Graph the line that has a slope of −13 and contains the point (3,−7)
Answers
Graph the line that has a slope of −13 and contains the point (3,−7) intercept is 32.
straight line graph can be represented two form
cartesian form ax+ by +c=0
slope intercept form y=mx +c
Where m is slope and c is the intercept in y axis
Value of m = change in y/change in x
back to question :- slope is -13
So, [y2-y1]/[x2-x1]= -13
{y+7/x-3 } = -13
y+7 = -13x +39
for intercept just put x=0
so y = 39-7
y=32
y= -13x +32
slope = -13
intercept = 32
Graph the line that has a slope of -1/3 and contains the point (3-7)
Plot the point (3,-7)
slope = -1/3 means y decreases 1/3 when x increases by 1
Let x increase by 3, then y decreases by 3(1/3) = 1
Put your pencil at (3,-7)
Increase x by 3 to (6,-7)
Decrease y by 1 to (6,-8)
Plot the point (6,-8)
Draw the graph as a line thru (3,-7),(6,-8)
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[tex]\huge{\underline{\underline{\mathcal{\bf\pink{AnSwer}}}}}[/tex]
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