C 89. What is the power of 5, so that 1 its value become ? (५ को घाताङ्क 25 कति हुदा त्यसको मान 25 हुन्छ ?) .7​

Given:

Total fish (Sea bass and mackerel) = [tex]7\dfrac{2}{5}[/tex] pounds

Sea bass = [tex]4\dfrac{5}{8}[/tex] pounds

He gave away [tex]1\dfrac{7}{8}[/tex] pounds of mackerel.

To find:

The remaining mackerel.

Solution:

We know that,

Mackerel = Total fish - Sea bass

[tex]\text{Mackerel}=7\dfrac{2}{5}-4\dfrac{5}{8}[/tex]

[tex]\text{Mackerel}=\dfrac{37}{5}-\dfrac{37}{8}[/tex]

[tex]\text{Mackerel}=\dfrac{296-185}{40}[/tex]

[tex]\text{Mackerel}=\dfrac{111}{40}[/tex]

He gave away [tex]1\dfrac{7}{8}[/tex] pounds of mackerel. So, the remaining mackerel is:

[tex]\text{Remaining Mackerel}=\dfrac{111}{40}-1\dfrac{7}{8}[/tex]

[tex]\text{Remaining Mackerel}=\dfrac{111}{40}-\dfrac{15}{8}[/tex]

[tex]\text{Remaining Mackerel}=\dfrac{111-75}{40}[/tex]

[tex]\text{Remaining Mackerel}=\dfrac{36}{40}[/tex]

[tex]\text{Remaining Mackerel}=\dfrac{9}{10}[/tex]

Therefore, the remaining Mackerel is [tex]\dfrac{9}{10}[/tex] pounds or 0.9 pounds.

Answer:

The amount of Mackerel left is 9/10.

Step-by-step explanation:

total fish = 7 2/5 pounds

sea bass = 4 5/8

The amount of mackerel =

[tex]7\frac{2}{5}-4\frac{5}{8}\\\\=\frac{37}{5}-\frac{37}{8}\\\\=\frac{296-185}{40}\\\\=2 \frac{31}{40}[/tex]

Mackerel left =

[tex]2 \frac{31}{40}-1\frac{7}{8}\\\\= \frac{111}{40}-\frac{15}{8}\\\\=\frac{111-75}{40}\\\\=\frac{36}{40}\\\\=\frac{9}{10}[/tex]

Cost of jacket = $20

No. Of jackets = 1

Let the cost of shirt be x

No of shirts = 5

ATQ

5x + 1(20) = 95

5x + 20 = 95

5x = 95 - 20

5x = 75

x = 75/5

x = 15

Therefore cost of each shirt was $15

Answered by Gauthmath must click thanks and mark brainliest

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Answer:

I really can't read this

Step-by-step explanation:

Answer:

1.46 dollars per pound

Step-by-step explanation:

Take the total cost and divide by the number of pounds

7.30 dollars / 5 pounds

1.46 dollars per pound

Answer:

1.46

Step-by-step explanation:

Unit rate is the amount for only one pound. To do this, divide 7.30 and 5.

Divide:

7.3 / 5 = 1.46

Each pound is $1.46

Hope this helped.

9514 1404 393

Answer:

  (5, -6)

Step-by-step explanation:

x-coordinates measure the distance to the right of the y-axis. Moving a point 4 units to the right adds 4 to its x-coordinate.

y-coordinates measure distance up from the x-axis. Moving a point 4 units down subtracts 4 from its y-coordinate.

  (1, -2) +(4, -4) = (1 +4, -2 -4) = (5, -6) . . . . image of translated point

Answer:

45- s= 21

s= 45- 21

=24

so the answer is 24

Answer:

y = 3x+2

Step-by-step explanation:

First find the slope using the slope formula

m= (y2-y1)/(x2-x1)

   = ( -1 - -4)/(-1 - -2)

   = (-1 +4)/ (-1 +2)

   = 3/1

  = 3

The slope intercept formula is

y = mx+b where m is the slope and b is the y intercept

y = 3x+b

Using the point (-1,-1) and substituting into the equation

-1 = 3(-1)+b

-1 = -3+b

-1+3 = b

2 = b

y = 3x+2

Answer:

[tex]\begin{array}{cc}{Status} & {Probability} & {1} & {0.0845} & {2} & {0.1127} & {3} & {0.1870} & {4} & {0.1927}& {5} & {0.4231} \ \end{array}[/tex]

