Answer:
About 11 Weeks
Step-by-step explanation:
I found out by multiplying 11 by 20 and got 220. Then, adding 50 is 270, which is just over 259. It's not ten because 200 is just underneath his goal.
2.
Translate the following word phrase into an algebraic expression: six times four less than three
times x
Answer:
6 × ( 3x - 4)
Step-by-step explanation:
Not much to explain.
Hope this helps!
If there is something wrong, please let me know
Matt invests £1800 for 2 years at a simple interest rate of 10%.
How much money will he get back in interest?
Answer:
Step-by-step explanation:
P = 1800
R = 10%
T = 2 years
I = PRT
= 1800 * 10/100 * 2
= 1800 * 0.1 * 2
I = £360
The amount that will be gotten back as interest will be £360
Principal = £1800
Rate = 10%
Time = 2 years
Simple Interest will be calculated as:
= (P × R × T) / 100
= (£1800 × 10 × 2)/100
= £36000/100
= £360
Therefore, the interest is £360.
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https://brainly.com/question/24355322
t 0 2 4 6 8 10
P(t) 0 36 43 47 52 60
Kunyu's family has an above ground swimming pool in the shape of a cylinder, with a radius of 10 feet and a height of 5 feet. The pool contains 1000 cubic feet of water at time t=0. During the time interval 0≤t≤10 hours, water is pumped into the pool at the rate () cubic feet per hour. The table above gives values of () for selected values of . During the same time interval, water is leaking from the pool at the rate of () cubic feet per hour, where ()=18−0.04.
(Note: The volume V of a cylinder with radius r and height h is given by =2ℎ .)
Find the rate at which the volume of water in the pool is increasing at time t=6 hours. How fast is the water level in the pool rising at t=6 hours? Indicate units of measure in both answers.
Answer:
a. 24.12 ft³/hr b. 0.0768 ft/hr
Step-by-step explanation:
a. Find the rate at which the volume of water in the pool is increasing at time t=6 hours.
The net rate of change of volume of the cylinder dV/dt = volume flow rate in - volume flow rate out
Since volume flow rate in = P(t) and volume flow rate out = R(t),
dV/dt = P(t) - R(t)
[tex]\frac{dV}{dt} = P(t) - 18e^{0.04t}[/tex]
We need to find the rate of change of volume when t = 6.
From the table when t = 6, P(6) = 47 ft³/hr
Also, substituting t = 6 into R(t), we have R(6)
[tex]\frac{dV}{dt} = P(t) - 18e^{0.04t}[/tex]
[tex]\frac{dV}{dt} = 47 - 18e^{0.04X6}\\\frac{dV}{dt} = 47 - 18e^{0.24}\\\frac{dV}{dt} = 47 - 18 X 1.27125\\\frac{dV}{dt} = 47 - 22.882\\\frac{dV}{dt} = 24.118 ft^{3}/hr[/tex]
dV/dt ≅ 24.12 ft³/hr
So, the rate at which the water level in the pool is increasing at t = 6 hours is 24.12 ft³/hr
b. How fast is the water level in the pool rising at t=6 hours?
Since the a rate at which the water level is rising is dV/dt and the volume of the cylinder is V = πr²h where r = radius of cylinder = 10 ft and h = height of cylinder = 5 feet
dV/dt = d(πr²h)/dt = πr²dh/dt since the radius is constant and dh/dt is the rate at which the water level is rising.
So, dV/dt = πr²dh/dt
dh/dt = dV/dt ÷ πr²
Since dV/dt = 24.12 ft³/hr and r = 10 ft,
Substituting the values of the variables into the equation, we have that
dh/dt = dV/dt ÷ πr²
dh/dt = 24.12 ft³/hr ÷ π(10 ft)²
dh/dt = 24.12 ft³/hr ÷ 100π ft²
dh/dt = 0.2412 ft³/hr ÷ π ft²
dh/dt = 0.2412 ft³/hr
dh/dt = 0.0768 ft/hr
So, the arate at which the water level is rising at t = 6 hours is 0.0768 ft/hr
find the area of the semi circle plss
Answer:
Step-by-step explanation:
Find the missing side round your answer to the nearest tenth
Answer: 15
Step-by-step explanation:
You can afford to invest $150 per month in an annuity that earns 4% per year, compounded monthly. How long will it take before your investment is worth $6000?
Answer:
how long will it take before your investment is wort$6000?
:
The width of a rectangle is 5 cm more than triple its length. The perimeter of the
rectangle is 240 cm. What is the length and width of the rectangle?
