can anyone help me with this one​

Answer:

there very old

Explanation:

The force exerted by the explosion on the piston is 2.4 N.

The given parameters:

The force exerted on the piston by the explosion is calculated as follows;

F = PA

where;

A is the area of the piston in m²

The surface area of the piston in square meter is calculated as follows;

[tex]A = 80 \ cm^2 \times \frac{(1m)^2}{(100 \ cm)^2} \\\\A = 0.008 \ m^2[/tex]

The force exerted by the explosion on the piston is calculated as follows;

[tex]F = 300 \ (N/m^2)\ \times \ 0.008 \ (m^2)\\\\F = 2.4 \ N[/tex]

The complete question is here:

In a car engine, fuel is ignited within a cylinder to cause an explosion that moves a piston. If the explosion exerts 300 Pa of pressure on a piston with a surface area of 80 cm^2, what is the force exerted on the piston?

Learn more about force and pressure here: https://brainly.com/question/22930937

Answer:

[tex]1\; \rm V[/tex].

Explanation:

Ohm's Law give the following relationship between the potential [tex]V[/tex] across a conductor, the electrical resistance [tex]R[/tex] of that conductor, and the current [tex]I[/tex] through that conductor:

[tex]V = I \, R[/tex].

It is given that the current through this conductor is [tex]I = 1\; {\rm A}[/tex], and that the electrical resistance of this conductor is [tex]R = 1\; \rm \Omega[/tex].

Note, that the unit of electrical resistance Ohm is a composite unit; [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex] (volts per ampere.)

Substitute the value of [tex]I[/tex] and [tex]R[/tex] into the equation [tex]V = I \, R[/tex] from Ohm's Law to find the potential across this conductor:

[tex]\begin{aligned}V &= I \, R \\ &= 1\; {\rm A} \times 1\; {\rm \Omega} \\ &= 1\; {\rm A} \times 1\; {\rm V \cdot A^{-1}} \\ &= 1\; {\rm V}\end{aligned}[/tex].

The water behind a hydroelectric dam stores gravitational potential energy since it is at a higher level than the water on the other side of the dam. As the water falls, this potential energy is converted into kinetic energy, which turns turbines to generate electricity. Often, the water comes from behind a dam built across a river valley. The water high up behind the dam contains gravitational potential energy . This is transferred to kinetic energy as the water rushes down through tubes inside the dam. The moving water drives electrical generators , which may be built inside the dam.

Answer:

17.8954903 or 17.9 mph

Explanation:

m/s is meters per second. 1609.344 meters is one mile. There are 3,600 seconds in an hour.  8 meters *3600 seconds= 28,800.  28,800/1609.344 = 17.8954903. Simplify to 17.9

Answer:

Tom

Explanation:

if for example both their work is 40 and Tom stops working after 2 hours but Claudia continues and stops after 3 hours when you divide their work by their time Claudia will get a lower number of power.

(in your explanation maybe use different numbers based on you book or notes)

Answer:

Claudia had more power. She did more work than Tom, and she did it in less time.

Explanation:

sample answer on edmentum. maybe change it up. hope this helps:)

Answer:

Black

Explanation:

Why do you call that flower a "red" rose? Could it be because it appears red in a typical 'wideband' solar or household light? That must mean that when the light of many colors shines on it, the rose absorbs everything except red, and red is the only light left to bounce off of it toward your eyes. If that's the case, and you illuminate it with the light of any single color other than red, then the rose will absorb that light and appear black.

Answer:

They go same in the vaccum

Answer:

its B hope you have a good Day

If the wave velocity and frequency of a wave are both doubled, the wavelength will remain the same.

The wavelength of a wave shows the spatial orientation of distance between two successive crest in a wave medium.

The wavelength λ is expressed by using the relation:

[tex]\mathbf{\lambda = \dfrac{v}{f}}[/tex]

Now, if velocity and  frequency of wave is both doubled, the wavelength will   remain the same.

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Answer:

  C

Explanation:

Most discussions of refraction will have a diagram similar to that of C.

The angle of incidence is measured from the normal to the boundary, as is the angle of refraction. The product of the sine of the angle and the index of refraction is the same for the media on either side of the boundary.

  n₁·sin(θ₁) = n₂·sin(θ₂)

For media, such as optical fiber, that has an index of refraction greater than 1, the angle of refraction will be smaller in that media than the angle of incidence coming from air.

