Hearing rattles from a snake, you make two rapid displacements of magnitude 1.8 m and 2.4m. Draw sketches, roughly to scale, to show how your two displacements might add to give the following resultant of magnitudes.
a. 4.2 m
b. 0.6 m
c. 3.2 m

Answer:

(a) The negative charge on one of the charges is -8.79630245 × 10⁻⁷C

(b) The positive charge on one of the other charges is 8.79630245 × 10⁻⁷C

Explanation:

The given parameters are;

The force of attraction between the two spheres = 0.0988 N

The distance between their centers = 44.5 cm = 0.445 m

Therefore, we have;

[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{d^2}[/tex]

Therefore, we have;

[tex]0.0988 \ N = -\dfrac{8.99 \times 10^9 N\cdot m^2 \cdot C^{-2}\cdot q_1 \cdot q_2}{(0.445 \ m)^2}[/tex]

Therefore, we have;

q₁·q₂ = -0.0988 N × (0.445 m)²/(8.99 × 10⁹ N·m²·C⁻²) = -2.17629255 × 10⁻¹² C²

q₁·q₂ = -2.17629255 × 10⁻¹² C²...(1)

When the two charges are connected, we get;

[tex]F_2 = \dfrac{k \cdot \left (\dfrac{q_1 + q_2}{2} \right) ^2}{d^2}[/tex]

Therefore, we have;

[tex]q_1 + q_2 = \sqrt{\dfrac{4 \cdot F_2 \cdot d^2}{k} }[/tex]

[tex]q_1 + q_2 = \sqrt{\dfrac{4 \times 0.0276 \ N \times(0.445 \ m)^2}{8.99 \times 10^9 N\cdot m^2 \cdot C^{-2}} } = 1.59446902743 \times 10^{-6} \ C[/tex]

q₁ + q₂ = 1.59446902743 × 10⁻⁶ C...(2)

From, equation (2), we have;

q₁ = 1.59446902743 × 10⁻⁶ C -  q₂

Plugging in the value of q₁ in equation (1) givens;

q₁·q₂ = -2.17629255 × 10⁻¹²

Therefore, we have;

(1.59446902743 × 10⁻⁶ -  q₂) × q₂ = -2.17629255 × 10⁻¹²

Which gives;

-q₂² + 1.59446902743 × 10⁻⁶·q₂+2.17629255 × 10⁻¹² = 0

Solving, with a graphing calculator, we get;

q₂ = 2.4741×10⁻⁶ C, or -8.79630245 × 10⁻⁷C

q₁ = 8.79630245 × 10⁻⁷C or -2.4741×10⁻⁶ C

Therefore, we have;

(a) The negative charge on one of the charges = -8.79630245 × 10⁻⁷C

(b) The positive charge on one of the other charges = 8.79630245 × 10⁻⁷C

Answer:

1.52 × 10⁻²⁰ J

Explanation:

The electrical potential difference is defined as the amount of work done in carrying a unit charge from one point to another point in an electric field. Electric potential difference is measured in volts. It is given by the formula:

ΔV = ΔU / q

ΔV is electric potential difference between the two points, ΔU is the work done and q is the unit charge.

Given that ΔV = 0.095 V, q = 1.6 × 10⁻¹⁹ C. Hence:

ΔU = ΔV.q

ΔU = 0.095 V * 1.6 × 10⁻¹⁹ C

ΔU = 1.52 × 10⁻²⁰ J

The electric potential difference is the amount of effort done in an electrical field to shift a unit charge from one spot to another.The electric potential difference will be 1.52×10⁻²⁰J.

What is the electric potential difference ?

The electrical potential difference is the amount of effort done in an electrical field to shift a unit charge from one spot to another.

Traditional current flows from positive to negative terminals, signifying positive charge transfer in that direction.

