Answer:
i don't know but my father i think he can't answer this
The part of the circuit that converts electrical energy into other forms
Answer:
Load
Explanation:
The load in an electric circuit is any device that converts electrical energy into another form of energy.
Calculate the net force acting on a body of mass 20 kg moving with a
uniform velocity of 4 ms-1.
Answer:
0 N
Explanation:
Uniform velocity means no acceleration and therefore no net force.
What is the object' velocity between O s and 2 s?
Answer:
Explanation:
Acceleration b/c 0m/s/2s =0m/s²
Suppose a cannon is sitting on top of a 50.0 m high hill and a 5.00 kg cannon ball is fired with a velocity of 30.0 m/s at some unknown angle. What is the velocity of the cannon ball when it strikes the earth?
The final velocity of the cannon ball when it strikes the earth is 43.36 m/s.
The given parameters:
Height of the hill, h = 50 mMass of the cannon, m = 5 kgVelocity of the ball, v = 30 m/sThe final velocity of the cannon ball when it strikes the earth is calculated by applying the principle of conservation of energy as follows;
[tex]P.E_i + K.E_i = P.E_f + K.E_f\\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = g(0) + \frac{1}{2} v_f^2\\\\2gh_i + v_i^2 = v_f^2\\\\v_f = \sqrt{2gh_i + v_i^2 } \\\\v_f = \sqrt{(2 \times 9.8 \times 50) \ \ + \ \ 30^2} \\\\v_f = 43.36 \ m/s[/tex]
Thus, the final velocity of the cannon ball when it strikes the earth is 43.36 m/s.
Learn more about conservation of energy here: https://brainly.com/question/166559
Michelle recently started selling her invention: A bed that looks like it floats in mid-air. The bed is actually suspended by magnetic forces. Michelle is a(n)
Answer:
Explanation:
designer
illusionist
engineer
entrepreneur
salesperson
human
inventor
BECAUSE OF THEIR A PAIR OF SUNGLEASSES ON THE DASHBOARD WILL CONTINUE MOVING FORWARD WHEN THE CAR TURNS SHARPLY
a. Acceleration
b. inertia
c. velocity
d. weight
Answer:
b. inertia
Explanation:
BECAUSE OF THEIR inertia A PAIR OF SUNGLEASSES ON THE DASHBOARD WILL CONTINUE MOVING FORWARD WHEN THE CAR TURNS SHARPLY.
Kyle, a 23-year-old-male, feels as if he is always on the “edge of his seat,” as if something is going to happen. He also has problems sleeping. Kyle feels nervous continuously and cannot seem to relax. When asked if he is nervous about something in particular, he can’t pinpoint the source of his anxiety.
Based on the information given, it can be posited that Kyle has a general anxiety disorder.
Generalized Anxiety Disorder is a disorder that is characterized by persistent and excessive worry about different things. People with the disorder may anticipate disaster and are concerned about money, health, family, or other issues.
Some of the effective ways of treatment are spending more time with family and friends, doing regular exercises , enough sleeping, etc.
Learn more about disorder on:
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As the amount of charge on either of two charged objects increases, the electric force between the objects decreases.
O True O False
Answer:
False.
Explanation:
provided the distance between the forces remains the same, the force will increase with increased charge, whether attractive or repulsive.
A solid, uniform sphere with a mass of 2.5 kg rolls without slipping down an incline plane starting from rest at a vertical height of 19 m. If the sphere has a radius of 0.60 m, what is the angular speed of the sphere at the bottom of the incline plane
Answer:
1/2 m v^2 + 1/2 I ω^2 = m g h conservation of energy
I = 2/5 m R^2 inertia of solid sphere
1/2 m v^2 + 1/5 m ω^2 R^2 = m g h
1/2 v^2 + 1/5 v^2 = g h
v^2 = 10 g h / 7 = 1.43 * 9.80 * 19 m^2/s^2 = 266 m^2/s^2
v = 16.3 m/s
v = R ω
ω = 16.3 / .6 = 27.2 / sec
Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 1.60 cm from the axis to equal 300000 g (where g is the acceleration due to gravity).
Express your answer numerically in revolutions per minute.
Answer:
Explanation:
300000(9.8) = ω²(0.0160)
ω = 13555 rad/s
13555 rad/s (60 s/min/ 2π rad/rev) = 129,445 rev/min
What are the two fundamental ways energy and momentum are moved from one place to another?
The two fundamental ways energy and momentum are moved from one
place to another are through the mass and velocity.
The formula for momentum is mass multiplied with velocity.
