Consider the piecewise function shown on the graph. Over which interval of the domain does the graph represent an exponential function?

Answer:

The relation between individual and society is very close. Essentially, “society” is the regularities, customs and ground rules of antihuman behavior. ... Man is biologically and psychologically equipped to live in groups, in society. Society has become an essential condition for human life to arise and to continue.

Answer:

let the polynomial be

f(x)=x³+2kx+2

is divided by

g(x)=x+2

hence

(x+2) is a factor of f(x)

so comparing with x-a we get a=-2

so

f(a)=0

f(-2)=(-2)³+2*-2*k+2

0=-8-4K+2

4k=-6

K=-6/4

k=-3/2

again

when divided by x+1

g(x)=x+1

hence

x+1 is a factor

so a=-1

f(-1)=-(1)³+2*-1*k+2

0=-1-2k+2

0=1-2k

k=1/2

The value of k is 1/2 when divided by x+1

and

K =-3/2 when divided by x+2

Answer:

DE=27

EF=13

DG=13

GF=27

Step-by-step explanation:

12x+3=5x+17

12x-5x=17-3

u'll get 14 then simply it by the numbe of X u'll get 2 then replace the X with the number

Answer:

-60

Step-by-step explanation:

Answer:

The answer is "25 ml".

Step-by-step explanation:

Dose[tex]= 500 \ mg\\\\[/tex]

Solution [tex]= 100\ \frac{mg}{teaspoonful}\\\\[/tex]

Calculating the Conversions:

Teaspoonful [tex]= 5 \ ml \ \text{(Ounce = 30 ml = 6 Tablespoonsful)}[/tex]

[tex]\therefore\\\\Solution = \frac{100\ mg}{ 5\ ml} = 20\ \frac{mg}{ml}\\\\Dose \ volume = \frac{500\ mg}{ 20\ \frac{mg}{ml}} = 25\ ml[/tex]

Answer:

sorry I don't know

sorry I Don't know

Answer:100

Step-by-step explanation:

Given

Last year 160 new candidates submitted to work for agency

It is expected to increase by 25% that is , increase in one year should be

[tex]\Rightarrow 160+160\times 25\%\\\Rightarrow 160(1+0.25)\\\Rightarrow 160\times 1.25\\\Rightarrow 200[/tex]

200 application in the upcoming year. So, in 6 months, agency must have accepted 100 applications.

Answer:

Total number of students in the college = 200 student

Step-by-step explanation:

Given:

Number of student make dean's list = 67 student

Percentage of student make dean's list = 33.5% of all student

Find:

Total number of students in the college

Computation:

Total number of students in the college = Number of student make dean's list / Percentage of student make dean's list

Total number of students in the college = 67 / 33.5%

Total number of students in the college = 67 / 0.335

Total number of students in the college = 200 student

Answer:

6.75x + 5.50y = 186.75

Step-by-step explanation:

The stuffed mushrooms cost 6.75 dollars and the tomato bread costs 5.50 dollars.

Answer:

186.75

Step-by-step explanation:

6.75x+5.50y=186.75

Answer:

you can plug it back into the original equation to see if it fits the solution. if not then you have another solution you need to solve for.

Answer:

if we're talking on linear equations, then the two equations would intersect at one point. or when you solve it, it'll be only 1 number that can fit that equation.

p.s.: sub to #gauthmath# sub reddit if ya can ^^

Answer:

"97" is the appropriate answer.

Step-by-step explanation:

Given:

Number of trees,

= 485

Orchards of trees,

= 5

The number of trees in each orchard will be:

= [tex]\frac{Number \ of \ trees}{Orchards \ of \ trees}[/tex]

= [tex]\frac{485}{5}[/tex]

= [tex]97[/tex]

Answer:

The volume of the cube is 21952.

