Guys please i need help on this, i will give brainliest to the right answers

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

[tex]p_1 = \frac{20}{100} = 0.2[/tex]

[tex]s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04[/tex]

p2 -> 1997

10 out of 100, so:

[tex]p_2 = \frac{10}{100} = 0.1[/tex]

[tex]s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03[/tex]

Distribution of p1 – p2:

[tex]p = p_1 - p_2 = 0.2 - 0.1 = 0.1[/tex]

[tex]s = \sqrt{s_1^2+s_2^2} = \sqrt{0.04^2 + 0.03^2} = 0.05[/tex]

Confidence interval:

[tex]p \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].  

The lower bound of the interval is:

[tex]p - zs = 0.1 - 1.645*0.05 = 0.01775 [/tex]

The upper bound of the interval is:

[tex]p + zs = 0.1 + 1.645*0.05 = 0.18225 [/tex]

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Solution :

P(H) = 0.7  ;  P(T) = 0.3

If heads, then Urn H,  1 blue and 4 red marbles.

If tails, then Urn T ,  3 blue and 1 red marbles.

a).

P ( choosing a Red marble )

= P (H) x P( Red from Urn H) + P (T) x P( Red from Urn T)

[tex]$=0.7 \times \frac{4}{5} + 0.3 \times \frac{1}{4}$[/tex]

= 0.56 + 0.075

= 0.635

b).  If P (B, if coin showed heads)

If heads, then marble is picked from Urn H.

Therefore,

P (Blue) [tex]$=\frac{1}{5}$[/tex]

             = 0.2

c). P (Tails, if marble was red)

[tex]$=P (T/R) = \frac{P(R/T)}{P(R)} \ P(T)$[/tex]

Where P (R/T) = P ( red, if coin showed tails)

                        [tex]$=\frac{1}{4}$[/tex]

                        = 0.25 (As Urn T is chosen)

P (R) =  P (Red) = 0.635 (from part (a) )

P (T) = P (Tails) = 0.3

∴ [tex]$P(T/R) = \frac{0.25 \times 0.3}{0.635}$[/tex]

                = 0.118

Answer:

The answer to your questions are given below.

Step-by-step explanation:

To answer the question given above, we shall determine the value of x in each equation. This can be obtained as follow:

5x - 2x - 4 = 5

3x - 4 = 5

Collect like terms

3x = 5 + 4

3x = 9

Divide both side by 3

x = 9/3

x = 3

5x - (3x - 1) = 7

Clear the bracket

5x - 3x + 1 = 7

2x + 1 = 7

Collect like terms

2x = 7 - 1

2x = 6

Divide both side by 2

x = 6/2

x = 3

x + 2x + 3 = 9

3x + 3 = 9

Collect like terms

3x = 9 - 3

3x = 6

Divide both side by 3

x = 6/3

x = 2

2(2x - 3) = 6

Clear the bracket

4x - 6 = 6

Collect like terms

4x = 6 + 6

4x = 12

Divide both side by 4

x = 12/4

x = 3

4x - (2x + 1) = 3

Clear the bracket

4x - 2x - 1 = 3

2x - 1 = 3

Collect like terms

2x = 3 + 1

2x = 4

Divide both side by 2

x = 4/2

x = 2

5(x + 3) = 25

Clear the bracket

5x + 15 = 25

Collect like terms

5x = 25 - 15

5x = 10

Divide both side by 5

x = 10/5

x = 2

SUMMARY:

x = 2

x + 2x + 3 = 9

4x - (2x + 1) = 3

5(x + 3) = 25

x = 3

5x - 2x - 4 = 5

5x - (3x - 1) = 7

2(2x - 3) = 6

Answer:

Step 1:  Complete the first equation

0.01 is a hundredth, therefore if we have 1.86 then we have 186 hundredths.

Step 2:  Complete the second equation

1.86 / 2 = 0.93

0.01 is a hundredth, therefore if we have 0.93 then we have 93 hundredths.

Step 3:  Complete the third equation

1.86 / 2 = 0.93

Step-by-step explanation:

you cannot just put the actual numbers in and calculate ?

and you can't provide the correct problem statement, as it seems.

I assume you mean

an = 3n² - 1

a sequence starts with a1, so, n>=1

a1 = 3×1² - 1 = 3-1 = 2

a2 = 3×2² -1 = 3×4 - 1 = 12 - 1 = 11

a3 = 3×3² - 1 = 3×9 - 1 = 27 - 1 = 26

a4 = 3×4² - 1 = 3×16 - 1 = 48 - 1 = 47

a5 = 3×5² - 1 = 3×25 - 1 = 75 - 1 = 74

there, that is all there is to it. you really needed help with that ?