9514 1404 393
Answer:
length: 28.75 cmwidth: 91.25 cmStep-by-step explanation:
Let L represent the length of the rectangle. Then the width is W=5+3L, and the perimeter is ...
P = 2(L+W)
240 = 2(L +(5 +3L))
120 = 5 +4L
115 = 4L
115/4 = L = 28.75 . . . . cm
W = 5+3L = 5 +3(28.75) = 91.25 . . . . cm
The length and width of the rectangle are 28.75 cm and 91.25 cm.
Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. (Enter your answers as a comma-separated list.) F(x) = sin(x/2) , [π/2,3π/2]
Answer:
The numbers 3(pi)/2, 5(pi)/2 satisfy the conclusion of Rolle's Theorem
Step-by-step explanation:
1. The function must be continuous.
Trigonometric functions are continuous.
2. It must be true that f(a) = f(b) = 0
For this case sin(pi) = sin(3pi) = 0
3. Therefore by Rolle's Theorem, there exist a point, x, such that f(x) = 0
For this case f(x) = cos(x)
And cos(x) = 0 at x = 3(pi)/2,5(pi)/2
Which of the following equations is written in standard form?
A. 2+3x−6y=0
B. 4x−2y=0
C. −8x+4y=1
D. −3y+x−4=0
Answer:
Choice B.
[tex]4x - 2y = 0[/tex]
Step-by-step explanation:
Has integer coefficients and equal to 0.
What is the length of the line?
WILL GIVE BRAINLIEST!!
Answer:
18
Step-by-step explanation:
6^2 plus 3^2 = 324, square root 324 =18
Answer:
[tex]\sqrt{45}[/tex]
Step-by-step explanation:
The line represents the hypotenuse of a right triangle with legs 6 and 3. For any right triangle, the Pythagorean Theorem states that [tex]a^2+b^2=c^2[/tex], where [tex]a[/tex] and [tex]b[/tex] are two legs of the triangle and [tex]c[/tex] is the hypotenuse.
Therefore, we have:
[tex]6^2+3^2=c^2,\\c^2=36+9,\\c=\boxed{\sqrt{45}}[/tex]
Vectors u and v are perpendicular. ||u|| = 5√2 units, and ||v|| = 6√2 units. ||u + v|| ≈ ? units
A. 11.04
B. 11.05
C. 15.55
D. 15.56
Answer:
15.56
Step-by-step explanation:
Given the vectors ||u|| = 5√2 units, and ||v|| = 6√2 units.
||u + v|| ≈ 5√2 + 6√2
||u + v|| ≈ (5+6)√2
Since √2≈ 1.4142
||u + v|| ≈ 11(1.4142)
||u + v|| ≈ 15.56
Hence the correct option is D
Answer: 11.05
Step-by-step explanation: got it right
you buy butter at 3 dollars a pound one portion requires 2oz of butter how much for one portion
Answer:
0.375 dollars
Step-by-step explanation:
1 pound = 16 oz
1 oz = 1/16 pound
2 oz = 2/16
2/16 * 3 = 0.375
can jack built 1/5 of a shed in the same time that kyle can build 5/8 of shed,
how much of a shed will jack have built when kyle finished building 1 shed?
=============================================================
Explanation:
Let's say the shed comes in 40 equal pieces. Each piece takes the same amount of time to assemble. Why am I picking 40? Because 8*5 = 40.
This will allow us to rewrite the fractions with a common denominator.
1/5 = 8/40 .... multiply top and bottom by 85/8 = 25/40 .... multiply top and bottom by 5So Jack can build 8/40 of the shed in the same amount of time Kyle can build 25/40 of the shed.
Instead of writing fractions (which honestly are a pain to deal with), I'm going to write "8 pieces" and "25 pieces" to represent "8/40" and "25/40" respectively. Just keep in mind that there are 40 pieces total.
So again, Jack can assemble 8 pieces in the time it takes Kyle to assemble 25 pieces.
---------------
The ultimate goal is to have Kyle assemble 40 pieces while Jack puts together some unknown number of pieces (some number between 8 and 40). Let's say it's x.
We can then form this proportion
[tex]\frac{\text{Jack's initial 8 pieces}}{\text{x pieces}}=\frac{\text{Kyle's initial 25 pieces}}{\text{goal of 40 pieces}}[/tex]
which simplifies or cleans up to
5/x = 25/40
-----------------
Let's solve for x using cross multiplication
8/x = 25/40
8*40 = x*25
320 = 25x
25x = 320
x = 320/25
x = 12.8
So in the time it takes Kyle to assemble all 40 pieces, Jack can put together 12.8 pieces of the shed. However, we can't have Jack put together some fractional piece, because each "piece" is as small as it gets. We can't get any smaller. It would be like saying a fractional part of an atom or a lego block.
