Answer:
C. 29.21 m³
Explanation:
Given the following data;
Initial volume, V1 = 3.4 m³Initial pressure, P1 = 18.9 atmFinal pressure, P2 = 2.2 atmTo find the final volume, we would use Boyle's law;
Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.
Mathematically, Boyles law is given by;
PV = K
[tex] P_{1}V_{1} = P_{2}V_{2} [/tex]
Making V2 the subject of formula, we have;
[tex] V_{2} = \frac {P_{1}V_{1}}{P_{2}} [/tex]
Substituting the values into the formula, we have;
[tex] V_{2} = \frac {18.9 * 3.4}{2.2} [/tex]
[tex] V_{2} = \frac {64.26}{2.2} [/tex]
Final volume, V2 = 29.21 m³
Calculate the weight of the object of mass
20kg. (g= 10 m/s^2)
Answer:
mass= 20kg
g=10m/s2
weight is F=mg
F=20×10
F=200N
Now you need to put handles on your cookware! You have five different options, including metals and nonmetals such as wood. Based on specific heat, which material would be the best choice? the material with the smallest specific heat the material with the greatest specific heat the material whose specific heat is farthest from the specific heat of the metal pan the material whose specific heat is closest to the specific heat of the metal pan.
Answer: B the material with the greatest specific heat
Explanation:
Just did the assignment
Answer:
B. The material with the greatest specific heat
Explanation:
A coin of mass 0.0050 kg is placed on a horizontal disk at a distance of 0.14 m from the center, as shown above. The coin doesn’t slip and the time it takes for the coin to make a complete revolution is 1.5 s.
A)The figure below shows the disk and coin as viewed from above. Draw and label vectors on the figure below to show instantaneous acceleration and linear velocity vectors for the pin when it is at the position shown below.
B)Determine the linear speed of the coin
C)The rate of rotation of the disk is gradually increased. The coefficient of stats if friction between the coin and the disk is 0.50. Determine the linear speed of the coin when it just begins to slip.
D)If the experiment in part c were repeated with a second, identical coin glued to the top of the first coin, how would this affect the answer to part c? Explain.
A) Figure attached below
B) The linear speed of the coin = 0.59 m/s
C) Linear speed as coin begins to slip = 0.83 m/s
D) The tangential speed will remain the same as seen in part C
Given data :
mass of coin = 0.0050 kg
Distance of coin from the center of disk = 0.14 m
Time to make a complete revolution = 1.5 s
A) Diagram showing the vectors on the figure is attached below
B) Determine the Linear speed of the coinLinear speed of coin = 2 * π * ( 0.14 ) / 1.5
= 0.59 m/s
C) Determine the linear speed of the coin when it just begins to slipgiven that: friction between coin and disk = 0.50
Friction becomes maximum when coin begins to slip
Maximum frictional force (Fmax) = uV
where V = mg
∴ Fmax = u*mg ---- ( 1 )centripetal force = [tex]\frac{mv^{2} }{r}[/tex] ---- ( 2 )Equating equations ( 1 ) and ( 2 ) to determine the linear speed ( v )
v² = u*r*g
∴ v = √(u*r*g ) = √( 0.5 * 0.14 * 9.8 )
= 0.83 m/s
D) If the experiment is repeated with a second coin glued to the top of the first coin the tangential speed will remain the same
Hence we can conclude that The linear speed of the coin = 0.59 m/s Linear speed as coin begins to slip = 0.83 m/s , The tangential speed will remain the same as seen in part C
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Drag each tile to the correct location.
Match each process to where it occurs in the carbon cycle.
Ingestion
fossilization
decomposition
combustion
light
energy
oxygen
carbon
dicadde
- sugar
minerak
water
All rights reserved
The order of the location of each process in the carbon cycle are as follows;
Ingestion → Decomposition → Fossilization → CombustionReasons:
Ingestion; During the ingestion process, the products of the direct Sunlight and photosynthesis, which
are energy rich chemical substances are ingested by herbivores.
Decomposition; The plants and animals die and undergo decomposition.
Fossilization; A long period the decomposed plants and animals manifest
into hard petrified materials, with their parts transformed to fossils.
Combustion; The remains of plants and animals, subjected to heat and
pressure due to compression, as when as bacteria decomposition that
removes several other elements, leaving a carbon and hydrogen rich
sludge that can be processed into fuel used for combustion. The
combustion process produces carbon dioxide which restarts the cycle.
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The parking brake on a 1200kg automobile has broken, and the vehicle has reached a momentum of 7800kg.m/s. What is the velocity of the vehicle?
Answer:
Velocity of the vehicle (v) = 6.5 m/s
Explanation:
Mass of automobile (m) = 1200 kg
Momentum of vehicle (p) = 7800 kg m/s
By using formula of momentum:
[tex] \rm p = mv \\ \rm 7800 = 1200 \times v \\ \rm v = \frac{7800}{1200} \\ \rm v = 6.5 \: m {s}^{ - 1} [/tex]
The density of air is 1.3 kg/m'. Calculate the mass of air in the room.
Answer:
The density of air is 1.3 kg/m'. Calculate the mass of air in the room.
Which particles within the atom are electricity charged?
a. Electrons only.
b. Neutrons only.
c. Protons only.
d. Electrons and protons.
e. Protons and neurons.
Answer:
I think b sorry if wrong
Explanation:
it b sorry if wrong
Answer:
Given that these particles make up atoms, they are often referred to as subatomic particles. There are three subatomic particles: protons, neutrons and electrons. Two of the subatomic particles have electrical charges: protons have a positive charge while electrons have a negative charge:
How can you decrease the amount of input force of a wheel and axle?
Explanation:
hmm by the increasing the size of wheel and decreasing axle
An object is moving with a constant velocity of 311 m/s. How long will it take it to travel 9000 m?
[tex]\text{Given that,}\\\\\text{Velocity, v= 311 m s}^{-1}\\\\\text{Displacement, s = 9000 m}\\\\\text{Since velocity is constant,}\\\\s=vt\\\\\implies t =\dfrac{s}v = \dfrac{9000}{311} = 28.94 ~ \text{sec}.[/tex]
A car traveling in a northeasterly direction at a rate of 50 km/h represents which of the following?
A.
deceleration
B.
velocity
C.
speed
D.
acceleration
Answer:
c.
Explanation:
Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector.
Formula
s = \frac{d}{t}
s = speed
d = distance traveled
t = time elapsed
What did Ernest Rutherford expect to happen when he aimed a beam of particles at a thin gold foil
Answer:
he expected a fire to happen I think
Answer:
When Ernest Rutherford aimed a beam of particles at a thin gold foil he expected that the particles would be deflected slightly after passing through the foil.
Explanation:
hope it helped
In the fermentation of alcohol, sugars in the liquid are converted to alcohol and bubbles are formed on the surface of the liquids. Which gas forms the bubbles?
Answer:
I believe it is Carbon Dioxide because after yeast breaks down the glucose (sugar) molecule, it forms/creates CO2 and Ethanol. (though it might be Ethanol that creates the bubbles) I am not quite sure if this is correct, but I hope it helps! :,)
Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a factor of five and the mass of object 2 is multiplied by a factor of two, what will the new gravitational force be between the objects?
A. F2
B. 1/2F
C. 0.1F
D. 2F/5
E. 5F
J. 10F
Please help will mark brainliest
If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is
F' = G (5m₁) (2m₂) / d²
F' = 10 Gm₁m₂ / d²
but this is really just F' = 10F. So J is the correct choice.
Hi there!
Using Newton's Law of Universal Gravitation:
[tex]\large\boxed{F_g = G\frac{m_1m_2}{d^2}}[/tex]
Fg = Force of gravity (N)
G = Gravitational Constant
m₁ = mass of object 1 (kg)
m₂ = mass of object 2 (kg)
d = distance between the objects (m)
There is a direct relationship between the masses of the objects and the resulting force of gravity, so we can plug new values in:
[tex]F_g = G\frac{5m_12m_2}{d^2}} = 10G\frac{m_1m_2}{d^2}} = 10F_g[/tex]
Thus, the correct answer is J. 10Fg.
How charged objects can affect other objects without touching them. ?
A 2-year-old child is prescribed cyclosporine. The parent says the child doesn't like taking the liquid medication. Which statement by the nurse is most appropriate
Given what we know, we can say that the most appropriate response by the nurse is to indicate that the parent should dilute the medicine in chocolate milk in order to make it more palatable.
Why is this an appropriate response?This is an appropriate response given that it offers a possible solution for the problem.The nurse is first showing that the problem presented by the parent is being taken seriously.Then, without criticizing the parent, a healthy and viable solution is offered.Therefore, we can confirm that since this response is a calm and thought-out response that respects the patient and offers a viable solution, it can be considered the most appropriate statement by the nurse.
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What two things related to sedimentary rocks do you see at the Grand Canyon ?
Answer:
sandstone and mudstone
Explanation:
Why does calcium chloride have a greater affect on colligative properties verses sodium
chloride?
Answer:
Calcium chloride is very effective, working at temperatures below most products, and is significantly more effective than sodium chloride because of its ability to extract moisture from its surroundings and to cause exothermic or heat generating reactions.
