The distance between adjacent nodes in a standing wave pattern is 25.0 cm. What is the
wavelength? If the frequency is 200. Hz, what is the speed of the wave?

Answers

Answer 1

Answer:

Answer:

Speed of the wave in the string will be 3.2 m/sec

Explanation:

We have given frequency in the string fixed at both ends is 80 Hz

Distance between adjacent antipodes is 20 cm

We know that distance between two adjacent anti nodes is equal to half of the wavelength

So \frac{\lambda }{2}=20cm

2

λ

=20cm

\lambda =40cmλ=40cm

We have to find the speed of the wave in the string

Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec

So speed of the wave in the string will be 3.2 m/sec


Related Questions

A compound eye __________. ANSWER Unselected is composed of thousands of prisms that focus light onto only a few photoreceptor cells Unselected All of the listed responses are correct. Unselected works best for resolving stationary images Unselected contains many individual light detectors, each with its own lens Unselected is possessed only by insect

Answers

Answer:

contains many individual light detectors, each with its own lens

Explanation:

The compound eye is found mainly in insects and crustaceans, it is composed of individual receptor units, each with its focus, sensing nerve; each one gives a small image of the environment, so the image is mosaic type, not a complete integral image of the environment.

When reviewing the different statements, the correct one is

contains many individual light detectors, each with its own lens

What are three differences and similarities between a Vernier Calipers and a Micrometer? (please leave a good answer)

Answers

Answer:

Explanation:

Vernier scale

Mathematical tool

A vernier scale, named after Pierre Vernier, is a visual aid to take an accurate measurement reading between two graduation markings on a linear scale by using mechanical interpolation; thereby increasing resolution and reducing measurement uncertainty by using vernier acuity to reduce human estimation error. Wikipedia

Purpose: Measuring more precisely than could be done unaided when reading a uniformly divided straight or circular measurement scale

Creator: Pierre Vernier

Year invented: 1631

..............................................................................................................................................................................................................................................................................................

A micrometer is a measuring instrument that can make extraordinarily precise measurements. Most micrometers are designed to measure within one one-thousandth of an inch! That's a close fit. Exact measurements like this are necessary when even the smallest of space between objects can cause problems or difficulties.

Micrometer

Mathematical tool

A micrometer, sometimes known as a micrometer screw gauge, is a device incorporating a calibrated screw widely used for accurate measurement of components in mechanical engineering and machining as well as most mechanical trades, along with other metrological instruments such as dial, vernier, and digital calipers. Wikipedia

Operation supported: Component measurement

Purpose: Precision measurement of a component

Variant: Digital mics, Bench micrometer, Limit mics, Digit mics, MORE

Component: Screw, Spindle, Ratchet stop, Anvil, Frame, Barrel, Thimble lock, Thimble

Application: Mechanical Engineering, Machining

Which type of electromagnetic wave is deliberately used in some
circumstances to cause damage to living cells in the human body?
A. Infra-red
B. Gamma rays
C. Microwaves
D. Radio waves.

Answers

Gamma rays

used in radiotherapy

any correct ans guess for 30 pts and brainlist​

Answers

Answer:

a) ii

b) i

c)iii

d)iii

e) i

f)iii

Explanation:

i hope this will help

Answer:

the answer of b is N and d is mol

Give reason.


b} String roller is an example of wheel and axel .Why?

Answers

Explanation:

string roller is called an example of wheel and axel because The thin rod which needs to be turned is called the axle and the wider object fixed to the axle, on which we apply force is called the wheel.

hence the we apply force on the roller and the string gets tight.

A 5.41 kg ball is attached to the top of a vertical pole with a 2.37 m length of massless string. The ball is struck, causing it to revolve around the pole at a speed of 4.75 m/s in a horizontal circle with the string remaining taut. Calculate the angle θ, between 0∘ and 90∘, that the string makes with the pole. Use g=9.81 m/s2.

