the area of a square whose length is 4.5 m

Answer:

1/4 is on the second line

3/8 is the the third one

3/8 is bigger

Hope This Helps!!!

Answer:

Hope this helps you.......

When multiplying the same variable to different exponents add the exponents and multiply the constant numbers:

3x x 2x = 6x

^2 + ^3 = ^5

Answer is a. 6x^5

Answer:

3x

Step-by-step explanation:

because both terms are common 12 and 6 is 3 and x² and x is x

The approximate percentage error on the weight of the beaker is 5%

Percent error is the difference between estimated value and the actual value in comparison to the actual value and is expressed as a percentage. In other words, the percent error is the relative error multiplied by 100.

Error = Actual value - estimated value =

Actual value = 82g, Estimated value = 78g

Error = 82 - 78 which is 4

percent error = error/estimated x 100%

percent error = 4/78 x 100 which is 5%

In conclusion the percent error is 5%

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The expression that is equivalent to the expression, 3 + 2x − 9 − 4x + 11 + 5x − x, is: 2x + 5.

Expressions that have the same value are said to be equivalent expressions.

Evaluate 3+2x−9−4x+11+5x−x:

3 + 2x − 9 − 4x + 11 + 5x − x

Add like terms together

2x - 4x + 5x - x + 3 - 9 + 11

2x  + 5

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Answer:

Step-by-step explanation:

The expression that is equivalent to the expression, 3 + 2x − 9 − 4x + 11 + 5x − x, is: 2x + 5.

Answer:

I think the correct answer is D since the arrows go infinite ways. Let me know if im right. :)

Step-by-step explanation:

Answer:

I think the answer is D please forgive me if I'm wrong

Answer:

5

Step-by-step explanation:

The distance between the points in RISE/RUN is 10/2.

10/2 = 5. Your slope is 5

Hope that helps. Brainliest is appreciated

Answer:

Identity property.

Step-by-step explanation:

Any number added to 0 keeps its original value, keeping its identity.

Answer:

length times witdth times height

Given the inequality expression:

w−0.8>−2.4

Inequalities are expressions separated by an unequal sign.

According to the given question, we need to find the solution for "w"

w−0.8>−2.4

Add 0.8 to both sides

w−0.8+0.8>−2.4 + 0.8

w > -2.4 + 0.8

Simplify the result by adding to have:

w > -1.6

Find the number line representing the solution attached;

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Answer:

48 ÷12 will help you 48 is cost divided by total cost which means cost of one adult and one child

Explanation:

Let's say we started at point B (-6, 3). To get to point A(-4,2), we move down 1 and to the right 2. This movement determines the slope.

slope = rise/run = -1/2

rise = -1 and run = 2

A negative rise value means we go downhill when moving to the right.

Answer:

Step-by-step explanation:

Conclusion:

Therefore, y = -2.

Hoped this helped.

[tex]GeniusUser[/tex]

Answer:

2x3 + 10x2 - x - 18

Step-by-step explanation:

hope this helps! goodluck & enjoy the rest of ur day /or night.

Answer:

(4x2 - x - 7) + (2x3 + 6x2 - 11) Adding polynomials

Step-by-step explanation:

Answer:

I am not sure the answer is , if its minus ,divade ,multiply or plus but down the answer is correct

Step-by-step explanation:

17x - 75

× = 75÷17

x= 4.4117647059

Answer:So firstly, plug in the numbers into the expression:

Next, solve the exponents:

Next, solve the multiplications:

Lastly, combine everything, and your answer will be -23.

Step-by-step explanation:

Answer:

-23

Step-by-step explanation:

By substituting the given numeric values for x,y and z into the expression.

That is

(3)3−2(5)2−3(3)3+(−3)4

------------------------------------------------

I'll evaluate each term separately.

(3)3=3×3×3=9×3=27

2(5)2=2×(5×5)=2×25=50

3(3)3=3×(3×3×3)=3×27=81

(−3)4=[(−3)×(−3)]×[(−3)×(−3)]=9×9=81

-------------------------------------------------

Replace these values back into the expression , noting the values which are subtracted.

⇒27−50−81+81=27−50=−23

Answer:

the answer is 270714.285714 or just  270714.2 careful \

Step-by-step explanation:

Using the t-distribution, it is found that:

a) Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that significantly more electricity is used at the student center, on average, on weekdays than weekend days.

b) The 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days is (3.56, 33.18).

Item a:

At the null hypothesis, it is tested if there is no difference, that is, the subtraction is at most 0, hence:

[tex]H_0: \mu_1 - \mu_2 \leq 0[/tex]

At the alternative hypothesis, it is tested if there is difference, that is, the subtraction is positive, hence:

[tex]H_1: \mu_1 - \mu_2 > 0[/tex]

The standard errors are given by:

[tex]s_1 = \frac{32.07}{\sqrt{60}} = 4.14[/tex]

[tex]s_2 = \frac{43.29}{\sqrt{30}} = 7.9[/tex]

The distribution of the difference has mean and standard deviation given by:

[tex]\overline{x} = \mu_1 - \mu_2 = 112.63 - 94.26 = 18.37[/tex]

[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{4.14^2 + 7.9^2} = 8.92[/tex]

The standard deviation are given for the samples, hence, the t-distribution is used.

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

In which [tex]\mu = 0[/tex] is the value tested at the hypothesis.

