How far dose a kangaroo travel in 2 minutes

Answers

Answer 1
According to my knowledge, kangaroo travelers 1.3 kilometers in 2 minutes

Related Questions

pls answer quickly

Students at a school were asked to state their preferences in music. Results of the survey are shown in the circle chart.

What percent of students preferred rock and classical music?

A) 15%

B) 26%

C) 39%

D) 57%​

Answers

Answer:

B) 26%

Step-by-step explanation:

The yellow part of the graph represents Rock, which is 15%, and the red part of the graph represents Classical. So, you simply add them together.

Answer:

B) 26%.

Step-by-step explanation:

Find the Rock percentage in the chart. (15%)

Find the Classical percentage in the chart. (11%)

Add the Rock and Classical percentages together. (26%)

Graph the function f(x)=3/2x-4. Use the line tool and select two points to graph.

Answers

Answer:

Slope = 3/2

y-intercept = -4

x  |  y

0  -4

2   -1

Step-by-step explanation:

Solve the inequality: 4(2x-11) is less than equal to -12 + 2(x-4) No "files" please and also need an explanation

Answers

[tex]4(2x-11) \leq -12 +2(x-4)\\\\\implies 8x - 44 \leq -12 + 2x -8\\\\\implies 8x -44 \leq 2x -20\\\\\implies 4x - 22 \leq x - 10~~~~~~~~~~~~~~~~~~~;[\text{Dividing both sides by 2}]\\\\\implies 4x -22 +22 \leq x -10 +22~~~~~~;[\text{Adding 22 to both sides}]\\\\\implies 4x \leq x+12\\\\\implies 4x -x \leq x+12-x~~~~~~~~~~~~~~~~;[\text{Subtracting x from both sides}]\\\\\implies 3x \leq 12\\\\\implies x \leq 4 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~;[\text{Dividing both sides by 3}][/tex]

[tex]\text{Interval solution,} ~(-\infty, 4][/tex]

The soccer team provides 5 liters of water for the coaches and 1.25 liters of water for each player during practice.
Which equation represents the total number of liters of water, w, based on the number of players, p?

Answers

Answer:

y=1.25x+5

Step-by-step explanation:

please ban me i want you to send a moderator

Please help!!!!!!!!!!

Answers

Answer:

its c

Step-by-step explanation:

The diameters of a circle is 7m. Find its area to the nearest tenth?? Help please

Answers

Area =[tex]\pi r^{2}[/tex]

The diameter is double the length of the radius

7 ÷ 2 = 3.5

3.5 × 3.5 = 12.25

[tex]12.25\pi[/tex] = 38.4845100064751

38.4845100064751 rounded to the nearest tenth is 38.5

Answer:

A = 38.5 sq meters

Step-by-step explanation:

A = πr²

since diameter is 7, then radius is 7/2

A = π(7/2)²

A = 38.48

A = 38.5 rounded to nearest tenth

ill give a braineist if answered... CORRECTLY

Answers

0.5x+0.3y>=3
sorry I don't know how to make the less
than or equal to sign
Step-by-step explanation:
he can buy X amount of gumballs if he
buys Y amount of jawbreakers and that will
be less than or equal to $3
to graph, you must plug the number O into
the X spot and solve.
0.5(0) +0.3y>=3
next plug in for Y
0.5x+0.3(0) >=3
plot these two points on the graph and
draw a line through them

20(d – 4) + 4d *less than sign and a line under it* 8

Answers

Answer:

the anser od 20(d-4)+4d is5

its math can someone help

Answers

Answer:

$2.5/game

Step-by-step explanation:

To find Slope, Change of rate

find two points on the graph

I selected : (4,14) and (8, 24)

Slope: y2-y1/x2-x1

24-14/8-4

10/4

5/2

=2.5

so the rate of change is $2.5/game

WILL GIVE BRAINLYIST
Andre is in charge of cooking broccoli and zucchini for a large group. He has to spend all $17 he has and can carry 10 pounds of veggies. Zucchini costs $1.50 per pound and broccoli costs $2 per pound. One graph shows combinations of zucchini and broccoli that weigh 10 pounds and the other shows combinations of zucchini and broccoli that cost $17.

Graph

A combination of veggies that costs $17 but does not weigh 10 pounds.

Select all that apply.



Group of answer choices

D. 10 pounds of zucchini and 1 pound of broccoli

B. 4 pounds of zucchini and 6 pounds of broccoli

A. 6 pounds of zucchini, and 4 pounds of broccoli

C. 2 pounds of zucchini and 7 pounds of broccoli

Answers

Answer:

Andre has 4 pounds of Broccoli and 6 pounds of Zucchini.

