Answer:
[tex](x^2+y^2)^3 = 16x^2y^2[/tex]
Step-by-step explanation:
We want to convert the polar equation:
[tex]\displaystyle r = 2 \sin 2\theta[/tex]
To rectangular form.
Recall the double-angle identity for sine:
[tex]\displaystyle \sin 2\theta = 2\sin\theta\cos\theta[/tex]
Hence:
[tex]\displaystyle r = 4\sin\theta\cos\theta[/tex]
Since x = rcosθ and y = rsinθ:
[tex]\displaystyle r = 4\left(\frac{x}{r}\right)\left(\frac{y}{r}\right)[/tex]
Multiply:
[tex]\displaystyle r = \frac{4xy}{r^2}[/tex]
Recall that x² + y² = r². Hence:
[tex]\displaystyle r = \frac{4xy}{x^2 + y^2}[/tex]
By squaring both sides:
[tex]\displaystyle r^2 = \frac{16x^2y^2}{(x^2+y^2)^2}[/tex]
Substitute:
[tex]\displaystyle x^2+y^2 = \frac{16x^2y^2}{(x^2+y^2)^2}[/tex]
And multiply. Therefore:
[tex](x^2+y^2)^3 = 16x^2y^2[/tex]
find the area of a triangle with a base of 12 ft and a height of 2ft
Answer:
1/2×2×12=12 feet
Step-by-step explanation:
1/2× base area × height
Select THREE expressions that are equivalent to -16x - 68.
A. -4(4x - 17)
B. -2(8x + 34)
C. 2( - 8x - 34)
D. 4( - 4x - 17)
E. 8( - 2x - 8)
got it wrong the first time :(
Answer:
b, c, d
Step-by-step explanation:
Is the equation below written in standard form? If not, select which explanation best applies to why the equation
is not written in standard form.
12 = 2x + 4y
A. the requirement that A 20 is not satisfied
B. the requirement that A and B are not both zero is not satisfied
C. A, B, and C do not have a greatest common factor of 1
D. the equation is written in standard form
Answer:
D
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers
12 = 2x + 4y , that is
2x + 4y = 12 ← is in standard form
Peter, Jan, and Maxim are classmates. Their total score for the last test was 269. Peter's score was higher than Jan's score and higher than Maxim's score. What could be peters least possible score?
Answer:
91
Step-by-step explanation:
P>J and P>M
269 -> split into 3 parts
Approx is 90
IF Peter's score is 90, then the other 2 scores could be 90 and 89
+ 1 to Peter's score
Hence Peter's least possible score could be 91.
Help with this plz?
Topic (Similarity)
Answer:
MATH
Step-by-step explanation:
Find the value of x. I need help ASAP
Answer:
x is 30 degrees
Step-by-step explanation:
if line 4x+ky=11 and line y=8x-3 are parallel find the value of k
pls help me asap thank you step by step please!!
Answer:
k=-1/2
Step-by-step explanation:
u have to change line 4x + ky=11 to this form:
y=11/k-4x/k
then, if 2 lines are parallel, their slopes have to equal
so: 8=-4/k -> k=-1/2
determine the equation of a parallel line to x=5
Answer:
x = constant ( other than 5)
Step-by-step explanation:
The slope of a line x=5 is undefined
Parallel lines have the same slope
So any line that is vertical ( slope undefined) will be parallel
Whats the answer hurry !!
Answer:
[tex]=\frac{81m^2n^5}{8}[/tex]
Step-by-step explanation:
One is given the following expression:
[tex]\frac{(3m^-^1n^2)^4}{(2m^-^2n)^3}[/tex]
Simplify, distribute the exponent outside of the parenthesis by the terms inside of it. Remember, when a value that already has an exponent is raised to another exponent, the equivalent of these two values is multiplying the exponents together. Use this property here:
[tex]=\frac{(3m^-^1n^2)^4}{(2m^-^2n)^3}[/tex]
[tex]=\frac{3^4m^(^-^1^)^(^4^)n^(^2^)^(^4^)}{2^3m^(^-^2^)^(^3^)n^3}[/tex]
[tex]=\frac{81m^-^4n^8}{8m^-^6n^3}[/tex]
Now simplify this fraction. Keep in mind that a fraction is another way of representing the operation of division. When one wants to divide terms raised to an exponent, one must make sure that these terms have a like base. Then one will subtract the exponents from each other. Do this step with terms that have a variable base:
[tex]=\frac{81m^-^4n^8}{8m^-^6n^3}[/tex]
[tex]=\frac{81m^(^-^4^)^-^(^-^6^)n^(^8^)^-^(^3^)}{8}[/tex]
[tex]=\frac{81m^-^4^+^6n^8^-^3}{8}[/tex]
[tex]=\frac{81m^2n^5}{8}[/tex]
Cho đa thức f(x) = biết rằng f(1)=f(-1); f(2)=f(-2).
