The image shown here is a good illustration of which law?

Answer:

See explanation below

Explanation:

In this case we have reaction of addition. In this case a diene reacting with an acid as HBr. This reaction is known as Hydrohalogenation, and, as we have a diene, this kind of reaction can be done as 1,4 addition. Which means that the reaction will be undergoing with an adition in the carbon 1, and carbon 4.

At room temperature we can expect that this reaction can be done in thermodynamic conditions, Now, as the problem states that is forming 4 products, we can expect products of a 1,2 addition too. This product can be formed if the reaction is taking place in the most stable carbocation, and then, by resonance, we can expect the 1,4 product too.

Now, the HBr can be attacked by the double bond of the first position, giving two possible products or by the double bond of the third position giving the other two products. These products are all possible, obviously the most stable will be the major of all of them, but the other three are perfectly possible. One product is formed without doing much, and the other by resonance. Same happens with the other double bond.

In the picture below, you have the mechanism for all the 4 products.

Hope this helps

Answer:

four A

Explanation:

Answer: B) One

Explanation: One carbon dioxide molecule should be added to the products side to balance the equation and obey the law of conservation of matter.

Also, just took the test. One is correct.

Answer:

jayfeather friend me

Explanation:

Table 1. Summary of the Straight-Chain Alkanes

Name Formula Number of Structural Isomers

Octadecane C18H38

Nonadecane C19H40

Eicosane C20H42 366,319 (!)

29 more rows

The formula of the alkanes the molecule contains 28 hydrogen atoms is [tex]C_1_3H_2_8[/tex], i.e., tridecane.

Alkanes are organic compounds made up entirely of single-bonded carbon and hydrogen atoms with no other functional groups.

Alkanes have the general formula CnH2n+2 and are classified into three types: linear straight-chain alkanes, branched alkanes, and cycloalkanes.

Alkanes are important raw materials in the chemical industry and the main component of gasoline and lubricants.

Natural gas is primarily composed of methane and ethane and is used for heating, cooking, and power generation (gas turbines).

Natural gas and petroleum are separated from the alkanes. Natural gas is primarily composed of methane, with trace amounts of other low molecular weight alkanes.

All other alkanes are derived from petroleum, which is a complex mixture of many compounds.

Here, the formula for 28 hydrogen atom containing alkane is

[tex]C_1_3H_2_8[/tex]

Thus, this given formula is of tridecane.

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Answer:

The equilibrium concentrations of HF = 0.058 , F2 = 0.006M , HClO =0.16M , and ClO2 = 7.7 × 10⁻⁷M.

Explanation:

The Ka values for HClO₃ and HF are given as 2.9 × 10⁻⁸ and 6.6 × 10⁻⁴ respectively. The molar concentration for HF = 0.23/ 3.60L = 0.064 M and 0.57/ 3.60 = 0.16 M.

When HF is reacted with water, it ionizes to form H₃O⁺ and F⁻. The concentration of H₃O⁺ and F⁻ can be calculated below:

HF(aq) <------------------------> H30^+ + F^-.

Ka = [H^+] [F^-]/[HF] .

6.6× 10^-4 = [x][x]/ ( 0.064- x).

x = 0.0060 M.

The concentration of H₃O⁺ and F⁻ = 0.0060 M respectively.

The pH = - log [ H₃O⁺ ] = -log [0.0060] = 2.22.

When HClO is reacted with water, it ionizes to form H₃O⁺ and F⁻. The concentration of H₃O⁺ and ClO⁻ can be calculated below:

HClO(aq) <------------------------> H30^+ + ClO^-.

Ka = [H^+] [ClO^-]/[HClO] .

6.6× 10^-4 = [0.006 + x] [x]/ ( 0.16 - x).

x = 7.7 × 10^-7M.

[ClO^-] = 7.7 × 10^-7 M.

[HClO] = 0.16 - 7.7 × 10^-7 = 0.16M.

[F^-] = 0.006 M.

