Find each key feature of the function shown in the graph. Write the range and domain in interval notation, and assume all values are integers. What's the domain and range for this graph ?

9514 1404 393

Answer:

Step-by-step explanation:

Let s represent the number of sodas sold. Then the number of hot dogs sold is (s-50) and the total is ...

  s +(s -50) = 218

  2s = 268 . . . . . . . . . add 50

  s = 134 . . . . . . . divide by 2

134 sodas were sold; 84 hot dogs were sold.

Given:

The function is:

[tex]g(x)=f(x+2)-3[/tex]

To find:

The statement that best compares the graph of g(x) with the graph of f(x).

Solution:

The transformation is defined as

[tex]g(x)=f(x+a)+b[/tex]                .... (i)

Where, a is horizontal shift and b is vertical shift.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

We have,

[tex]g(x)=f(x+2)-3[/tex]               ...(ii)

On comparing (i) and (ii), we get

[tex]a=2[/tex]

[tex]b=-3[/tex]

Therefore, the graph of g(x) is shifted 2 units left and 3 units down.

Hence, the correct option is C.

Answer:

61.42 units

Step-by-step explanation:

Perimeter = sum of all sides of surrounding the figure = circumference of a circle + 2(length of the rectangle)

Note: two semicircles = 1 full circle

Perimeter = πd + 2(L)

Where,

Diameter of the circle (d) = 10

Length of rectangle (L) = 15

Plug in the values

Perimeter = π*10 + 2(15)

Perimeter = 10π + 30

≈ 61.42 units (approximated to nearest tenths)

Answer:

7 / 17 ;

10 / 17 ;

5 / 17

Step-by-step explanation:

Guests :

Mother = 1

Aunts = 3

Uncles = 3

Brothers = 4

Male cousin = 1

Female cousin = 5

_________________

Total guests = 17

Since each of the guests have an equal probability of arrival :

Probability that first guest to arrive :

Brother or uncle :

Number of brothers =4

Number of uncles = 3

P(brother or uncle) = required outcome / Total possible outcomes

Required outcome (number of brothers + uncles) = (4 + 3) = 7

Total possible outcomes = total guests = 17

P(brother or uncle) = 7 / 17

2.)

P(brother or cousin) :

Required outcome = (number of brothers + cousins) = (4 + 1 + 5) = 10

Total possible outcomes = total guests = 17

P(brother or cousin) = 10/17

3.)

P(brother or mother) ;

Required outcome = (number of brothers + mother) = (4+1) = 5

Total possible outcomes = total guests = 17

P(brother or mother) = required outcome / Total possible outcomes = 5 / 17

Answer:

the speed of the boat is 6.67 ft/s

Step-by-step explanation:

Given;

height of the winch, h = 12 ft

the rate at which the winch pulls, the rope, = 4 ft/s

This form a right triangle problem;

let the height of the right triangle = h

let the base of the triangle = b (this corresponds to the horizontal displacement of the boat)

let the hypotenuse side = c

c² = b² + h²

[tex]2c\frac{dc}{dt} = 2b\frac{db}{dt} + 2h \frac{dh}{dt}\\\\The \ height \ of \ the \ winch \ is \ not \ changing \\\\2c\frac{dc}{dt} = 2b\frac{db}{dt} + 2h (0)\\\\2c\frac{dc}{dt} = 2b\frac{db}{dt} \\\\c\frac{dc}{dt} = b\frac{db}{dt} ----(*) \\\\when;\\\\the\ hypotenuse \ c = 15 \ ft\\\\the \ the \ the \ height, h = 12 \ ft\\\\the \ base, b \ becomes ;\\\\b^2 = c^2 -h^2\\\\b^2 = 15^2 - 12^2\\\\b^2 = 81\\\\b = \sqrt{81} \\\\b = 9 \ ft\\\\\\from \ the \ equation (*) \ above;\\\\[/tex]

[tex]c\frac{dc}{dt} = b \frac{db}{dt} \\\\dc/dt = 4 \ ft/s, \ \ c = 15 \ ft, \ \ b = 9 \ ft\\\\15 (4) = 9\frac{db}{dt} \\\\60 = 9 \frac{db}{dt} \\\\\frac{db}{dt} = \frac{60}{9} = 6.67 \ ft/s[/tex]

Therefore, the speed of the boat is 6.67 ft/s

Answer:

a) 675 b) 1050 c) 675 d)455 e) 120

Step-by-step explanation:

Answer:a, 0,293

Step-by-step explanatThe number of ways to get any 3 students from 25 given students is :

25C3 = 2300

Let A be the event that has 1 Male and 2 Female

15C1*10C2=675

The probability of having 1 Male and 2 Female is

675/2300=0.293 ion:

Answer: A)  4√2 units

Step-by-step explanation:

Use the distance formula to find the distance(d) between Point D and Point C:

[tex]d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]

[tex]d=\sqrt{(8-4)^{2}+(2-(-2))^{2}}=\sqrt{(4)^{2}+(4)^{2}}=\sqrt{16+16} =\sqrt{32} =4\sqrt{2}[/tex]

Answer:

9.42 meters

Step-by-step explanation:

diameter = 8 m

radius = 4 m

Length of arc = radius * central angle in radians

= 4 * 3[tex]\pi[/tex] / 4

= 12[tex]\pi[/tex] / 4

= 3[tex]\pi[/tex]

= 66 / 7

= 9.42 m

The length of the arc of a circle of diameter 8 meters subtended by a central angle of 3pi/4 radians is 9.42 meters.

The arc period of a circle can be calculated with the radius and relevant perspective using the arc period method.

expalination:

⇒angle= arc/radius

= 3pi/4 radians

diameter = 8 m

radius = 4 m

Length of arc = radius * central angle in radians

⇒4 * 3 / 4

⇒12 / 4 = 3

⇒66 / 7

⇒9.42 m

Hence the arc of a circle is 9.42 m.

Learn more about arc of a circle here:-https://brainly.com/question/2005046

#SPJ2

Answer:

C. rotation 180º about the origin

Step-by-step explanation:

Given

Quadrilaterals GWVY and G'W'V'Y'

Required

Describe the transformation rule

Pick points Y and Y'

[tex]Y = (5,-4)[/tex]

[tex]Y' = (-5,4)[/tex]

The above obeys the following rule:

[tex](x,y) \to (-x,-y)[/tex]

When a point is rotated by 180 degrees, the rule is:

[tex](x,y) \to (-x,-y)[/tex]

Hence, (c) is correct

Answer:

CAD = 25°

Step-by-step explanation:

The angles are shown to be equal in the figure so BAC = CAD.

Answer:

so 3 people both read their books and watched films.

Step-by-step explanation:

n(U) = 50

n(A) = 18 ( read books)

n(B) = 28 ( watched films)

n(A U B) with a line at the top = 7

so

Finding n(AUB)

n( A U B) with a line at the top = n(A) + n(B) - n( A n B)

7 = 50-n(A U B)

or, n( A U B) = 50 - 7

so, n(A U B) = 43

Then

n( A U B) = n(A)+n(B)-n(A n B)

43 = 18 + 28 - n( A n B)

or, 43 = 46 - n(A n B)

or, n(A n B) = 46 - 43

so, n(A n B) = 3

Answer:

13.73 in^2 because the circle's area is 50.27 in^2

Answer:

"Type II error" is the right answer.

Step-by-step explanation:

Thus the above is the right answer.

Answer:

[tex]V(x) = [\frac{x}{x + 1} + \frac{2}{x-3}] * \frac{x^3 - 9x}{x}[/tex]

[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]

[tex]V(50) = 2548.17[/tex]        [tex]V(100) = 10098.10[/tex]       [tex]V(1000) = 999201.78[/tex]

[tex]x = 54.78[/tex]

Step-by-step explanation:

Given

[tex]V(x) = [C_1(x) + C_2(x)](H(x))[/tex]

[tex]C_1(x) = \frac{x}{x+1}[/tex]

[tex]C_1(x) = \frac{2}{x-3}[/tex]

[tex]H(x) = \frac{x^3 - 9x}{x}[/tex]

Solving (a): Expression for V(x)

We have:

[tex]V(x) = [C_1(x) + C_2(x)](H(x))[/tex]

Substitute known values

[tex]V(x) = [\frac{x}{x + 1} + \frac{2}{x-3}] * \frac{x^3 - 9x}{x}[/tex]

Solving (b): Simplify V(x)

We have:

[tex]V(x) = [\frac{x}{x + 1} + \frac{2}{x-3}] * \frac{x^3 - 9x}{x}[/tex]

Solve the expression in bracket

[tex]V(x) = [\frac{x*(x-3) + 2*(x+1)}{(x + 1)(x -3)}] * \frac{x^3 - 9x}{x}[/tex]

[tex]V(x) = [\frac{x^2-3x + 2x+2}{(x + 1)(x -3)}] * \frac{x^3 - 9x}{x}[/tex]

[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * \frac{x^3 - 9x}{x}[/tex]

Factor out x

[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * \frac{x(x^2 - 9)}{x}[/tex]

[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * (x^2 - 9)[/tex]

Express as difference of two squares

[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * (x- 3)(x + 3)[/tex]

Cancel out x - 3

[tex]V(x) = [\frac{x^2-x+2}{(x + 1)}] *(x + 3)[/tex]

[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]

Solving (c): V(50), V(100), V(1000)

[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]

Substitute 50 for x

[tex]V(50) = [\frac{(50^2-50+2)(50 + 3)}{(50 + 1)}][/tex]

[tex]V(50) = \frac{(2452)(53)}{(51)}][/tex]

[tex]V(50) = 2548.17[/tex]

Substitute 100 for x

[tex]V(100) = [\frac{(100^2-100+2)(100 + 3)}{(100 + 1)}][/tex]

[tex]V(100) = \frac{9902)(103)}{(101)}[/tex]

[tex]V(100) = 10098.10[/tex]

Substitute 1000 for x

[tex]V(1000) = [\frac{(1000^2-1000+2)(1000 + 3)}{(1000 + 1)}][/tex]

[tex]V(1000) = [\frac{(999002)(10003)}{(10001)}][/tex]

[tex]V(1000) = 999201.78[/tex]

Solving (d): V(x) = 3000, find x

[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]

[tex]3000 = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]

Cross multiply

[tex]3000(x + 1) = (x^2-x+2)(x + 3)[/tex]

Equate to 0

[tex](x^2-x+2)(x + 3)-3000(x + 1)=0[/tex]

Open brackets

[tex]x^3 - x^2 + 2x + 3x^2 - 3x + 6 - 3000x - 3000 = 0[/tex]

Collect like terms

[tex]x^3 + 3x^2- x^2 + 2x - 3x - 3000x + 6 - 3000 = 0[/tex]

[tex]x^3 + x^2 -3001x -2994 = 0[/tex]

Solve using graphs (see attachment)

[tex]x = -54.783[/tex] or

[tex]x = -0.998[/tex] or

[tex]x = 54.78[/tex]

x can't be negative. So:

[tex]x = 54.78[/tex]

Answer:

sorry in dont know the ans

Answer:

6

Step-by-step explanation:

21-20 = 1

20-18 =2

18 -15 = 3

15-11 = 4

We are subtracting 1 more each time

11-5 = 6

Answer:

C

Step-by-step explanation:

Answer:

A. False

B. True

C. False

D. True

Step-by-step explanation:

Only three dimensional subspace for R3 is R3 itself. In a 3 d subspace there are 3 basis vectors which are all linearly independent vectors. Dimension of a vector is number of subspace in that vector. Finite set can generate infinite dimension vector space.

Answer:

-7 degrees

Step-by-step explanation:

the temperature was 16 degrees then was the decrease by 23 degrees so subtract 23 from 16 and the answer is -7

Answer:

48

Step-by-step explanation:

.08x600=48

Answer:

Step-by-step explanation:

total patients = 600

% of patients had eye surgery = 8%

Number of patients that had eye surgery ?= x

% of pt that had eye surgery =  no. of pt that had surgery/ total number of pt

8/100= x/600

x=(8x600) /100

x= 4800/100

x= 48

Number of patients that had eye surgery were 48

Answer:

More nurses with a baccalaureate degree is estimated to pass the exam but this was not a significant difference.

Step-by-step explanation:

Answer:

As x increases, the rate of change of g exceeds the rate of change of f.  

Step-by-step explanation:

Given

[tex]f(x) = 90x^2 + 180x + 92[/tex]

[tex]\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4} & {5} & f(x) & {92} & {362} & {812} & {1442} & {2252} & {3242} \ \end{array}[/tex]

[tex]g(x) = 6^x[/tex]

[tex]\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4} & {5} & g(x) & {1} & {6} & {36} & {216} & {1296} & {7776} \ \end{array}[/tex]

Required

Which of the options is true?

