Determine the type of triangle that is drawn below.
5.89
X
V
38°
90°
4.53
7.43
52°
W

Determine The Type Of Triangle That Is Drawn Below.5.89XV38904.537.4352W

Answers

Answer 1

Answer:

Right-triangle

Scalene

Step-by-step explanation:

[] This is a right triangle because it has an angle that is 90°

[] This is a scalene triangle because all of the sides are different lengths

          -> We can also tell this is scalene because none of the angles are the same degree

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather


Related Questions

Find the missing term and the missing coefficient.
(6a −_)5a =_a2 − 35a

Answers

Answer:

[tex](6a-7)5a=30a^2-35a[/tex]

Step-by-step explanation:

Message if you want a detailed explanation.

pls help. pls show work as well thank you:)

Answers

Answer:

Step-by-step explanation done

Find y when = 22, if y varies directly as x,
and y = 39 when x = 7.

Answers

Answer:

let,

x=ky

y=39 when x=7 so,

7=39k

or, k=7/39

now, when x=22

22=7y/39

or, y=39×22/7

or, y=858/7

or, y=122.57 (rounded to the nearest hundredth)

square root of 800 to the nearest thousandth

Answers

The answer is most likely 28.2843

Answer:

28.284

Step-by-step explanation:

I don’t know if this is enough but please help me

Answers

Answer:

1 A

2c

3B

4f

do not use the last one f(X)=x

Step-by-step explanation:

What are the solutions to the system of equations?

{y=2x²−6x+3
{y=x−2

Answers

Answer:

x = 1, y = −1

x = 5/2, y = 1/2

Step-by-step explanation:

From the question given above, the following data were obtained:

y = 2x² − 6x + 3 ........ (1)

y = x − 2 ...... (2)

We can obtain the solutions to the equation as follow:

y = 2x² − 6x + 3 ........ (1)

y = x − 2 ...... (2)

Substitute the value of y in equation 2 into equation 1

y = 2x² − 6x + 3

y = x − 2

2x² − 6x + 3 = x − 2

Rearrange

2x² − 6x − x + 3 + 2 = 0

2x² − 7x + 5 = 0

Solve by factorization

Obtain the product of 2x² and 5. The result is 10x².

Find two factors of 10x² such that their sum will result to −7x.

The factors are −2x and −5x.

Replace −7x in the equation above with −2x and −5x as shown below:

2x² − 2x − 5x + 5 = 0

2x(x − 1) − 5(x − 1) = 0

(x − 1)(2x − 5) = 0

x − 1 = 0 or 2x − 5 = 0

x = 1 or 2x = 5

x = 1 or x = 5/2

Substitute the value of x into equation 2 to obtain y

y = x − 2

x = 1

y = 1 − 2

y = −1

x = 5/2

y = x − 2

y = 5/2 − 2

y = (5 − 4)/2

y = 1/2

SUMMARY:

x = 1, y = −1

x = 5/2, y = 1/2

which expression is equivalent to 10 a+ 3b -2a+b

Answers

Answer:

Step-by-step explanation:

Simplify like terms.

10a-2a+3b+b = 8a+4b

Answer:

8a +4b

4(2a+b)

Step-by-step explanation:

10 a+ 3b -2a+b

Combine like terms

10a-2a   +3b+b

8a +4b

We can factor out 4

4(2a+b)

PLEASE HELP!
Find the value of x.

Answer Options:
A. 12
B. 11
C. 10
D. 16

Answers

Answer: C) 10

Explanation:

We use the intersecting chords theorem here.

This is the idea where multiplying the pieces of each chord lead to the same product

6*x = 5*12

6x = 60

x = 60/6

x = 10

Answer:

C.) 10

Step-by-step explanation:

I got it correct on founders edtell

How to find interquartilte range

Answers

Answer:  Choice C) 8.5

============================================================

Explanation:

Each x represents a data point location.

So, for example, having an x over 60 means 60 is part of the set.

The set of values we're working with is

{59,60,61,63,63,64,66,68,70,71,71,73}

The repeated values are due to the fact we have a stack of two 'x' markers, and they occur at 63 and 71.

To find the IQR (interquartile range), we'll first need to find the median of this set. That's the middle most value.

Count out the number of values to find that there are n = 12 values.