So we'll round 12.8 down to 12.
Jack can assemble 12 pieces in the time it takes Kyle to assemble 40 pieces.
Let's then convert this back to fraction form
12 pieces = 12/40 of a shed = 3/10 of a shed.
Find x on this triangle
Answer:
I didn't find the answer in the options
the height of the bigger triangle is 11√6/√3 = 11√2
x = 11√2 × √2 = 11×2 = 22
Answered by GAUTHMATH
Find the area of Parallelogram ABCD given M< A=30° AB=10in AD=6in A=
Answer:
30 in²
Step-by-step explanation:
Parallelogram height is,
6/2 (since it's a 30°-60°-90° triangle)
= 3
Area = base × height
= 10×3 in²
= 30 in²
Answered by GAUTHMATH
State if the scenario involves a permutation or a combination. Then find the number of possibilities.
The batting order for nine players on a 12 person team.
Permutation/Combination:
Answer:
Step-by-step explanation:
combination
is answer of this question
A random variable X is generated as follows. We flip a coin. With probability p , the result is Heads, and then X is generated according to a PDF f X|H which is uniform on [0,1] . With probability 1−p the result is Tails, and then X is generated according to a PDF f X|T of the form
f X|T (x)=2x,if x∈[0,1]. (The PDF is zero everywhere else.)
1. What is the (unconditional) PDF f X (x) of X ? For 0≤x≤1 : f X (x)=
2. Calculate E[X] .
Answer:
Following are the solution to the given points:
Step-by-step explanation:
For point a:
[tex]fx|H(x) = 1;0< x<1\\\\fX|T(x) = 2x; 0\leq x \leq 1\\\\fx(x) = P(H \bigcap X = x) +P(T \bigcap X=x)\\\\[/tex]
[tex]=P(H)fX|H(x)+P(T)fX|T(x)\\\\= p(1) + (1-p)2x\\\\= p(1 -2x)+2x\\\\[/tex]
Using the PDF of the X value
[tex]fX(x) =2x +p(1 - 2x); \ 0\leq x\leq 1[/tex]
0 ; otherwise
For point b:
[tex]E(X)=\int^{1}_{0} \ x fX (x)\ dx=\int^{1}_{0} \ x(2x+p(1-2x))\ dx\\\\=\int^{1}_{0} \ (2x^2+(x-2x^2)p) dx\\\\[/tex]
[tex]= 2(\frac{x^3}{3}) + (\frac{x^2}{2}-2(\frac{x^3}{3}) \begin{vmatrix} x=1\\ x=0\end{vmatrix} \\\\[/tex]
[tex]= \frac{2}{3} + (\frac{1}{2} - \frac{2}{3})p\\\\= \frac{2}{3} -\frac{p}{6}\\\\= \frac{(4 - p)}{6}[/tex]
Three numbers are in the ratio of 1:2:4. If 3 is added to the first and 8 is subtracted from the third, the new numbers will be the first and third terms of an A.P., whose second term is the second number. Find the original numbers.
9514 1404 393
Answer:
5, 10, 20
Step-by-step explanation:
Suppose the three numbers are x, 2x, and 4x. Then they have the required ratios. After the transformation, we have ...
((x+3) +(4x -8))/2 = 2x . . . . . 2nd term is average of 1st and 3rd
5x -5 = 4x ⇒ x = 5
The original numbers are 5, 10, 20.
_____
After the adjustment, the arithmetic sequence is 8, 10, 12.
If the price of a stapler increase from Rs 50 to Rs 54, find the percentage increase?
HELPinjjgk go hhjkkggb jjj
Answer:
what i dont understand
Step-by-step explanation:
There are 11 green marbles and 12 orange marbles in a bag. You randomly
choose one of the marbles. What is the probability of choosing a green marble?
[tex]\\ \Large\sf\longmapsto 11+12[/tex]
[tex]\\ \Large\sf\longmapsto 23[/tex]
[tex]\boxed{\Large{\sf P(G)=\dfrac{No\:of\:green\:marbles}{Total\:marbles}}}[/tex]
[tex]\\ \Large\sf\longmapsto P(G)=\dfrac{11}{23}[/tex]
Answer:
11/23
Step-by-step explanation:
11 green marbles and 12 orange marbles = 23 marbles
P(green) = green marbles / total marbles
= 11/23
Solve the equation below:
5x – 11 = 19
x = 4
x = 6
x = 4.4
x = 1.6
pls answer i need help today
Answer:
x=6
Step-by-step explanation:
5x - 11 = 19
5x = 30
x = 6
20characters
5x = 19+11 5x = 30 x = 30/5 x = 6
A car is traveling at a rate of 80 miles per hour. Assume that 1 mile is equal to 1.6km.
what is the rate:. km/h
distance traveled in 3 hours: km
I think that car travelled 128 km in one hour and 384km in 3 hours
Answer: 384 km
Step-by-step explanation:
Convert m/ph to k/ph by multiplying the equivalent of 1 mile in kilometers
(1m = about 1.6km) by the total number of miles.
80 x 1.6 = 128
You now have the distance traveled per hour in m/ph converted to k/ph.
All you do now is multiply it by the time traveled:
(128 kilometers per one hour for 3 hours)
128 kph x 3 = 384km
What is the discriminat of 2x+5x^=1
Answer:
don't know...........
A postmix beverage machine is adjusted to release a certain amount of syrup into a chamber where it is mixed with carbonated water. A random sample of 25 beverages was found to have a mean syrup content of fluid ounces and the sample standard deviation is fluid ounces. Find a 95% two-sided confidence interval on the mean volume of syrup dispensed. Assume population is approximately normally distributed. Round your answers to 3 decimal places.
Answer:
(1.1155 ; 1.1245)
Step-by-step explanation:
Given that :
Sample mean, xbar = 1.12
Sample standard deviation, s = 0.011
Sample size, n = 25
Since we are using the sample standard deviation, we use the T distribution ;
The confidence interval is defined as :
C. I = Xbar ± Tcritical * s/√(n)
Degree of freedom, df = n - 1 = 24
Tcritical(0.05, 24) = 2.064
C. I = 1.12 ± (2.064 * 0.011 / √25)
C.I = 1.12 ± 0.0045408
Lower boundary = (1.12 - 0.0045408) = 1.1155
Upper boundary = (1.12 + 0.0045408) = 1.1245
(1.1155 ; 1.1245)
compute (-12)+(-8)+30
Answer:
10
Step-by-step explanation:
(-12) + (-8) +30
-(12+8)+30
-20 + 30
10
What is the y-intercept of the line that has a slope of `-4` and passes through the point (4, -6)`?
Answer:
(0, 10)
Step-by-step explanation:
Answer:
y = -4x + 10
Step-by-step explanation:
y = -4x + b
-6 = -4(4) + b
-6 = -16 + b
10 = b
consider a study conducted to determine the average protein intake among an adult population. Suppose that a confidence level of 85% is required with an interval about 10 units wide. if a preliminary data indicates a standard deviation of 20g, what sample of adults should be selected for the study?
Answer:
made up of about 20 common amino acids. The proportion of these amino acids varies as a characteristic of a given protein, but all food proteins—with the exception of gelatin—contain some of each. Amino nitrogen accounts for approximately 16% of the weight of proteins. Amino acids are required for the synthesis of body protein and other important nitrogen-containing compounds, such as creatine, peptide hormones, and some neurotransmitters. Although allowances are expressed as protein, a the biological requirement is for amino acids.
Proteins and other nitrogenous compounds are being degraded and resynthesized continuously. Several times more protein is turned over daily within the body than is ordinarily consumed, indicating that reutilization of amino acids is a major feature of the economy of protein metabolism. This process of recapture is not completely efficient, and some amino acids are lost by oxidative catabolism. Metabolic products of amino acids (urea, creatinine, uric acid, and other nitrogenous products) are excreted in the urine; nitrogen is also lost in feces, sweat, and other body secretions and in sloughed skin, hair, and nails. A continuous supply of dietary amino acids is required to replace these losses, even after growth has ceased.
Amino acids consumed in excess of the amounts needed for the synthesis of nitrogenous tissue constituents are not stored but are degraded; the nitrogen is excreted as urea, and the keto acids left after removal of the amino groups are either utilized directly as sources of energy or are converted to carbohydrate or fat.
raphael made 2 pies and gave half of one pie to his grandmother. he wants to share the remaining pie with his neighbors so he cuts them into pieces that are each 3/8 of a pie. How many neighbors can have a slice of pie?
2.WHICH OF THE FOLLOWING IS A NON- NUMERIC DATA ? Required to answer. Single choice.
(1) 1,2,3,4,5,6
(2) 2,8,4,5,8
(3) A,B,AB,O
(4) NONE OF THE ABOVE
Answer:
3.) A,B,AB,O
Step-by-step explanation:
Non-numeric data refers to categorical data, or data that is not expressed quantitatively. Answers (1) and (2) contain quantitative data, so they would be eliminated as potential answer choices and therefore (4) would also be eliminated. This leaves answer (3), which does not have quantitative data and is therefore non-numeric.