A. At [tex]x \approx 4.39[/tex], f(x) has the same rate of change as g(x)

Rate of change is calculated as:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

For f(x)

[tex]f(x) = 90x^2 + 180x + 92[/tex]

[tex]f(4.39) = 90*4.39^2 + 180*4.39 + 92 = 2616.689[/tex]

So, the rate of change is:

[tex]m = \frac{2616.689}{4.39} = 596.06[/tex]

For g(x)

[tex]g(x) = 6^x[/tex]

[tex]g(4.39) = 6^{4.39} = 2606.66[/tex]

So, the rate of change is:

[tex]m = \frac{2606.66}{4.39} = 593.77[/tex]

The rate of change of both functions are not equal at x = 4.39. Hence, (a) is false.

B. Rate of change of g(x) is greater than f(x) with increment in x

Using the formula in (a), we have:

[tex]\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4} & {5} & f(x) & {92} & {362} & {812} & {1442} & {2252} & {3242} & m &\infty & 362 & 406 & 480 & 563 &648.4\ \end{array}[/tex]

[tex]\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4} & {5} & g(x) & {1} & {6} & {36} & {216} & {1296} & {7776} & m & \infty & 6 & 18 & 72 & 324 & 1555 \ \end{array}[/tex]

From x = 1 to 4, the rate of change of f is greater than the rate of g.

However, from x = 5, the rate of change of g is greater than the rate of f.

This means that (b) is true.

The above table further shows that (c) and (d) are false.

Answer:

Step-by-step explanation:

C

Answer:

[tex]y = -\frac{1}{2}x - 1[/tex]

Step-by-step explanation:

In order for two lines to be parallel they must have the same slope. In other words the m constant in the line equation needs to match

[tex]y = mx + b[/tex]

This means for the equation we're trying to find, we already know m. It's just -1/2 since that's the slope of the line it needs to be parallel to.

Next, let's find the constant b. We know the slope, and we know it goes through points (-4, 1), so let's plug this into our equation

[tex]y = -\frac{1}{2}x + b\\1 = - \frac{1}{2}\times{-4} + b\\1 = 2 + b\\b = -1[/tex]

Now that we have both constants, we know the equation of the line.

[tex]y = -\frac{1}{2}x - 1[/tex]

To convince yourself this is correct, let's plot these two lines.

Answer: (d)

Step-by-step explanation:

Given

There are six flavors of ice-cream that is chocolate, vanilla, strawberry, birthday cake, rocky road, and butter pecan

First ice-cream can be tasted in 6 different ways

Second can be in 5 ways

similarly, remaining in 4, 3, 2 and 1 ways

Total no of ways are  [tex]6\times5\times 4\times 3\times 2\times 1=720\ \text{ways}[/tex]

Option (d) is correct.

Solution :

I have a lottery ticket that will pay off $ 10 with a 45% chance and a friend of mine has a chance of 20% by paying off $ 25.

It is based on Double risk dilemma.

Individual --- trade ticket (-1)  ----24 (win(25) (0.20))                    

                                               ----- -1 (lose ) (0.80)

               ----- keep trade -------10 (win 10) (0.45)

                                        ----- 0 (lose) (0.55)

Next, solve the decision tree using expected monetary value.

EVM (keep ticket) = 0.45 (10) + 0.55 (0) = $ 4.50

EVM (trade ticket) = 0.20 (24) + 0.80 (-1) = $ 4

Therefore, we keep the ticket and do not trade.

Answer:

√9 × √6

√54

√27 × √2

Step-by-step explanation:

We can obtain the answer to the question given above as illustrated below:

3√6

Recall

a√b = √(a×a×b)

Thus,

3√6 = √(3×3×6)

3√6 = √(9 × 6)

Recall

√(a × b) = √a × √b

√(9 × 6) = √9 × √6

Therefore,

3√6 = √9 × √6

Recall

√9 × √6 = √(9 × 6)

√9 × √6 = √54

Thus,

3√6 = √54

Recall

√54 = √(27 × 2)

√54 = √27 × √2

Therefore,

3√6 = √27 × √2

Therefore,

3√6 = √9 × √6 = √54 = √27 × √2

To solve the problem.

W=m×g

W=28×10

W=280.

The weight of a dog on the surface of earth is 280N.

Answer:

274.68N and 45.36N respectively

Step-by-step explanation:

Weight of any object is the mass in kilograms(kg) multiplied by the gravity in meter per square second(m/s^2). The gravity on earth is 9.81m/s^2 and on moon is 1.62m/s^2...so since the gravity varies the weight of the dog will also vary. The wight on earth would be 28kg multiplied by 9.81m/s^2 which would be 274.68N and the weight on moon would be 28kg multiplied by 1.62m/s^2 which would be 45.36N.