find the missing side length in the image below​

The value of vector v that is perpendicular to the plane through the points is,

⇒ v = (6, - 27, - 24)

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

Points are,

A = (5,−4,4), B = (−5,0,−3), and C = (−4,2,−5).

Hence, We get;

AB = [- 10, 4, - 7]

AC = [-9, 6, -9]

So, The value of vector v that is perpendicular to the plane through the points is,

⇒ v = AB x AC

⇒ v = (- 10, 4, - 7) x (- 9, 6, - 9)

⇒ v = (6, - 27, - 24)

Thus, The value of vector v that is perpendicular to the plane through the points is,

⇒ v = (6, - 27, - 24)

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Answer:

Step-by-step explanation:b

No real roots. Roots will have imaginary numbers. This means the quadratic is either always above the axis, or always below.

One real root. The graph touches the  x -axis in one place.  →

Two real roots. The graph crosses the x -axis twice.

The number of edges in the given figure is 15. The correct option is B.

One of the first areas of mathematics is geometry, along with arithmetic. It is concerned with spatial characteristics like the separation, shape, size, and relative placement of objects.

The shape is made up of the triangular prism and the trapezoidal prism the total number of edges in the shape will be 15.

Therefore, the number of edges in the given figure is 15. The correct option is B.

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Answer:

answer of question number 1 is 2400, 2880, 3600 respectively.

answer of question number 2 is 1384 and 1680.

Step-by-step explanation:

100×24=2400

120×24=2880

150×24=3600

692×2=1384

420×4=1680

Answer:

The situation that represents this situation is:

[tex]t = \frac{60}{n}[/tex]

Step-by-step explanation:

The amount of time t needed to assemble the set is inversely  proportional to the number people n working.

This means that:

[tex]t = \frac{k}{n}[/tex]

In which k is the constant of proportionality.

Twelve people can assemble the set in 5 hours.

This means that for [tex]n = 12, t = 5[/tex]. We use this to find k.

[tex]t = \frac{k}{n}[/tex]

[tex]5 = \frac{k}{12}[/tex]

[tex]k = 12*5 = 60[/tex]

Write an equation to represent the situation.

[tex]t = \frac{60}{n}[/tex]

Answer:

[tex]P(x \le 5) = 0.0110[/tex]

Step-by-step explanation:

Given

[tex]n = 17[/tex] -- number of properties

[tex]p = 60\%[/tex] --- probability of selling a property

Required

[tex]P(x \le 5)[/tex]

The question is an illustration of binomial probability, and it is calculated using:

[tex]P(x ) = ^nC_x * p^x * (1 - p)^{n-x}[/tex]

So, we have:

[tex]P(x \le 5) = P(x = 0) +P(x = 1) +P(x = 2) +P(x = 3) +P(x = 4) +P(x = 5)[/tex]

[tex]P(x=0 ) = ^{17}C_0 * (60\%)^0 * (1 - 60\%)^{17-0} = 1.71798692*10^{-7}[/tex]

[tex]P(x=1 ) = ^{17}C_1 * (60\%)^1 * (1 - 60\%)^{17-1} = 0.00000438086[/tex]

[tex]P(x=2 ) = ^{17}C_2 * (60\%)^2 * (1 - 60\%)^{17-1} = 0.00005257039[/tex]

[tex]P(x=3 ) = ^{17}C_3 * (60\%)^3 * (1 - 60\%)^{17-3} = 0.00039427799[/tex]

[tex]P(x=4 ) = ^{17}C_4 * (60\%)^4 * (1 - 60\%)^{17-4} = 0.00206995948[/tex]

[tex]P(x=5 ) = ^{17}C_5 * (60\%)^5 * (1 - 60\%)^{17-5} = 0.008072842[/tex]

So, we have:

[tex]P(x \le 5) = 1.71798692*10^{-7}+0.00000438086+0.00005257039+0.00039427799+0.00206995948+0.008072842[/tex]

[tex]P(x \le 5) = 0.01059420251[/tex]

[tex]P(x \le 5) = 0.0110[/tex]

Answer:

In a class of 50 students, 30 participated in athletics and 25 participated in music. Drawing a Venn- diagram , calculate how many students ...