Answer:

it should be letter c 5/3 I could be wrong but I hope this help

Answer:

Step-by-step explanation:

First, we add them all up.

98+70+52+87+46+120+72+41 = 586

Now, we divide 586 by the number of things there are. 586 / 8 = 73.25.

The mean of the swear words condition is 73.25.

Answer:

Step-by-step explanation:

When you're looking to find things like f(2) and f(4) and f(-3000), etc. the number inside the parenthesis is an x value. Look to the graph, find that x value, and locate the y value that corresponds to it. f(2) = -8. f(-1) = 4. f(1) = -4. See?

Answer:

does not exist

Step-by-step explanation:

that what i put hope it helps

=ac-b(cosc-ccosa)

=sinc/sina

9514 1404 393

Answer:

Step-by-step explanation:

The sum of torques about the pivot point is zero when the system is in equilibrium. That means the total of clockwise torques is equal to the total of counterclockwise torques. For this purpose, torque can be modeled by the product of mass and its distance from the pivot. The uniform beam can be modeled as a point mass at its center.

__

a) Let E represent the location of the center of mass of the beam. So, AE = 1.5 m. Then the distance from C to E is AC-AE = AC -1.5 and the CCW torque due to the beam's mass is (16 kg)(AC -1.5 m).

The distance from B to C is 3 m - AC, so the CW torque due to the particle at B is (7 kg)(3 -AC m)

These are equal, so we have ...

  16(AC -1.5) = 7(3 -AC)

  16AC -24 = 21 -7AC . . . . . eliminate parentheses

  23AC = 45 . . . . . . . . . . . add 7AC+24

  AC = 45/23 ≈ 1.957 . . divide by the coefficient of AC

  AC ≈ 2.0 meters . . . . rounded to 1 dp

__

b) The torques in this scenario are ...

  M(0.7) = 16(0.8) +7(2.3) . . . . . . AD = 0.7 m, DE = 0.8 m, DB = 2.3 m

  M = 28.9/0.7 ≈ 41.286 . . . . simplify, divide by the coefficient of M

  M = 41.3 kg . . . . rounded to 1 dp

_____

Additional comment

Torque is actually the product of force and distance from the pivot. Here, the forces are all downward, and due to the acceleration of gravity. The gravitational constant multiplies each mass, so there is no harm in dividing the equation by that constant, leaving the sum of products of mass and distance.

9514 1404 393

Answer:

  $313.37

Step-by-step explanation:

The compound interest formula is used to find that value.

  A = P(1 +r/12)^(12t)

P compounded monthly at annual rate r for t years.

  A = $200(1 +0.05/12)^(12·9) ≈ $313.37

Answer:

7

This question is tying to introduce an idea that

eventually becomes a calculus question ....

(4^2 + 3(4)) - (0^2+3(0))

             4 - 0

28 - 0       = 7

   4

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

1. Approach

The average rate of change can simply be defined as the slope of a line that passes through any two points on a coordinate plane. In this situation, one is given a function, and one is asked to find the rate of change over an interval.

Given function: [tex]f(x)=x^2+3x[/tex]

Intervale, [tex][0, 4][/tex]

This can be done by evaluating the endpoints of the interval by substituting them into the function. Then writing the resulting the form of a point on the coordinate plane ([tex]x, y[/tex]). Finally, one can find the slope of the line that passes through the points by using the following slope formula,

[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Where ([tex]x_1,y_1[/tex]) and ([tex]x_2,y_2[/tex]) are coordinate points.

2. Find the points

With the function (f(x)), substitute the end points of the itnerval ( [0, 4] ) into the function to generate coordinate points,

[tex]f(x)=x^2+3x[/tex]

[ 0, 4 ]

[tex]f(0)=(0)^2+3(0)\\=0 + 0\\ =0[/tex]

Point: (0, 0)

[tex]f(4)=(4)^2+3(4)\\= 16 + 12\\ = 28[/tex]

Point: (4, 28)

3. Find the average rate of change,

Now substitute the points the formula to find the slope, then simplify to evaluate

[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

(0, 0), (4, 28)

Substitute,

[tex]\frac{y_2-y_1}{x_2-x_1}\\\\=\frac{28-0}{4-0}\\\\=\frac{28}{4}\\\\= 7[/tex]

The average rate of change is 7.

Answer:

1) A

B) 5.818 stops

Step-by-step explanation:

Number One is less than or equal to 21 because the person only has 21 dollars, so she can't spend more than 21.