Answers

Answer:

θ = 66º

Explanation:

This exercise of Newton's second law must be solved in part, let's start by finding the slowing down acceleration of the ball

           a = v² / r

the radius of the circle is

          sin θ = r / L

          r = L sin θ

           

we substitute

          a = v² /L sin θ

now let's write Newton's second law

vertical axis

            T_y -W = 0

             T_y = W

radial axis

            Tₓ = m a                 (1)

let's use trigonometry for the components of the string tension

             cos θ = T_y / T

             sin θ = Tₓ / T

             Tₓ = T sin θ

we substitute in 1

            T sin θ = [tex]\frac{m \ v^2}{L \ sin \theta}[/tex]

             T L sin² θ = m v²

we write our system of equations

             T cos θ  = m g

             T L sin ² tea = m v²

we divide the two equations

             L [tex]\frac{sin^2 \theta}{cos \theta}[/tex] = v² / g

             (1 -cos²)/ cos θ  = [tex]\frac{v^2 }{g \ L}[/tex]

             1 - cos² θ  =  [tex]\frac{4.75^2}{9.81 \ 2.37}[/tex]   cos θ

             cos² θ + 0.97044 cos θ -1   = 0

we change variable    cos  θ = x

             x² + 0.97044 x - 1 =0

             x= [tex]\frac{-0.97 \pm \sqrt{0.97^2 - 4 1} }{2}[/tex]

           since the square root is imaginary there is no real solution to the problem, suppose that the radius is 1 m r = 1 m

           T sin θ = [tex]\frac{m \ v^2}{ r}[/tex]

           T cos θ  = m g

resolved

           tan θ =  [tex]\frac{v^2}{ r g}[/tex]

           θ = tan⁻¹ ( 4.75²/ 1 9.81)

           θ = 66º

Reference frame definitely changes when also changes

Answers

Reference frame definitely changes when the body is changing. That is the reason that in order to describe the position of a point that moves relative to a body that is moving relative to the Earth, it is usually convenient to use a reference frame attached to the moving body.

the diameter of circular park is 80 m find its area​

Answers

Explanation:to find the area you must first find the radius given you have the diameter you cut the diameter in half giving you 40 then you follow the formula “A= (pie)r (squared) leaving you with

answer:5024

3 write the three laws given by kepler.How did they help Newton to arrive at the inverse square law of gravity?​

Answers

Answer:

Kepler's laws apply: First Law: Planetary orbits are elliptical with the sun at a focus. Second Law: The radius vector from the sun to a planet sweeps equal areas in equal times. Third Law: The ratio of the square of the period of revolution and the cube of the ellipse semimajor axis is the same for all planets.

A water heater marked 4 kW takes 4 minutes to heat 1 kg of water from 20 °C to 50 °C. The cost of electrical energy per kWh
is $0.120. What will be the total cost of energy consumption?

Answers

The total cost of the energy consumption for the given time period is $0.0364

The given parameters include;

power rating of the heater, P = 4 kW = 4000 Wtime taken to completely boil the water,[tex]t = 4 \min = 4 \min \times \frac{1 \ h}{60 \ \min} = 0.067 \ h[/tex]mass of the water, m = 1 kginitial temperature of the water, t₁ = 20 ⁰Cfinal temperature of the water, t₂ = 50 ⁰Cspecific heat capacity of water, c = 4200 J/kg⁰Ccost of electrical energy = $0.12

The total energy consumed in the process of heating the water;

Total electrical Energy  = Energy of the heater (kWh) + Energy of the heated water (kWh)

Energy of the heater (kWh) = power x time

                                = 4 kW x 0.067 h

                                 = 0.268 kWh

Energy of the heated water (J) = mcΔt

where;

Δt is the change in temperature = t₂ - t₁

                                                      = 50 ⁰C  -  20 ⁰C = 30⁰C

Energy of the heated water (J) = 1 x 4200 x 30

                                               = 126,000 J

Electrical power of the heated water (Watts) = [tex]\frac{126,000 \ J}{4 \ \min} \times \frac{1 \min}{60 \ s} = 525 \ W[/tex]

Energy of the heated water (kWh) = [tex]\frac{525}{1000} \times 4\min\times \frac{1 \ hr}{60 \min} = 0.035 \ kWh[/tex]

Total electrical Energy  = 0.268 kWh  +  0.035 kWh

                                       = 0.303 kWh

The total cost of the energy consumed is calculated as;

[tex]Total \ cost = \frac{\$ \ 0.12}{kWh} \times 0.303 \ kWh = \$ \ 0.0364[/tex]

Therefore, the total cost of the energy consumption is $0.0364

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After release of jet, energy is lost by the engine. How principle of conservation of energy is obeyed in this condition.​

Answers

Answer:

The principle of conservation of energy states that in a closed system, the energy can neither be created nor destroyed between interacting particles and remains constant or transformed from one form to another

In the jet engine, the release of jet changes the number of interacting particles in the engine, and given that energy cannot be created in the instantaneously closed system of the engine, energy is carried away and therefore lost by particles in the jet exhaust

The conservation of energy principle is therefore obeyed in the condition in which the jet engine losses energy by the release of jet

Explanation:

What will happen to the velocity and momentum of each ball when the small ball hits the heavier large ball?

Answers

most of the momentum is transferred to the ball on top. Since the collision in this situation is elastic, momentum is conserved, meaning the momentum of both balls before hitting the floor is equal to the momentum of both balls right after the collision.

The small ball will transfer its momentum to the heavier ball. Since the momentum gets conserved. The velocity will depend upon the mass of the balls.

What is the law of conservation of momentum?

According to the law of conservation of momentum. The momentum of the body before the collision is always equal to the momentum of the body after the collision.

The momentum of the body is given by the product of the mass and velocity of the body.

According to the law of conservation of momentum

Momentum before collision =Momentum after collision

Hence the small ball will transfer its momentum to the heavier ball.

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byeeeeeeeeeeeejdiiwidjwdjj2xi2idiwidisididie

Answers

Answer:

Be serious or else CEO of brainly will kick you out

A converging lens of focal length 20cm, forms a real image twice the size of the object. Calculate:
i) the power of the lens;
ii) the position of the image.

Answers

Answer:

Solition given:

focal length(f)=20cm

size of image(v)=2x

size of object(u)=x

we have

power of lens= reciprocal to focal length=1/20=0.05/cm

ii.

the position of the image is beyond C.

Explanation:

See the attachment !!!!!!!

Una partícula efectúa un MAS cuya ecuación es: x=0,3 cos (2t + /6) m. Determinar: Amplitud, frecuencia angular, fase inicial, periodo, frecuencia de oscilación y posición en t=0,25 s

Answers

Answer:

The answer is below

Explanation:

Una partícula efectúa un MAS cuya ecuación es: x=0.3cos (2t + π/6) m. Determinar: Amplitud, frecuencia angular, fase inicial, periodo, frecuencia de oscilación y posición en t=0.25 s

Solution:

La ecuación de la onda es:

x = A cos (ω t + Ф), donde:

A = amplitud, ω = frecuencia angular = 2 π / T = 2 π f, Ф = fase inicial, f = frecuencia, T = período

Por lo tanto, comparando la ecuación de la onda con x = 0.3cos (2t + π / 6), obtenemos:

a) A = 0.3

b) ω = 2 rad / s

c) Ф = π / 6 rad

d) ω = 2π / T

2 = 2π / T

T = 3.14 s

e) ω = 2πf

2 = 2πf

f = 0.32 Hz

f) en t = 0.25 s:

x (t) = 0.3cos (2 * 0.25 + π / 6) = 0.22 m

Answer the following questions 1 What is the difference between mass and weight of an object. Will the mass and weight of an object on the earth be same as their values on Mars ? Why? ​

Answers

Answer:

difference between mass and weight is that mass is amount of matter in a material while weight is a measure of how the force of gravity acts upon that mass.the mass of an object will be same on earth and mars but its weight on both planets will be different.


1. What type of VOM reading requires the meter to be placed in series with the circuit?
A. Resistance
B. Voltage
C. Current
O
D. Power

Answers

Answer:

C.  Current.

Explanation:

In a series circuit the current is equal in all of its components, so to measure the current we put the meter in series with the circuit.

1.Convert 340 cm into m *(answer=0.34m)

2.What is the weight of potatoes of mass 75kg on the surface of the earth? *(ans=735 N)

[g=9.8 m/s^2

[g=9.8 m/s^2]

3.The weight of body is 420 N.Calculate its mass. *(42.857 kg)*


Answers are all given so i just need the process please (i will mark you brainliest please..

Answers

Answer:

1.for the first one 100centimeters make 1 meter therefore

100cm-1m

340cm-x

340/100

=3.4

the answer is supposed to be 3.4, maybe there's a mistake with the question or the answer

2.the weight of a body is given by the formula

mass×gravity,in this case the mass is 75kg and the gravity is 9.8

weight=75×9.8

=735N

3.for this one the mass of a body is given by the formula

mass=weight/gravity

=420/9.8

=42.8kg

I hope this helps

which statement accurately describes how the acceleration of an object in free fall changes

Answers

Answer:

A ball rolls off the table and free falls to the ground. Which statement accurately describes its acceleration? Its acceleration is downward but remains a constant value as it falls.

Observe the given figure and find the the gravitational force between m1 and m2.​

Answers

Answer:

The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N

Explanation:

The details of the given masses having gravitational attractive force between them are;

m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m

The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

[tex]F =G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}[/tex]

Where;

F = The gravitational force between m₁ and m₂

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r₂ = 0.1 m + 0.15 m = 0.25 m

Therefore, we have;

[tex]F = 6.67430 \times 10^{-11} \ N \cdot m^2/kg \times \dfrac{20 \ kg\times 50 \ kg}{(0.1 \ m+ 0.15 \ m)^{2}} \approx 1.06789 \times 10^{-6} \ N[/tex]

The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N

Un auto se desplaza por una carretera recta a una velocidad de 85 km/h. Al cabo de 2 horas, ¿qué distancia habrá recorrido, en metros?

Answers

Answer:

Distancia, D = 170,000 metros

Explanation:

Dados los siguientes datos;

Velocidad = 85 km/h Tiempo = 2 horas

Para encontrar la distancia recorrida, en metros;

Matemáticamente, la distancia recorrida por un objeto se calcula mediante la fórmula;

Distancia = velocidad * tiempo

Sustituyendo los valores en la fórmula, tenemos;

Distancia = 85 * 2

Distancia = 170 kilómetros

A continuación, convertiríamos el valor en kilómetros a metros;

Conversión:

1 kilómetros = 1000 metros

170 kilómetros = D metros

Multiplicación cruzada, tenemos;

D = 170 * 1000

D = 170,000 metros

Por lo tanto, habría viajado 170,000 metros después de 2 horas.

A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.25 ms2.25 ms from an initial speed of 4.25 m/s4.25 m/s . What is the magnitude of the average contact force exerted on the leg, assuming the total mass of the hand and the forearm to be 1.75 kg1.75 kg

Answers

Answer:

The force is 3305.6 N.

Explanation:

Final velocity, v = 0

time, t = 2.25 ms

initial velocity, u = 4.25 m/s

mass, m = 1.75 kg

Let the acceleration is a.

Use first equation of motion.

v = u + a t

0 = 4.25 + a x 0.00225

a = - 1888.9 m/s^2

The force is

F = ma

F = 1.75 x 1888.9

F = 3305.6 N

Wat is acceleration!!!!!​

Answers

Answer:

Acceleration is the rate of change of velocity with time.its system international unit is meters per second square.

I hope this helps

A long distance runner running a 5.0km track is pacing himself by running 4.5km at 9.0km/h and the rest at 12.5km/h. What is his average speed?

Answers

Answer:

9.26 km/h

Explanation:

Applying,

V' = D'/t'............... Equation 1

Where V' = Average speed, D' = Total distance, t' = total time.

Given: D' = 5 km

But,

v = d/t............ Equation 2

Where v = speed , d = distance, t = time

t = d/v............ Equation 3

Given: d = 4.5 km, v = 9 km/h, and d = 0.5 km, v = 12.5 km/h

Therefore,

t₁ = 4.5/9 = 0.5 hours

t₂ = 0.5/12.5

t₂ = 0.04 hours

Therefore,

V' = 5/(0.5+0.04)

V' = 5/0.54

V' = 9.26 km/h

Which are characteristics of a prokaryotic cell? Select three options.