Step-by-step explanation:

V = L x W x H

because a cube's sides are all the same, the length, width, and height are also the same. So we use the formula:

V= S^3

(S standing for side)

we know the height is 28 and as all sides measure the same we use the equation:

V= 28^3

28^3 = 21952

So, V= 21952

Answer:

try 14n

Step-by-step explanation:

Answer:

[tex]r \: = 2sin2 \theta \\ = > r = 2.2sin\theta.cos\theta \\ = > r = 4sin\theta.cos\theta \: \\ \\ \sf \: we \: know \: that \: \\ x = r \: cos\theta \: \therefore \: cos\theta = \frac{x}{r} \\ \\ y = r \: sin\theta \: \therefore \: sin\theta = \frac{y}{r} \\ \\ \sf \: now \\ \\ r = 4 \times \frac{y}{r} \times \frac{x}{r} \\ = > {r}^{3 } = 4xy \\ \\ \sf \: again \: \: r = \sqrt{ {x}^{2} + {y}^{2} } \\ \\ = > {( \sqrt{ {x}^{2} + {y}^{2} } })^{3} = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{ \frac{3}{2} } = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{3} = 16 {x}^{2} {y}^{2} [/tex]

Please mark me as Brainliest

[tex] \bf \: f(x) = \frac{3}{2} \times {2}^{x} \\ \\ = > \bf \: f(0) = \frac{3}{2} \times {2}^{0} = \frac{3}{2} \times 1 = \frac{3}{2} = 1.5 \\ \\ = > \bf \: f(1) = \frac{3}{2} \times {2}^{1} = 3 \\ \\ = > \bf \: f(2) = \frac{3}{2} \times {2}^{2} = 6 \\ \\ = > \bf \: f( - 1) = \frac{3}{2} \times {2}^{ - 1} = \frac{3}{2} \times \frac{1}{2} = \frac{3}{4} = 0.75 \\ \\ = > \bf \: f( - 2) = \frac{3}{2} \times {2}^{ - 2} = \frac{3}{2} \times \frac{1}{4} = \frac{3}{8} = 0.375[/tex]

Answer:

SA=2πrh+2πr2=2·π·12·3+2·π·122≈282.7cm2

Answer:

C. Kiometers per hour. I think

Answer:

678

Step-by-step explanation:

12*11=132

11*9=99

12*9=108

132+99+108=339

339*2=678

Answer:

[tex]\sqrt[2]{8}[/tex]

Step-by-step explanation:

Remember the basic format of a fraction raised to a fractional exponent:

[tex]a^\frac{b}{c}=\sqrt[b]{a^c}[/tex]

Some terms to keep in mind are the following:

(a) is the base

(c) is the exponent

(b) is the index

Apply this information to the given problem:

[tex]2^\frac{3}{2}[/tex]

In this case, (2) is the base, and the index; (3) is the exponent. Apply the general format of the fraction exponent to change the expression from an exponent to a radical.

[tex]2^\frac{3}{2}=\sqrt[2]{2^3}[/tex]

Simplify the term under the radical:

[tex]\sqrt[2]{2^3}=\sqrt[2]{8}[/tex]

Answer:

17.y=-x+12

18.y=-1/4x+7

Step-by-step explanation:

17.a Solve for y (y=-5+x)

17. b Reciprocal (y=-1x-5)

17. c Subsitute equation into (8,-1) (-1=-13=y=x+12)

18.a Subtract y values and x values= (6-4)/(4-12)=2/-8=-1/4, this will be your slope

18. b Plug in -1/4 into either of the two ordered pairs to find y value=(12,4)=(4=-3)=y value=7.

18. c=y=-1/4x+7

Answer:

66%

Step-by-step explanation:

[tex]-10x\:+\:\left(20\cdot \left(1-x\right)\right)=\:0[/tex]

x = [tex]\frac{2}{3}[/tex] = .666 = 66%

Given:

Volume of a sphere is [tex]\dfrac{28}{3}[/tex] times the surface area.

To find:

The surface area and the volume of the sphere.

Solution:

Volume of a sphere:

[tex]V=\dfrac{4}{3}\pi r^3[/tex]              ...(i)

Surface area of a sphere:

[tex]A=4\pi r^2[/tex]                      ...(ii)

Where, r is the radius of the sphere.

Volume of a sphere is [tex]\dfrac{28}{3}[/tex] times the surface area.

