Suppose a car is traveling at 22.8 m/s, and the driver sees a traffic light turn red. After 0.404 s has elapsed (the reaction time), the driver applies the brakes, and the car decelerates at 9.00 m/s2. What is the stopping distance of the car, as measured from the point where the driver first notices the red light?

Answers

Answer 1

Answer:

38.09 m

Explanation:

We'll begin by calculating the distance travelled by the car during the reaction time. This can be obtained as follow:

Reaction time (tᵣ) = 0.404 s

Initial velocity (u) = 22.8 m/s,

Distance travelled during the reaction time (sᵣ) =?

sᵣ = utᵣ

sᵣ = 22.8 × 0.404

sᵣ = 9.21 m

Next, we shall determine the distance travelled by the car when the brake was applied. This can be obtained as follow:

Initial velocity (u) = 22.8 m/s

Acceleration (a) = –9 m/s² (since the car is decelerating)

Final velocity (v) = 0 m/s

Distance travelled when the brake was applied (s₆) =?

v² = u² + 2as₆

0² = 22.8² + (2 × –9 × s₆)

0 = 519.84 – 18s₆

Collect like terms

0 – 519.84 = –18s₆

–519.84 = –18s₆

Divide both side by –18

s₆ = –519.84 / –18

s₆ = 28.88 m

Finally, we shall determine the stopping distance of the car, as measured from the point where the driver first notices the red light. This can be obtained as follow:

Distance travelled during the reaction time (sᵣ) = 9.21 m

Distance travelled when the brake was applied (s₆) = 28.88 m

Stopping distance =?

Stopping distance = sᵣ + s₆

Stopping distance = 9.21 + 28.88

Stopping distance = 38.09 m


Related Questions

Jojo and Roro begin side-by-side at one end of the playground. At the same moment, they begin to move toward the other end of the playground, Jojo at a constant velocity of 3.0 m/s, Roro at a constant velocity of 2.0 m/s. Sometime during her trip, Roro stops to rest for 2.0 s, but then starts again at her original constant speed. When Jojo reaches the end of the playground, she is 10 m ahead of Roro.
(a) For how much time did Roro move?
(b) How far did Roro move? (Set it up, good notation, equations in symbols first, etc.)

Answers

Answer:

Roro's total travel time = 6 seconds out of which he rested for 2 seconds

Distance covered by Roro = 8 meters

Explanation:

Given that :

Jojo:

Constant velocity, v = 3m/s

Travel time = h

Roro:

Constant velocity, v = 2m/s

Roro rest for 2 seconds

Travel time = h - 2

Recall:

Distance = speed * time

Distance covered by Jojo:

3 * h = 3h

At this distance ;

Roro's distance = 3h - 10

Using formula :

Roro's distance = 2 * (h - 2)

Hence,

2(h - 2) = 3h - 10

2h - 4 = 3h - 10

2h - 3h = - 10 + 4

-h = - 6

h = 6

Hence, Roro moved for :

h - 2 = 6 - 2 = 4seconds

Distance moved by Roro:

2(h - 2) = 2(6 - 2) = 2(4) = 8 meters

The nearest neighbor interaction force is of magnitude 481 nanoNewtons, e.g., the magnitude of the force of the leftmost electron on the proton, or the magnitude of the force of any of the three on its nearest neighbor electron. Calculate the size of the net force on the leftmost proton.

Answers

Answer:

 F = 120.25 10⁻⁹  N

Explanation:

In this exercise, the force between the closest neighbors is indicated by f = 481 10⁻⁹ N, in general between the one-dimensional solid the distances remain the same, if the distance between the first neighbor is d, the distance between the second neighbors is 2d.

For most solids the attractive forces are electrical, therefore force is proportional to the electrical charges and the inverse of the distance squared,

             F = [tex]k \frac{q_1 q_2}{r^2}[/tex]

if we call fo the force for the first neighbors

              F₀ = k \frac{q_1 q_2}{d^2}

the force for the second neighbors r= 2d  

              F = k \frac{q_1 q_2}{(2d)^2}

              F = F₀ / 4

let's calculate

              F = 481 10⁻⁹ / 4

              F = 120.25 10⁻⁹  N

Meandering valleylike features on the Moon's surface are called

Answers

Answer:

Meandering valley like features on the Moon's surface are called rilles

Explanation:

NOUN

rilles (plural noun)

a fissure or narrow channel on the moon's surface.