Figure C applies.

Answer:

Hope it will help you a lot.

Answer:

Higher frequencies of light have shorter wavelengths.

Simplicity of conducting the study is to archival research as ability to test large numbers of participants is to surveys.

Archival research is a type of research which involves seeking out and extracting the evidence from archival records. These archival records may be held together either in the collection of institutions, such as libraries and museums, or in the custody of the organization that originally generated or accumulated them, or in that of a successor object.

Archival research can be contrasted with the secondary research, which involves identification and consulting the secondary sources related to the topic of enquiry; and with the other types of primary research and empirical investigation such as fieldwork and experiment.

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Answer:b. 5.0 meters

Explanation: d² = 3²+4²

d² = 9+16

d² = 25

d = √25

d = 5m

The magnitude of the displacement is 5 m as shown in the diagram. Option B is correct.

What is displacement?

Displacement can be defined as the total change in the position of the object. It is a vector quantity.

From the Pythagorean theorem,

[tex]d =\sqrt { 3^2 +4^2}\\\\d = \sqrt {25}\\\\d = 5[/tex]

Therefore, the magnitude of the displacement is 5 m.

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Answer:

Answer is 1000kg

Hope it help

Answer:

0.02m/s^2

Explanation:

Answer:

Weight=F=MA=52*8.87=461.24

Hi there!

Recall Newton's Second Law:

[tex]\large\boxed{\Sigma F = ma}[/tex]

∑F = net force (N)

m = mass (kg)

a = acceleration (m/s²)

We must begin by solving for the acceleration using the following:

a = Δv/t

In this instance:

Δv = 3 m/s

t = 2.5 sec

a = 3/2.5 = 1.2 m/s²

Now, plug this value along with the mass into the equation for net force:

[tex]\Sigma F = 5(1.2) = \boxed{6 N}}[/tex]

Answer:

[tex]\boxed {\boxed {\sf 6 \ Newtons}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration. The mass of the object is 5 kilograms, but the acceleration is unknown.

We can find acceleration using the following formula:

[tex]a= \frac{ \Delta v}{t}[/tex]

The velocity of the object increases by 3 meters per second. It accelerates in 2.5 seconds.

Substitute the values into the formula.

[tex]a= \frac{3 \ m/s}{2.5 \ s}[/tex]

[tex]a= 1.2 \ m/s/s = 1.2 \ m/s^2[/tex]

Now we know the mass and acceleration.

Substitute the values into the force formula.

[tex]F=ma[/tex]

[tex]F= (5 \ kg)(1.2 \ m/s^2)[/tex]

[tex]F= 6 \ kg*m/s^2[/tex]

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 6 kilogram meters per second squared is equal to 6 Newtons.

[tex]F= 6 \ N[/tex]

Using the gravitational force of F= G(m1*m2/r^2)

m1= 5.97 x 10^24 kg (Earth)

m2= 1.99 x 10^30 kg (Sun)

r= 1.48 x 10^11 m

G is a known value, it is 6.672 x 10^-11

All units are proper. Therefore plug in the values and you get 3.16 x 10^22 N.

Let me know if I calculated this wrong and it is something else so I can delete this. Thank you. I don't want to make other students put down the wrong answer.

Answer:

[tex]\boxed {\boxed {\sf F_g \approx 3.62 *10^{22} \ N}}[/tex]

Explanation:

We are asked to find the gravitational force between Earth and the Sun. Use the following formula:

[tex]F_g= \frac{Gm_1m_2}{r^2}[/tex]

G is the universal gravitational constant. One mass (m₁) is the Earth and the other (m₂) is the Sun. r is the distance between the planets.

Substitute the values into the formula.

[tex]F_g = \frac{ (6.67*10^{-11} N*m^2/kg^2)(5.97*10^{24} \ kg)(1.99*10^{30} \ kg) }{ (1.48 *10^{11} \ m)^2}}[/tex]

Multiply the numerator. The units of kilograms cancel.

[tex]F_g = \frac {7.9241601 *10^{44} \ N*m^2}{ (1.48 *10^{11} \ m)^2 }[/tex]

Solve the exponent in the denominator.

[tex]F_g= \frac {7.9241601 *10^{44} \ N*m^2}{ 2.1904*10^{22} \ m^2}[/tex]

Divide. The units of meters squared cancel.