O contains DNA

O lacks DNA

O contains ribosomes

O lacks ribosomes

O contains a nucleus

O lacks a nucleus

I NEED THIS QUICKLY

Answers

Answer:

A. Contains DNA

C. Contains ribosomes

F. Lacks a nucleus

Explanation:

A car travels first 10 km in 20 minutes and another 10 km in 30 minutes. What is the average speed of the car in m/s?

Answers

Total distance = 10 km + 10 km = 20 km

1 km = 1000 m

20km x 1000 = 20,000 m

Total time = 20 min. + 30 min. = 50 minutes

Average speed = Distance /  time

Average speed = 20,000/50 min

Average speed = 400 m/s

A man pulls his luggage on a 30 degree incline with a constant force of 25 N. How
much work does he do after walking 20.0 m?
a) 430 J
b) 330J
c) 1500J
d) 250 J

Answers

Force=F=25NDisplacement=s=20mAngle=30°

We know

[tex]\boxed{\sf W=Fscos\theta}[/tex]

[tex]\\ \sf\longmapsto W=25(20)cos30°[/tex]

[tex]\\ \sf\longmapsto W=500\times \dfrac{\sqrt{3}}{2}[/tex]

[tex]\\ \sf\longmapsto W=250\sqrt{3}[/tex]

[tex]\\ \sf\longmapsto W=250(1.73)[/tex]

[tex]\\ \sf\longmapsto W\approx 430J[/tex]

Option a) 430 J work done he do after walking 20.0 m.

What is work?

Work, in physics, is a measure of energy transfer that happens when an object exists moved over a distance by an external force at least part of which exists involved in the direction of the displacement.

Displacement exists as the distance moved in a straight line, in a provided direction, from the starting point. Displacement exists as a vector quantity as it includes size and direction.

An angle stands the figure formed by two rays, named the sides of the angle, sharing a standard endpoint, named the vertex of the angle.

Force=F=25NDisplacement=s=20mAngle=30°

⇒[tex]W=Fcos\theta[/tex]

⇒[tex]W=25(20)cos 30^{0}[/tex]

Then,

⇒[tex]W=50*\sqrt{3} /2[/tex]

⇒[tex]W=250\sqrt{3}[/tex]

Hence,

⇒[tex]W=250(1.73)[/tex]

[tex]W[/tex] approximately 430J.

Hence, Option a) 430 J work done he do after walking 20.0 m.

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#SPJ2

Guys please help this is very important it would be greatly appreciated if you would add the work. Thank you !!

Answers

Answer:

enjoy

Explanation:

The number of time a cricket chirps in a minute is a function of the temperature in the formula: n=4t-160, where n=number of times a cricket chirps a minute and t=temperature in farenheit. You can use the temperature t=(1/4)n+40 to estimate the temperature based on the number of chirps per minute.

A skipper on a boat notices wave crests passing his anchor chain every 5.6 s . He estimates the distance between wave crests to be 16 m . He also correctly estimates the speed of the waves. Find this speed.

Answers

Answer:

v = 2.85 m/s

Explanation:

Given that,

A skipper on a boat notices wave crests passing his anchor chain every 5.6 s.

The distance between wave crests to be 16 m.

We need to find the speed of the waves. The speed of a wave can be calculated by the formula as follows :

[tex]v=f\lambda\\\\v=\dfrac{\lambda}{T}\\\\v=\dfrac{16}{5.6}\\\\v=2.85\ m/s[/tex]

So, the speed of the wave is 2.85 m/s.

beansFe(aq) + Al(s) → beansAl(aq) + Fe(s) (7 points) a. What type of reaction is this? Explain what you think happened.b. This is also another type of reaction. What is it? Give another common example of this type of reaction.c. Do you think it is OK to eat the green beans? Explain why, or why not.