Chọn câu đúng :
A. f ( x ) = f ( −x) với mọi x
B. f ( x ) = − f ( −x) với mọi x
C. f ( x ) = 2 f ( −x) với mọi x
D. f ( x ) = 3 f ( −x) với mọi x
Answer:
A
Giải thích:
f(1)=f(x)
f(-1) và f(-2)= f(-x)
=> f(1)=f(-1) =A. f(x)=f(-x)
find the measure of the indicated angle to the nearest degree
Answer:
39.401
Step-by-step explanation:
In the given figure, if AOB is a straight line, then ∠BOC is
Answer:
acute angle.
Step-by-step explanation:
because it is 60 degree
Nếu AOB là một đường thẳng thì góc BOC =90°
Please help me with this on the image
Step-by-step explanation:
The total of the number of computers he sold in 2015 is 67.
The total of the number of computers he sold in 2016 is 61.
The total of the number of computers he sold in 2017 is 71.
He sold 35 computers in Quarter 1, 24 in Quarter 2, 61 in Quarter 3, and 79 in Quarter 4.
He sold the most computers in 2017 and the least in Quarter 2.
Therefore, to find the total number of computers he sold all time, we add 67, 61, and 71 together to get 199.
Hope this helped!
Answer with Step-by-step explanation:
From the given table
(a)
In quarter 1
Computer sold in 2015=12
Computer sold in 2016=15
Computer sold in 2017=8
Total computer sold in quarter 1=12+15+8=35
In quarter 2
Computer sold in 2015=9
Computer sold in 2016=10
Computer sold in 2017=5
Total computer sold in quarter 2=9+10+5=24
In quarter 3
Computer sold in 2015=21
Computer sold in 2016=17
Computer sold in 2017=23
Total computer sold in quarter 3=21+17+23=61
In quarter 4
Computer sold in 2015=25
Computer sold in 2016=19
Computer sold in 2017=35
Total computer sold in quarter 4=25+19+35=79
In 2015
Total number of computer sold=12+9+21+25=67
In 2016
Total number of computer sold=15+10+17+19=61
In 2017
Total number of computer sold=8+5+23+35=71
(b)He sold the most computers in 2017
(c) He sold the least computers in quarter 2.
Can someone explain this
Answer:
x=30/tan(22)
x= 74.2526056
Step-by-step explanation:
Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AD = 4 and dc =2 what is the length of ad
Question is slightly wrong .We have to find BD
AD=4CD=2we know
[tex]\boxed{\sf BD^2=AD\times DC}[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow BD^2=4\times 2[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow BD^2=8[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow BD=\sqrt{8}[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow BD=2√2[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow BD=2(1.4)[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow BD=2.8[/tex]
SOMEONE PLEASE HELP ME ITS URGENT (PICTURE)
Answer:
Question #1
x and its opposing side are equal in length. One of the sides have no fence.Set up an equation to find x:
[tex]x+x+10=26\\2x=26-10\\2x=16\\x=8[/tex]
The length of the side marked x is 8.0 m.
Question #2
New length = 10 + 1 = 11 cmNew width = xNew perimeter = old perimeter = 34 cmSet up an equation to find x
[tex]11+11+x+x=34\\2x=34-22\\2x=12\\x=6[/tex]
The new width is 6 cm.
what is the exponents
Find the value of 9x + 4y, when x = 4 and y = -3.
Answer:
hope found the answers bye.
Step-by-step explanation:
9x + 4y - 4 = 0
Putting in the x-value of -1, we get:
9(-1) + 4y - 4 = 0
Simplifying:
-9 + 4y - 4 = 0
Combining the -9 and the -4:
4y - 13 = 0
Getting rid of the -13 by adding 13 to both sides:
4y - 13 + 13 = 0 + 13
4y = 13
Dividing both sides by 4:
y = 13/4
Checking: Is 9(-1) +4(13/4) -4 really zero? Yes!
Phil’s age is 7 years more than times Peter’s age. Also, 4 times Phil’s age is 2 years less than twice Peter’s age. If x is Peter’s age in years, identify the equation that represents this situation and identify the solution to the equation
Answer:
simultaneous equations
Step-by-step explanation:
phils age =7x
Peter age=x
scenario 2
phils age = 4(7x)
Peter age= 2x-2
[tex]7x + x = 4(7x) + 2x - 2[/tex]
Number 13 I don’t get it
===========================================
Explanation:
The two equations given to us are
ab = 3ab^2 = 18Divide the second equation over the first equation and that would lead to b = 6
Notice how the 'a' terms divide to 1 and go away, i.e. cancel out.
The b terms divide to (b^2)/b = b
The right hand side values divide to 18/3 = 6
So that's how we end up with b = 6
-------------------------
Now if b = 6, then we can say,
ab = 3
a*6 = 3
a = 3/6
a = 1/2
Or we could say
ab^2 = 18
a*6^2 = 18
a*36 = 18
a = 18/36
a = 1/2
What is the solution set to this equation?
log_4(x + 3) + log_4x = 1
Answer:
x=1
Step-by-step explanation:
log_4(x + 3) + log_4x = 1
We know that loga(b) + loga(c) = loga(bc)
log_4(x + 3)x = 1
Raise each side to the base of 4
4^log_4(x + 3)x = 4^1
(x+3)x = 4
x^2 +3x = 4
Subtract 4 from each side
x^2 +3x -4 = 0
Factor
(x+4) (x-1) =0
Using the zero product property
x= -4 x=1
But x cannot be negative since logs cannot be negative
x=1
Answer:
A.. x = 1.