[tex]F_g=3.61767718 *10^{22} \ N[/tex]

The original values all have 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 7 in the thousandth place tells us to round the 1 up to a 2.

[tex]F_g \approx 3.62 *10^{22} \ N[/tex]

The gravitational force between Earth and the Sun is approximately 3.62 *10²² Newtons.

Answer

C

hope this helps!!

*please mark brainliest if correct!! Trying to level up!!

110 grams

mass of salt + mass of water

10 + 100

110g

Answer:

110 grams

Explanation:

If you were to mix 7 grams of sugar into 100 grams of water, how much will the total mass of the solution be?

No mass was gained or lost, so the mass would be 107 grams.

100 grams

107 grams

93 grams

95 grams

No mass was gained or lost, so the mass would be 107 grams.

(For your problem it would be 10+ 100= 110g)

The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

The given parameters:

The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;

[tex]\Sigma F = 0\\\\T_1 sin(\theta) + T_2 sin(\theta) - W = 0[/tex]

where;

The weight of the seashell is calculated as;

[tex]1.42 \times sin(75) \ + \ 1.42 \times sin(75) \ - W = 0\\\\2.743 - W = 0\\\\W = 2.743 \ N[/tex]

The mass of the seashell is calculated as follows;

[tex]W = mg\\\\m = \frac{W}{g} \\\\m = \frac{2.743}{9.8} \\\\m = 0.28 \ kg[/tex]

Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

Learn more about equilibrium forces here: https://brainly.com/question/8045102

For this case, the relationship between the two forces is given by:

F1 = nF2

Where,

Then, replacing the values we have:

F1 = (2.2)(202)

Having the calculations we have:

F1 = 444.4N

Answer: The output force that only lifts the load is F1 = 444.4N.

Answer:

Yes.

Explanation:

Displacement is a vector quantity, meaning it has to be a straight graph jointing from starting point to final point and has a direction as well as magnitude and it can also be negative as well as positive and zero.

Displacement is also changes in position (points) of distance. A distance is scalar quantity meaning it only has magnitude and does not have direction. Since distance is scalar quantity, it cannot be negative. Also graph of distance can be a curve graph or any graph.

So when does displacement equal to distance? If an object is moving in straight path or line in one/fixed direction, both displacement and distance are same.

Because if a distance is a straight path and the displacement is simply a straight line (or ray) jointing from starting point to end point, both distance and displacement are both straight path or rays. Since distance and displacement have same graph, we can conclude that both are same in values.

If we go by calculus, given x = 2t as example of straight graph where x stands for position and t stands for time. We can find the displacement from b to a by using the following formulas:

Displacement

[tex]\displaystyle \large{s=\int\limits^b_a {v} \, dt}[/tex]

Distance

[tex]\displaystyle \large{l=\int\limits^b_a {|v|} \, dt}[/tex]

v stands for velocity which we can find from:

Velocity

[tex]\displaystyle \large{v=\frac{dx}{dt}}[/tex]

If you have learnt calculus, first, differentiate x = 2t with respect to t.

[tex]\displaystyle \large{v=2}[/tex]

Then substitute v = 2 in s and l to find find if both displacement and distance are equal in straight path.

Displacement

[tex]\displaystyle \large{s=\int\limits^b_a {2} \, dt}\\\displaystyle \large{s=[2t]\limits^b_a}\\\displaystyle \large{s=2b-2a = 2(b-a)}[/tex]

Distance

[tex]\displaystyle \large{l=\int\limits^b_a {|2|} \, dt}\\\displaystyle \large{l=\int\limits^b_a {2} \, dt}\\\displaystyle \large{l=[2t]\limits^b_a}\\\displaystyle \large{l=2b-2a=2(b-a)}[/tex]

Since both displacement and distance are equal when integrating on straight graph, we can conclude that an object moving in straight fixed point has same distance and displacement.

Answer:

Explanation:

An open train car rolls along a track while it is being filled with sand. There is negligible friction. The speed of the train car will be slowed down.

Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor.

Friction always moves an object in a direction that is counter to the direction that it is traveling or attempting to move.

Speed indicates the rate of movement of something or someone. If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance x time.

Therefore, an open railway car is packed with sand and is rolling along a track. Very little friction exists. The railway car's speed will be slowed down.

To learn more about friction, refer to the link:

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Answer:

?????

Explanation:

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