The list splits into two halves that are n/2 = 12/2 = 6 items each

Between slots 6 and 7 is where the median is located.

The value in slot 6 is 64 and the value in slot 7 is 66. Average those two items to get (64+66)/2 = 65

The median is 65

---------------------------------

Next, we'll form two groups L and U such that

L = set of items lower than the median

U = set of items larger than the median

Because n is even, we simply just break the original set into two equal groups (6 items each)

L = {59,60,61,63,63,64}

U = {66,68,70,71,71,73}

The values of Q1 and Q3 represent the medians of L and U in that order.

The median of set L is (61+63)/2 = 62, so Q1 = 62

The median of set U is (70+71)/2 = 70.5, which is Q3

-----------------------------------

To summarize everything so far, we have found

Q1 = 62Q3 = 70.5

Subtract those items to get the IQR

IQR = Q3 - Q1

IQR = 70.5 - 62

IQR = 8.5 which points us to choice C as the final answer.

PLEASE HELP!!
BRAINLYEST TOO 1st

Answers

9514 1404 393

Answer:

  A, C

Step-by-step explanation:

Any table with no repeated x-values is a relation that is a function.

marked price of an item is 4000, what will be it's selling price having 20% discount and 10% vat.​

Answers

Answer:

I HOPE IT WILL HELP

EXPLANATION IS IN THE PHOTO .

Another way to do it is by

Multiplying the original value by the discounted percent, the percent taxed but add one to it.

(4,000)(.80)(1+10/100)= 3,520

4000 is the original value
.80 is the value of the item with 20% off
1.1 gives value after tax, adding the one allows you to see the value of the item after tax.




show the work please and thank you

Answers

Answer:

Option a, 13

if you solve it, you get 13 as the answer

³√(5x-1)=4

or, 5x-1=64

or, 5x=65

or, x=13

Nigel's age (n) is 3 years more
than his sister's age (s).

A. N = 3N + 3
B. N =3s
C. N = 3 + s
D. S = -3s/n

Answers

Answer:

b

Step-by-step explanation:

n=3s

~~~~~~~~~~~~~~~~~

If (3+√5)(4-√5)=a+b√5, where a and b are integers, then what is the value of a + b?

Answers

54 = 2 x 3³
So, if a and b are integers, a=2 and b=3

(solving rate problems). Michelle can
complete a
landscaping job in 6
days and Danielle
can complete the
same job in 4 days.
Working together, in
how many days
could they complete
the job

Answers

They could complete the job together in 2.4 days

The known parameters are;

The number of days it would take Michelle to complete the landscaping job = 6 days

The number of days it would take Danielle to complete the landscaping job = 4 days

The unknown parameter;

The number of days can the job be completed if they work together

The process of finding the solution;

The rate at which Michelle works = 1/6 of the landscaping work per day

The rate at which Danielle works = 1/4 of the landscaping work per day

Method;

Find their combined work rate, from which the time would take them to complete the job together can be found

Let, C, represent their combined work rate

Therefore, we have;

C = (1/6 + 1/4) = 5/12 of the landscaping (work) job/(per) day

The number of days they could complete the, 1, job = 1 job(work)/(5/12 (work)job/day) = 12/5 days = 2.4 days

∴ The number of days they could complete the job together = 2.4 days.

Learn more about unit rate here;

https://brainly.com/question/19605901

Thank you so much thank y’all for your help

Answers

Answer:

2(4) + 2(l) >14 (second option is the answer).

Second option!
Hope this is correct!

solve for θ.
sin(74) = cos(θ)

1. 6°
2. 74°
3. 36°
4. 16° ​

Answers

Sin74 = Cos16

cause 16 + 74 = 90

Whenever the sum of two angles is equal with 90, the Sin of one is equal with the Cos of the other like :

Sin(30) = Cos(60)

and also

Tan(30) = Cot(60)

Answer:

16

Step-by-step explanation:

sin(74) = cos(x)

sin(x)=cos(90-x)

sin (74) = cos(90-74)

sin 74 = cos( 16)

Write a function rule for table
Is it a, b, c or d?

Answers

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (1, 4) and (x₂, y₂ ) = (2, 5 ) ← 2 ordered pairs from the table

m = [tex]\frac{5-4}{2-1}[/tex] = [tex]\frac{1}{1}[/tex] = 1

The line crosses the y- axis at (0, 3 ) → c = 3

y = x + 3 ← equation of line → A

A rectangular field is to be fenced off, and then divided in two by a fence running parallel to one of the sides. If 996 meters of fencing can be used, find the dimensions of the field that will maximize the total area, and then find the maximum area. List the smaller dimension first.

Answers

Solution :

Maximize, S = xy

subject to 2x + 2y = 996

So,

2x + 2y = 996

2(x + y) = 996

x + y = 498

y = 498 - x

Therefore,

S = x (498 - x)

S = 498x - [tex]x^2[/tex]

S = [tex]-x^2 + 498x[/tex]

[tex]$S = -(x^2-498x + 249^2) + 300^2$[/tex]

[tex]$S= -(x-249)^2 + 249^2$[/tex]

S = x (498 - x)

S = 498x - [tex]x^2[/tex]

[tex]$\frac{dS}{dx}= 498 - 2x$[/tex]

[tex]$\frac{dS}{dx}= 0$[/tex]

498 - 2x = 0

2x = 498

x = 249

∴ y = 498 - x

  y = 498 - 249

     = 249

Answer:

A = 249 x 249 = 62001 square meter.

Side is L = 249 m

Step-by-step explanation:

Total length of the fence is 996 m.

Let the length is L and the width is W.

Perimeter = 2 (L + W)

996 = 2 (L + W)

498 = L + W

L = 498 - W ...... (1)

Let the area is

A = L W

A = (498 - W) W

A = 498 W - W^2

Differentiate with respect to W.

dA/dW = 498 - 2 W

Put it equal to zero.

498 - 2 W = 0

W = 249 m

Now, L = 498 - 249 = 249 m

Differentiate with respect to W again

[tex]\frac{d^2A}{dW^2} = - 2[/tex]

As it is negative so the area is maximum.  

The maximum area is

A = 249 x 249 = 62001 square meter.

Side is L = 249 m

15) The sum of one-fourth, one-ninth and one- third of a number is 25. Find the number.​

Answers

Answer:

Step-by-step explanation:

(1/4 + 1/9 + 1/3)x = 25.

x = 36

Answer:

Let the number be x

(1/4 + 1/9 + 1/3) * x = 25

25/36 * x = 25

25x = 25*36

x = 25*36/25

x = 36

Step-by-step explanation:

1. Calculate the slope of a line going trough A (-4,3) and B (0,6)
2. Calculate the slope of a line with a run of 3 and a rise of 9
3. Calculate the equation if two points are (1,6) and (5,0)

Answers

1. 1/2 2. 3 3. x=-1.5x+7.5

