Find the length of the third side. If necessary, round to the nearest tenth.
10
11
Answers
Answer:
14.9
Step-by-step explanation:
The solution is 14.86
The length of the third side of the right angle triangle is 14.86
What is a Triangle?
A triangle is a plane figure or polygon with three sides and three angles.
A Triangle has three vertices and the sum of the interior angles add up to 180°
Let the Triangle be ΔABC , such that
∠A + ∠B + ∠C = 180°
The area of the triangle = ( 1/2 ) x Length x Base
For a right angle triangle
From the Pythagoras Theorem , The hypotenuse² = base² + height²
Given data ,
Let the triangle be ΔABC
Now , the triangle ABC is a right angle triangle
And the value of the base of the triangle BC = 10
The value of the height of the triangle AB = 11
Now , the hypotenuse of the triangle AC is calculated from Pythagoras Theorem
For a right angle triangle
From the Pythagoras Theorem , The hypotenuse² = base² + height²
Substituting the values in the equation , we get
AC² = AB² + BC²
AC² = 11² + 10²
AC² = 121 + 100
AC² = 221
Taking square roots on both sides of the equation , we get
AC = 14.86
Therefore , the value of AC is 14.86
Hence , The length of the hypotenuse of the right angle triangle is 14.86
To learn more about triangles click :
https://brainly.com/question/16739377
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Answer:
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Step-by-step explanation:
150 copies will cost $15.00. How many copies can be made for $6.00?
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Answer:
60 copies
Step-by-step explanation:
$15/150 = 0.1 each copy costs 1 cent
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60 copies
Step-by-step explanation:
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Mixed number- 3 3/4
Decimal- 3.75
Step-by-step explanation:
use K.C.F (Keep Change Flip)
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1). 3
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Answers
Step-by-step explanation:
IF A=5, B=3
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The like terms are the terms that can be put
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Answers
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Step-by-step explanation:
convert to improper fraction:
13/3 - 8/3
then solve:
13/3 - 8/3 = 5/3
convert back to a mixed number (unless your not supposed to, if that is the case then "5/3" is your answer):
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At a party, the punch bowl is hemispherical, with 2 foot radius and open at the top. The fruit punch weighs 66 pounds per cubic foot. At the beginning of the party the bowl is full to the brim. The rules for serving punch require each person to fill the ladle, raise it exactly 1 foot above the top of the owl (without spilling!), and then pour the punch into a cup at that level. After 10 minutes, 30 people have filled 30 cups, and the punch remaining in the bowl is 4 inches deep. Draw a picture of the situation, and then set up the integral for the work W involved in raising the punch until the punch remaining in the bowl has a depth of only 4 inches. Include all pertinent information in the integral, but do not evaluate the integral.
Answers
Answer:
W = ∫ [−2/3 to 0] 66π (2−y)(1−y²) dy = 2332π/27
Step-by-step explanation:
Vertical cross-section of bowl is a semi-circle of radius 1, centered at (0,0)
x² + y² = 1 (for y ≤ 0)
Bottom of bowl is at y = −1
Top of bowl is at y = 0
When punch is 4 inches deep, this 1/3 ft above bottom of bowl:
y = −1+1/3 = −2/3
So we integrate from y = −2/3 to y = 0
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Area of cross section at height y is πr²= πx² = π(1−y²)
Since each person is to lift ladle 2 feet above the top of the bowl, then distance = 2−y
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