if p(q) = q^2 + 4q − 12,then what is p(−1)?

Answer:

a equals  and b equals 7

Step-by-step explanation

divide both side by 3 getting a+b=(28/3)

subtract b from both sides getting a=(28/3)-b

to solve for b its the same way so b=(28/3)-a

you can then substitute

Answer: The answer is D, the first ten amendments to the constitution.

Answer:

₹4000

Step-by-step explanation:

₹800/10 books

₹80/1 book

(₹80/1 book)*(50) = ₹4000

Answer:

D) Zero solutions

Step-by-step explanation:

9 - 5x = 8 - 3x - 1 - 2x

9 - 5x = 7 - 5x

9 = 7

Zero solutions

i took the quiz its D. Zero

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

[tex]\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}[/tex]

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

[tex]\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}[/tex]

Another identity is:

[tex]\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}[/tex]

Therefore:

[tex]\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}[/tex]

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

[tex]\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}[/tex]

Another identity:

[tex]\displaystyle \large{\sin^2x+\cos^2x=1}[/tex]

Therefore:

[tex]\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}[/tex]

Hence proved, this is proof by using identity helping to find the specific identity.

Step-by-step explanation:

$103.23

$100

$45.34

+_____

=248.57

Answer:

First, round $19.83 to make the mental math easier.  Then round the tip as well.  Then you can easily multiply the two rounded numbers to find the value.

Step-by-step explanation:

Answer:

what grade are u in so I know

The solution to the original equation will be -2 and -6

Given the function [tex](x + 3)^2 + (x + 3) - 2 = 0.[/tex]

If u = x + 3, the function in terms of "u" will be;

[tex]u^2+u-2=0[/tex]

Factorize the resulting equation as shown:

[tex]u^2+u-2=0\\u^2+2u-u-2=0\\u(u+2)-1(u+2)=0\\(u-1)(u+3) = 0\\u=1 \ and \ -3[/tex]

Since x + 3 = u

x = u - 3

If u  = 1

x = 1 - 3  = -2

If u  = -3

x = -3 - 3  = -6

Hence the solution to the original equation will be -2 and -6

Correct question:

Solve (x + 3)^2 + (x + 3) – 2 = 0. Let u = Rewrite the equation in terms of u. (u2 + 3) + u – 2 = 0 u2 + u – 2 = 0 (u2 + 9) + u – 2 = 0 u2 + u + 1 = 0 Factor the equation. What are the solutions of the original equation?

Learn more on factorization here: https://brainly.com/question/25829061

Answer:

-13h - 12

Step-by-step explanation:

3(-6h - 4) + 5h

-18h - 12 + 5h

-13h - 12

hope this helps! :D

have a miraculous day, and brainliest is immensely appreciated!! <3

Answer:

12, 63 and 21 sum to 96

.....

Answer:

[tex]\left(h,\:k\right)=\left(-\frac{3}{2},\:\frac{9}{4}\right),\:p=-\frac{1}{4}[/tex]

Step-by-step explanation:

[tex]x^2+3x+y=0[/tex]

[tex]4\left\bigg(-\frac{1}{4}\right)\left\bigg(y-\frac{9}{4}\right)=\left\bigg(x-\left\bigg(-\frac{3}{2}\right)\right)^2[/tex]

[tex]\bold{\mathrm{Therefore\:parabola\:properties\:are:}}[/tex]

[tex]\left(h,\:k\right)=\left(-\frac{3}{2},\:\frac{9}{4}\right),\:p=-\frac{1}{4}[/tex]

Answer:

$156.63

Step-by-step explanation:

223.75 - (223.75 x .3) = 156.625

Im good at math, what do you need help with?

Answer:

15km

Step-by-step explanation:

45mins = 25km

1 min =25/45

=5/9

27mins=5/9×27

=15km

Answer:

30

Step-by-step explanation:

4(3)^2 +(3*-2)

4*9-6=36-6=30

Answer:

30

Step-by-step explanation:

Substitute x = 3 and y = - 2 into the expression

4x² + xy

= 4(3)² + 3(- 2)

= 4(9) - 6

= 36 - 6

= 30

The value of x is [tex]\mathbf{8\dfrac{1}{3}}[/tex]

The objective of this question is to evaluate and determine the value of x. The fraction given in the question consists of algebraic expressions and, we need to solve it through following process;

∴

[tex]\mathbf{\dfrac{x-1}{3-x} + \dfrac{3}{4}=-1 }[/tex]

Collect like terms

[tex]\mathbf{(\dfrac{x-1}{3-x})=-1 -\dfrac{3}{4}}}[/tex]