Answers

Answer:

tôi đoán lagf  pjhAWN ỨNG HÓA HỌC

Explanation:

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Find the approximate area of the shaded region below, consisting of a right triangle with a circle cut out of it. Use 3.14 as anapproximation for90 m402,794 square meters1,256 square meters974 square metersO 6,844 square meters ______is the first country to print a book . An astronaut on Pluto attaches a small brass ball to a 1.00-m length of string and makes a simple pendulum. She times 10 complete swings in a time of 257 seconds. From this measurement she calculates the acceleration due to gravity on Pluto. What is her result a) Express the prime number 31 as the difference of two squares? 31 = The cost,c(x), for a taxi ride is given by c(x)=3x+2.00, where x is the number of minutes. What does the slope mean for this situation Shaun is planting trees along his driveway, and he has 66 redwoods and 66 pine trees to plant in one row. What is the probability that he randomly plants the trees so that all 66 redwoods are next to each other and all 66 pine trees are next to each other Can you please help me QuestionIf a triangle has sides of length x x + 2, and x - 4, what is the perimeter of the triangle in terms of x? 3 - 603x - 23x + 2O 3x + 6 I'LL GIVE BRAINLIEST !!! FASTERplease explain how do you get the answer ! Which kind of narrator is aware that he or she is constructing a story which implies thatthe story and characters are not real?A. IntrusiveB. Self-consciousC. InadequateD. Unreliable For which of the following reactions is the enthalpy change equal to the second ionization energy of nitrogen? Find the transpose of AB During the month of August, Ranson Productions applied overhead to jobs using an overhead rate of $0.60 per dollar of direct labor. Actual direct labor in August was 12,000 hours at $15.00 per hour, for a total of $180,000. Estimated overhead in August was $111,600.Actual overhead was composed of the following items:Indirect materials $ 16,400Indirect labor 22,000Utilities 24,500Depreciation 38,700Repair expense 13,500Total $115,100How much overhead was applied during August by Ranson Productions?A. $115,100B. $108,000C. More information is needed to answerD. $111,600 What effect did the narrator's efforts have on his friend, Usher?A. The narrator's efforts had no effect on Usher.B. The narrator inspired Usher to great feats of creativity.C. The narrator's presence made Usher ill.D. The narrator succeeded in making Usher feel happier. If f(x) = 5x squared -3 and g(x) = x squared - 4x -8, find (f-g)(x) The January 1, Year 1 trial balance for the Tyrell Company is found on the trial balance tab. The beginning balances are assumed. Tyrell Co. entered into the following transactions involving short-term liabilities. (Use 360 days a year.) Year 1. Apr. 20 Purchased $40,250 of merchandise on credit from Locust, terms n/30. May 19 Replaced the April 20 account payable to Locust with a 90-day, 10%, $35,000 note payable along with paying $5,250 in cash. July 8 Borrowed $80,000 cash from NBR Bank by signing a 120-day, 9%, $80,000 note payable. Aug. 17 Paid the amount due on the note to Locust at the maturity date. Nov. 5 Paid the amount due on the note to NBR Bank at the maturity date. Nov. 28 Borrowed $42,000 cash from Fargo Bank by signing a 60-day, 8%, $42,000 note payable. Dec. 31 Recorded an adjusting entry for accrued interest on the note to Fargo Bank. Year 2 Jan. 27 Paid the amount due on the note to Fargo Bank at the maturity date.Required:Prepare the 2016 journal entries related to the notes and accounts payable of Tyrell Co. QuesWhere does Ivan Jakovlevitch find Major Kovaloff's nose?A. At the Isaac BridgeO B. At the newspaper officeO C. In his barbershopO D. In his breakfast bread The metal sample suspected of being aluminum is warmed and then submerged into water, which is near room temperature. The final temperature of the water and the metal is given below. The specific heat capacity of water is 4.18 J/g.oC. Calculate the specific heat capacity of the metal based on the data below. Remember heat lost = heat gained.Type of metal used: Trial 1 Trial 2 Trial 3Mass of metal, g 2.746 g 2.750 g 2.900 gMass of water, g 15.200 g 15.206 g 15.201 gInitial Temp. of Water, oC 24.7 oC 24.6 oC 24.5 oCInitial Temp. of Metal, oC 72.1 oC 72.2 oC 71.9 oCFinal Temp of Water & Metal,oC 26.3 oC 26.2 oC 24.7 oCT for water, oC ______ ______ ______T for metal, oC ______ ______ ______Specific heat capacity of metal, J/g.oC ______ ______ ______Average specific heat capacity, J/g .oC ______ (use two significant figures due to T of water) It takes 5 minutes for 10 people to drink 25 pints of water. At this rate, how long would it take 15 people to drink 155 pints of water help please tries 2 times