Momentum= mass × velocity
The two factors in which momentum and energy is moved from one place to
another is however through how much and how fast the object is moving
which validates the answer.
Read more on https://brainly.com/question/1042017
What is the difference between speed and velocity?
Hope you could get an idea from here.
Doubt clarification - use comment section.
Qué velocidad –en m/s– tiene un móvil, que recorre 15 km en 20 minutos
(es para hoy por faaaa)
Answer:
Explanation:
15 km(1000 m / km) / (20 min(60 s/min)) = 12.5 m/s
Which kind of chemical reaction is best
represented by the following equation?
BaCl2 + Na2S04 --> 2NaCl + BaSO4
A. Synthesis
B. Single displacement
C. Decomposition
D. Double displacement
Answer:
Synthesis
Explanation:
[tex] \color{lime}{ \sf better \: luck \: on \: your \: exam \: lol}[/tex]
Who won the noble prize for physics. He led a coalition of scientists who argued to control nucleus weapons
Answer:
Linus Pauling
Explanation:
Prize motivation: "for his fight against the nuclear arms race between East and West." Linus Pauling received his Nobel Prize one year later, in 1963.
How much work does an elephant do while moving a circus wagon 60 meters with a pulling force of 240N
Answer:
14,400
Explanation:
You need to do 240x60 and you would get the answer as 14,000
all pressure topics in physics
K
Mission CG9: Weightlessness
Consider the several locations along a roller coaster
track. In which location(s) would the riders feel less
than their normal weight? Select all that apply.
Location A
Location B
Location C
a
=-10 m/s/s, dn
--2 m/s/s, up
a--6 m/s/s, dn
Location D
Location E
x=-12 m/s/s, dn
---6 m/s/s, up
The locations where the riders feel less than their normal weight are Location A, Location C and Location D.
The given parameters;
Location A, a = 10 m/s² downLocation B, a = 2 m/s² upLocation C, a = 6 m/s² downLocation D, a = 12 m/s² downLocation E, a = 6 m/s² upThe normal weight of the riders is calculated by applying Newton's second law of motion as follows;
W = mg
W = 9.8m
The apparent weight of the riders for the upward acceleration is calculated as follows;
[tex]R = m(g + a)[/tex]
The apparent weight of the riders for the downward acceleration is calculated as follows;
[tex]R = m(g - a)[/tex]
The apparent weight of the riders at location A is calculated as follows;
[tex]R_ A = m(9.8 - 10)\\\\R_ A = -0.2 m[/tex]
The apparent weight of the riders at location B is calculated as follows;
[tex]R_B = m(9.8 + 2)\\\\R_B = 11.8 m[/tex]
The apparent weight of the riders at location C is calculated as follows;
[tex]R_C = m(9.8 - 6)\\\\R_C = 3.8 m[/tex]
The apparent weight of the riders at location D is calculated as follows;
[tex]R_D = m(9.8 - 12)\\\\R_D = -2.2 m[/tex]
The apparent weight of the riders at location E is calculated as follows;
[tex]R_E = m(9.8 + 6)\\\\R_E = 15.8 m[/tex]
Thus, the locations where the riders feel less than their normal weight are;
Location ALocation CLocation D.Learn more about Newton's second law and reading of a scale here: https://brainly.com/question/11603452
3. A ball is dropped from the roof of a building 55 meters tall. What is the approximate time of fall?
(Neglect air resistance and round to 2 decimal places).
Answer:
3.35 seconds
Explanation:
Use one of the equations of accelerated motion:
Δd = v1Δt+1/2aΔt^2
and rearrange for Δt which is time
Δt = √(2Δd)/a
now we can substitute in the values
a= 9.8 (acceleration due to gravity) and Δd= 55 as that is the height of the building
Δt = √(2*55)/9.8
Δt = 3.3503s
what is dispersion of light?
Answer:
[tex] \huge \bold \blue{ \underline{ answer}}[/tex]
The splitting up of light into its constituent colours while passing from one medium to the other is called dispersion.
A 21 newton force keeps a 3 kg object in uniform circular motion. The speed of the object is 9 m/s. The magnitude of the centripetal acceleration is
3 m/s^2
7 m/s^2
27 m/s^2
30 m/s^2
Answer:
Explanation:
F = ma
a = F/m = 21/3 = 7 m/s²
Just like our bodies, Earth's cycles tend to maintain a balance or equilibrium .
An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?
Answer:
Explanation:
acceleration= change in velocity/time taken
acceleration= 93/49
=2.02
Use the circuit diagram to decide if the lightbulb will
light. Justify your answer.