PLEASE HELP! THIS IS TO BE TURNED IN IN ABOUT 3 MINUTES!!!!!!!
How must the net force be acting on an object in order for the object to have a circular motion? What is this type of force called?​

Answers

The direction of the net force is in the same direction as the acceleration. So for an object moving in a circle, there must be an inward force acting upon it in order to cause its inward acceleration. This is sometimes referred to as the centripetal force requirement.

If a skaters mass increases how does that effect kinetic energy

Answers

Answer:

By paying close attention to the formula for average kinetic energy, we can see that by increasing the mass by a proportional amount will lead to an increase in the total average kinetic energy. There is a direct relationship being observed between the values.

A car initially traveling 7 m/s speeds up uniformly at a rate of 3 m/s2 until it reaches a velocity of 22 m/s. How much time did it take the car to reach this final velocity?

Answers

Answer:

t = 5 s

Explanation:

Data:

Initial Velocity (Vo) = 7 m/sAcceleration (a) = 3 m/s²Final Velocity (Vf) = 22 m/sTime (t) = ?

Use formula:

[tex]\boxed{t=\frac{Vf - Vo}{a}}[/tex]

Replace:

[tex]\boxed{t=\frac{22\frac{m}{s} -7\frac{m}{s}}{3\frac{m}{s^{2}}}}[/tex]

Solve the subtraction of the numerator:

[tex]\boxed{t=\frac{15\frac{m}{s}}{3\frac{m}{s^{2}}}}[/tex]

It divides:

[tex]\boxed{t=5\ s}[/tex]

How much time did it take the car to reach this final velocity?

It took a time of 5 seconds.

What are used to measure temperature.

Answers

Answer:

A thermometer is an instrument that measures temperature.

Explanation:

a thermometer everyone knows this

Does fg increase or decrease when one mass increases

Answers

Answer:

It increases because fg means Force of gravity so When the mass of the two objects  increases with mass and increases the distance between an object

There you go!!!

A basketball with a mass of 20 kg is accelerated with a force of 10 N. If resisting forces are ignored, what is the acceleration of the basketball?

Answers

I’m pretty sure it would be 10/20= 0.5m/s2

A hanging wire made of an alloy of titanium with diameter 0.05 cm is initially 2.7 m long. When a 15 kg mass is hung from it, the wire stretches an amount 1.68 cm. A mole of titanium has a mass of 48 grams, and its density is 4.54 g/cm3. Based on these experimental measurements, what is Young's modulus for this alloy of titanium

Answers

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y  = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

3. A car has a mass of 1,000 kilograms. If a net force of 2,000 N is exerted on the car, what is its acceleration?

Answers

Answer:

2 m/s^2

Explanation:

Acceleration = Force/mass

= 2,000/1,000

= 2

hmu if u brave shawtys

Answers

Answer:

BET, & done ✌

Answer:

boop

Explanation:

A pendulum has a period of 6.98s. Calculate the length of the pendulum. Use
9.8m/s^2 for gravity. *

Answers

Answer:

Length, l = 0.126 meters.

Explanation:

Given the following data;

Period = 6.98s

Acceleration due to gravity, g = 9.8m/s²

To find the length, l;

[tex] Period, T = 2 \pi \sqrt {lg} [/tex]

Substituting into the equation, we have;

[tex] 6.98 = 2*3.142 \sqrt {l*9.8} [/tex]

[tex] 6.98 = 6.284 \sqrt {9.8l} [/tex]

[tex] \frac {6.98}{6.284} = \sqrt {9.8l} [/tex]

[tex] 1.1108 = \sqrt {9.8l} [/tex]

Taking the square of both sides

[tex] 1.1108^{2} = 9.8l [/tex]

[tex] 1.2339 = 9.8l [/tex]

[tex] l = \frac {1.2339}{9.8} [/tex]

Length, l = 0.126m.

Please answer the question

Answers

Answer:

Option B. 300 m/s².

Explanation:

From the question given above, the following data were obtained:

Mass (m) of student = 100 Kg

Mass (m) of ball = 1.5 Kg

Force (F) applied on the ball = 450 N

Acceleration (a) of ball =?

From Newton's 2nd law,

F = ma

Where

F => Force applied

m => mass of object

a => acceleration of object.

With the above formula, we can obtain the acceleration of the ball as follow:

Mass (m) of ball = 1.5 Kg

Force (F) applied on the ball = 450 N

Acceleration (a) of ball =?

F = ma

450 = 1.5 × a

Divide both side by 1.5

a = 450 / 1.5

a = 300 m/s²

Therefore, the acceleration of the ball is 300 m/s²

Two forces P and Q act on an object of mass 7.00 kg with Q being the larger of the two forces. When both forces are directed to the left, the magnitude of the acceleration of the object is 1.40 m/s2. However, when the force P is directed to the left and the force Q is directed to the right, the object has an acceleration of 0.700 m/s2 to the right. Find the magnitudes of the two forces P and Q .

Answers

Answer:

Explanation:

Q is larger than P . When two forces act in the same direction , Resultant force  

can be calculated by adding them up . When two forces act in the opposite  direction , Resultant force  can be calculated by subtracting  them .

Force = mass x acceleration .

In the first case

Resultant force = mass x acceleration

P + Q = 7 x 1.4 = 9.8 N

In the second case

Q - P = 7 x 0.7 = 4.9

Adding up these two equations

2 Q = 14.7

Q = 7.35 N

P = 9.8 - 7.35 = 2.45 N .

Why can’t a real machine ever have 100% efficiency

Answers

Answer:

Almost all machines require energy to offset the effects of gravity, friction, and air/wind resistance. Thus, no machine can continually operate at 100 percent efficiency.

6th grade science I mark as brainliest !

Answers

1) Compound is the correct answer2) Molecule is the correct answerPlease let me know if I am wrong.
The first answer is compound and the second answer is molecule

Electric and gravitational forces have many similar features because they follow idenitical mathematical formulas. In particular,________ in electricity plays the equivalent role of mass in gravity, while_______ , plays a role corresponding to free-fall acceleration. Because of this kinematics describing projectiles in gravity would carry over to electricity, but the main difference is that in electricity we have__________ , while in gravity mass is always positive, which means gravity is_______ , but electricity________ .

Answers

Answer:

Electric and gravitational forces have many similar features because they follow idenitical mathematical formulas. In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field, plays a role corresponding to free-fall acceleration. Because of this kinematics describing projectiles in gravity would carry over to electricity, but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive, which means gravity is always attractive, but electricity could be attractive and repulsive.

Explanation:

The formulas of Electric and gravitational fields are as follow

Electric Field

F(electric)=kq1q2/r^2

Gravitationlal Fieeld

F(grav)=GMm/r^2

As you see both follow the inverse square law in the formula

Both of these act between two bodies without having any contact. The gravitational field acts on the mass of an object Whereas the electric field acts on the charge.

The gravitational field can only attractive while the electric field can be attractive or repulsive.

Normally electric field is stronger than the gravitational field.

In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

What is gravitational force?

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Electric and gravitational forces have many similar features because they follow identical mathematical formulas.

In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

Plays a role corresponding to free-fall acceleration. Because of these kinematics describing projectiles in gravity would carry over to electricity,

but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive,

which means gravity is always attractive, but electricity could be attractive and repulsive.

Hence, in particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

To learn more about the gravitational force refer to the link;

https://brainly.com/question/24783651

A student stretches a spring, attaches a 1.20 kg mass to it, and releases the mass from rest on a frictionless surface. The resulting oscillation has a period of 0.750 s and an amplitude of 15.0 cm. Determine the oscillation frequency, the spring constant, and the speed of the mass when it is halfway to the equilibrium position.

Answers

Answer:

the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Explanation:

Given that;

mass of the object m = 1.20 kg

period of oscillation = 0.750 s

Amplitude ( A/x) = 15.0 cm = 0.15 m

now;

a) Determine the oscillation frequency;

oscillation frequency f = 1/T

we substitute

f = 1 / 0.750 s

f = 1.33 Hz

Therefore, the oscillation frequency is 1.33 Hz

b) Determine the spring constant;

we solve for spring constant from the following expression;

T = 2π√(m/k)

k = 4π²m / T²

so we substitute

k = (4π² × 1.20) / (0.750)²

k = 47.3741 / 0.5625

k =  84.22 N/m

Therefore, the spring constant is 84.22 N/m

c) determine the speed of the mass when it is halfway to the equilibrium position

So, at equilibrium, the energy is equal to K.E

such that;

1/2mv² = 1/2kx²

mv² = kx²

v² = kx² / m

v = √( kx²/m)

we substitute

v = √( 84.22×(0.15 m)²/ 1.2 )

v = √( 1.89495 / 1.2 )

v = √ 1.579125

v = 1.26 m/s  

Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

The study of heat is ____?

Answers

Explanation:

thermodynamics is the study of heat.

Answer The study of heat and its relationship to useful work is called thermodynamics and involves macroscopic quantities such as pressure, temperature, and volume without regard for the molecular basis of these quantitie

Explanation:

A 7300 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.20 m/s2 and feels no appreciable air resistance. When it has reached a height of 575 m , its engines suddenly fail so that the only force acting on it is now gravity. Part A What is the maximum height this rocket will reach above the launch pad

Answers

Answer:

Explanation:

We shall first calculate the velocity at height h = 575 m .

acceleration a = 2.2 m /s²

v² = u² + 2 a s

u is initial velocity , v is final velocity , s is height achieved

v² = 0 + 2 x 2.2 x 575

v = 50.3 m /s

After 575 m , rocket moves under free fall so g will act on it downwards

If it travels further by height H

from the relation

v² = u² - 2 g H

v = 0 , u = 50.3 m /s

H = ?

0 = 50.3² - 2 x 9.8 H

H = 129.08 m

Total height attained by rocket

= 575 + 129.08

= 704.08 m .

2. A force of 10 N is applied to an object which accelerates at a rate of 2m/s2. What is the mass
of the object?
(10 Points)
10 kg
5 kg
2 kg
20 kg

Answers

5 kg because to find mass you’re going to divide force by acceleration 10/2 is 5

a 90 kilogram dog runs across the dog park at a speed of 6.5 meters per second. what is the magnitude and direction of the average force required to stop the dog in .85 seconds?

Answers

Answer:

am not sure about the answer

Explanation:

you need to find out the amount of force it's going in for example 10n or 100n then you need to times it the distance then devide by the time

Please answer the question

Answers

Answer:

D

Explanation:

He walked a shorter distance, she walked a longer distance but got that wing thingies

What inspired Ronald McNair to do science

Answers

Answer:

While working as a staff physicist at hughes Research Laboratories McNair learned that the National Aeronautics and Space Administration (NASA) was looking for scientist to join the shuttle program;)

How much force does it take to give a 70 kg object an acceleration of 20 mls2

Answers

Answer:

heyy

Explanation:how r uuu

Which subatomic particle is NOT found in the nucleus of an atom? *

protons
neutrons
electrons

Answers

Answer:

Electrons

Explanation:

Only Protons and Neutrons are found in the nucleus

electrons, only protons and neutrons are found within the nucleus.

A ball of mass 0.3 kg flies through the air at low speed, so that air resistance is negligible. (a) What is the net force acting on the ball while it is in motion

Answers

Answer:

X axis   F=0

Y axis    Fg = - 2.94 j ^

Explanation:

The motion of a ball in air where the air residence is indicated to be negligible can be analyzed using Newton's second law.

We set a reference system, where the x-axis is horizontal and the y-axis vertical.

X axis

There are no forces on this axis, therefore the ball goes at constant speed.

Force is zero

Y axis  

In this axis it is subjected to the acceleration of gravity that creates a force equal to the weight of the body, in a vertical direction.

           Fg = m g

           Fg = 0.3 9.8

           Fg = 2.94 N

           Fg = - 2.94 j ^

the boold are vectors; negative sign indicates that the force eta directed vertically downward

Do You think History is the most important subject that deserves first place? Do you see a way that learning history could assist you in your future career?

Answers

yes

Explanation:

history is an important class and it helps to you understand what went on in the past so that we can learn from our mistakes and help us grow

A 0.500 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 44.0 pC charge on its surface. What is the potential near its surface

Answers

Answer:

Explanation:

Radius of sphere R = .250 x 10⁻² m

Potential on the surface V = k Q / R , where Q is charge on the surface ,  R is radius of the surface and k = 9 x 10⁹

Q = 44  x 10⁻¹² C

V = 9 x 10⁹ x 44  x 10⁻¹² /  ( .25 x 10⁻²)

= 1584 x 10⁻¹ Volt .

= 158.4 Volt

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