Step-by-step explanation:

Given

The above table

Required

The discrete probability distribution

The probability of each is calculated as:

[tex]Pr = \frac{Frequency}{Total}[/tex]

Where:

[tex]Total = 2140+ 2853 + 4734 + 4880 + 10715[/tex]

[tex]Total = 25322[/tex]

So, we have:

[tex]P(1) = \frac{2140}{25322} = 0.0845[/tex]

[tex]P(2) = \frac{2853}{25322} = 0.1127[/tex]

[tex]P(3) = \frac{4734}{25322} = 0.1870[/tex]

[tex]P(4) = \frac{4880}{25322} = 0.1927[/tex]

[tex]P(5) = \frac{10715}{25322} = 0.4231[/tex]

So, the discrete probability distribution is:

[tex]\begin{array}{cc}{Status} & {Probability} & {1} & {0.0845} & {2} & {0.1127} & {3} & {0.1870} & {4} & {0.1927}& {5} & {0.4231} \ \end{array}[/tex]

Answer:

this and that and that is this

Step-by-step explanation:

step by step

Answer:

D.

Step-by-step explanation:

sin Y = opposite side / hypotenuse

= 38/63.

Answer:

D

Step-by-step explanation:

[tex]Sin \ y = \frac{opposite \ side}{hypotenuse}\\\\Sin \ y = \frac{38}{63}[/tex]

Answer: SS Error

Step-by-step explanation:

The SS Error refers to the sum of the squares of the deviations of the observations, from their mean. It is simply the total variance from the observations on the study.

In performing a one-way ANOVA, the SS Error measures the variability of the observed values around their respective means and this is done through the summation of the squared differences between each observed value of the response and its corresponding treatment mean.

Answer:

15 years

Step-by-step explanation:

Given the quadratic regression model:

y = 8x² - 40x+6 ; where

y = Number of people attending graduate school ;

x = number of years

The value of x when y = 1206

The equation becomes :

1206 = 8x² - 40x+6

1206 - 6 = 8x² - 40x

1200 = 8x² - 40x

Divide through by 8

150 = x² - 5x

x² - 5x - 150 = 0

x² - 15x + 10x - 150 = 0

x(x - 15) + 10(x - 15)

x - 15 = 0 or x + 10 = 0

x = 15 or x = - 10

Number of years can't be negative,

Hence, x = 15 years

Step-by-step explanation:

We'll find the distance using the all-famous "Distance Formula." You'll probably come across it quite a bit, so it's best to have it written down somewhere.

The Distance Formula: [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

Our points are (8, -3) and (4, -7), so we'll plug in those numbers accordingly.

For reference:

x2 = 4

x1 = 8

y2 = -7

y1 = -3

The calculation:

(substitute)

[tex]\sqrt{(4-8)^2+((-7)-(-3))^2 }[/tex]

(simplify)

[tex]\sqrt{(-4)^2+(-4)^2 }[/tex]

(square things)

[tex]\sqrt{16+16 }[/tex]

(add)

[tex]\sqrt{32}[/tex]

Answer:

[tex]\sqrt{32}[/tex]

Answer:

[tex]\boxed {\boxed {\sf C. \sqrt{32}}}[/tex]

Step-by-step explanation:

The distance between 2 points can be determined with the following formula.

[tex]d= \sqrt{(x_2-x_1)^2+ (y_2-y_1)^2[/tex]

In this formula, (x₁, y₁) and (x₂, y₂) are the 2 points. We want to find the distance between the points (8, -3) and (4, -7). If we match the value with its corresponding variable, then we see:

Substitute the values into the formula.

[tex]d= \sqrt{(4-8)^2+(-7--3)^2[/tex]

Solve inside the parentheses.

[tex]d= \sqrt {(-4)^2+(-4)^2[/tex]

Solve the exponents.

[tex]d= \sqrt {16+16[/tex]

Add.

[tex]d= \sqrt {32}[/tex]

This radical can be simplified, but since it is an answer choice, we can leave it as is.

The distance between the points (8, -3) and (4, -7) is √32 and choice C is correct.

Answer:

it should be 3

Step-by-step explanation:

I hope this help

Answer: Yes you are correct. The answer is choice A

============================================================

Explanation:

If you used the z-table, you should find that P(Z < 1) = 0.84 approximately.

So by symmetry, P(Z > -1) = 0.84 approximately as well.