[HF] = 0.064 - 0.006 = 0.058 M.

Answer:

[tex]\mathbf{C_{Out} = C_o \ exp \Big [ - \Big ( \dfrac{1}{\dfrac{V}{Q} } + k \Big) t \Big ] }[/tex]

Explanation:

The equation that describes the concentration of the radon in the basement with time Ct is;

[tex]\mathbf{C_{Out} = C_o \ exp \Big [ - \Big ( \dfrac{1}{\theta} + k \Big) t \Big ] }[/tex]

where;

[tex]C_o[/tex] = concentration of the radon

[tex]C _ {Out}[/tex] = allowable radon concentration

k = decay rate constant

= theoretical detention

t = time needed to lower the radon concentration

The theoretical detention [tex]\theta =\dfrac{V}{Q}[/tex]

∴

[tex]\mathbf{C_{Out} = C_o \ exp \Big [ - \Big ( \dfrac{1}{\dfrac{V}{Q} } + k \Big) t \Big ] }[/tex]

Answer:

92.6

Explanation:

6 mol x 18.02 g of H2o --> 3 mol x 58.33 g  Mg(OH)2

108.12 g of h2o --> 174.99 of Mg(OH)2

g of H2O is 150 g of Mg(OH)2

150g x 108.12g / 174.99 =

92.67

Answer:

More exactly this number is 6.02 x 1023 10 2 3 .

Answer:

Option B. 100 N in row one and 30 N in row two

Explanation:

To know the the correct answer to the question, do the following:

For Row 1:

Force to the right (Fᵣ) = 100 N

Net force (Fₙ) = 0 (since it is balanced)

Force to the left (Fₗ) =?

Fₙ = Fᵣ – Fₗ

0 = 100 – Fₗ

Collect like terms

0 – 100 = – Fₗ

– 100 = – Fₗ

Multiply through by –1

Fₗ = 100 N

For Row 2:

For the net force to be unbalanced, it means that one of the force is greater or lesser than the other.

In the question given above, the force to the left is given as 50 N and it show it is greater than the force to be right. The other force must be lesser than 50 N to result in unbalanced force according to the illustration from the question.

From the options given above, option B has a lesser force (i.e 30 N) for row 2 compared to option C which has a greater force (60 N) for row 2.

Therefore, option B gives the correct answer to the question.

Answer:

Very dense.

Explanation:

Conceptually, you are taking a large amount of atoms and putting them into a small container.  This means the spaces between atoms has to be smaller and the substance is more dense. (see image)

Mathematically, the equation for density is mass divided by volume ([tex]Density=\frac{m}{v}[/tex] ). If you divide a big number by a small number, you still have  a pretty big number (ex 4/2=2 versus 6/1=6)

Answer:

water

Explanation:

water is made up of both hydrogen and oxygen (h2o)

Answer:

B highlands and polar, very little percipitation is found in polar regions, and high lands contributes to that

Explanation:

Answer:

B!

Explanation:

got it right on quiz. edu2021

Answer:

215.9 cm

Explanation:

1 foot= 30.5cm

30.5cm times 7 1/12=215.9cm

The given height of David is 7 ft, 1.0 inch, so in centimeters, the height will be 216.4 cm.

A conversion factor is a number that is used to multiply or divide one set of units into another. When converting to an equal value, the appropriate conversion factor must be used.

We must convert one unit to another in order to achieve accuracy and avoid measurement confusion.

We do not, for example, measure the length of a pencil in kilometers. In this case, one must convert kilometers (km) to centimeters (cm) (cm).

To convert feet to centimeters, multiply the given foot length by 30.48 cm.

So,

Height in cm will be = 7.1 x 30.48

Height in cm = 216.4cm

Thus, the height of David in centimeters is 216.4 cm.