B can be solved through the equation by first subtracting $5, and then dividing 2.75 by 16.

Answer:

χ²R = 8.643

χ²L = 42.796

0.20 < σ < 0.45

Step-by-step explanation:

Given :

Sample size, n = 23

The degree of freedom, df = n - 1 = 23 - 1 = 22

At α - level = 99%

For χ²R ; 1 - (1 - 0.99)/2= 0.995 ; df = 22 ; χ²R = 8.643

For χ²L ; (1 - 0.99)/2 = 0.005 ; df = 22 ; χ²L = 42.796

The confidence interval of σ ;

s * √[(n-1)/χ²L] < σ < s * √[(n-1)/χ²R)]

0.28 * √(22/42.796) < σ < 0.28 * √(22/8.643)

0.2008 < σ < 0.4467

0.20 < σ < 0.45

Answer:

17 instructors

Step-by-step explanation:

If each instructor will get 10 children, we have to divided the total number of children taking swimming lessons by the number of children assigned to each instructor (10):

165/10 = 16.5

Unfortunately, we can't have 16 and a half instructors. Since 5 children are remaining, we can round up 16.5 to 17 and get 17 instructors. This implies that 16 instructors will teach 10 children (160 in total) and 1 instructor will teach 5 children (5 in total). 160+5 = 165 total children.

Answer:

Hence the required probability is, 3/4

Step-by-step explanation:  

At the shelter, he likes :  

a male coolie, a female coolie, a male boxer, a female boxer, a male beagle, a female beagle, a male Labrador, and a female Labrador.  

Let, A denote the event of selecting a male coolie and B denote the event of selecting a male Labrador.  

P(A) = 1/8 = P(B)  

Here the probability of selecting a puppy except A & B is,  

P(AUB)c = 1 - P(AUB) = 1 - { P(A) + P(B) } = 1 - 1/8 - 1/8 = 3/4

Answer:

Option C. √5/3

Step-by-step explanation:

We'll begin by simplifying √15 / 3√3. This can be obtained as follow:

√15 / 3√3

Rationalise

√15 / 3√3 × (√3 /√3)

(√15 × √3) / (3√3 × √3)

√45 / (3 × 3)

√45 / 9

Recall:

√45 = √(9 × 5) = √9 × √5 = 3√5

Thus,

√45 / 9 = 3√5 / 9

√45 / 9 = √5 / 3

Therefore,

√15 / 3√3 = √5 / 3

Thus, option C gives the right answer to the question.

Answer:

53 by 83.5.

just divided the two numbers by 1/4

Answer:

848 and 1336

Step-by-step explanation:

You would actually multiply 212 and 334 by 4.

You need to multiply 1/4 by 4 to get 1.

212 x 4 = 848

334 x 4 =1336

Answer:

5y + 6x = 40

Step-by-step explanation:

hope it is well understood?

Given:

Minni is arranging 3 different music CDs in a row on a shelf.

To find:

The sample space for the arrangement of a jazz CD (J), a pop CD (P), and a rock CD (R).

Solution:

We know that the total number of ways to arrange n items is n!.

Minni is arranging 3 different music CDs in a row on a shelf. So, the total number of ways is:

[tex]3!=3\times 2\times 1[/tex]

[tex]3!=6[/tex]

The sample space for the arrangement of a jazz CD (J), a pop CD (P), and a rock CD (R) is:

{JPR, JRP, PJR, PRJ, RJP, RPJ}

Therefore, the required sample space is {JPR, JRP, PJR, PRJ, RJP, RPJ}.

Answer:

RPJ, JPR, PRJ, JRP, RJP, JPR.

Step-by-step explanation:

Answer: hello your question is poorly written attached below is the complete question

answer:

1 ) =  I (

2) = F

3) = Z

4) = D

Step-by-step explanation:

attached below is the required solution.

1 ) =  I ( The sequence diverges to infinity )

2) = F ( The sequence has a finite non-zero limit )

3) = Z ( The sequence converges to zero )

4) = D ( The sequence diverges )

9514 1404 393

Answer:

  24

Step-by-step explanation:

Corresponding lengths are proportional. The ratio of the full length to the given part is ...

  (30 +x)/30 = 45/25

  1 +x/30 = 1 +4/5 . . . perform the division

  x/30 = 4/5 . . . . . . . . subtract 1

  x = 30(4/5) = 24

The missing side length is 24.