We'll convert the z score z = -1 into its corresponding x score

z = (x-mu)/sigma

-1 = (x-180)/15

-15 = x-180

x-180 = -15

x = -15+180

x = 165

We don't land on any of the answer choices listed, but we get fairly close to 165.2, which is choice A. So you are correct.

I have a feeling that the table you have is probably more accurate than the one I'm using, so it's possible that you'd land exactly on 165.2 when following the steps above.

Answer:

194.9

Step-by-step explanation:

ON EDG

Answer:

110 feet

Step-by-step explanation:

Take x as the width of the field.

4x = 440 feet

x = 440 feet ÷ 4

x = 110 feet

So, the field is 110 feet wide #

A perfect correlation is denoted by:

A. +1.0 and -1.0

Answer:

Step-by-step explanation:

Use the coordinates (30, 1) and (150, 5) to solve this. Time is always an x thing, while things like distance and weight and value are y things. Put them into the slope formula:

[tex]m(\frac{miles}{sec})=\frac{5-1}{150-30}=\frac{4}{120}=\frac{1}{30}[/tex]  This translates to:

The rocket is ascending at a constant rate of 1 mile every 30 seconds; or, conversely, for every 30 seconds the rocket is flying, it is traveling 1 mile.

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Answer:

The answer is "720"

Step-by-step explanation:

The amount of different slates candidates:

[tex]n=\frac{N!}{(N-k)!}\\\\[/tex]

   [tex]=\frac{10!}{(10-3)!}\\\\=\frac{10!}{7!}\\\\=\frac{10\times 9 \times 8 \times 7! }{7!}\\\\=10\times 9 \times 8\\\\=90\times 8\\\\=720[/tex]

9514 1404 393

Answer:

  geometric sequence

Step-by-step explanation:

The terms of the sequence have a common ratio of -12/3 = -4, so the sequence is geometric. The general term is ...

  an = 3(-4)^(n-1)

so the sum can be written as ...

  [tex]\displaystyle\sum_{n=0}^\infty3(-4)^n[/tex]

(Note the summation starts at n=0, corresponding to a first term of 3.)

Answer:

16 and 3

Step-by-step explanation:

Let x and y represent the positive integers. We know that

[tex]x + y = 19[/tex]

[tex]xy = 48[/tex]

Isolate the top equation for the x variable.

[tex]x = 19 - y[/tex]

Substitute into the second equation.

[tex](19 - y)y = 48[/tex]

[tex]19y - {y}^{2} = 48[/tex]

[tex] - {y}^{2} + 19y = 48[/tex]

[tex] - {y}^{2} + 19y - 48[/tex]

[tex](y - 16)(y - 3)[/tex]

So our values are

16 and 3.

Answer:

(0, 3)

Step-by-step explanation:

y = 3 is the horizontal tangent to y = x^2+3, and passes the parobala at (0, 3)

Answer:

y=2x+8

Step-by-step explanation:

Hope this helps

Answer:

The third side is increasing at an approximate rate of about 0.444 meters per minute.

Step-by-step explanation:

We are given a triangle with two sides having constant lengths of 13 m and 19 m. The angle between them is increasing at a rate of 2° per minute and we want to find the rate at which the third side of the triangle is increasing when the angle is 60°.

Let the angle between the two given sides be θ and let the third side be c.

Essentially, given dθ/dt = 2°/min and θ = 60°, we want to find dc/dt.

First, convert the degrees into radians:

[tex]\displaystyle 2^\circ \cdot \frac{\pi \text{ rad}}{180^\circ} = \frac{\pi}{90}\text{ rad}[/tex]

Hence, dθ/dt = π/90.

From the Law of Cosines:

[tex]\displaystyle c^2 = a^2 + b^2 - 2ab\cos \theta[/tex]

Since a = 13 and b = 19:

[tex]\displaystyle c^2 = (13)^2 + (19)^2 - 2(13)(19)\cos \theta[/tex]

Simplify:

[tex]\displaystyle c^2 = 530 - 494\cos \theta[/tex]

Take the derivative of both sides with respect to t:

[tex]\displaystyle \frac{d}{dt}\left[c^2\right] = \frac{d}{dt}\left[ 530 - 494\cos \theta\right][/tex]

Implicitly differentiate:

[tex]\displaystyle 2c\frac{dc}{dt} = 494\sin\theta \frac{d\theta}{dt}[/tex]

We want to find dc/dt given that dθ/dt = π/90 and when θ = 60° or π/3. First, find c:

[tex]\displaystyle \begin{aligned} c &= \sqrt{530 - 494\cos \theta}\\ \\ &=\sqrt{530 -494\cos \frac{\pi}{3} \\ \\ &= \sqrt{530 - 494\left(\frac{1}{2}\right)} \\ \\&= \sqrt{283\end{aligned}[/tex]

Substitute:

[tex]\displaystyle 2\left(\sqrt{283}\right) \frac{dc}{dt} = 494\sin\left(\frac{\pi}{3}\right)\left(\frac{\pi}{90}\right)[/tex]

Solve for dc/dt:

[tex]\displaystyle \frac{dc}{dt} = \frac{494\sin \dfrac{\pi}{3} \cdot \dfrac{\pi}{90}}{2\sqrt{283}}[/tex]

Evaluate. Hence:

[tex]\displaystyle \begin{aligned} \frac{dc}{dt} &= \frac{494\left(\dfrac{\sqrt{3}}{2} \right)\cdot \dfrac{\pi}{90}}{2\sqrt{283}}\\ \\ &= \frac{\dfrac{247\sqrt{3}\pi}{90}}{2\sqrt{283}}\\ \\ &= \frac{247\sqrt{3}\pi}{180\sqrt{283}} \\ \\ &\approx 0.444\text{ m/min}\end{aligned}[/tex]

The third side is increasing at an approximate rate of about 0.444 meters per minute.

9514 1404 393

Answer:

  0.444 m/min

Step-by-step explanation:

I find this kind of question to be answered easily by a graphing calculator.

The length of the third side can be found using the law of cosines. If the angle of interest is C, the two given sides 'a' and 'b', then the third side is ...

  c = √(a² +b² -2ab·cos(C))

Since C is a function of time, its value in degrees can be written ...

  C = 60° +2t° . . . . . where t is in minutes, and t=0 is the time of interest

Using a=13, and b=19, the length of the third side is ...

  c(t) = √(13² +19² -2·13·19·cos(60° +2t°))

Most graphing calculators are able to compute a numerical value of the derivative of a function. Here, we use the Desmos calculator for that. (Angles are set to degrees.) It tells us the rate of change of side 'c' is ...

  0.443855627418 m/min ≈ 0.444 m/min

_____

Additional comment

At that time, the length of the third side is about 16.823 m.

__

c(t) reduces to √(530 -494cos(π/90·t +π/3))

Then the derivative is ...

  [tex]c'(t)=\dfrac{494\sin{\left(\dfrac{\pi}{90}t+\dfrac{\pi}{3}\right)}\cdot\dfrac{\pi}{90}}{2\sqrt{530-494\cos{\left(\dfrac{\pi}{90}t+\dfrac{\pi}{3}}}\right)}}}\\\\c'(0)=\dfrac{247\pi\sqrt{3}}{180\sqrt{283}}\approx0.443855...\ \text{m/min}[/tex]

Answer:

Consider the angle Ф.

the line opposite to Ф is the perpendicular -> PQ = 5cm

The base is the line with whom the perpendicular has 90° angle -> PR = 12cm

Finally, hypotenuse is the line opposite to the 90° which is QR= 13cm

Answer:

hypotenuse = QR = 13 cm

Perpendicular = PQ = 5 cm

Base = PR = 12 cm

Answer:

(-6,0) and (0,-6) are the points on the graph

Answer:

Step-by-step explanation:

1 are = 100 m²

Assuming the ten squares are congruent, the area of each square is 160/10 = 16 are

16 are × 100 m²/are = 1600 m²

each side is √1600 = 40 m

The length of side of plot is 40 meters.

The total space occupied by a flat (2-D) surface or shape of an object is known as area.

Draw a square on a piece of paper with a pencil. It has two dimensions. The term "area" refers to the area that the shape occupies on the paper.

Now picture your square as being comprised of smaller unit squares. The number of unit squares required to cover a 2-D shape's total surface area is used to calculate its area.

Given the area of 10 square plot is 160 are,

here 1 are = 100 m²

area of 10 square plot = 160 x 100 = 16,000 m²

area of 1 square plot = 16000/10 = 1600 m²

area of square is "a²"

where a is side of square

area = a² = 1600 m²

a = √1600

a = 40 m

Hence the length of side of each plot is 40 meters.

Learn more about area;

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