I been on this for days and no one can give me a right answer ​

Answer:

Using 3.14   for pi  A = 113.0  ft^2

Using the pi button A = 113.1 ft^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

A = pi ( 6)^2

A = 36 pi

Using 3.14 for an approximation for pi

A = 36(3.14) = 113.04

To 1 decimal

113.0

Using the pi button

A = 113.0973355

A = 113.1

Answer:

5/y^3

Step-by-step explanation:

which expression is equivalent to 5y^-3

for example a^-1 = 1/a

5y^-3 = 5/y^3

Answer:

a. In first study, the treatment is not imposed on the subjects, whereas in the second study the treatment is imposed on subjects.

Step-by-step explanation:

In the first study, observation are made on 300 adults who eat 3 servings of vegetables a day on average. The second study has further intensified the research which imposed treatment on the subjects. The random samples of adults are observed in both studies.

Answer:

9

Step-by-step explanation:

First multiple of 8 in that range is 8(2)=16.

The last multiple of 8 in that range is 8(10)=80.

So we just need to find how many numbers there are between 2 and 10. inclusive.

10-2+1=9

It's also not that long to write out and count.

1-2

2-3

3-4

4-5

5-6

6-7

7-8

8-9

9-10

9 numbers there are

Multiply those 9 numbers by i you will have all multiples of 8 btw 15 and 85.

8(2)=16

8(3)=24

8(4)=32

8(5)=40

8(6)=48

8(7)=56

8(8)=64

8(9)=72

8(10)=80

9514 1404 393

Answer:

  20

Step-by-step explanation:

A whole can be divided into two pieces that are each 1/2 of the whole.

 (10 wholes) × (2 pieces per whole) = 20 pieces

If you're familiar with surface integrals, start by parameterizing the surface by the vector-valued function,

r(u, v) = 3 cos(u) sin(v) i + 3 sin(u) sin(v) j + 3 cos(v) k

with 0 ≤ u ≤ 2π and 0 ≤ v ≤ arccos(1/√8).

Then the area of the surface (I denote it by S) is

[tex]\displaystyle\iint_S\mathrm dA = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}\left\|\dfrac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm dv\,\mathrm du \\\\ = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}9\sin(v)\,\mathrm dv\,\mathrm du \\\\ =18\pi \int_0^{\arccos\left(1/\sqrt8\right)}\sin(v)\,\mathrm dv = \boxed{\frac{9(4-\sqrt2)\pi}2}[/tex]

Answer: 2

Step-by-step explanation:

We know by different of squares, (x-y)(x+y)=74. Since we need to find the smallest possible answer for x+y, we let x+y=2, where both x and y = 1.

Answer:

-12

Step-by-step explanation:

that is b

PMA = 37

CMT =  101 - 54 =47

Total = 37 + 47 = 84

Answer: A. 84

Answer:

Kindly check explanation

Step-by-step explanation:

The variables in the heavenly chocolate dataset is attached below :

Variables are classed as either Categorical or Quantitative.

Categorical variables are used for non - numeric variables which are used to group values based on labels whole quantitative variables are those which are numeric.

Therefore, the variables ;

Customer = Quantitative (represented with number values)

Day = Categorical (Non-numeric)

Browser = Categorical (Non - numeric)

Time = Quantitative (contains numeric values)

Pages viewed = Quantitative (contains numeric values)

Amount spent = Quantitative (contains numeric values)

Quantitative variables are most appropriate to summarize using ungrouped frequency as the attributed of the data can be adequately ibtia Ed without have to seperates or place data into categories.

Answer:

− 8 a ^7

Step-by-step explanation:

See picture for steps :)

Answer:

Mr. Abernathy purchased 10 of $1.50 wrenches, 10 of $2.50 wrenches, 5 of $4 wrenches and 6 of $3 wrenches.

Step-by-step explanation:

Answer:

3 hours 30 minutes

Step-by-step explanation:

Jan :2 hours

her husband : 1 hour 30 minutes

2hr + 1 ½ hrs = 3 ½ hrs...that is 3 hours 30 minutes....?

Answer:

in five (5) ways a committee can be formed from 7 men and 5 women

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Number of attendees the first day = x.

Solve the following equation for x:

Answer:

25x + 100 = 11300

25x = 11200

448 = x

Step-by-step explanation:

the certain number is 448

Answer: [tex]y=-\frac{2}{5}x+12[/tex]

y = mx + b

m = slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{18-8}{-15-10}=\frac{10}{-25}=\frac{2(5)}{-5(5)}=-\frac{2}{5}[/tex]

The y-intercept(b) can be found by substituting a point into the function.

[tex]y = -\frac{2}{5}x + b \\\\8=-\frac{2}{5}(10) + b\\\\8=-4+b\\\\b=8+4=12[/tex]

Therefore, the function is:

[tex]y=-\frac{2}{5}x+12[/tex]

Answer:

25.40

Step-by-step explanation:

tickets  ( 2 at 10.95 each) = 2* 10.95 = 21.90

popcorn ( 1 at 7.50)         = 7.50

Total cost before discount

21.90+7.50=29.40

subtract the discount

29.40-4.00 =25.40

Answer:

Yep! That's correct!

Step-by-step explanation:

We know that Marilyn and her sister are each getting a ticket that cost $10.95. They are also getting a $7.50 popcorn to share. Let's add those values up.

(10.95 * 2) + 7.50 {Multiply 10.95 by 2 to get 21.90.}

21.90 + 7.50 {Add 7.50 to 21.90 to get 29.40}

$29.40 (without the credit) in toal

A credit on a movie reward card functions as a discount, so what we need to do next is subtract 4 from 29.40. That will get us $25.40 as the total cost.

After doing the math, I can deduce that your answer is correct!

Answer:

In a residual plot against x that does NOT suggest we should challenge the assumptions of our regression model, we would expect to see a _____.

c. horizontal band of points centered near 0

Step-by-step explanation:

This residual graph or plot shows the residual values (or the difference between the observed y-value (from scatter plot) and the predicted y-value (from regression equation line) on the vertical axis and displays the independent variable on the horizontal axis.  A linear regression model becomes appropriate for a dataset when the points are randomly dispersed around the horizontal axis near 0; otherwise, a nonlinear model becomes more appropriate.

Answer:

12.04

Step-by-step explanation:

Find the number in the hundredth place  4  and look one place to the right for the rounding digit  1 . Round up if this number is greater than or equal to  5  and round down if it is less than  5 .

Correct options are -10 and 10

-7 + (-10² - 19)³/⁴ = 20

-7 + (100 - 19)^3/4 = 20

-7 + (81)^3/4 = 20

-7 + 27 = 20

20 = 20

RHS = LHS

-7 + (10² - 19)^3/4 = 20

-7 + (100 - 19)^3/4 = 20

-7 + (81)^3/4 = 20

-7 + 27 = 20

20 = 20

RHS = LHS

Rest options are incorrect

Answered by Gauthmath must click thanks and mark brainliest

Answer:

B and C, so 10 and -10

Step-by-step explanation:

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

x  ≈  0.13893498

Answer:

y=-2/3x+6

Step-by-step explanation:

Graph it

Answer:

y= -2/3 x + 6

Step-by-step explanation:

1. In the graph, you can see the points (0,6) and (6,2)

2. Since you have all the available options, you can input both points into all equations.

3. In this case, the correct answer is y= -2/3 x + 6

Answer:

Ray weighed 150 pounds two years ago.

Step-by-step explanation:

11/100 = 16.5/x

11x = 16.5(100)

11x = 1,650

(11x)/11 = (1,650)/11

x = 150

About time that he should start going to the gym!

Answer:

[tex]C(x) = \left[\begin{array}{ccc}4x &0 \le x \le 2& \\4 +2x &2 < x \le 6& \\16 &6<x\le 8& \end{array}\right[/tex]

Step-by-step explanation:

Given

See attachment for question

Required

The piece-wise function

From the attachment, we have:

(1) $4/hr for first 2 hours

This is represented as:

[tex]C(x) = 4x[/tex]

The domain is: [tex]0 \le x \le 2[/tex]

(2) $2/hr for next 4 hours

Here, we have:

[tex]Rate = 2[/tex]

The total cost in the first 2 hours is:

[tex]C(x) = 4x[/tex]

[tex]C(2) = 4*2 = 8[/tex]

So, this function is represented as:

[tex]C(x) = C(2) + Rate * (Time - 2)[/tex] ----- 2 represents the first 2 hours

So, we have:

[tex]C(x) = C(2) + Rate * (Time - 2)[/tex]

[tex]C(x) =8 + 2(x - 2)[/tex]

Open brackets

[tex]C(x) =8 + 2x - 4[/tex]

Collect like terms

[tex]C(x) =8 - 4+ 2x[/tex]

[tex]C(x) =4+ 2x[/tex]

The domain is:

[tex]2 < x \le 2 + 4[/tex]

[tex]2 <x \le 6[/tex]

(3) 0 charges for the last 2 hours

The maximum charge from (2) is:

[tex]C(x) =4+ 2x[/tex]

[tex]C(6) = 4 + 2*6[/tex]

[tex]C(6) = 4 + 12[/tex]

[tex]C(6) = 16[/tex]

Since there will be no additional charges, then:

[tex]C(x) = 16[/tex]

And the domain is:

[tex]6 < x \le 8[/tex] --- 8 represents the limit

So, we have:

[tex]C(x) = \left[\begin{array}{ccc}4x &0 \le x \le 2& \\4 +2x &2 < x \le 6& \\16 &6<x\le 8& \end{array}\right[/tex]

Answer:

[tex]y=-\frac{8}{7}x+4[/tex]

Step-by-step explanation:

A line is perpendicular to another if its slope is the negative reciprocal of the other.

Your lines are in slope intercept form here, y=mx+b, where m is the slope. We can see the given line has slope [tex]\frac{7}{8}[/tex]. The negative reciprocal of that is [tex]-\frac{8}{7}[/tex], which is the slope of the third answer choice.

Answer:

Paired t test

H0 : μd = 0

H1 : μd > 0

Critical value = 3.499

Test statistic = 2.230

Reject H0 if test statistic > Critical value

Kindly check explanation.

Step-by-step explanation:

Given the data :

110 90 120 98 100 100 90 110

124 100 102 120 110 110 123 120

The hypothesis :

H0 : μd = 0

H1 : μd > 0

Tcritical value, df = n - 1 = 8 - 1 = 7

Tcritical(0.01, 7) = 3.499

The difference, d = (-14,-10,18,-22,-10,-10,-33,-10)

The test statistic :

Xdbar / Sd/√n

The mean difference, Xdbar = Σx / n = - 11.375

The standard deviation of difference, Sd = 14.431

The test statistic :

-11.375 / (14.431/√8) ;

-11.375 / 5.102

= 2.230

Decison :

Reject H0 if test statistic > Critical value

Since ; 2.230 <3.499 ;

We fail to reject the null

Answer:

11/20

Step-by-step explanation:

I think the given integral reads

[tex]\displaystyle \int_{-3}^3 \int_0^{9-x^2} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

In cylindrical coordinates, we take

x ² + y ² = r ²

x = r cos(θ)

y = r sin(θ)

and leave z alone. The volume element becomes

dV = dx dy dz = r dr dθ dz

Then the integral in cylindrical coordinates is

[tex]\displaystyle \boxed{\int_0^\pi \int_0^{(\sqrt{35\cos^2(\theta)+1}-\sin(\theta))/(2\cos^2(\theta))} \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta}[/tex]

To arrive at this integral, first look at the "shadow" of the integration region in the x-y plane. It's the set

{(x, y) : -3 ≤ x ≤ 3 and 0 ≤ y ≤ 9 - x ²}

which is the area between a paraboloid and the x-axis in the upper half of the plane. So right away, you know θ will fall in the first two quadrants, so that 0 ≤ θ ≤ π.

Next, r describes the distance from the origin to the parabola y = 9 - x ². In cylindrical coordinates, this equation changes to

r sin(θ) = 9 - (r cos(θ))²

You can solve this explicitly for r as a function of θ :

r sin(θ) = 9 - r ² cos²(θ)

r ² cos²(θ) + r sin(θ) = 9

r ² + r sin(θ)/cos²(θ) = 9/cos²(θ)

(r + sin(θ)/(2 cos²(θ)))² = 9/cos²(θ) + sin²(θ)/(4 cos⁴(θ))

(r + sin(θ)/(2 cos²(θ)))² = (36 cos²(θ) + sin²(θ))/(4 cos⁴(θ))

(r + sin(θ)/(2 cos²(θ)))² = (35 cos²(θ) + 1)/(4 cos⁴(θ))

r + sin(θ)/(2 cos²(θ)) = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))]

r  = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))] - sin(θ)/(2 cos²(θ))

Then r ranges from 0 to this upper limit.

Lastly, the limits for z can be converted immediately since there's no underlying dependence on r or θ.

The expression above is a bit complicated, so I wonder if you are missing some square roots in the given integral... Perhaps you meant

[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

or

[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{\sqrt{9-x^2-y^2}} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

For either of these, the "shadow" in the x-y plane is a semicircle of radius 3, so the only difference is that the upper limit on r in either integral would be r = 3. The limits for z would essentially stay the same. So you'd have either

[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

or

[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{\sqrt{9-r^2}} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]