in cubic centimeters (cm³) is 2000.
b. The volume of the petrol in the can in litres;
1000 cm³ = 1 litre
2500 cm³ = x litres
Cross-multiplying, we have;
1000x = 2500
x = 2500/1000
x = 2.5 litres.
Therefore, the volume of the petrol in the can in litres is 2.5.
PLEASE HELP GIVING BRAINLIEST ANSWER
Explain why your PE and KE are usually not both high at the same time (If PE is high then usually KE is low)
What simple machine can best be described as "a simple machine that uses an inclined plane wrapped around a rod"? *
a wedge
a screw
a wheel and axle
a lever
Which image best illustrates diffraction
Answer:
There is no image
Explanation:
Answer: Send me image than I will be able to help
Explanation:
Q4. What is the speed of light in a block of glass that
has an Index of refraction of 1.11?