Answer:
The light bulb will NOT light because the lower switch being closed makes a short circuit. The light will have a high resistance and the electricity will choose to flow the easiest way possible through the low resistance wires.
Explanation:
what is the relationship between work and mechanical advantage
Anyone know? plzz It's a grade.
Answer:
Gregor Mendal discovered the basic laws of inheritance he concluded that genes come in pairs and are are inherited from each parent. Rosalind Franklin discovered the structure of DNA(Deoxyribonucleic Acid), and RNA(Ribonucleic Acid). She also discovered about the double helix structure of DNA. She works on the composition of the human body and her discoveries were vast. Watson and Clark were one of the greatest genetic discoverers ever. They were the ones who rose modern molecular biology. In short terms, they were the ones concerned with how genes work and there role in DNA Replication.
Explanation:
A container holds 192 g of oxygen gas at a pressure of 8.00 atm.
How much heat Q is required to increase the temperature by
145 °C at constant volume?
The quantity of heat (Q) that is required to increase the temperature at constant volume is 18,082.95 Joules.
Given the following data:
Mass of oxygen gas = 192 gPressure = 8.00 atmTemperature = 145°CScientific data:
Ideal gas constant, R = 8.314 J/molKMolar mass of oxygen gas = 32 g/mol.To determine the quantity of heat (Q) that is required to increase the temperature at constant volume:
First of all, we would find the number of moles of oxygen gas.
[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{192}{32}[/tex]
Number of moles = 6 moles.
At constant volume, the heat capacity for a diatomic gas is given by:
[tex]C_v = \frac{5}{2} R\\\\C_v =\frac{5}{2} \times 8.314[/tex]
Heat capacity = 20.785 J/molK.
At constant volume, the quantity of heat (Q) is given by this formula:
[tex]Q = nC_v \Delta T\\\\Q=6 \times 20.785 \times 145[/tex]
Quantity of heat (Q) = 18,082.95 Joules
Note: [tex]\Delta T[/tex] = 145°C = 145 K (since the difference is the same).
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What initial speed v is required if the blocks m1 =2.5 kg and m2=1.5 kg are to travel a distance d =7.0cm before coming to rest? Assume the coefficient of kinetic friction between m1 and the tabletop is ųk=0.21
Answer:
OPTRIMUM PRIDE URGH URGH URGH
Explanation:
AHHAAHAHAHAHA
Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula
KE = one half.mv2, where m is the mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of
0.8 m will be 4 m/s, and use this speed for each calculation.
Record your calculations in Table A of your Student Guide.
When the mass of the bottle is 0.125 kg, the KE is
✔ 1
kg m2/s2.
When the mass of the bottle is 0.250 kg, the KE is
✔ 2
kg m2/s2.
When the mass of the bottle is 0.375 kg, the KE is
✔ 3
kg m2/s2.
When the mass of the bottle is 0.500 kg, the KE is
✔ 4
kg m2/s2.
Answer included in Question
Answer:
kinetic energy is given as KE = (0.5) m v²given that : v = speed of the bottle in each case = 4 m/s when m = 0.125 kg KE = (0.5) m v² = (0.5) (0.125) (4)²
Explanation:
Answer:
1. 0.5 2. 2 3. 3.75 4. 5
Explanation:
Car 1 of mass m1 is waiting at a traffic light.
Car 1 is struck from behind by Car 2 of mass m2.
The two cars stick together after the collision.
Car 2 was traveling at v2i = 30.0 m/s before the collision.
What is the kinetic, in [J], of the system after the collision if m1 = 2500 kg and m2 = 1000 kg?
Answer:
Explanation:
Conservation of momentum
2500(0) + 1000(30) = (2500 + 1000)v
v = 8.57 m/s
KE = ½(2500 + 1000)8.57² = 128,571.428... = 128 KJ
The kinetic energy of the system after the collision would be 128.5 KJ.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
As given in the problem Car 1 of mass m1 is waiting at a traffic light.
Car 1 is struck from behind by Car 2 of mass m2. The two cars stick together after the collision. Car 2 was traveling at v2i = 30.0 m/s before the collision.
By using the conservation of the momentum,
2500(0) + 1000(30) = (2500 + 1000)v
v = 8.57 m/s
The final velocity of the system comes out to be 8.57 m/s.
The kinetic energy of the system after the collision,
KE =1/2×(2500 + 1000)×8.57² = 128,571.4
= 128.5 KJ
Thus, the kinetic energy of the system after the collision would be 128.5 KJ.
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