Step-by-step explanation:

Answer:

A and C

Step-by-step explanation:

6 pounds of Zucchini, and 4 pounds of broccoli equals to $17 and 2 pounds of Zucchini, and 7 pounds of broccoli equals to $17. Hope this helps.

PLEASE HELP ME I'M FAILING MATH-

Select the correct texts in the passage. Julian factored the expression
[tex] {2x}^{4} + {2x}^{3} - {x}^{2} - x[/tex]
His work is shown. At which step did Julian make his first mistake, and which statement describes the mistake?

[tex]julian \: should \: have \:factored \:( {2x}^{2} - 1) \: as \: a \: difference \: of \: squares \: \\ \\ julian \: incorrectly \: factored \: - 1 \: from \: the \: second \: group \: of \: terms \: \\ \\ julian \: should \: have \: factored \: 2x \: from \: all \: terms \: instead \: of \: x \: \\ \\ julian \: incorrectly \: factored \: {2x}^{2} \: from \: the \: first \: group \: of \: terms[/tex]




Answers

He incorrectly factored -1

Julian factored the expression of 2x^4 + 2x³ - x²- x, the step 2 ( x (2x² (x + 1)) - 1(x − 1)) is wrong statement.

What is an expression?

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

We have been given an expression as;

2[tex]x^{4}[/tex] + 2x³ - x²- x

Step 1;

x(2x³ + 2x²- x − 1)

Step 2;

x (2x² (x + 1)) - 1(x − 1)

Step 3;

x²(2x²-1) (x + 1)(x - 1)

Hence, Julian incorrectly factored -1 from the second group of terms.

we can write the correct factored as;

x (2x²- 1))(x + 1)

Therefore, Julian factored the expression of 2[tex]x^{4}[/tex] + 2x³ - x²- x, the step 2 ( x (2x² (x + 1)) - 1(x − 1)) is wrong statement.

To know more about an expression follow;

brainly.com/question/19876186

#SPJ5

PLEASE HELP ASAP!!
Complete this item.
For the following figure, can you conclude that l || m? Select true or false.

Answers

Answer:

true

Step-by-step explanation:

Line l and line m are parallel to each other which means the statement is true.

[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]

The statement is True !

In the given figure, the two lines are parallel to one another ~ because pair of corresponding angles are equal.

An amusement park has two themed resorts, Stargazer Suites and Retro Retreat. The graph and table below display the cost of the stay, y, for different numbers of nights, x, for the two different resorts.
Which statement correctly compares the nightly rates at Stargazer Suites and Retro Retreat?

The nightly rate at Stargazer Suites is $15 more than the nightly rate at Retro Retreat.

The nightly rate at Stargazer Suites is $25 more than the nightly rate at Retro Retreat.

The nightly rate at Retro Retreat is $30 more than the nightly rate at Stargazer Suites.

The nightly rate at Retro Retreat is $80 more than the nightly rate at Stargazer Suites.

The nightly rate at each resort is the same.

Answers

Answer:

to confusing

Step-by-step explanation:

Answer:

The nightly rate at Stargazer Suites is $25 more than the nightly rate at Retro Retreat.

Step-by-step explanation:

working together two mathletes solve 32 math problems in a certain amount of time how many problems will 3 mathletes solve if they together at the same rate for the same amount of time

Answers

If they together at the same rate for the same amount of time, they will solve 48 math problems,

From the question, we can see that two mathletes solve 32 math problems in a certain amount of time, this can be written as:

2 mathletes = 32 math problems

In order to determine the number of problems for 3 mathletes, this is expressed as:

3 mathletes = x

DIvide both expressions:

2/3 = 32/x

Cross multiply

2x = 3* 32

x = 3 * 16

x = 48math problems

Hence if they together at the same rate for the same amount of time, they will solve 48 math problems,

Learn more on proportion here: https://brainly.com/question/1496357

15% of what is 12? Please

Answers

15*X/100=12

15x=1200

X=1200/15

x=80

See attachment for answer and math work.

The perimeter of the triangle is 20.6 centimeters. What is the unknown side length?

Answers

Answer:

OK so a triangle has 3 sides and the perimeter around it is 20.6 cm to find the unknown for the length of a side it would be 20.6 ÷3 which is = to 6.86 to 2 decimal places

Step-by-step explanation:

20.6÷3

= 6.86 cm to 2 dp

75,15,3 find the 6th term

Answers

Answer:

0.024

Step-by-step explanation:

75, 15, 3, ...

Now, let's take a look at thus pattern.

You'll notice how the numbers decrease.

Divide 75 by 5.

We get 15

Divide 15 by 5.

We get 3.

Then we have the pattern now.

3 ÷ 5 = 0.6 (4th term)

0.6 ÷ 5 = 0.12 (5th term)

0 12 ÷ 5 = 0.024 (6th term)

I hope it helps.