[tex]V=\dfrac{28}{3}\times A[/tex]

[tex]\dfrac{4}{3}\pi r^3=\dfrac{28}{3}\times 4\pi r^2[/tex]

Multiply both sides by 3.

[tex]4\pi r^3=112\pi r^2[/tex]

[tex]\dfrac{\pi r^3}{\pi r^2}=\dfrac{112}{4}[/tex]

[tex]r=28[/tex]

Using (i), the volume of the sphere is:

[tex]V=\dfrac{4}{3}\times \dfrac{22}{7}\times (28)^3[/tex]

[tex]V\approx 91989[/tex]

Using (ii), the surface area of the sphere is:

[tex]A=4\times \dfrac{22}{7}\times (28)^2[/tex]

[tex]A=9856[/tex]

Therefore, the surface area of the sphere is 9856 sq. units and the volume of the sphere is 91989 cubic units.

Answer:

y = 2x -4

Step-by-step explanation:

2y = 4x - 8

Divide each side by 2

2y/2 = 4x/2 - 8/2

y = 2x -4

Answer:

Option D, 52

Answered by GAUTHMATH

Answer: l,j,k

Step-by-step explanation:

Answer: 56

Step-by-step explanation:

Let x be the number that is supposed to be subtracted from 61.

Given

61 - x = 5

Add both sides by x

61 - x + x = 5 + x

61 = 5 + x

Subtract 5 on both sides

61 - 5 = 5 + x - 5

x = 56

Hope this helps!! :)

Please let me know if you have any questions

Answer:

x = ±i ,  x=1

Step-by-step explanation:

(x^2+1)(x-1)=0

Using the zero product property

x^2 +1 = 0   x-1= 0

x^2 = -1       x=1

Taking the square root of the equation on the left

sqrt(x^2) = sqrt(-1)

x = ±i   where  i is the imaginary number

We still have x=1 from the equation on the right

Answer:

V = 276.32 ft^3

Step-by-step explanation:

Volume of a cylinder is

V = pi r^2 h

The diameter is 4 so the radius is d/2 = 4/2 = 2

V = (3.14) ( 2)^2 * 22

V = 276.32 ft^3

Answer:

The equation is true.

Step-by-step explanation:

In order to solve this problem, one must envision a right triangle. A diagram used to represent the imagined right triangle is included at the bottom of this explanation.  Please note that each side is named with respect to the angle is it across from.

Right angle trigonometry is composed of a sequence of ratios that relate the sides and angles of a right triangle. These ratios are as follows,

[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}[/tex]

One is given the following equation,

[tex]\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0[/tex]

As per the attached reference image, one can state the following, using the right angle trigonometric ratios,

[tex]sin(A)=\frac{a}{c}\\\\sin(B)=\frac{b}{c}\\\\cos(A)=\frac{b}{c}\\\\cos(B)=\frac{a}{c}[/tex]

Substitute these values into the given equation. Then simplify the equation to prove the idenity,

[tex]\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0[/tex]

[tex]\frac{\frac{a}{c}+\frac{b}{c}}{\frac{b}{c}+\frac{a}{c}}+\frac{\frac{b}{c}-\frac{a}{c}}{\frac{a}{c}-\frac{b}{c}}=0[/tex]

[tex]\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}[/tex]

Remember, any number over itself equals one, this holds true even for fractions with fractions in the numerator (value on top of the fraction bar) and denominator (value under the fraction bar).

[tex]\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}[/tex]

[tex]\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{-(a-b)}{c}}{\frac{a-b}{c}}[/tex]

[tex]1+(-1)=0[/tex]

[tex]1-1=0[/tex]

[tex]0=0[/tex]

Answer:

15x^9

Step-by-step explanation:

A=l x w

5x^4 times 3x^5 is basically 3*5*x^4*x^5

when you multiply exponents with the same base, you add the exponents, so it becomes 15x^9

Answer:

C is correct

Step-by-step explanation:

a is wrong because: 1*-1*-1*-1 =1

b) 1*1*1*1 =1

d) 1*-1*1*1 =1

only c 1*-1*-1*1 =-1 at the end of polynomial