Answer:

ok

Step-by-step explanation:

t7y7y8 I am not going out for the

9514 1404 393

Answer:

  D

Step-by-step explanation:

Choose the table in which all of the y-values are 4 times the corresponding x-values.

If there is a row in a table in which y is not 4x, reject that table. For example, in the first row of the first table we have x=0, so y = 4(0) = 0, but the table has y=4. The first table can be rejected.

Answer:D got the question and got it right

Step-by-step explanation:

x y

2 8

4 16

8 32

Answer:

Newton's law of coming states that the rate at which an object cools is proportional to the differences in temperature between the object and the object's surroundings.

Answer:

It is the rate of heat loss of a body that is directly proportional to the difference in the temperatures between the body and its surroundings.                                                  Q= h* A* (T(object) -T(environment) )

Answer:

n = 8√2

Step-by-step explanation:

From the question given above, the following data were obtained:

Angle θ = 60°

Opposite = 4√6

Hypothenus = n =?

The value of n can be obtained by using the sine ratio as illustrated below:

Sine θ = Opposite / Hypothenus

Sine 60 = 4√6 / n

√3/2 = 4√6 / n

Cross multiply

n × √3 = 2 × 4√6

n × √3 = 8√6

Divide both side by √3

n = 8√6 / √3

Rationalise

n = 8√6 / √3 × (√3/√3)

n = 8√(6×3) / 3

n = 8√18 / 3

Recall

√18 = √(9×2) = √9 × √2 = 3√2

Thus,

n = 8√18 / 3

n = 8 × 3√2 / 3

n = 8√2

Answer:1.5

Step-by-step explanation:

Answer:

A)

[tex]k=0[/tex]

B)

[tex]\displaystyle \begin{aligned} 2k + 1& = 2\ln 20 + 1 \\ &\approx 2.3863\end{aligned}[/tex]

C)

[tex]\displaystyle \begin{aligned} k - 3&= \ln \frac{1}{2} - 3 \\ &\approx-3.6931 \end{aligned}[/tex]

Step-by-step explanation:

We are given the function:

[tex]\displaystyle h(x) = 20e^{kx} \text{ where } k \in \mathbb{R}[/tex]

A)

Given that h(1) = 20, we want to find k.

h(1) = 20 means that h(x) = 20 when x = 1. Substitute:

[tex]\displaystyle (20) = 20e^{k(1)}[/tex]

Simplify:

[tex]1= e^k[/tex]

Anything raised to zero (except for zero) is one. Therefore:

[tex]k=0[/tex]

B)

Given that h(1) = 40, we want to find 2k + 1.

Likewise, this means that h(x) = 40 when x = 1. Substitute:

[tex]\displaystyle (40) = 20e^{k(1)}[/tex]

Simplify:

[tex]\displaystyle 2 = e^{k}[/tex]

We can take the natural log of both sides:

[tex]\displaystyle \ln 2 = \underbrace{k\ln e}_{\ln a^b = b\ln a}[/tex]

By definition, ln(e) = 1. Hence:

[tex]\displaystyle k = \ln 2[/tex]

Therefore:

[tex]2k+1 = 2\ln 2+ 1 \approx 2.3863[/tex]

C)

Given that h(1) = 10, we want to find k - 3.

Again, this meas that h(x) = 10 when x = 1. Substitute:

[tex]\displaystyle (10) = 20e^{k(1)}[/tex]

Simplfy:

[tex]\displaystyle \frac{1}{2} = e^k[/tex]

Take the natural log of both sides:

[tex]\displaystyle \ln \frac{1}{2} = k\ln e[/tex]

Therefore:

[tex]\displaystyle k = \ln \frac{1}{2}[/tex]

Therefore:

[tex]\displaystyle k - 3 = \ln\frac{1}{2} - 3\approx-3.6931[/tex]

9514 1404 393

Answer:

  5.423 miles

Step-by-step explanation:

Let x represent the distance to run. Then the remaining distance to the point that is closest to the island is (6-x) miles. The straight-line distance (d) to the point x from the island is given by the Pythagorean theorem:

  d² = 1² +(6 -x)² = x² -12x +37

  d = √(x² -12x +37)

The total travel time is the sum of times running and swimming. Each time is found from ...

  time = distance/speed

  total time = x/4 + d/2 = x/4 +(1/2)√(x² -12x +37)

__

The total time will be minimized when its derivative with respect to x is zero.

  t' = 1/4 +(1/4)(2x -12)/√(x² -12x +37) = 0

Multiplying by 4 and combining fractions, we can see the numerator will be ...

  √(x² -12x +37) +2x -12 = 0

Subtracting the radical term and squaring both sides, we get ...

  4x² -48x +144 = x² -12x +37

  3x² -36x +107 = 0

The quadratic formula tells us the smaller of the two roots is ...

  x = (36 -√(36² -4(3)(107)))/(2(3)) = (36 -√12)/6 ≈ 5.423 . . . mi

You should run 5.423 miles west to minimize the time needed to reach the island.

__

A graphing calculator solves this nicely. The attached graph shows the time is a minimum when you run 5.423 miles.

5(2x^2-x-2)(x-2)

Step-by-step

Answer:  [tex]5(\frac{10x^3}{5}+\frac{-25x^2}{5}+\frac{20}{5}) \\\\5(2x^3-5x^2+4)\\\\5(2x^2-x-2)(x-2)[/tex]

Answer:

A

Step-by-step explanation:

Because we can rearrange the equation and get:

x²=5+4

x²=9

[tex]x = \sqrt{9} [/tex]

[tex]x = + 3 \: \: or \: \: - 3[/tex]

Answer:

(-∞,∞) is the domain.

2 is the range

Step-by-step explanation:

Answer:

q = [tex]\sqrt{2}[/tex]

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin30° = [tex]\frac{1}{2}[/tex] , then

sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{q}{2\sqrt{2} }[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )

2q = 2[tex]\sqrt{2}[/tex] ( divide both sides by 2 )

q = [tex]\sqrt{2}[/tex]

Answer:

200

Step-by-step explanation:

6.6/3.3 = 2

10^-2 - (-4) = 10^2

The answer is 2 * 10^2 or 200.

Answer: Because they are corresponding angles (second option is the answer).

Answer:

second option...because they are corresponding angles..

STEP BY STEP EXPLANATION: corresponding angles are formed when two parallel lines are intersected by the transversal

the corresponding angles are 2 and 6

Answer:

Step-by-step explanation:

I think you got it correct. The reciprical of this function is y = x.

Answer:

YWX = DFE

Step-by-step explanation:

AAS means angle angle side. so, we need 2 angles and 1 side.

we have 1 side and one angle confirmed.

so, we need one of the other two angles (W or Y vs. F or D) confirmed.

they probably want W and F as answer, as Y and D would make it a special case of AAS : ASA.

Answer:

The sum of 1/6 and 1/7 would be 13/42, or, if you wanted the answer in decimal form rounded to the nearest hundredth, it would be about 0.31.

To find the sum of 1/6 and 1/7, we cannot simply add the numerators together and maintain the same denominator. This is because 1/6 and 1/7 have different denominators, so we don't know which denominator to maintain!

To fix this we need to find a number that is divisible by both 6 and 7. One easy way to do this is to multiply the two numbers together:

6 x 7 = 42

If we were to change the denominator to 42 for each fraction, we could add the numerators together and maintain a denominator of 42. However, this means we must change the numerator of each fraction along with its denominator.

Let's start with 1/6. We can multiply 6 by 7 to obtain 42, but this means we also have to multiply 1 by 7 to keep the fraction proportionate. If the fraction does not maintain the same proportion, it will be a completely different fraction!

We know that 1 x 7 = 7, so it is safe to say that 1/6 is equal to 7/42.

We can apply the same logic to 1/7. Since 7 x 6 is 42 we need to multiply 1 by 6 along with 7. Note: you cannot multiply each number by 7 this time, because 7 x 7 would be 49, not 42. In multiplying the numerator and denominator by 6 we know that 1/7 = 6/42.

Now we have an equation of:

6/42 + 7/42

Now we can add it as we would normally by adding the numerators and keeping the denominator to get:

6/42 + 7/42 = 13/42

If you needed the answer in decimal form it would be about 0.3095238095, or 0.31 rounded to the nearest hundredth.

I hope this helped.

Answer:

it is missing a scale because it should be at the bottom of the map

Answer:

a) 2.06

b) variance = 270.90 , std = 275.14

Step-by-step explanation:

a) Determine Expected rate of return

attached below is the calculated table for the solution provided

∴ Expected rate of return = ∑ Xp(x) = -6.46 + 3.84 + 4.68 = 2.06

b) Determine the variance and standard deviation

Variance ( Vx ) = E(x)^2 - [ Expected rate of return ]^2

                         = 275.14 - ( 2.06 )^2 ≈ 270.90

standard deviation = √ variance = √270.90 = 16.459

note : E(x)^2 = ∑ x^2 p(x) = 275.14

Answer:

x=−16/3 or x=2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x2+10x−8=24

Step 2: Subtract 24 from both sides.

3x2+10x−8−24=24−24

3x2+10x−32=0

Step 3: Factor left side of equation.

(3x+16)(x−2)=0

Step 4: Set factors equal to 0.

3x+16=0 or x−2=0

Answer:

(a)

[tex]\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}[/tex]

(b)

[tex]P(3 \le x \le 6) = 0.30[/tex]

[tex]P(4 \le x)=0.60[/tex]

Step-by-step explanation:

Given

[tex]F(x) = \left[\begin{array}{ccc}0& x<1 &\\0.30&1 \le x<3 &\\0.40&3 \le x < 4& &0.45 &4 \le x<6 &\\0.60 & 6 \le x < 12 & & 1 & 12 \le x\end{array}\right[/tex]

Solving (a): The pmf

This means that we list out the probability of each value of x.

To do this, we simply subtract the current probability value from the next.

So, we have:

[tex]\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}[/tex]

The calculation is as follows:

[tex]0.30 - 0 = 0.30[/tex]

[tex]0.40 - 0.30 = 0.10[/tex]

[tex]0.45 - 0.40 = 0.05[/tex]

[tex]0.60 - 0.45 = 0.15[/tex]

[tex]1 - 0.60 = 0.40[/tex]

The x values are gotten by considering where the equality sign is in each range.

[tex]1 \le x < 3[/tex] means [tex]x = 1[/tex]

[tex]3 \le x < 4[/tex] means [tex]x = 3[/tex]

[tex]4 \le x < 6[/tex] means [tex]x=4[/tex]

[tex]6 \le x < 12[/tex] means [tex]x = 6[/tex]

[tex]12 \le x[/tex] means [tex]x = 12[/tex]

Solving (b):

[tex](i)\ P(3 \le x \le 6)[/tex]

This is calculated as:

[tex]P(3 \le x \le 6) = F(6) - F(3-)[/tex]

From the given function

[tex]F(6)= 0.60[/tex]

[tex]F(3-) = F(1) = 0.30[/tex]

So:

[tex]P(3 \le x \le 6) = 0.60 - 0.30[/tex]

[tex]P(3 \le x \le 6) = 0.30[/tex]

[tex](ii)\ P(4 \le x)[/tex]

This is calculated as:

[tex]P(4 \le x)=1 - F(4-)[/tex]

[tex]P(4 \le x)=1 - F(3)[/tex]

[tex]P(4 \le x)=1 - 0.40[/tex]

[tex]P(4 \le x)=0.60[/tex]