Solve.

x/2=−0.73

What is the solution to the equation?

Enter your answer as a decimal in the box.

x =

Answers

x/2 = -0.73

To solve for x multiply both sides by 2:

x = -1.46

The answer is X= -1.45

6x2 + 108x + 707 = 5

Answers

Answer:

[tex]x=-9\pm6i[/tex]

Step-by-step explanation:

[tex]6x^2+108x+707=5[/tex]

[tex]6x^2+108x+702=0[/tex]

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{-108\pm\sqrt{(108)^2-4(6)(702)}}{2(6)}[/tex]

[tex]x=\frac{-108\pm\sqrt{-5184}}{12}[/tex]

[tex]x=\frac{-108\pm72i}{12}[/tex]

[tex]x=-9\pm6i[/tex]

I really need help it’s due in two days

Answers

Answer:

Step-by-step explanation:

The answer is "Impossible to solve" , because there is no rule for function at point x = 7 . The given function has domain ( - ∞ , 2 ) ∪ { 2 } ∪ ( 2 , 7 ) ⇒ 7 is not a part of domain!!!

-3/1x+1=10
Somebody answer please

Answers

Answer:

Step-by-step explanation:

3

+

1

1

=

1

0

1

3

=

9

3

3

=

9

3

=

3   answer

P/s: I don’t understand the question so I do it in two ways

bro can anybody please help :(!!

Answers

Answer:

This is what i got

2.
If you were to flip a coin 20 times, what is the probability
you would get at most 13 heads?
a) .9423
b) .1316
c) .0577
d) .0739

Answers

Answer:

A) .9423

Step-by-step explanation:

The chance of getting at most 13 heads is 0.9423

"The square root of two times a number subtract five is equal to ten."

Answers

It would be √2 x n - 5 = 10.

[tex]x3 = -8[/tex] i want the answer

Answers

Answer:

x=-8/3

Step-by-step explanation:

What is the relation between the sine and cosine values of angles in each quadrant? How would you use the 60° angle to find sine and cosine of 120°, 240°, and 300°? What angles could we find sine and cosine for using information for π/4 and π/6?

Answers

The angles, 60°, [tex]\displaystyle \frac{\pi}{4}[/tex] and [tex]\displaystyle \frac{\pi}{6}[/tex] are special angles that have known trigonometric ratio values.

First part;

The sine and cosine gives the coordinates of the tip of the radius of a unit circle as it rotates P(cos(θ), sin(θ))

Second part;

With the knowledge of the sine and cosine of 60°, we have; sin(60°) = sin(120°), sin(240°) = -sin(60°), sin(300°) = -sin(60°)cos(120°) = -cos(60°), cos(240°) = -cos(60°), cos(300°) =  cos(60°)  

Third part;

[tex]\displaystyle \frac{\pi}{4}[/tex] can be used to find the sine and cosine of [tex]\displaystyle \frac{3 \cdot \pi}{4}[/tex], [tex]\displaystyle \frac{5 \cdot \pi}{4}[/tex], and [tex]\displaystyle \frac{7 \cdot \pi}{4}[/tex]  [tex]\displaystyle \frac{\pi}{6}[/tex], can be used to find the sine and cosine of [tex]\displaystyle \frac{5 \cdot \pi}{6}[/tex], [tex]\displaystyle \frac{7 \cdot \pi}{6}[/tex], and [tex]\displaystyle \frac{11 \cdot \pi}{6}[/tex]

Reasons:

First Part;

Considering a unit circle with the center at the origin of the graph, we have;

The sine of the angle, θ, rotated by the radius is the vertical distance of a point P on the circle which is the location of the radius, from the horizontal axis.

The cosine of the angle, θ, is the horizontal distance of P from the vertical axis, such that we have;

The coordinates of point P = (cos(θ), sin(θ))

In the four quadrant, we have;

First Quadrant; All trigonometric ratios are positive

Second Quadrant; sine is positive

Third Quadrant; Tan is positive

Fourth Quadrant; Cosine is positive

Second part;

We have; At 120°, the point P is the same elevation from the horizontal axis, therefore;

sin(60°) = sin(120°) = 0.5·√3

However, the x-coordinate of the point P is in the negative direction, therefore, we get;

cos(120°) = -cos(60°) = -0.5

Similarly from the quadrant relationship, we have;

240° is in the third quadrant, and it is 60° below the negative horizontal line, therefore;

sin(240°) = -sin(60°) = -0.5·√3

cos(240°) = -cos(60°) = -0.5

300° is in the fourth quadrant, and it is 60° below the positive x-axis, therefore;

sin(300°) is negative and cos(300°) is positive

Which gives;

sin(300°) = -sin(60°) =  -0.5·√3

cos(300°) =  cos(60°) = 0.5

Third part;

