이
Determine the the nuclei indicated in blanks in the
right side when Radium (Ra-226) undergoes an
alpha decay
Ne
226/ 88
Ra -->
+

Answer:

NaBH₄

Explanation:

First, we need to write the chemical formula of all the compounds:

Benzil: C₁₄H₁₀O₂

Sodium Borhydride: C₁₄H₁₀O₂

Hydrobenzoin: C₁₄H₁₄O₂

Now, let's write the reaction that is taking place and write all the products:

C₁₄H₁₀O₂ + 2NaBH₄ + 2H₂O -----------> C₁₄H₁₄O₂ + 2BH₃ + 2NaOH

We can see that the reaction is already balanced, so we don't need to do anything else.

The question of this exercise is to determine the limiting reagent of the reaction, in other words, the reagent that controls the reaction and produces the 2.22 g of the hydrobenzoin. And to know this we need to see the mole ratio in both reactants, and compare them to the given moles (That can be obtained with the given masses and MW)

According to the above reaction, we have a mole ratio of 1:2, so, let's calculate the moles of benzil and the borohydride, and see which of them is the limiting reactant:

moles C₁₄H₁₀O₂ = 2.56 / 210.23 = 0.0122 moles

moles NaBH₄ = 0.38 / 37.83 = 0.01 moles

moles  C₁₄H₁₄O₂ = 2.22 / 214.26 = 0.0103 moles

We have the moles of every species, now, let's see the mole ratio

If 1 mole of C₁₄H₁₀O₂ -----------> 2 moles of NaBH₄

Then 0.0122 moles C₁₄H₁₀O₂ ----------> X moles of NaBH₄

Solving for X:

X = 0.0122 * 2 / 1 = 0.0244 moles of NaBH₄ are required.

However, we only have 0.01 moles of NaBH₄, and we need so much more of this to completely react with the moles of the benzil. Therefore we can safely assume that the limiting reagent is the NaBH₄

Another data that we can use for this, is the fact the produced moles were 0.0103, and this value is nearest to the moles of NaBH₄ rather than the moles of the benzil.

Hope this helps

Answer:

London dispersion forces between octane molecules

Explanation:

Water is a polar solvent and the molecules of water are held together by hydrogen bonds.

On the other hand octane is a nonpolar molecule held together only by weak dispersion forces.

We know that the interaction of substances depend on the nature of intermolecular forces present in each substance. As a result, water can not interact with octane because octane molecules predominantly have a different kind of intermolecular force between them- the London dispersion forces.

Answer: [tex]H_2O_2\rightarrow H_2+O_2[/tex]

Explanation:

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

According to law of conservation of mass, mass can neither be created nor be destroyed. Thus the number of atoms of each element must be same on reactant and product side. Thus chemical equations are balanced.

The balanced equation for the decomposition reaction  of hydrogen peroxide is:

[tex]H_2O_2\rightarrow H_2+O_2[/tex]

Decomposition is a type of chemical reaction in which a chemical breaks into two or more molecules or atoms. One reactant breaks into two products which can be shown as:

                                         XY----->X + Y

The decomposition reaction of hydrogen peroxide can be written as:

                                              [tex]H_{2}O_{2} = H_{2} + O_{2}[/tex]

Therefore, the balanced chemical reaction of decomposition of hydrogen peroxide will be:

                                             [tex]H_{2}O_{2} = H_{2} + O_{2}[/tex]

To learn more about decomposition reaction follow the given link:

https://brainly.com/question/8009068

Using Avogrado's constant (6.022e23):

4(6.022e23) = 2.41e24

Answer:

gtjgyjtjyjjjjk

Explanation:

Answer:

I guess you mean by non element example. Non element examples have more than one elements. Carbon dioxide is a non element example since caebon dioxide has 2 oxygen atoms + 1 carbon atom = carbon dioxide.

I think catalyst is also a non element example because catalyst is inorganic which means that it is not a living thing. Since catalyst is in brass and brass is a non element example, I think catalyst is also a non element example.

Hope that helps, thank you !!

Answer:

0.491 mol NaCl

Explanation:

Convert from grams to moles using the molar mass of NaCl:

28.7 g NaCl x 1 mol NaCl/58.44 g NaCl = 0.491 mol NaCl

The molar mass (58.44 g) can be found from adding the molar masses of the individual elements (Na and Cl); the g NaCl will cancel out (dimensional analysis), leaving you with mol NaCl.

Answer:

temperature of the reaction vessel

Explanation:

temperature of the reaction vessel

The value of the rate constant for a gas phase chemical reaction can be changed by increasing the: A. temperature of the reaction vessel.

In Chemistry, rate constant is typically used with rate law to tell the reaction rate or rate of a chemical reaction that is affected by activation energy.

Mathematically, the rate law is given by this formula:

[tex]R = k[A]^x[B]^y[/tex]

Where:

Generally, the value of the rate constant for a gas phase chemical reaction can be changed by increasing the temperature of the vessel (container) that is used in conducting the chemical reaction.

Read more on rate constant here: brainly.com/question/24749252

Answer:

do you have names or pictures?

Explanation:

Answer:

Explanation:

The end product of Photosynthesis is glucose that is used in cellular respiration to make ATP. The glucose is then turned back into carbon dioxide, which is used in photosynthesis. While water is broken down to form oxygen during photosynthesis, in cellular respiration oxygen is combined with hydrogen to form water.

Answer:

Ice cap

Explanation:

See its polar so like north pole and north pole is ice cap.

Answer:

Ice cap

Explanation:

Answer:

Explanation:

Calcium is Ca

Carbon is C

Chlorine is Cl

Answer:

Moles to grams carbon dioxide

1 mole is equal to 1 moles Carbon Dioxide, or 44.0095 grams.