Explanation:
Hope this helps
19. A beach ball is rolling in a straight line toward you at a speed of 9 m/sec. Its momentum is 3 kg'm/sec.
What is the mass of the beach ball? moss - 0.33
aroto from 10mle to speed of 14 m/s The mass of the bicycle
The mass of the beach ball is 0.33 kg
From the question,
We are to determine the mass of the beach ball.
Using the formula
ρ = mv
Where ρ is the momentum
m is the mass
and v is the velocity
From the given information,
ρ = 3 kg m/sec
v = 9 m/sec
Putting the parameters into the formula, we get
3 = m × 9
∴ m = 3 ÷ 9
m = 0.33 kg
Hence, the mass of the beach ball is 0.33 kg
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A well chosen lifetime activity is something that should hold a person's interest for a long time.
Please select the best answer from the choices provided.
T
F
Answer:
true
Explanation:
as long as you are interested, you are happy
Since lifetime activities are done for a lifetime, it is true that a well chosen lifetime activity is something that should hold a person's interest for a long time.
What is a lifetime activity?A lifetime activity is an activity which an individual decides to do for a lifetime.
A lifetime activity should be able to hold a person's interest for a long time, else it could lead to frustration.
Some lifetime activities include:
choice of careersmarriage family relationshipsTherefore, it is true that a well chosen lifetime activity is something that should hold a person's interest for a long time.
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The change in the momentum of an object is represented by the following formula:
Impulse = (Force)(time) = change in momentum
I = F • t = pfinal – pinitial
A 1.0 kg rabbit traveling east at 10 m/s spots a predator, turns around, and then begins to travel west at 21 m/s.
What is the change in momentum of the rabbit, and what is another term for this concept?
The rabbits change of momentum is
A. 31 kg•m/s east
B. 31 kg•m/s west
C. 15.5 kg•m/s, west
D. 15.5 kg•m/s, east
This value can also be referred to as
E. Collisions
F. Potential energy
G. Kinetic energy
H. Impulse
Please help will mark brainliest
Hi there!
Recall that:
Change in momentum = mass × change in velocity
Or:
Δp = mΔv = m(vf - vi)
Plug in the given values. We can assign east to be positive and west to be negative in this instance (Velocity is a vector with direction).
Thus:
Δp = (1)(-21 - 10) = -31 kgm/s OR 31 kgm/s WEST.
The correct answer is B.
Change in momentum is EQUIVALENT to the quantity of IMPULSE.
The correct answer is H.
Physicists call any change in energy an impulse true or false?
A wave traveling at 230 m/sec has a wavelength of 2.1 meters. What is the frequency of this wave?
Answer:
109.52 HzExplanation:
The frequency of the wave when given it's velocity and wavelength only can be found by using the formula
[tex]f = \frac{c}{ \lambda} \\ [/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in meters
From the question we have
c = 230 m/s
[tex] \lambda[/tex] = 2.1 m
[tex]f = \frac{230}{2.1} = 109.523809... \\ [/tex]
We have the final answer as
109.52 HzHope this helps you
Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help
guide the content of your paragraph.
1. According to your data, was your hypothesis for each experiment correct? (Be sure to refer to your data and graphs
when answering this question.)
2. Summarize the conclusions that you can draw from this experiment. Use the questions above to gulde your ideas.
3. Summarize any difficulties or problems you had in performing the experiment that might have affected the results.
Describe how you might change the procedure to avoid these problems.
4. Give at least one more example from real life where the principles demonstrated in this lab are evident.
Answer:
Sample answer: part 1:
What was your hypothesis?
This is what you wanted to prove or study with the experiment. Reading the question I can see that the experiment seems to study the relation between the viscosity of honey and the temperature, so the hypothesis may be something like:
"The viscosity of honey decreases as temperature increases".
According to your data, do you think your hypothesis was correct?
Here you need to see your experimental data, probably, you found that yes, as you increase the temperature the viscosity decreases.
The last thing we need to do here is to summarize difficulties and problems that you had in the experiment, and propose how you could solve them in order to have a better experiment.
Obviously, this depends on how you performed the experiment, but for example, if you saw that the temperature of the honey increased too fast, you could say:
"one problem was that the temperature of the honey increased too fast"
And one way to solve that would be submerging the honey in a water bath so the temperature increases a bit slower.
part 2:
Viscosity depends strongly on temperature, but this relation depends also on the given material.
Generally, we would see that the viscosity decays exponentially as the temperature increases.
So for the first question:
What effect did the temperature have on the viscosity of the honey?
You should have seen that, as the temperature increased, the viscosity decreased.
Now, we need to give some practical examples where knowledge of viscosity is important.
The first one is for cleaning: We know that if we increase the temperature, the viscosity decreases. Thus if we have some object with some viscous thing on it, increasing the temperature will cause it to be easier to clean.
Another example is to store/transport viscous things, for example, honey, it is actually a lot easier to pour honey in bottles if you first heat it a little, so it becomes less viscous.
So there you have two examples where knowing about viscosity (and how it relates to temperature) may be important.
Explanation:
which term is defined by the interaction between two charged particles?
Answer: Electromagnetism
The term which is defined by the interaction between two charged particles is known as electromagnetism.
What is an electromagnet?The study of charge and the fields and forces it generates is known as electromagnetism. Electromagnetism has two components: electricity and magnetism.
The special theory of relativity, developed by Albert Einstein in 1905, proved beyond a shadow of a doubt that both are components of the same reality. But in reality, magnetic and electric forces behave very differently and are modeled by various equations. Electric charges can produce forces whether they are stationary or moving. On the other hand, magnetic forces are only created by moving charges and only affect charges that are moving.
Thus, the term is known as electromagnetism.
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What coefficient is needed in front of H2O to balance the equation below?
Let a, b, c be the coefficients in the balanced reaction,
a P₄O₁₀ + b H₂O ⇒ c H₃PO₄
Count the number of each atom on either side of the reaction:
• P : 4a = c
• O : 10a + b = 4c
• H : 2b = 3c
Suppose a = 1. Then from the first equation,
c = 4•1 ⇒ c = 4
and from the third equation,
2b = 3•4 = 12 ⇒ b = 6
The third equation is also satisfied:
10a + b = 4c ⇒ 10•1 + 6 = 4•4 ⇒ 16 = 16
So, the balanced reaction is
P₄O₁₀ + 6 H₂O ⇒ 4 H₃PO₄
which makes D the correct answer.
[tex] \huge \rm༆ question ༄[/tex]
Calculus proof of second equation of motion ~
Newton's second equation of motion :-
S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]
This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.
So let's see what pieces of information (bundles of equations) do we have with us, initially.
We have, a very primary equation with us,
dS/dt = v… (I)
(Considering motion in a straight line only)
And we also have the equation
dv/dt = a…(II)
Simply replacing the v in eqn (II) by eqn (I), we find
d2S/dt^2 = a…(III)
This is what we need to solve. It's easy.
You know,
d2S/dt^2 = d/dt(dS/dt) = a
⟹ dS/dt = ∫adt = at+c1
Since, dS/dt is the velocity of the particle,
Therefore, at t = 0, dS/dt|t = 0 = u
⟹ u = a∗0 + c1 = c1
⟹ c1 = u
Therefore, dS/dt = u + at
Thus, S = ∫(udt + atdt)
⟹ S = ut + 1/2at^2 +c^2
If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0
This makes S = S0 +ut + 1/2at^2
Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),
We get
S = ut + 1/2at^2
Hope it helps :)
A racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction). It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/a to the left (-x direction).what is the magnitude of the racquetball's change in momentum?
The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.
Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).
mass m = 42g = 42/1000 = 0.042kg
initial velocity before collision u = 7 m/s
It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,
velocity after collision v = 7 m/s
To calculate the magnitude of the racquetball's change in momentum, we will use the formula below
Change in momentum = Mv - Mu
Since momentum is a vector quantity, we will consider the direction.
Change in momentum = 0.042 x 7 - ( 0.042 x - 7)
Change in momentum = 0.294 + 0.294
Change in momentum = 0.588 kgm/s
Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.
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Helppppp 30pointsssssssssssssssssss
Answer:
so sorry i don't know the answer so sorry
Why would poor clusters of galaxies be more likely to have irregular shapes then rich
clusters
These Milky Way companion galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small Magellanic clouds (left and right, respectively).
What clusters of galaxies likely to have irregular shapes?In comparison to a rich cluster, the poor cluster typically has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large Magellanic clouds are the two most well-known examples of atypical galaxies.
When two galaxies collide, irregular galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the centre of a massive spiral galaxy.
Therefore, Rich clusters are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its members strongly because of its low bulk.
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It requires a 70.4 N force (parallel to the inclined plane) to pull a 5.86 kg box up a 58.1° inclined plane with a rope at a constant speed. (a) What is the coefficient of kinetic friction between the inclined plane and the box?
(b) If the rope were to break, what acceleration would the box experience as it slid down the ramp?
Answer:
0.667; 4.965
Explanation:
Look at the picture I attached for the force analysis.
a) The coefficient=Friction/Normal Force. Because it's at constant speed, the force of friction + mgsin58.1° (because it's on an inclined plane and has split forces) is equal to the applied force (70.4N). Normal force is not equal to weight force though, because the box is on an inclined plane; it's equal to mgcos58.1°.
b) If it were to break, then the box no longer has an applied force, and the direction of friction has changed to up the inclined plane. F=m/a, so acceleration = mgsin58.1°- Friction/mass