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Answer:

1 g/cm3

Explanation:

The formula for density is mass/volume

The mass is 100 g and the volume is 100 cm3

100 g/100 cm3=1 g/cm3

Answer:

Melting: the substance changes back from the solid to the liquid. Condensation: the substance changes from a gas to a liquid. Vaporization: the substance changes from a liquid to a gas. Sublimation: the substance changes directly from a solid to a gas without going through the liquid phase.

Explanation:

The change in appearance of a substance when it changes its phase includes :

Change in volume : when a liquid substance is heated to its boiling point ( vaporization) the volume of the liquid substance will change when it turns into gas because gases have no definite volume or shape.

Change in Texture: When water freezes it changes its state from a liquid state to a solid state, also the appearance of the liquid water will undergo changes in its texture when it is in its' solid state ( i.e. the texture of ice is not exactly the texture of liquid water )  

Change in shape : when a solid substance changes its state from solid to gas ( sublimation ) the shape of the solid substance will be lost during the phase change.

Hence we can conclude that the change in the appearance of a substance when it changes its phase include. Change in volume, Change in texture and Change in shape.    

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Answer:

side-by-side, or lateral orbital overlap with the electron density concentrated on opposite sides of the internuclear axis.

Explanation:

Pi bond is a type of covalent bond in which the internuclear axis has regions of orbital overlap below and above it i.e on opposite sides. As a result of the orbital overlap, a node is created along the internuclear axis.

This ultimately implies that, a pi bond is formed due to the lateral (side-by-side) overlap of the unhybridized P-orbital comprising of at least a node along the internuclear axis.

Hence, a pi bond involves side-by-side, or lateral orbital overlap with the electron density concentrated on opposite sides of the internuclear axis.

Additionally, a node is typically formed where an electron cannot be found.

Answer:

those both are fossil fuel but coal is used for electricity,Petroleum is used for bikes

Answer:

C) Mass

Explanation:

Answer:

Explanation:

1:) A

Mostly just use context clues

2:) D

The climate on earth is mostly due to earth's atmosphere. So, no, the moon doesn't have similar weather

Answer:

1-butene

Explanation:

In this case, the problem is already stating and saying the reaction involved here.

1-bromobutane undergoes a dehydrohalogenation in presence of a base. This will cause an elimination reaction forming a product.

As this is an elimination product, this can be done in two ways.

The first way is with an unimolecular reaction where the halide is eliminated from the starting reactant in a two step reaction involving a carbocation formation. This is known as E1 reaction. However, the conditions for this reaction is to be in acid medium.

The second way is with a bimolecular reaction where the halide is eliminated from the starting reactant in just one step, and no carbocation is formed. This is known as E2 reaction and is commonly used with bases.

In the case of this problem, we are undergoing an E2 reaction, therefore, the mechanism of reaction is just one step, and when this happens, the base substract the hydrogen from Carbon 2, eliminates the bromide and forms a double bond, giving the 1-butene.

You can see the mechanism in the following picture.

Hope this helps

1-butene is the organic byproduct of 1-bromobutane's dehydrohalogenation in the presence of a base.

In the process of dehydrohalogenation, a molecule loses both a hydrogen and a halogen atom (such as a halogen from chlorine, bromine, or iodine) to create an unsaturated compound. The production of alkenes or alkynes, which are crucial in organic chemistry, is frequently accomplished using this reaction. Eliminating a hydrogen halide (HX) from a halogenoalkane or alkyl halide is the most important step in dehydrohalogenation. The E1 and E2 reactions are the two basic processes that can be used to do this. There are two steps in the E1 reaction. The halogenoalkane first passes through ionisation and creates a carbocation intermediate.

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Answer:   Chemical Change

Explanation:

because it probably doesnt change the physical anatomy of the object only the atoms/ molecule relations

Answer:

1. The Earth's orbit around the Sun is an ellipse, but it does change shape. ...

The tilt in the axis of the Earth is called its obliquity

Explanation:

2.Volcanic eruptions pump out clouds of dust and ash, which block out some sunlight.