Hence:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

[tex]t = \frac{18.37 - 0}{8.92}[/tex]

[tex]t = 2.06[/tex]

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05 and 30 + 60 - 2 = 88 df is [tex]t^{\ast} = 1.66[/tex]

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that significantly more electricity is used at the student center, on average, on weekdays than weekend days.

Item b:

The interval is:

[tex]\overline{x} \pm t^{\ast}s[/tex]

Hence:

[tex]\overline{x} - t^{\ast}s = 18.37 - 1.66(8.92) = 3.56[/tex]

[tex]\overline{x} + t^{\ast}s = 18.37 + 1.66(8.92) = 33.18[/tex]

The 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days is (3.56, 33.18).

A similar problem is given at https://brainly.com/question/25812826

Answer:

[tex]y=10x+24[/tex]

Step-by-step explanation:

Find the derivative of the function

[tex]p'(t)=\frac{d[p(t)]}{dt}=\frac{d}{dt}(3t^2-8t+3)=6t-8[/tex]

Determine the slope of p(t) at t=3:

[tex]p'(3)=6(3)-8=18-8=10[/tex]

Find p(3):

[tex]p(3)=3(3)^2-8(3)+3=3(9)-24+3=27-21=6[/tex]

Determine y-intercept:

[tex]y=mx+b[/tex]

[tex]6=10(3)+b[/tex]

[tex]6=30+b[/tex]

[tex]-24=b[/tex]

Final equation:

[tex]y=10x-24[/tex]

Answer:

We can make 3 whole groups of 2.

Hope that helps. x

Step-by-step explanation:

2, 4, 6, 8

The closest number near to 7 is 6 so we do 6 divided by 2 which equals 3.

Answer:

1 = --6

2 x=64

3 x= --5

4 x= --18

5 x=3

6 x=6

Step-by-step explanation:

GIMME BRANlIEST PLZZZ

Answer:

I believe it would be B.

Step-by-step explanation:

Half a circle is 180 degrees, which is the location of option B. In other words you just rotate it halfway around and you'll find it at 180°.

Step-by-step explanation:

Yards of red material = 1.75

Yards of blue material = 1.75 x 1.2 = 2.1 yards

So the blue material is 2.1 yards

Answer:

Send me a picture of the graph and I gottchu =)

Step-by-step explanation:

Answer:

I need a picture of the graph to answer that

Answer:

Step-by-step explanation:

Answer:

y=1/2x+8

Step-by-step explanation:

grab 2 points in this case (4,10) and (0,8)

use rise over run formula so it rises 2 and goes over 4

so 2/4 then simplify and you get 1/2

and the y intercept is 8 because thats when the slope touches the y line

so using the equation y=mx+b when m is slope and b is y interecpt

the answer should be y=1/2x+8

Answer:

y=2x+8

Step-by-step explanation:

8=b m=y_ý/x_x`=2

y=ax+b

y=2x+8

A box and whisker plot is made up of 5 pieces of information: the minimum, 1st/lower quartile, median, 3rd/upper quartile, and maximum.

Start by placing a dot on the minimum and maximum values. These are the "whiskers" of the box plot.

Next, we'll graph the lower and upper quartiles. On these values, draw vertical lines. We are given the lower quartile, but will need to find the upper quartile.

IQR = upper quartile - lower quartile

225 = x - 120

x = 345 minutes = 5 hours, 45 minutes

Now that we know the upper quartile, you will also draw a line on that value. Feel free to connect the lines to make the "box".

Lastly, we'll graph the median. This is another vertical line on the value. It should be directly in the middle of the lower and upper quartiles. It will be inside the box.

Hope this helps and if you have any further questions, please let me know! :)

Answer:

1/10

Step-by-step explanation:

We need to differentiate this with respect to x to see if we can find an expression for the derivative of y at various points.  That will be the slope of the tangent to the curve.  Then we want to see where that derivative might be infinite -- i.e., where the tangent is vertical.

It's not written as a function, but it can still be differentiated using the chain rule:

x2 + xy + y2 = 3

(2x) + (x dy/dx + y dx/dx) + (2y dy/dx) = 0

(I used parentheses to show the differentiation of each term in the original equation.)

2x + x dy/dx + y + 2y dy/dx = 0

2x + y = -x dy/dx - 2y dy/dx

2x + y = dy/dx (-x -2y)

-(2x + y)/(x + 2y) = dy/dx

We have the derivative of y, but it's defined partly in terms of y itself.  That's OK.  Let's go on...

So where would the slope be infinite?  That would happen when x + 2y = 0, or y = -x/2

Let's plug that in for y in the original equation to find points where that's the case.

x2 + xy + y2 = 3

x2 + x(-x/2) + (-x/2)2 = 3

x2 - x2/2 + x2/4 = 3

3x2 / 4 = 3

x2 = 4

x = ±2

So we have two x values where the tangent might be vertical.  Let's plug them into the equation and see what the y values are.  First x = 2...

x2 + xy + y2 = 3

4 + 2y + y2 = 3

y2 + 2y + 1 = 0

(y + 1)2 = 0

y = -1

So at the point (2, -1) the tangent is vertical.

Now try x = -2...

x2 + xy + y2 = 3

4 - 2y + y2 = 3

y2 - 2y + 1 =0

(y - 1)2 = 0

y = 1

So at the point (-2, 1) the tangent is vertical.