Step-by-step explanation:
log_4(x + 3) + log_4x = 1
log_4 x(x + 3) = log_4 4
Removing the logs:
x(x + 3) = 4
x^2 + 3x - 4 = 0
(x + 4)(x - 1) = 0
x = 1, -4.
We can ignore the -4 as there is no log of a negative.
simplify (4+√3)(4-√3)
Answer:
13
Step-by-step explanation:
(4+√3)(4-√3) = (4)^2-(√3)^2 =16-3 = 13
Answer:
Step-by-step explanation:
(a + b)(a -b) =a² - b²
a = 4 and b = √3
(4 + √3)(4 - √3)= 4² - (√3)²
= 16 - √3*√3
= 16 - 3
= 13
I WILL BE CHOOSING THE BRAINLIEST! PLEASE HELP ME!
What are different types of tools to find sides or angles in triangles. List and explain the conditions in which they are best applied.
(For example, the Pythagorean Theorem is particularly useful when there is a right triangle and two known sides and the third side is unknown.)
Answer:
If the triangle is similar by any axiom then the ratio of their sides will be equal then you can easily find the side of the triangle
OR
You can also find it by congurency.
Hope this helps
find the missing side of triangle
Using Pythagoras Theorem
[tex]\\ \sf\longmapsto B^2=H^2-P^2[/tex]
[tex]\\ \sf\longmapsto B=\sqrt{H^2-P^2}[/tex]
[tex]\\ \sf\longmapsto B=\sqrt{29^2-21^2}[/tex]
[tex]\\ \sf\longmapsto B=\sqrt{841-441}[/tex]
[tex]\\ \sf\longmapsto B=\sqrt{400}[/tex]
[tex]\\ \sf\longmapsto B=20[/tex]
** SOMEBOBY HELP ME**
Answer:
Step-by-step explanation:
If these were similar, then the ratio 35/18 (the top and bottom measures from each of the polygons) would have to equal the ratio 63/10 (the side measures from each of the polygons).
35/18 = 1.944444
63/10 = 6.3
They are not similar because the simplified ratios are not the same.
Find the value of x. Round
the nearest tenth.
Step-by-step explanation:
here's the answer to your question
it began 63°F, and the temp changed by 8°F over the course of 6 hours whats the minimum and maximum???
Answer:
Minimum Possible Temperature: 55° F
Maximum Possible Temperature: 71° F
Step-by-step explanation:
Beginning temperature: 63° F
Change in temperature: 8° F
If the temperature decreased: 63° F - 8 °F = 55° F
If the temperature increased: 63° F + 8° F = 71° F
Minimum Possible Temperature: 55° F
Maximum Possible Temperature: 71° F
2x - y - 4 = 0
3x + y - 9 = 0
What is the solution set of the given system?
A. {(6, 5)}
B. {(5, 6)}
C. {(13/5, 6/5)}
D. {(6/5, 13/5)}
Step-by-step explanation:
+ Both equations
You will get : 5x=13 ; x=13/5
and put x to the first equation
2*13/5-y=4
y=6/5
(13/5;6/5)
Answer is C
Hey can anyone help me pls
Answer:
6.8=6 8/5
.
.
.
.
.
.
.
hope it help
Amy has four more 20c coins than 5c coins. The total value of all her 20c and 5c is $3.80. How many 5c coins does Amy have?
Answer:
Amy has 12 5¢ coins
Step-by-step explanation:
Let x represent 20¢ coins and y represent 5¢ coins.
Amy has four more 20¢ coins than 5¢ coins. Hence:
[tex]x=y+4[/tex]
And the total value of all her coins is $3.80. Thus:
[tex]0.2x+0.05y=3.8[/tex]
This yields a system of equations:
[tex]\displaystyle \begin{cases} x=y+4 \\ 0.2x+0.05y=3.8\end{cases}[/tex]
We can solve by substitution. Substitute the first equation into the first:
[tex]\displaystyle 0.2(y+4)+0.05y=3.8[/tex]
Distribute:
[tex]\displaystyle 0.2y+0.8+0.05y=3.8[/tex]
Combine like terms:
[tex]\displaystyle 0.25y = 3[/tex]
And divide both sides by 0.25. Hence:
[tex]y=12[/tex]
Thus, Amy has 12 5¢ coins.
Using the first equation:
[tex]x=y+4[/tex]
Substitute:
[tex]x=(12)+4=16[/tex]
Thus, Amy has 16 20¢ coins.
In conclusion, Amy has 12 5¢ coins and 16 20¢ coins.