The given data in the problem is

[tex]\triangle V[/tex] is the electric potential difference between the inner and the outer cell wall = 0.095 V

[tex]\triangle U[/tex] is the amount of work done

q is the charge on the electron =1.6×10⁻¹⁹C

Electric potential difference is given by the formula

[tex]\triangle V=\frac{\triangle U}{q} \\\\ \triangle U=\triangle Vq\\\\\triangle U=0.095 V\times1.6\times10^{-19}\\\\ \triangle U=1.52\times10^{-20}J[/tex]

Hence the electric potential difference will be 1.52×10⁻²⁰J.

To learn more about the electric potential difference refer to the link;

https://brainly.com/question/9383604

Answer:

Explanation:

Impulse = change in momentum

Initial momentum = mass x initial velocity = 100 x 5 = 500 kg m/s

final momentum = mass x final velocity = 100 x - 4 = -400 ( - ve sign due to reversal of direction )

change in momentum = final momentum - initial momentum

= - 400 - 500 = - 900 kg m/s .

As it is - ve , it acts upwards .

So magnitude of  impulse on Perter = 900 kg m/s

Answer:

Vf = 29.4 m/s

h = 44.1 m

Explanation:

Data:

==================================================================

Final Velocity

Use formula:

Replace:

Multiply:

==================================================================

Height

Use formula:

Replace:

Multiply time squared:

Simplify the s², and multiply in the numerator:

It divides:

What is the velocity when falling to the ground?

The final velocity is 29.4 meters per seconds.

How high is the building?

The height of the building is 44.1 meters.

Answer:

it 1.5 meters

Explanation:

if u could put the option number it will be cool and hope it help and if it doesnt am really sorry ;)

Answer:

What was it

Explanation:

It would increase; g is inversely proportional to the square of the radius of the Earth. The correct option is A.

A current idea in geology that describes how the earth's crust is made up of a few big, hard plates that move independently of one another, causing deformation, volcanism, and seismic activity along their boundaries.

Because it explains how mountain ranges, earthquakes, volcanoes, shorelines, and other features often emerge where the moving plates contact along their boundaries, plate tectonics provides "the overall picture" of geology.

The Earth has been shrinking as it gradually cools, according to some geological hypotheses from the nineteenth century that have now been completely debunked.

If that were the case, it would rise since g is inversely proportional to the square of the Earth's radius.

Thus, the correct option is A.

For more details regarding geological theory, visit:

https://brainly.com/question/10134253

#SPJ2

Answer:lever

Explanation:

Answer:

A

Explanation:

Answer:

A) 1268 MeV

B)  299MeV/c

C) 1268 MeV

Explanation:

Given :

π meson rest energy = 139.6 MeV

Speed = 0.921c

proton at rest energy = 938.3 MeV

a) Find the total relativistic energy of resulting composite particle

E = E(meson) + E(proton)

  = [tex]\frac{(mc^2)_{meson} }{\sqrt{1-\frac{v^2}{c^2} } } + (mc^2)_{proton}[/tex]

  = [tex]\frac{139.6MeV}{\sqrt{1-\frac{(0.906c)^2}{c^2} } } + 938.3[/tex]

E = 1268 MeV

B) determine the total linear momentum of the composite particle

= 299MeV/c

attached below is the detailed solution

C) Determine the rest energy of the composite particle

E = 1268 MeV

Answer:

Well, you said the answer is A, so it’s A!

Answer:

a) V = 0.24 m/s

b) v = 1.53 m/s

Explanation:

In this case, we are asked to find two values that are pretty similar and use the same units, however, there are differences between them.

The average velocity is often referred to a vector quantity, therefore, if time is a scalar magnitude, we need to find the vector quantity of distance. In this case, is the displacement, which is also referred as a vector.

So, to calculate the average velocity we need to determine first the displacement of the person. As the person heads east and then west, his total displacement (D) is:

D = 55 - 40 = 15 m

Now the total time would be the time taken to go to the windmill and then, to a bench:

t = 25 + 37 = 62 s

Finally, the average speed is:

V = D/t

V = 15 / 62

The average speed is a scalar magnitude, so we use the covered distance by the person (d) and the total time:

d = 40 + 55 = 95 m

Then, the speed:

v = 95/62

Hope this helps

Answer:

Their bodies don't conduct electricity like we do.

Explanation:

Answer:

birds dont get shocked because they sit on their talons and their talons are a different type of skin then the rest of their body

Explanation:

Answer:

Acceleration

Explanation:

Answer: Acceleration

Explanation:

Answer:

Do you still need help??

Explanation:

Answer:

t = 2.01 s

Vf = 19.7 m/s

Explanation:

It's know through the International System that the earth's gravity is 9.8 m/s², then we have;

Data:

==================================================================

Time

Use formula:

Replace:

Everything inside the root is solved first. So, we solve the multiplication of the numerator:

It divides:

The square root is performed:

==================================================================

Final Velocity

use formula:

Replace:

Multiply:

==================================================================

How long does it take to reach the ground?

Takes time to reach the ground in 2.01 seconds.

How fast does it hit the ground?

Hits the ground with a speed of 19.7 meters per seconds.

Answer:

Hello the diagram related to your question is attached below

answer: a) 851 m/s

             b)  8506.1 secs

Explanation:

calculate the periodic time of the satellite using the equation below

t = [tex]\frac{2\pi }{R} \sqrt{\frac{(R+h)^{3} }{g} }[/tex]  --  ( 1 )

where ; R = 6370 km

h = 500 km

g = 9.81 m/s^2

input given values into equation 1

t = 5670.75 secs

next calculate the periodic time taken by the space craft  

a) determine the increase in speed

V = v - [tex]\sqrt{\frac{gR^2}{R + h} }[/tex]  

where ; v = 8463 m/s , R = 6370 km, h = 500 km

V = 851 m/s

b) Determine the periodic time for the elliptic orbit

τ = [tex]\frac{3t}{2}[/tex]

 = [tex]\frac{3*5670.76}{2}[/tex]  =  8506.1 secs

attached below is the remaining part of the detailed solution

Answer:

i think its ancestor

Explanation:

sry if im wrong

Answer:

scientists compare organisms DNA to support the theory that all species share a common Ancestor.

Answer:

4

2

1

3

Explanation:

Be safe, lovelies <3

Answer:

B

Explanation:

Friction is a force that opposes motion between any surfaces that are touching. Friction occurs because no surface is perfectly smooth Friction produces heat because it causes the molecules on rubbing surfaces to move faster and have more energy.

Answer:

d = 29.89 m

Explanation:

To solve this, we need to separate this problem in two parts.

One part would be the the time taken by the rock to actually hit the bottom, and the other part would be the time taken by the sound to reach the inspector.

Joining these two times we have:

t = t₁ + t₂    (1)

This time is 2.56 s.

Now, as we are asked to determine the distance from the top floor to the bottom, and we have two times taken in different ways, one by sound and the other the actual, we can say the same thing on distance, we need a distance relationed to the time taken by rock to hit the bottom, and the other distance relationet to the time taken by sound to reach the inspector.

Doing this we have that the distance traveled by the rock is:

y₁ = gt²/2

y₁ = 9.8t²/2 = 4.9t₁²    (2)

Now, the distance traveled by sound would be:

y₂ = v * t₂ = 336t₂   (3)

Remember that the speed of the sound is 336 m/s

From this last expression (3), we can actually write t₂ in function of t₁, using (1):

2.56 = t₁ + t₂

t₂ = 2.56 - t₁    (4)

Replacing (4) in (3):

y₂ = 336(2.56 - t₁)    (5)

Now that we have y₁ and y₂, we can equal (2) and (5), both expressions to get the value of t₁, and then, calculate the distance:

4.9t₁² = 336(2.56 - t₁)

4.9t₁² = 860.16 - 336t₁

4.9t₁² + 336t₁ - 860.16 = 0

Using the quadractic formula, we can calculate t₁:

t₁ = -336 ±√(336)² + 4*4.9*860.16 / (2*4.9)

t₁ = -336 ±√129,7555.136 / 9.8

t₁ = -336 ± 360.21 / 9.8     Using only the positive value we have:

t₁ = 2.47 s

This means that the rock hits the bottom in 2.47 s, and the remaining 0.09 s belongs to the time taken by sound. (2.47 + 0.09 = 2.56 s)

With this, we can calculate the distance of the rock using expression (2):

y₁ = 4.9 * (2.47)²

Hope this helps

Answer:

PRECAUTIONS

-The refracting faces of the glass prism should be smooth, transparent and without any air bubble or broken edge. ...

-Use a sharp pencil to draw boundary of the prism and rays of light.

-The alpins should have sharp tip and should be fixed exactly vertical to the plane of the paper.

Explanation:

Please give thanks to all my answers and please mark as brilliant and please follow me

Answer:

t = 5.88 10⁻² s

Explanation:

The speed of the sound wave after it is emitted by the bat is constant, so we can use the uniform motion relationships

          v = [tex]\frac{x}{t}[/tex]

          t = [tex]\frac{x}{v}[/tex]

in this case the distance is that of the sound in going from the bat to the insect and back

         x = 2d

         x = 2 10

         x = 20 m

let's calculate

        t = 20/340

        t = 5.88 10⁻² s

We can see that the time is very short, so the distance traveled by the two animals has little influence on the result.

Answer:

     l = 0.548 m

Explanation:

For this exercise we compensate by finding the speed of the car

         p = m v

         v = p / m

         v = 0.58 / 0.2

         v = 2.9 m / s

this is how fast you get to the ramp, let's use conservation of energy

starting point. Lowest point

         Em₀ = K = ½ m v²

final point. Point where it stops on the ramp

         [tex]Em_{f}[/tex] = U = m g h

  mechanical energy is conserved

          Em₀ = Em_{f}

          ½ m v² = m g h

           h = [tex]\frac{m v^2}{2 g}[/tex]

let's calculate

          h = [tex]\frac{0.2 \ 2.9^2}{2 \ 9.8}[/tex]

          h = 0.0858 m

to find the distance that e travels on the ramp let's use trigonometry, we look for the angle

          tan θ = y / x

          tan θ = 12/75 = 0.16

          θ = tan⁻¹ 0.16

          θ = 9º

therefore

           sin 9 = h / l

           l = h / sin 9

           l = 0.0858 / sin 9

           l = 0.548 m

Answer:

t = 12.6 seconds

Explanation:

Given that,

Initial velocity, u = 0

Acceleration of an electric vehicle, a = 2.3 m/s²

Final velocity, v = 29 m/s

We need to find the time elapses from start to stop. The acceleration of an object is given by the relation as follows :

[tex]a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{29-0}{2.3}\\\\t=12.6\ s[/tex]

So, 12.6 seconds is elapsed from start to stop.

Answer:

Gravitational

Explanation:

gravitational

Answer:

Gravitational

Explanation:

In order from strongest to weakest.

Strong nuclear

Electromagnetic

Weak nuclear

Gravitational

Answer:

* displacement from equilibrium position

* The spring constant,

Explanation:

The work done by a spring is two times the expressions

         W = ∫ F. dx

in a spring the force is given by hooke's law

          F = - k Δx

we substitute

         W = - k ∫ x dx cos θ

In the case of the spring, the displacement is in the same direction of work, therefore the angle is zero and the cosine is equal to 1

we integrate

           W = ½ k Δx²

we can see that we need two parts to calculate the work

* displacement from equilibrium position

          Δx = 12 -8 = 4 cm

* The spring constant, this constant can be found from the displacement measurements as a function of the applied force.