help please...what is the locus of the midpoints of all chords that can be drawn from a given point on a circle with a radius of 6. be exact with your answer.​

Answers

Answer:

the answer is a

Step-by-step explanation:

sory lawl

i mean e

answer e!

good luck w summer geometoery

The half life of a substance is 30 days. If there are 4.5 grams to start with, how much will be left after 23 days? Round to the nearest tenth of a gram. Be sure to label your answer.

Answers

65.4Step-by-step explanation:KHAN

Important formula:

[tex]N_t = N_0 (1/2)^\frac{t}{t_{1/2}}[/tex]

Here, you are trying to find Nt and you have N0 = 4.5g, t = 23 days, t1/2 = 30 days. Plug the values in and you should get 2.7g left after 23 days.

Pleeeeeeeeaaaaaaaaaaaasse help 71 points!!!!!!!!!

Answers

Answer:

54

Step-by-step explanation:

The perimeter is the sum of the outside

P = 8+4+5+10+( 4+10) +(8+5)

P = 54

Felix is now six times as old as Debbie. In twelve years time Felix will be two times as old as Debbie. How old are they​

Answers

Step-by-step explanation:

let debbie be x years

let felix be 6x years

in 12 years felix will be 2x older than debbie

do the calc

For a beverage, Lisa mixes cups of lemonade to cups of ice tea in a ratio of 2:5. Which of the following best describes the amount of lemonade to iced tea

Answers

Answer:

lemonade is 4:10 to ice or .4:1

Step-by-step explanation:

Assuming lemonade is 2 and tea is 5, you can use a table or multiply both reciprocals by 2 so 2x2 and 2x5 = 4:10. then if you want to see how much is in just once cup of tea divide by ten to each for the product of .4:1

Answer:  For every 2 cups of lemonade, there are 5 cups of iced tea.

if the ratio is 2:5 then for every 2 cups of lemonade there are 5 cups of tea.

it is just another way of saying the ratio

whats the area in square inches ​

Answers

Answer:

Area of triangle =1/2b×h

1/2×10×8.7

=44 square inches

Answer:

44

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh

where b is the base and h is the height

A = 1/2 (10) (8.7)

A= 43.5

Rounding to the nearest whole number

A = 44

The equation k(x+1)^2/3+(y+2)^2/4=1 represent circle if

Answers

Answer:

Can you Specify the Question?

mountains poem in nepali for class 7​

Answers

Step-by-step explanation:

म नजन्मिदै विधवा भएकी हिमाल

खै! किन हो मेरा यी हेर्ने नयनले उनलाइ

अझै पनि दिन र रातमा

सेतै लुगा पहिरिएकी देख्छ

अचम्म लाग्छ मलाइ पहिरिएकी सेतो लुगा माथि

मुनालले पाइला टेके पनि विष्ठा गरे पनि कहिल्यै

मैलो हुदैन सेतो लुगाको वास्तविक रङ

उत्तिकै सेतो देख्छु म

निर्जीव वस्तु भएनी हिमाललाइ

सजीव मनुस्यको जस्तै चोटको कल्पना गरेको छु मैले

किनकी चोटै चोटले ग्रसित भएकी उनी आजभोली

अपाङ्गको सिकार बनिसकेकी छिन

उनलाइ अन्धो भन्छु म किनकी उनी आँखा देख्दैनन

आँखा नदेखे पनि अरु कसैलाइ सुम्सुम्याउन समेत सक्दैनन

तर पनि कस्तुरी, डाफे,मुनाल,घोरल,चितुवा आदि जनावरहरुको

सहारा दिने आश्रय स्थल भएर उभिएकी छिन, के कम छिन र?

जमिन भित्र उनको खुट्टा गाडिएर होला

खुट्टाको दृश्य मैले अझै पनि देख्न पाएको छैन

कस्तो होला है! हिमालको खुट्टा ? सोचिरहन्छु म

सायद खुट्टा नै छैन र पो कहिल्यै पनि हिड्डुल गर्न सक्दैनन कि?

जब कुनै समयमा चुचुरोमा हावा बहन थाल्यो

एकदिन सेतो कपाल धरतीमा हाम फालेर

नदिहरु बढ्न थाले तर उहीँ बहेको हावाले

हिमालको श्रवण गर्ने कानको जाली

नै फुटाइदिएछ त्यही भएर म भन्छु

हिमाललाइ बहिरो पनि हुनुहुन्छ तपाईं

सधै टोलाएर बसेकी देख्छु म

रोजगारी भन्ने कुरा त उहीँ हो हिमाललाइ

बिहानीपख देखि सन्ध्या काल सम्म

प्रकृतिले बसिबसी ऐना टल्काउने

पदभार ग्रहण गराइदिएको छ जब घाम

झुल्किन्छ उनी अस्ताउन्जेल सम्म ऐना टल्काइरहन्छिन्

त्यसैले म भन्छु हिमाललाइ बिधवा भएर के भो त

खान लाउनको लागि रोजगारी मिलेकै छ क्यारे !

Sequence Problem Below

Answers

Answer:

[tex]\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppppppppppppppppppppppppp\dddddd \displaystyle \Large \boldsymbol{} t_1=\boxed{5} \\\\d=\boxed{-4} \\\\t_n=\boxed{9-4n}[/tex]

Step-by-step explanation:

[tex]\displaystyle\large \boldsymbol{Rule: t_n=S_{n}-S_{n-1}} \\\\\\S_n=7n-2n^2 \ \ \ \ then \\\\\Longrightarrow S_{n-1}=7(n-1)-2(n-1)^2 =7n-7-2n^2+4n-2 \\\\then \\\\\\S_{n}-S_{n-1}=7n\!\!\!\!\!\!\diagup-2n^2\!\!\!\!\!\!\diagup-7n\!\!\!\!\!\!\diagup+7+2n^2\!\!\!\!\!\!\diagup-4n+2=9-4n \\\\t_n=9-4n => t_1=5\\\\d=t_2-t_{1}=1-5=-4[/tex]

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