Explanation:

Moles to grams carbon dioxide

1 mole is equal to 1 moles Carbon Dioxide, or 44.0095 grams.

Answer:

b. Ni, Fe, Ti, K

Explanation:

The given elements are present in period 4 of periodic table. Now we will discuss the trend of atomic radius along period.

Atomic radius:

" It is the smallest distance from nucleus to the outer most valance shell of an atom"

When we move from left to right in the periodic table the number of valance electrons in an atom increase. The atomic size goes to decrease in same period because of edition of electron with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. In this way positive charge is also going to increase and this charge is greater in effect than the charge of electrons. This effect causes the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell come closer to the nucleus.

As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Ni ∠ Fe ∠ Ti ∠ K

Answer:

4d orbital.

Explanation:

Hello!

In this case, since zirconium's atomic number is 40, we fill in the electron configuration up to 40 as shown below:

[tex]1s^2,2s^2,2p^6, 3s^2,3p^6,4s^2,3d^{10},4p^6,5s^2,4d^2[/tex]

Thus, the orbital 4d is partially filled.

Best regards!

Answer:B

Explanation:

Maybe

Answer:B is correct

Explanation:

Answer:

3rd law

Explanation:

His third laws states that every action has an equal and opposite reaction. because you are putting force on your wall, the wall is giving the force of wall on your finger.

Answer:

The molar density of any ideal gas at STP is:

1 mol / 22.4 L = 0.04464 mol / L

The molar mass of F2 is: 2(19) = 38 g/mol

0.04464 mol / L * (38 g / mol) = 1.70 g/L

Explanation:

Answer:

[tex]1.05x10^{24}atoms[/tex]

Explanation:

Hello!

In this case, according to the definition of the Avogadro's number, it is possible to realize that one molecule of CO2 contains 3 moles of atoms, one of carbon and two of oxygen, thus, we have:

[tex]0.580molCO_2*\frac{3mol\ atoms}{1molCO_2} =1.74mol\ atoms[/tex]

Then, we use the Avogadro's number to obtain:

[tex]1.74mol\ atoms*\frac{6.022x10^{23}atoms}{1mol\ atoms} \\\\1.05x10^{24}atoms[/tex]

Best regards!

Answer:

The water phase with the smallest temperature increase when adding 10 kcal of heat is solid ice.

Explanation:

The rest of the statements are incorrect. The density of ice is lower than the density of water. The heat capacity of solid ice is greater almost twice the heat capacity of the liquid water. The heat capacity of vapors is less than heat capacity of liquid.

Answer:

A substance is a pure single form of matter. It cannot be separated into other kinds of matter by any physical process.

Answer:

P = 0.0166 mm Hg

Explanation:

To solve this question, we need to use the Clausius Clapeyron equation, which is a commonly used expression to calculate vapour pressure at a given temperature. We have the enthalpy of vaporization of the mercury, so, let's write the equation:

Clausius Clapeyron equation:

Ln (P₂ / P₁) = (-ΔHv / R)(1/T₂ - 1/T₁)    (1)

Where:

R: universal constant of gases (8.314 J / K.mol)

P₂: Vapour pressure at 43°C (or 316 K)

P₁: Pressure of mercury at the boiling point (1 atm)

T₂: temperature at 43 °C

T₁: Boiling point of mercury (357 °C or 630 K)

As we are given the boiling point of the mercury, we can safely assume that the pressure at this point is 1 atm, becuase remember that when a sustance boils, is because it's internal pressure has reached the atmospherical pressure of 1 atm. With this clear, all we just need to do is solve for P₂. We are going to do this very slowly so you can understand the process. First let's replace the given data:

Ln (P₂ / 1) = (-59100 J/mol / 8.314 J / K.mol) (1/316 - 1/630)

Ln P₂ = -7108.49 * (3.16x10⁻³ - 1.59x10⁻³)

Ln P₂ = -7108.49 * (1.51x10⁻³)

Ln P₂ = -10.7338

P₂ = 10⁽⁻¹⁰°⁷³³⁸⁾

P₂ = 2.18x10⁻⁵ atm

We can express this value in mm Hg and it will be:

P₂ = 2.18x10⁻⁵ * 760

Hope this helps

Answer:The correct names for the structure are:

--> 1. 1-bromo-3-chlorobenzene.

--> 3. meta-bromochlorobenzene.

--> 6. m-bromochlorobenzene.

Explanation:

Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.

Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.

The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:

--> the functional group is benzene

--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)

--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.

The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.

--> ortho or O : this is used when the substituents are close to each other in the benzene ring.

--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.

--> para or (p): This is used when the substituents are across each other in the benzene ring

From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.

Answer: [tex]CoI_2[/tex] : cobalt (II) iodide : correct

[tex]BaCl_2[/tex] : barium di chloride : incorrect

[tex]Cs_2O[/tex] : cesium oxide: correct

[tex]Rb_2S[/tex] : rubidium sulphite : incorrect

[tex]SrBr_2[/tex] : strontium (II) bromide : correct

Explanation:

The nomenclature of ionic compounds is given by:

1. Positive is written first followed by the oxidation state of metal in roman numerals in parenthesis.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

Hence, the name of [tex]CoI_2[/tex] is cobalt (II) iodide, [tex]BaCl_2[/tex] is barium (II) chloride, [tex]Cs_2O[/tex] is cesium oxide, [tex]Rb_2S[/tex] is rubidium sulphide and [tex]SrBr_2[/tex] is strontium (II) bromide.

Answer:

1-6

3 1 3 3 2 2

Explanation:

Answer:

B

Explanation:

B is a personal factor of resilience