[tex]\displaystyle \frac{\pi}{4} =45^{\circ}[/tex]

[tex]\displaystyle \frac{\pi}{6} =30^{\circ}[/tex]

The sine and cosine of 45° can be used to find the sine and cosine of (180° + 45°) = 225°, (360° - 45°) = 315°

Also, due to the mid location of the angle 45° on the quadrant, we have;

Another angles is the sines and cosine of (90° + 45°) = 135°

Therefore, [tex]\displaystyle \frac{\pi}{4}[/tex], can be used to find the sine and cosine of 135°, 225°, and 315°

[tex]\displaystyle 135^{\circ} = \mathbf{\frac{3 \cdot \pi}{4}}[/tex], [tex]\displaystyle 225^{\circ} = \frac{5 \cdot \pi}{4}[/tex], [tex]\displaystyle 315^{\circ} = \frac{7 \cdot \pi}{4}[/tex]

Therefore,

[tex]\displaystyle \frac{\pi}{4}[/tex] can be used to find the sine and cosine of [tex]\displaystyle \mathbf{\frac{3 \cdot \pi}{4}}[/tex], [tex]\displaystyle \mathbf{\frac{5 \cdot \pi}{4}}[/tex], and [tex]\displaystyle \mathbf{ \frac{7 \cdot \pi}{4}}[/tex]

Similarly, the sine and cosine of, [tex]\displaystyle \frac{\pi}{6}[/tex]  = 30° can be used to find the sine and cosine of 150°,  210°, and 330°.

[tex]\displaystyle 150^{\circ} = \frac{5 \cdot \pi}{6}[/tex], [tex]\displaystyle 210^{\circ} = \frac{7 \cdot \pi}{6}[/tex], and [tex]\displaystyle 330^{\circ} = \frac{11 \cdot \pi}{6}[/tex]

[tex]\displaystyle \frac{\pi}{6}[/tex], can be used to find the sine and cosine of [tex]\displaystyle \mathbf{ \frac{5 \cdot \pi}{6}}[/tex], [tex]\displaystyle \mathbf{ \frac{7 \cdot \pi}{6}}[/tex], and [tex]\displaystyle \mathbf{\frac{11 \cdot \pi}{6}}[/tex]

Learn more about the sine and cosine of angles here:

https://brainly.com/question/4372174

Answer:

Step-by-step explanation:

The cosine value of an angle is the x coordinate of the point the angle corresponds to on the unit circle, and the sine value of an angle is the y coordinate of that point. 120, 240, and 300 all form 60 degree reference angles which in turn forms 30-60-90 triangles which help to find the sine and cosine of these corresponding angles. Pi/4 radians converts to 45 degrees which forms a 45-45-90 special triangle on the unit circle which has its own known trigonometric ratio. Pi/6 radians converts to 30 degrees which forms a 30-60-90 triangle on the unit circle which also has a known trigonometric ratio. These ratios help find the sine and cosine of the angles on the unit circle which corresponds to a point on the coordinate plane.

HELP PLEASE!!!
What is the ratio of 1713.57^2/4113.87^3.

Answers

Answer:

  4.21747×10^-5

Step-by-step explanation:

Your calculator can do the division for you. The ratio is about 4.21747×10^-5.

__

This is approximately 10/237109.

Show all work pls ty (:

Answers

There hope it helps ÙnÚ

ALGEBRA​ Find ​x and ​y so that each quadrilateral is a parallelogram.
(Please do at least 2, but doing all 4 would be greatly appreciated, and i will mark u brainliest.)

Answers

7) 2y=y+19
y=19
2x-8=x+16
2x=x+24
x=24
8) y=14
x=3
9) x=44
y=20
10) x=17
y=9

Question 34, the answer is C. I just need the working. Tysm

Answers

Answer:

C

Step-by-step explanation:

∠ ABC = 90° ( angle in a semicircle )

Using the cosine ratio in right triangle ABC and the exact value

cos30° = [tex]\frac{\sqrt{3} }{2}[/tex] , then

cos30° = [tex]\frac{adjacent }{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{10}{AC}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )

AC × [tex]\sqrt{3}[/tex] = 20 ( divide both sides by [tex]\sqrt{3}[/tex] )

AC = [tex]\frac{20}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ( rationalising denominator )

AC = [tex]\frac{20\sqrt{3} }{3}[/tex]

radius AO = [tex]\frac{1}{2}[/tex] AC = [tex]\frac{1}{2}[/tex] × [tex]\frac{20\sqrt{3} }{3}[/tex] = [tex]\frac{10\sqrt{3} }{3}[/tex] → C

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