Answer: -1

Step-by-step explanation:

sum of 2 and 3   subtracted   from the product of 2    difference of 7 and 4

            (2+3)            -                         2                                 (  7    -    4   )   =  -1  

       (2+3)-2(7-4) =

        5 - 2(3) =

         5-6 = -1

The sum of 2 and 3 subtracted from the product of 2 and the difference of 7 and 4 is equivalent to 1.

Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

We have the sum of 2 and 3 subtracted from the product of 2 and the difference of 7 and 4

From the question, we can model the equation as -

x = 2 × (7 - 4) - (2 + 3)

x = 2(3) - 5

x = 6 - 5

x = 1

Therefore, the sum of 2 and 3 subtracted from the product of 2 and the difference of 7 and 4 is equivalent to 1.

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Answer:

x = 12

Step-by-step explanation:

Missing length of the segment is the altitude of the right triangle.

Based on the geometric mean theorem, we would have the following:

h = √(ab)

Where,

h = x

a = 16

b = 9

Plug in the values:

x = √(16*9)

x = √144

x = 12

Given:

The given values are:

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

[tex]r^2=0.9435996398[/tex]

[tex]r=0.9713905701[/tex]

To find:

The exponential regression equation for the given values (Rounded to three decimal places).

Solution:

The general form of exponential regression equation is:

[tex]y=a\cdot b^x[/tex]          ...(i)

Where, a is the initial value and b is the growth/decay factor.

We have,

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

Round these numbers to three decimal places.

[tex]a\approx 0.209[/tex]

[tex]b\approx 2.507[/tex]

Substitute [tex]a=0.209, b=2.507[/tex] in (i) to find the exponential regression equation.

[tex]\hat{y}=0.209\cdot 2.507^x[/tex]

Therefore, the correct option is C.

[tex] - | 4 | < x < - |1| [/tex]

dunno if that's the desired form tough, but it states the same definition

The given inequality rewritten using absolute value sign​ as |-4|<x<|-1|.

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

The given inequality is -4<x<-1.

An absolute value inequality is an expression with absolute functions as well as inequality signs.

Here, using absolute value sign​ we get

|-4|<x<|-1|

Therefore, the given inequality rewritten using absolute value sign​ as |-4|<x<|-1|.

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Answer: False

Step-by-step explanation:

This is because sin 0 is equal to 0 but cot 0 is equal to undefined

Answer:

5 %

Step-by-step explanation:

1000 g = 1 kg

50 kg = 0.05 kg

0.05 = 5%

Therefore, 50 g as a percentage of 1kg is 5%.

Answer:  [tex]\$162[/tex]

Step-by-step explanation:

Given

There are 210 units of hotel

Each room charge $90 when fully occupied

occupied room charges is $24 per day

Suppose x rooms are vacant, so, there 210-x occupied

Daily expense on maintenance[tex]=(210-x)\times 24[/tex]

Earning from 210-x rooms[tex]=(210-x)(90+x)[/tex]

Profit(P)=Earning - Expense

[tex]\Rightarrow P=(210-x)(90+x)-(210-x)24\\\Rightarrow P=21,600+210x-90x-x^2-5040+24x\\\Rightarrow P=-x^2+144x+16,560\\[/tex]

To get the maximum profit, determine the derivative of P w.r.t. x and equate it to zero

[tex]\Rightarrow \dfrac{dP}{dx}=-2x+144\\\\\Rightarrow -2x+144=0\\\\\Rightarrow x=72[/tex]

Charges for maximum profit is [tex]90+72=\$162[/tex]

Number of occupied rooms are [tex]210-72=138[/tex]

The hotel charge per day will be $162  in order to maximize daily profit.

Given that,  Hotel has 210 units

Let us consider that x rooms are vacant.

Total occupied rooms = [tex](210-x)[/tex]

Since, Each occupied room costs $24 per day to service and maintain

So, Total expense = [tex]24*(210-x)=5040-24x[/tex]

Since, For  all rooms are occupied when the hotel charges $90 per day for a room. For every increase of x dollars in the daily room rate, there are x rooms vacant.

So, Total earing = [tex](210-x)*(90+x)=-x^{2} +120x+21600[/tex]

Profit = Total earning - Total expense

[tex]P=-x^{2} +120x+21600-5040+24x\\\\P=-x^{2} +144x+16560[/tex]

In order to maximize profit, Differentiate profit expression with respect to x.

    [tex]\frac{dP}{dx}=\frac{d}{dx}(-x^{2} +144x+16560) \\\\\frac{dP}{dx}=-2x+144=0\\\\\\x=\frac{144}{2}=72[/tex]

Thus, Hotel charges per day for maximum profit = [tex]90+x=90+72=162[/tex]

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