Answer:
a) 75
b) 4.33
c) 0.75
d) [tex]3.2 \times 10^{-13}[/tex] probability that no one in a simple random sample of 100 young adults owns a landline
e) [tex]6.2 \times 10^{-61}[/tex] probability that everyone in a simple random sample of 100 young adults owns a landline.
f) Binomial, with [tex]n = 100, p = 0.75[/tex]
g) [tex]4.5 \times 10^{-8}[/tex] probability that exactly half the young adults in a simple random sample of 100 do not own a landline.
Step-by-step explanation:
For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.
This means that [tex]p = 0.75[/tex]
(a) On average, how many young adults do not own a landline in a random sample of 100?
Sample of 100, so [tex]n = 100[/tex]
[tex]E(X) = np = 100(0.75) = 75[/tex]
(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?
[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33[/tex]
(c) What is the proportion of young adults who do not own a landline?
The estimation, of 75% = 0.75.
(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?
This is P(X = 100), that is, all do not own. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}[/tex]
[tex]3.2 \times 10^{-13}[/tex] probability that no one in a simple random sample of 100 young adults owns a landline.
(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?
This is P(X = 0), that is, all own. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}[/tex]
[tex]6.2 \times 10^{-61}[/tex] probability that everyone in a simple random sample of 100 young adults owns a landline.
(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?
Binomial, with [tex]n = 100, p = 0.75[/tex]
(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?
This is P(X = 50). So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}[/tex]
[tex]4.5 \times 10^{-8}[/tex] probability that exactly half the young adults in a simple random sample of 100 do not own a landline.
35 POINTS HELP in the figure above the circle has center O and radius 6 what is the length of arc acb
Answer:
9.425 or 3π
Step-by-step explanation:
arc length = 2πr(θ/360)
The angle is 90˚ as indicated by the square symbol.
ABC = 2π6(90/360) = 9.425 or 3π
1. Given the line of best fit y = 6.2x + 13, what is the residual for the point (10,80)? (1 pt)
A. 75
B. 5
C. 499
D. 55
Answer:
c
Step-by-step explanation:
The residual for the point line (10,80) is option A 75. at the given line which best fits y = 6.2x + 13.
What is a straight line graph?The graph follows a straight line equation shows a straight line graph.
equation of a straight line is y=mx+cy represents vertical line y-axis.x represents the horizontal line x-axis. m is the slope of the lineslope(m)=tan∅=y axis/x axis.
c represents y-intercepts (it is the point at which the line cuts on the y-axis)Straight line graphs show a linear relationship between the x and y values.
solving the equation:-
y = 6.2x + 13
putting value of X = 10
Y = 6.2 * 10 + 13
Y = 62 + 13
Y = 75
Hence the line best fit = 75.
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Please find the missing ? Explanation need it
Answer:
the answer is 3.162
Step-by-step explanation:
the figure below is made up of a square, a quadrant and a semicircle. the length of the square is 12cm. find the area of the shaded parts.
Answer:
P=2pi×r
P=2×12pi=24pi
24pi÷4=6pi
6pi÷2=3pi
p=2×6×pi
p=12pi
12pi÷2=6pi
permiter=3pi+6pi+12=40.27
that is for part a
A composite figure is made up of one simple figure.
True or
False
Answer:
False
Step-by-step explanation:
A composite figure would be any irregular shapes and can be made up of multiple shapes
SAT scores are normally distributed with a mean of 1,500 and a standard deviation of 300. An administrator at a college is interested in estimating the average SAT score of first-year students. If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample? Make sure to give a whole number answer.
Answer:
The administrator should sample 968 students.
Step-by-step explanation:
We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.88}{2} = 0.06[/tex]
Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].
That is z with a p-value of [tex]1 - 0.06 = 0.94[/tex], so Z = 1.555.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
Standard deviation of 300.
This means that [tex]n = 300[/tex]
If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample?
This is n for which M = 15. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]15 = 1.555\frac{300}{\sqrt{n}}[/tex]
[tex]15\sqrt{n} = 300*1.555[/tex]
Dividing both sides by 15
[tex]\sqrt{n} = 20*1.555[/tex]
[tex](\sqrt{n})^2 = (20*1.555)^2[/tex]
[tex]n = 967.2[/tex]
Rounding up:
The administrator should sample 968 students.
The average score of all golfers for a particular course has a mean of 65 and a standard deviation of 4.5 . Suppose 81 golfers played the course today. Find the probability that the average score of the golfers exceeded 66 . Round to four decimal places.
Answer:
Answer:
The probability that the average score of the 49 golfers exceeded 62 is 0.3897
Step-by-step explanation:
A physicist examines 10 water samples for iron concentration. The mean iron concentration for the sample data is 0.711 cc/cubic meter with a standard deviation of 0.0816. Determine the 90% confidence interval for the population mean iron concentration. Assume the population is approximately normal.
Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Step 2 of 2: Construct the 90% confidence interval. Round your answer to three decimal places. Lower endpoint? Upper endpoint?
Answer:
Poggers
Step-by-step explanation:
PLEASE HELP LOOK AT PICTURE
Find the missing length indicated
Answer:
x = 960
Step-by-step explanation:
x=√{576×(576+1024)}
or, x = √(576×1600)
or, x = √576×√1600
or, x = 24×40
or, x = 960
Answered by GAUTHMATH
Answer:
Step-by-step explanation:
I need help answering this question asap
Answer:
Step-by-step explanation:
Present value takes ____________.
A. Compounding rate.
B. Discounting rate.
C. Inflation rate.
D. Deflation rate
Marnie just finished setting herself up at a cozy spot at the airport. Her laptop is ready, phone within reach, and her papers are organized, but now, she's hungry. What should she do? a) Take her phone and laptop with her to get something to eat b) Leave her stuff, but get a snack really quickly O c) Put her coat over her laptop to hide it and go get a snack O d) Ask the person next to her to watch her stuff
Answer:
a) someone will steal her stuff in any other situation even if a stranger watches it
Round to the nearest whole number.
6.4
Answer:
6
Step-by-step explanation:
Therefore, the number 6.4 rounded to the nearest whole number is 6. * If the number you are rounding off is followed by 0,1,2,3,4, round the number down. To find 6.4 rounded to the nearest whole number.
Please Mark me brainliest
In an assembly-line production of industrial robots, gearbox assemblies can be installed in one minute each if holes have been properly drilled in the boxes and in ten minutes if the holes must be redrilled. Twenty-four gearboxes are in stock, 6 with improperly drilled holes. Five gearboxes must be selected from the 24 that are available for installation in the next five robots. (Round your answers to four decimal places.) (a) Find the probability that all 5 gearboxes will fit properly. (b) Find the mean, variance, and standard deviation of the time it takes to install these 5 gearboxes.
Answer:
The right answer is:
(a) 0.1456
(b) 18.125, 69.1202, 8.3139
Step-by-step explanation:
Given:
N = 24
n = 5
r = 7
The improperly drilled gearboxes "X".
then,
⇒ [tex]P(X) = \frac{\binom{7}{x} \binom {17}{5-x}}{\binom{24}{5}}[/tex]
(a)
P (all gearboxes fit properly) = [tex]P(x=0)[/tex]
= [tex]\frac{\binom{7}{0} \binom{17}{5}}{\binom{24}{5}}[/tex]
= [tex]0.1456[/tex]
(b)
According to the question,
[tex]X = 91+5[/tex]
Mean will be:
⇒ [tex]\mu = E(x)[/tex]
[tex]=E(91+5)[/tex]
[tex]=9E(1)+5[/tex]
[tex]=9.\frac{nr}{N}+5[/tex]
[tex]=9.\frac{5.7}{24} +5[/tex]
[tex]=18.125[/tex]
Variance will be:
⇒ [tex]\sigma^2=Var(X)[/tex]
[tex]=V(9Y+5)[/tex]
[tex]=81.V(Y)[/tex]
[tex]=81.n.\frac{r}{N}.\frac{N-r}{N}.\frac{N-n}{N-1}[/tex]
[tex]=81.5.\frac{7}{24}.\frac{24-7}{24}.\frac{24-5}{24-1}[/tex]
[tex]=69.1202[/tex]
Standard deviation will be:
⇒ [tex]\sigma = \sqrt{69.1202}[/tex]
[tex]=8.3139[/tex]
6( n - 2) in word form please c:
Answer:
six in parenthesis n minus two
Step-by-step explanation:
2 ways could be:
A. N minus two then multiply by six
B. Six times parentheses n minus two end parentheses
Determine whether or not the given procedure results in a binomial distribution. If not, identify which condition is not met. Spinning an American roulette wheel 8282 times and recording the number the ball lands on.
Answer:
No, binomial distribution cannot be applied.
Step-by-step explanation:
We known that a Binomial Distribution depends on provided experiment , a binomial distribution have only 2 outcomes. For example, when we flip a coin in the air, then the possible outcomes are Head and Tail.
But in the context, an American roulette wheel has [tex]37[/tex] outcomes. It means when we spin the American Roulette wheel, ball may lend on any of the numbers between 0 to 36. So there are more than [tex]2[/tex] outcomes.
Therefore, binomial distribution can not be applied here.
I need help with C,D,E,F,G thank you
Answer:
D = 120 Degrees , E : x = 14 , F: <JHK = 21, G: Summplementary Angle is 96 Degrees
Step-by-step explanation:
4X+2X = 180
6X=180
X=30
<ABD = 4X = 4(30) = 120
Which of the following statements best describes the effect of replacing the graph of y = f(x) with the graph of y = f(x) − 11? The graph of y = f(x) will shift up 11 units. The graph of y = f(x) will shift right 11 units. The graph of y = f(x) will shift left 11 units. The graph of y = f(x) will shift down 11 units.
Answer:
The graph of y = f(x) will shift down 11 units
Step-by-step explanation:
is the sequence 1/6, 1/2, 3/2,9/2 arithmetic, or geometric
Answer:
geometric
Step-by-step explanation:
Ivan caught a total of 7 2/5 pounds of fish one day. Of the fish caught, 4 5/8 pounds were sea bass and the rest were mackerel. He gave away 1 7/8 pounds of mackerel. How many pounds of mackerel did he have left.
Given:
Total fish (Sea bass and mackerel) = [tex]7\dfrac{2}{5}[/tex] pounds
Sea bass = [tex]4\dfrac{5}{8}[/tex] pounds
He gave away [tex]1\dfrac{7}{8}[/tex] pounds of mackerel.
To find:
The remaining mackerel.
Solution:
We know that,
Mackerel = Total fish - Sea bass
[tex]\text{Mackerel}=7\dfrac{2}{5}-4\dfrac{5}{8}[/tex]
[tex]\text{Mackerel}=\dfrac{37}{5}-\dfrac{37}{8}[/tex]
[tex]\text{Mackerel}=\dfrac{296-185}{40}[/tex]
[tex]\text{Mackerel}=\dfrac{111}{40}[/tex]
He gave away [tex]1\dfrac{7}{8}[/tex] pounds of mackerel. So, the remaining mackerel is:
[tex]\text{Remaining Mackerel}=\dfrac{111}{40}-1\dfrac{7}{8}[/tex]
[tex]\text{Remaining Mackerel}=\dfrac{111}{40}-\dfrac{15}{8}[/tex]
[tex]\text{Remaining Mackerel}=\dfrac{111-75}{40}[/tex]
[tex]\text{Remaining Mackerel}=\dfrac{36}{40}[/tex]
[tex]\text{Remaining Mackerel}=\dfrac{9}{10}[/tex]
Therefore, the remaining Mackerel is [tex]\dfrac{9}{10}[/tex] pounds or 0.9 pounds.
Answer:
The amount of Mackerel left is 9/10.
Step-by-step explanation:
total fish = 7 2/5 pounds
sea bass = 4 5/8
The amount of mackerel =
[tex]7\frac{2}{5}-4\frac{5}{8}\\\\=\frac{37}{5}-\frac{37}{8}\\\\=\frac{296-185}{40}\\\\=2 \frac{31}{40}[/tex]
Mackerel left =
[tex]2 \frac{31}{40}-1\frac{7}{8}\\\\= \frac{111}{40}-\frac{15}{8}\\\\=\frac{111-75}{40}\\\\=\frac{36}{40}\\\\=\frac{9}{10}[/tex]
if you run 250 ft of cable and lose rate 3.6 dB how much rate you lose at 100 ft
Answer:
99
Step-by-step explanation:
99
Joe nas to take two quizzes tomorrow. He nas only enough time to study one of them. • The science quiz has 7 true-or-false questions. • The English quiz has 3 multiple-choice questions. Joe calculates the probability that he will get each question correct by guessing. ?
Answer:
C.
Step-by-step explanation:
Science questions are T/F. That's .5 or [tex]\frac{1}{2}[/tex] chance to get it right.
7 questions. Each with a [tex]\frac{1}{2}[/tex].
That's [tex](\frac{1}{2})^{7}[/tex]
[tex](\frac{1}{2})^{7}[/tex] = [tex]\frac{1}{128}[/tex] = .0078 = .008 rounded
English questions are multiple choice. 4 choices. That's .25 or [tex]\frac{1}{4}[/tex]
3 questions. Each [tex]\frac{1}{4}[/tex]
That's [tex](\frac{1}{4})^{3}[/tex]
[tex](\frac{1}{4})^{3}[/tex] = [tex]\frac{1}{64}[/tex] = .0156 = .016 rounded
The probability of getting all questions correct is 0.004 which is lower than for science (0.016).
Science questions are said to have a 6 out of 6 correct answer range and a 0.5 chance of being answered properly.
So, P(6) = 0.5⁶
P(6) = 0.016
We are informed that there are 4 out of 4 correct answers for English, with a 0.25 chance of getting it right.
Thus; P(4) = 0.25⁴ = 0.004
Thus, we conclude that they will have to study English.
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Social media is popular around the world. Statista provides estimate of the number of social media users in various countries in as well as the projections for . Assume that the results for surveys in the United Kingdom, China, Russia, and the United States are as follows.
Use Social Media United Kingdom China Russia United States
Yes 480 215 343 640
No 320 285 357 360
Required:
a. Conduct a hypothesis test to determine whether the proportion of adults using social media is equal for all four countries. What is the p-value? Using a .05 level of significance, what is your conclusion?
b. What are the sample proportions for each of the four countries? Which country has the largest proportion of adults using social media?
c. Using a 0.05 level of significance, conduct multiple pairwise comparison tests among the four countries. What is your conclusion?
Answer:
Kindly check explanation
Step-by-step explanation:
The data table :
Use of SM _UK _China _ Russia _US _ col total
Yes ______480 __215 ___343 __640 _ 1678
No _______320 _ 285 ___357__ 360 _ 1322
Row Total__ 800 _500 __ 700_ 1000_ 3000
H0 : p1 = p2 = p3 = p4
H1 : p1 ≠ p2 ≠ p3 ≠ p4
Test statistic :
χ² = Σ(observed - Expected)² / Expected
Expected value of each cell = (Row total * column total) / N
N = grand total
Expected Values:
447.467 _279.667 _ 391.533 _ 559.333
352.533 _ 220.333 _ 308.467 _ 440.667
χ²=(2.36536+14.9527+6.01605+11.6337+3.00232 18.9793+7.63611+14.7665) = 79.352
Degree of freedom, df = (row-1)*(column-1) = (2 - 1) * (4 - 1) = 1 * 3 = 3
Using the Pvalue from Chisquare calculator :
Pvalue(79.352, 3) = 0.00000000001
Decision region :
Reject H0 ; If Pvalue < α
α = 0.05
Since 0.000000001 < 0.05 ; Reject H0 and conclude that not all population proportion are equal.
Sample proportion :
Phat = number of yes, x / total
For UK, Phat = 480/800 = 0.6
For China , Phat = 215/500 = 0.43
For Russia , Phat = 343/700 = 0.49
For US, Phat = 640/1000 = 0.64
Suppose the variable x is represented by a standard normal distribution. What is the probability of x > 0.3 ? Please specify your answer in decimal terms and round your answer to the nearest hundredth (e.g., enter 12 percent as 0.12).
Answer: 0.38
Step-by-step explanation:
Since the variable x is represented by a standard normal distribution, the probability of x > 0.3 will be calculated thus:
P(x > 0.3)
Then, we will use a standard normal table
P(z > 0.3)
= 1 - p(z < 0.3)
= 1 - 0.62
= 0.38
Therefore, p(x > 0.3) = 0.38
The probability of x > 0.3 is 0.38.
The five number summary of a dataset is given as
0, 4, 12, 14, 20
An observation is considered an outlier if it is below _______
An observation is considered an outlier if it is above _______
The five number summary of a dataset is given as
2, 8, 14, 18, 20
An observation is considered an outlier if it is below _______
An observation is considered an outlier if it is above _______
.
.
Given:
The five number summary of two data sets are given as:
a) 0, 4, 12, 14, 20
b) 2, 8, 14, 18, 20
To find:
The range for the outliers.
Solution:
We know that,
An observation is considered an outlier if it is below [tex]Q_1-1.5(IQR)[/tex]
An observation is considered an outlier if it is above [tex]Q_3+1.5(IQR)[/tex]
Where, IQR is the interquartile range and [tex]IQR=Q_3-Q_1[/tex].
The five number summary of two data sets are given as:
0, 4, 12, 14, 20
Here, [tex]Q_1=4[/tex] and [tex]Q_3=14[/tex].
Now,
[tex]IQR=14-4[/tex]
[tex]IQR=10[/tex]
The range for the outliers is:
[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-1.5(10),14+1.5(10)][/tex]
[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-15,14+15][/tex]
[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-11,29][/tex]
An observation is considered an outlier if it is below -11.
An observation is considered an outlier if it is above 29.
The five number summary of two data sets are given as:
2, 8, 14, 18, 20
Here, [tex]Q_1=8[/tex] and [tex]Q_3=18[/tex].
Now,
[tex]IQR=18-8[/tex]
[tex]IQR=10[/tex]
The range for the outliers is:
[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-1.5(10),18+1.5(10)][/tex]
[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-15,18+15][/tex]
[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-7,33][/tex]
An observation is considered an outlier if it is below -7.
An observation is considered an outlier if it is above 33.
exchange rate for rand is 7 for $1 how any dollars would u receive is u exchange 21 rand
Answer:
$3
Step-by-step explanation:
7 rands for $1
7×3=21
21 rands for $3
Answer:
$3
Step-by-step explanation:
7 rand = 1 dollar
Divide both sides by 7 rand.
1 = (1 dollar)/(7 rand)
Notice that the fraction (1 dollar)/(7 rand) equals 1, so multiplying by it will not change the amount, just the units.
21 rand * (1 dollar)/(7 rand) =
= 21/7 dollar
= 3 dollar = $3
2x+3=60 thì x băng bao nhieu
Answer:
x=57/2
Step-by-step explanation:
2x+3=60
<=> 2x=57
=> x=57/2
Simplify |3 − 11| − (15 ÷ 3 + 2) 2
Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly targeted and destroyed, what is the probability that no more than 11 vessel transporting nuclear weapons was destroyed
Answer:
0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.
Step-by-step explanation:
The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
Fleet of 18 means that [tex]N = 18[/tex]
9 are carrying nuclear weapons, which means that [tex]k = 9[/tex]
9 are destroyed, which means that [tex]n = 9[/tex]
What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?
This is:
[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]
In which
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021[/tex]
[tex]P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666[/tex]
Then
[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687[/tex]
0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.
