The height (in centimeters) at time t (in seconds) of a small mass oscillating at the end of a spring is h(t)=5sin(2πt). Estimate its instantaneous velocity at t=3

Answers

Answer 1

Answer:

 h (3) = 0

Explanation:

In this exercise they give us the expression that governs the movement

           h (t) = 5 sin (2πt)

remember that the angles are in radians.

To calculate the instantaneous velocity we substitute

           h (3) = 5 sin (2π 3)

           h (3) = 0

therefore the body this is its position of equilibrium


Related Questions

A wave in which the movement of the wave is perpendicular to the movement of the wave traveling through the medium-compression wave (longitudinal wave)

True or false?

Answers

Answer:

I'm rusty sorry if I'm wrong but true?

Which of these is an effect of gravity?
А
A cup placed on a table won't float away.
B
You can throw a ball or a rock up.
С
The brakes on a bike can make it stop.
D
Liquid water can become a gas.

Answers

Answer:

(A)

A cup placed on a table won't float away

In the 1986 Olympic Games, Abdon Pamich of Italy won the 50 km walk, in
4h, 11 min and 11.2 s. Find his average speed in m/s.

Answers

Answer: 4

Explanation: because my pet monkey said it was

What is the symbol for carbonate ?

Answers

It is HCO3 the symbol of carbonate

Identify and sketch all the external forces acting on the chair. Because the chair can be represented as a point particle of mass m, draw the forces with their tails centered on the black dot in the middle of the chair. Be certain to draw your forces so that they have the correct orientation. Draw the vectors starting at the black dot. The location and orientation of the vectors will be graded. The length of the vectors will not be graded.

Answers

Answer:

y axis normal (N) and the weight (W)

x axis  pplied force (F) and friction force (fr)

Explanation:

If we have a chair on a horizontal surface, the normal (N) and the weight (W) of the body act on the vertical axis.

On the x axis, the applied force (F) acts in the direction of movement and the friction force (fr) in the opposite direction of movement.

In this exercise we assume that the body tends to move to the right, all the forces can be seen in the adjoint

Astronomers study the electromagnetic radiation emitted by distant stars and planets to determine things like: how far away they are, their temperatures and speed, etc. Based on what you learned in this class, explain why the NASA Hubble Space Telescope is better for observing the electromagnetic radiation emitted from stars and planets at 560 km above sea level compared to the Keck telescope in Hawaii, which is 4 km above sea level

Answers

Answer:

This same Hawaii telescope, which would be 4 km across water level, can't provide an appropriate version of distanced planetary bodies. A further overview is provided below.

Explanation:

The surface area of that same earth's orbit seems to be approximately 480 km heavy. The atmosphere isn't translucent to the only certain wavelength range of the radioactivity. Not because all-stars, as well as gliders, emit specific wavelengths, but several of them generate ultraviolet as well as infrared. Those same radiations have either been mediated primarily as well as passes through the atmosphere. Due to the Blockage, they can't even be interpreted with such a similar quality unless the telescope would be positioned throughout the portion of the atmosphere.

A 6.00 nC is 2.00 m from a 3.00 nC charge. Find the magnitude of the electric field at a point midway between
the two charges? Which way does the electric field point, towards the positive or the negative charge?

Answers

Answer:

E_total = 26.97 N/C

Electric field points towards the positive charge

Explanation:

We are given;

Charge 1; q1 = 6 nC = 6 × 10^(-9) C

Charge 2; q2 = 3 nC = 3 × 10^(-9) C

Distance between both charges; R_o = 2 m

Since we want to find electric field midway, the distance midway is r = 2/2 = 1 m

Using coulumbs law;

E = kq/r²

Where k is a constant with a value of 8.99 × 10^(9) N.m/C²

Thus;

E1 = kq1/r²

E1 = (8.99 × 10^(9) × 6 × 10^(-9))/1²

E1 = 53.94 N/C

Similarly;

E2 = kq2/r²

E2 = (8.99 × 10^(9) × 3 × 10^(-9))/1²

E2 = 26.97 N/C

Since both electric fields are positive, it means that they are both moving towards the midpoint of the distance between both charges.

This implies they will have opposite directions.

Thus, total electric field at the midway point is;

E_total = E1 - E2

E_total = 53.94 - 26.97

E_total = 26.97 N/C

A car accelerates from zero to a speed of 110
km/hr in 15 seconds. What is the car's rate of
acceleration?

Answers

The car's rate of  acceleration : a = 2.04 m/s²

Further explanation

Given

speed = 110 km/hr

time = 15 s

Required

The acceleration

Solution

110 km/hr⇒30.56 m/s

Acceleration is the change in velocity over time

a = Δv : Δt

Input the value :

a = 30.56 m/s : 15 s

a = 2.04 m/s²

If a 500-pound object is moved 200 feet how much work is being done?
a. 200 FT LB
b. 500 FT LB
c. 1000 FT LB
d. 100,000 FT LB

Answers

Answer:

D

Explanation:

Work = Distance x Mass

work done = 100,000 FT LB

What is work done ?

Work is done whenever a force moves something over a distance or The work done by a force is defined to be the product of component of the force in the direction of the displacement and the magnitude of this displacement.

Work done = force * displacement

given :

force = 500 pound

displacement = 200 feet

work done = 500 * 200 = 100,000 FT LB

correct option is d. 100,000 FT LB

learn more about work done

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A spacecraft is flying away from the moon toward earth.

What will be true of the moon’s gravitational pull on the spacecraft?

It will decrease.

It will increase.
It will repel the spacecraft.
It will remain the same.

Answers

Answer:

it will  decrease

Explanation:

According to the law of universal gravitation, the gravitational force exerted by the moon on the spacecraft is equal to the product of their masses and inversely proportional to the square of the distance that separates them. Therefore, as the spacecraft moves away, its distance increases and the force of attraction exerted by the moon decreases.

Answer:

A. It will increase

Explanation:

I took the quiz on K12 and this was the correct option.

Hope I helped

Starting from rest, a wheel with constant angular acceleration turns through an angle of 25 rad in a time t. What will its angular velocity be after 3t?

Answers

Answer:

θ = 225 rad

Explanation:

given data

angle = 25 rad

to find out

angular velocity after 3t?

solution

let angular acceleration α in t

θ = ω × t + 0.5 × α × t²        ........................1

here ω  = 0 (initial velocity )

so put this value here

25 = 0 + 0.5 × α × t²             ..........................2

α = 25 ÷ (0.5 t²)

α = 50 ÷ t²                            .........................3

now here we take in 3t

θ = ω × 3t + 0.5 × α × (3t)²

for ω  = 0

θ = 0 + 0.5 × α × 9t²

now put value in eq 2

so

θ = (0.5) ×  (50 ÷ t²) ×  (3t)²

θ = 25 × 9

θ = 225 rad

Thomas knows that many machines transform electrical energy into other forms of energy

Answers

Question:-
So? Gd for him though

Answer:

Only the car transforms electrical energy into more than one form of energy.

Explanation:

The motion of the car is mechanical energy but it can also transform into another energy witch is electrical energy

Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 4.15 m/sm/s. Her husband Bruce suddenly realizes that she left in such a hurry that she forgot her lunch of bagels, so he runs to the window of their apartment, which is a height 55.2 mm above the street level and directly above the sidewalk, to throw them to her. Bruce throws them horizontally at a time 5.50 ss after Henrietta has passed below the window, and she catches them on the run. You can ignore air resistance.
(a) With what initial speed must Bruce throw the bagels so that Henrietta can catch the bag just before it hits the ground?
(b) Where is Henrietta when she catches the bagels?

Answers

Answer:

Explanation:

Distance travelled by Henrietta in 5.5 s = 4.15 x 5.5 = 22.825 m .

Time taken by lunch of bagels to fall vertically by 55.2 m . Let it be t .

s = ut + 1/2 g t²

55.2 = 0 + .5 x 9.8 x t²

t² = 11.26

t = 3.356 s

By the time the lunch of bagels touches the hand of Henrietta , she would have travelled further by distance

s = 3.356 x 4.15 = 13.9 m

She is now at distance of 22.825 + 13.9 = 36.725 m from window .

So lunch of bagels must travel a horizontal distance of 36.725 m in 3.356 s which the time of fall of bagel .

Speed of bagel = distance / time

= 36.725 / 3.356

= 10.94 m /s

b )

Henrietta is 36.725 m from window at the time when she catches the bangel.

to what temperature it will a 30 KG of glass raise if it absorbs 4275 joules of heat in its specific heat is 0.5 J/KG degree celsius. The initial temperature of the glass is 35°C

Answers

Answer:

230° C

Explanation:

A substance's specific heat tells you how much heat much either be added or removed from 1 g of that substance in order to cause a 1∘C

Iron has a specific heat of o.45 J/g °C. Removing -1.16 E 2 J of energy lowered the temperature of iron from 89 °C to 26.41 °C. What was the mass of the iron?

Answers

Answer:

m = 4.11 grams

Explanation:

Given that,

The specific heat of Iron, c = 0.45 J/g°C

Heat removed, [tex]Q=1.16\times 10^2\ J[/tex]

Initial temperature, [tex]T_i=89^{\circ} C[/tex]

Final temperature, [tex]T_f=26.41^{\circ} C[/tex]

We need to find the mass of the iron. We know that the heat removed in terms of specific heat is given by :

[tex]Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{-1.16\times 10^2}{0.45\times (26.41-89)}\\\\m=4.11\ g[/tex]

So, the mass of the iron is 4.11 grams.

How do projectors project the color black?

Answers

Answer:

Projectors do not project the color black. This makes sense since black is really the absence of light, and you can't project something that does not exist. When a projector sends a beam of light on to a wall or a projector screen so that an image is formed on the wall or screen, the parts of the image that look black are really a very dim white color (which we sometimes call gray).  - wtamu

Answer is:

Projectors do not project the color black.

A motorcycle reaches the speed of 40 m / s, how far does it travel in 10 seconds?

Answers

Answer:

d = 200 m

Explanation:

Data:

Initial Velocity (Vo) = 0 m/s Final Velocity (Vf) = 40 m/s Time (t) = 10 s Distance (d) = ?

Use formula:

[tex]\boxed{d=\frac{Vf+Vo}{2}*t}[/tex]

Replace:

[tex]\boxed{d=\frac{40\frac{m}{s}+0\frac{m}{s}}{2}*10s}[/tex]

Sum in the numerator:

[tex]\boxed{d=\frac{40\frac{m}{s}}{2}*10s}[/tex]

It divides:

[tex]\boxed{d=20\frac{m}{s}*10s}[/tex]

Simplify the seconds (s), and multiply:

[tex]\boxed{d=200\ m}[/tex]

How far does it go?

Travel a distance of 200 meters.

noooooooooooooooooooooooo

Answers

Answer:

yes

Explanation:

Answer:yeeeeeeeeeeeeeeeeeeeeeees

Explanation:

You are inside the Great Hall, 15 m from the north wall with the doors to the RMC, and centered between two open doors that are 3 m apart. Someone is blairing a 200 Hz tone outside the Great Hall so that it enters the doors as a plane wave. You hear a maximum intensity in your current position. As you walk along the direction of the wall with the doors (but maintain a distance 15 m from the wall), how far will you walk (in m) to hear a minimum in the sound intensity

Answers

Answer:

Δr = 0.425 m

Explanation:

This is a sound interference exercise, the expression for destructive interference is

          Δr = (2n + 1) λ / 2

in this case the movement is in the same direction as the sound, therefore the movement is one-dimensional

let's use the relationship between the speed of sound and its frequency and wavelength

          v = λ f

          λ = v / f

the first minium occurs for n = 0

           Δr = λ / 2

            Δr = v / 2f

            Δr = [tex]\frac{340}{2 \ 400}[/tex]

             Δr = 0.425 m

this is the distance from the current position that we assume in the center of the room

A baseball player hits a baseball. The mass of the ball is 0.15 kg. The ball accelerates at a rate of 60 m/s 2 . What is the net force on the ball to the nearest newton?

Answers

Answer:

Please find attached pdf

Explanation:

During a storm, a car traveling on a level horizontal road comes upon a bridge that has washed out. The driver must get to the other side, so he decides to try leaping the river with his car. The side of the road the car is on is18.0 m above the river, while the opposite side is only1.8 m above the river. The river itself is a raging torrent69.0 m wide.Part AHow fast should the car be traveling at the time it leaves the road in order just to clear the river and land safely on the opposite side?Part BWhat is the speed of the car just before it lands on the other side?

Answers

Answer:

Part A: The speed the car should be travelling when leaping the river is approximately 37.948 m/s

Part B: The speed of the car just before it lands is approximately 41.92345 m/s

Explanation:

The parameters of the car attempting leaping the river are;

The height of the car over the river = 18 m

The height of the opposite side of the bridge above the river = 1.8 m

The width of the river, x = 69.0 m

Part A

The time, 't' it would take the car to fall from 18 m above the river to 1.8 m above the river is given as follows;

t = √(2·h/g)

Where;

h = The height of the fall = 18 m - 1.8 m = 16.2 m

g = The acceleration due to gravity = 9.8 m/s²

∴ t = √(2×16.2 m/(9.8 m/s²)) = (9/7)·√2 s

The horizontal speed, 'vₓ', with which the car should be travelling at the time it leaves the road in order just to clear the river and land safely on the opposite side is given as follows;

vₓ = x/t = 69.0 m/((9/7)·√2 s) = (161/6)·√2 m/s ≈ 37.948 m/s

The horizontal speed the car should be travelling when leaping the river, vₓ ≈ 37.948 m/s

Part B;

The vertical velocity of the car is given as follows;

[tex]v_y[/tex]² = [tex]u_y[/tex]² + 2·g·h

∴ [tex]v_y[/tex]² =2·g·h = 2 × 9.8 m/s² × 16.200 m = 317.52m²/s²

[tex]v_y[/tex] = √(317.52 m²/s²) = (63/5)·√2 ≈ 17.819 m/s

The magnitude of the speed of the car, 'v', just before it lands is given using Pythagoras' theorem for resultant vectors as follows;

v = √([tex]v_y[/tex]² + vₓ²) = √(317.52 m²/s² +((161/6)·√2 m/s)²) ≈ 41.92345 m/s

The speed of the car just before it lands, v ≈ 41.92345 m/s.

50 points Two waves combine with constructive interference. What must be true of the
combined wave that forms?
A. It has a lower frequency than that of the original waves.
B. It has a higher amplitude than that of the original waves.
C. It has a higher frequency than that of the original waves.
D. It has a lower amplitude than that of the original waves.

Answers

Answer:

it has a higher amplitude than that of the original waves

Explanation:

trust me its right

The two waves combined with constructive interference have a higher amplitude than the original wave.

Which wave has the highest amplitude?

High energy waves are characterized by high amplitude. Low energy waves are characterized by their small amplitude. As explained in Lesson 2, wave amplitude is the maximum amount of particle movement on a medium from a resting position.

What are superposition and interference?

Superposition is a combination of two waves in the same place. Constructive interference occurs when two identical waves interfere in phase. Destructive interference occurs when two identical waves are exactly out of phase and overlap.

Learn more about higher amplitude waves at

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A wall clock has a minute hand with a length of 0.46 m and an hour hand with a length of 0.24 m. Take the center of the clock as the origin, and use a Cartesian coordinate system with the positive x axis pointing to 3 o'clock and the positive y axis pointing to 12 o'clock. Write the vector that describes the displacement of a fly if it quickly goes from the tip of the minute hand to the tip of the hour hand at 3:00 P.M. (Let vector D represents the displacement of the fly.)

Answers

Answer:

the vector that describes the displacement of a fly if it quickly goes from the tip of the minute hand to the tip of the hour hand at 3:00 P.M is ; { 0.24 m(i) - 0.46 m(j) }

Explanation:

Given the data in the question;

as illustrated in the image below,

3:00 pm means

the hour hand is on 3 i.e along x-axis

while the minute hand is on 12 i.e along y-axis

so Displacement will be;

D = ( 0.24 + 0i) - ( 0 + 0.46j )

D = { 0.24 m(i) - 0.46 m(j) }

Therefore, the vector that describes the displacement of a fly if it quickly goes from the tip of the minute hand to the tip of the hour hand at 3:00 P.M is ; { 0.24 m(i) - 0.46 m(j) }

Calculate the electric field associated to an electric dipole for two charges separated 10-8 m with a dipole moment of 10-33 C m. Do not use unit of measure, just a whole number. Give the result in standard notation, not in scientific notation. Use for the Coulomb constant the value k

Answers

Answer:

18 N/C

Explanation:

Given that:

Electric field constant, k = 9*10^9 N/c

Distance, r = 10^-8 m

Dipole moment, p = 10^-33

Using the relation for electric field due to dipole :

E = [2KP / r³]

E = (2 * (9*10^9) * 10^-33) ÷ (10^-8)^3

E = (18 * 10^9 * 10^-33) ÷ 10^-24

E = [18 * 10^(9-33)] ÷ 10^-24

E = (18 * 10^-24) / 10^-24

E = 18 * 10^-24+24

E = 18 * 10^0

E = 18 N/C


The kinetic theory states that the higher the temperature, the faster the

Answers

Answer: the higher the kinetic energy

Explanation:

What is the momentum of a 0.000015 kg mosquito flying straight at you with a velocity of 5.20 m/s?

Answers

Answer:

Momentum, [tex]p=7.8\times 10^{-5}\ N-m[/tex]

Explanation:

Given that,

Mass of a mosquito, m = 0.000015 kg

Velocity of the mosquito, v = 5.2 m/s

We need to find the momentum of the mosquito. The momentum of an object is given by :

p = mv

Put all the values in the above formula.

[tex]p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m[/tex]

So, the momentum of the mosquito is [tex]7.8\times 10^{-5}\ N-m[/tex].

Surface Features on earth combine to form the(blank) or area ,Will mark brainliest if someone give’s me the word that fit’s in there.

Answers

i believe it’s topography


A lunar eclipse occurs when the Moon passes through Earth's

Answers

False, when the moon passes between the earth and sun it’s a solar eclipse and lunar eclipse happens when earth passes between the moon and sun

Pls help!!
1 example of a conductor and 1 example of a insulator in your EVERYDAY world.

Answers

Answer:

here

Explanation:

Examples of insulators include plastics, Styrofoam, paper, rubber, glass and dry air.

Examples of conductors include metals, aqueous solutions of salts

Conductor= Metals are good conductors of heat, therefore cooking utensils, kettles, irons, boilers, are always made up of iron, copper, Aluminum, or their alloys.


Insulators= oppose electrical current and make poor conductors. Some common conductors are copper, aluminum, gold, and silver. Some common insulators are glass, air, plastic, rubber, and wood.

Hope it helps! :3

6th grade science I mark as brainliest !

Answers

Number 3 is atoms and number 4 is true text me if you get this right

Answer:

first is Atoms

4) is True

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