[tex]\mathbf{(\dfrac{x-1}{3-x})=-(\dfrac{7}{4}})}[/tex]

-4(x - 1) = -7(3 -x)

-4x + 4 = -21 + 7x

4x -7x = -21 - 4

-3x = - 25

[tex]\mathbf{x= \dfrac{25}{3}}[/tex]

[tex]\mathbf{x= 8\dfrac{1}{3}}[/tex]

Learn more about evaluating fractions here:

https://brainly.com/question/12023322

Answer:

160 servings

Step-by-step explanation:

Step One:

1 gallon=16 cups

1 cup=10 servings

Step Two:

Multiply 16 by 10

which gives you your answer 160

Answer:

(i) 4000

(ii) $5.00

Step-by-step explanation:

Let no. of shares of Company A be X

Let share price of Company B on Day 7 be $y

Share price of Company B on Day 12 = $(y-0.50)

(i)

Consider Day 7:

4.60x - 2000y = 7400................ (1)

Consider Day 12:

4.80x - 5000(y-0.50) = -5800

4.80x - 5000y + 2500 = -5800

4.80x - 5000y = -8300............... (2)

(1)*2.5:

11.5x - 5000y = 18500................. (3)

(3)-(2):

11.5x - 4.80x - 5000y + 5000y = 18500 + 8300

6.70x = 26800

x = 4000

(ii)

Sub. x = 4000 into (1):

4.60(4000) - 2000y = 7400

-2000y = 7400 - 18400

-2000y = -11000

y = 5.5

Share price of Company B on Day 12

= 5.50 - 0.50

= $5.00

Answer:

  40.5°

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

In this triangle, that means ...

  tan(x°) = 4.7/5.5

The angle is found using the inverse function:

  x° = arctan(4.7/5.5) ≈ 40.5°

Answer:

Step-by-step explanation:

1. 3 cans cost 90 cents

3=0.90 & x=2.7

by ratio:

3/0.9 = x/2.7

0.9x=8.1

x= 9

So you can buy 9 cans for 2.7 dollars

2. 10 Juice cost 3 dollars

by ratio:

10/3 = 4/x

10x=12

x=1.2

so you will spend 1.2 dollars to buy 4 juice packs

Answer:

x = (−2 ± √−12)/2

Step-by-step explanation:

Using the quadratic formula (search it up if you don't know what it is, but it's basically the first thing in the pic):

Answer:

  1. 125 cm³; 88.8 cm³; 1650 cm³; 0.11 m³

  2. about 1.47 kg

  3. can't tell what the volume of 1 jar is

Step-by-step explanation:

The relationship between volume, mass, and density is ...

  mass = volume × density

Solving for volume, we find ...

  volume = mass ÷ density

__

(a) 50 g/(0.4 g/cm³) = 125 cm³

(b) 770 g/(8.67 g/cm³) ≈ 88.8 cm³ . . . (rounded to 3 significant figures)

(c) 4000 g/(2.42 g/cm³) ≈ 1650 cm³ . . . (rounded to 3 significant figures)

(d) 80 kg/(720 kg/m³) ≈ 0.11 m³ . . . (rounded to 2 significant figures)

_____

The volume of the cylinder is ...

  V = πr²h

  V = π(4 cm)²(15 cm) = 240π cm³ ≈ 754.0 cm³

Using the above relation, we find the mass to be ...

  mass = (754.0 cm³)(1.95 g/cm³) ≈ 1470 g = 1.47 kg

_____

We cannot tell if the volume of each jar is 360 liters, or if that is the total volume of all 6 jars. Either way, we suspect a units problem, as the jars would have to be extremely large and unusually thin relative to what we usually think of as a jar for jam (0.77 m diameter; 0.2 mm thick). The density of the jam would be roughly 10 times the density of air, if that is the volume of all 6 jars. The problem would be more sensible if the units of volume were mm³, and the given volume is that of one jar.

The mass of jam in one jar is (5400/6 -200) = 700 g. Divide that by what you think the volume of one jar is in cm³ to find the density in g/cm³. (For comparison, the density of air is about 0.0012 g/cm³.)

_____

Additional comment

We have rounded the answers to 2 or 3 significant figures. In most cases, this is more than would be justified by the number of significant figures in the given measurements. For purposes of ongoing calculations, it is useful to keep intermediate results to at least 1 more significant figure than required for the answer.

x+(-2) >3

open the bracket

x-2>3

collect the like terms by taking 2 to the other side

x>3+2

x>6