Answer:

44.84 ml

Explanation:

14.86

+

15.0

+

14.980

_______

44.84

Answer:

Oh, you are supposed to look up the yearly temp, and yearly rain for a certain area. I did this before!

Answer:

Theres no drawing

Explanation:

Show drawing

Skeletal structural diagram and bond-line drawing are similar;

Parts of the question appear missing: The number of hydrogen atoms in the attached example bond-line drawing is 6 hydrogen atoms

The reason the above value is arrived at for the attached example bond-line diagram is as follows;

A bond-line drawing is the diagram showing the molecular structure of a compound, such that covalent bonds within the molecule are represented by lines with the number of lines indicating the number of covalent bonds.

A single covalent bond is represented by one line, double bonds by two lines while three parallel lines represents a triple bond.

In bond-line drawing, the lines symbolically infer the carbon to carbon bonds while the bonds to the hydrogen atoms are implied noting that each carbon has four covalent bonds. Hydrogen atoms attached to other heteroatoms are indicated with an H.

The number of hydrogen shown in the example diagram can be found by noting that the number of covalent bonds between the carbon atoms are three, therefore, the atom of the fourth bond not shown with a line is to a hydrogen atom

There are six such carbon atoms, one of which is attached to an oxygen atom, which gives five hydrogen atoms located on the ring

There is one more hydrogen atom attached to the oxygen in the hydroxyl group, the total number of hydrogen is therefore;

5 hydrogen on ring + One hydrogen in the hydroxyl group = 6 hydrogen atoms

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Answer:

It would be the Mantle,I believe

Answer:

26.7

Explanation:

The reaction that takes place is:

We convert the given masses to moles, using their respective molar masses:

The initial concentrations for each species are:

While the equilibrium concentration for CH₃OH, [CH₃OH]eq is:

We put the data in a table:

            CO      + 2H₂    ↔    CH₃OH

initial    0.185        0.225      ↔      0

eq          (0.185 - x) (0.225-2x)  ↔  x

We know that x = 0.052 M (That's the equilibrium concentration of CH₃OH).

We proceed to calculate [CO]eq and [H₂]eq:

Finally we calculate the equilibrium constant:

The equilibrium constant (Kc) for the reaction at this temperature is 26.7

CO + 2H₂   ⇄   CH₃OH

CO ⇒ [tex]\frac{26.9 g}{28 g/mol} = 0.961 mol[/tex]

H₂ ⇒  [tex]\frac{2.34 g }{ 2 g/mol} =1.17 mol[/tex]

CH₃OH ⇒ [tex]\frac{8.65 g}{32 g/mol} = 0.270 mol[/tex]

CO ⇒ [tex]\frac{0.961 mol}{5.19 L} = 0.185 M[/tex]

H₂ ⇒  [tex]\frac{1.17 mol}{5.19 L } = 0.225 M[/tex]

CH₃OH ⇒ 0

[tex]\frac{0.270 mol}{ 5.19 L} = 0.052 M[/tex]

We put the data in a table:

                                  CO   +   2H₂   ⇄    CH₃OH

Initial                         0.185        0.225           0

Equilibrium              (0.185 - x) (0.225-2x)    x

x = 0.052 M (That's the equilibrium concentration of CH₃OH).

We proceed to calculate [CO]eq and [H₂]eq:

[tex][CO]_{eq}= 0.185 - 0.052 = 0.133 M\\\\\\[H_2]_{eq} = 0.225 - 2*0.052 = 0.121 M[/tex]

[tex]K_c =\frac{[CH_3OH]_{eq}}{[CO]_{eq}[H_2_{eq}]^2} = 26.7[/tex]

Thus, the equilibrium constant (Kc) for the reaction at this temperature is 26.7

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Answer:

Hope this help you

Explanation:

The answer is 261.3368. We assume you are converting between grams Barium Nitrate and mole. You can view more details on each measurement unit: molecular weight of Barium Nitrate or mol The molecular formula for Barium Nitrate is Ba(NO3)2.

Answer:

0.382

Explanation: