there are 160 girls and 240 boys in a school
i. find the percent of girls in the school
ii. find the percent of boys in the school.​

Answers

Answer 1

Answer:

girls = 40%

boys = 60%

Step-by-step explanation:

Girls = 160

boys = 240

total students = 160+240

= 400

so,

percent of girls = (160/400)×100%

= (2/5)×100%

= 2×20%

= 40%

so,

percent of boys = 100% - 40%

= 60%


Related Questions

8xy + 3xy + x
please help, no wrong answers, thank you!

Answers

8xy + 3xy + x

= 11xy + x

= x(11y +1)

Write an equivalent expression for each of the following. Express your answers in the form a + bi or a - bi

(5 + i)(9 + i)

Help please

Answers

Answer:

44 +14i

Step-by-step explanation:

(5 + i)(9 + i)

FOIL

first 5*9 = 45

inner: 9i

outer :5i

last: i*i = i^2 = -1

Add togheter

45 + 9i+5i -1

Combine like terms

44 +14i

Find the volume of the prism.

Answers

Answer:

11,968

Step-by-step explanation:

I'm not sure, but I think its 11,968

a teacher bought sweets for her 40 students . if she gave each student 3 sweets , she would have 5 sweets left . How many sweets did she buy?​

Answers

Answer:

125 sweets

Step-by-step explanation:

Let the total # of sweets the teacher bought be the variable, x.

We can set up this equation to find the # of sweets she bought:

40 · 3 + 5 = x

Because she gave 3 sweets each to her 40 students, we have to multiply these two numbers to get the # of sweets the teacher gave out.

120 + 5 = x

Then, since there's 5 extra sweets left, we can add it to the # of sweets the teacher gave out to get the total amount of sweets she bought.

125 = x

x = 125

125 sweets

Answer:

Total sweets = 125

Step-by-step explanation:

Number of sweets given to each student = 3

Number of sweets given to 40 students = 40*3 = 120

Number of sweets left with the teacher = 5

Total sweets = 120 + 5 = 125

cosec^2θ-1/cosec^2θ=cos^2θ​

Answers

cosec(2t)=1/sin(2t) ==> 1/(2×cos(t)×sin(t))

cos(2t)= 1-2sin²t

or 2cos²t-1

or cos²t - sin²t

after we knew this informations we have to write it in the question

1/2×sint×cost-1/1/2×sint×cost=cos2t

-2×sint×cost+1/2sint×cost/1/2sint×cost=cos2t

the 2sint×cost will gone

-2×sint×cost+1=cos2t

lets take cos2t =1-2sin²t

-2×sint×cost+1=1-2sin²t

-2sint×cost=-2sin²t

cost=sint

that means the t is equal to 45 because sin45 and cos45 equal to √2/2

hopefully i didn't waste your time by reading and not understanding my English is not that good sorry

Answer:

see explanation

Step-by-step explanation:

Using the identities

cosec x = [tex]\frac{1}{sinx}[/tex]  , 1 - sin²θ = 1

Consider the left side

[tex]\frac{cosec^20-1}{cosec^20}[/tex]

= [tex]\frac{\frac{1}{sin^20}-\frac{sin^20}{sin^20} }{\frac{1}{sin^20} }[/tex]

= ( [tex]\frac{1}{sin^20}-\frac{sin^20}{sin^20}[/tex] ) × [tex]\frac{sin^20}{1}[/tex] ← distribute parenthesis by sin²θ

= 1 - sin²θ

= cos²θ

= right side, thus proven

Which are corresponding pairs​

Answers

Answer:

pandn

Step-by-step explanation:

jsubeuodoqok1kwnebhxhhw

emdndiiwjwkd

d

ddnjd

PLEASE HELP!
The table shows a representation of the number of miles a car drives over time.

A 2-column table with 4 rows. Column 1 is labeled Hours, x with entries 3, 4, 5, 6. Column 2 is labeled Miles, y with entries 195, 260, 325, 390. Pattern: Each x value is multiplied by 65 to get each y value.

What is the equation for this situation?
y = 195 +3
y = 195
y = 65 +3
y = 65


Which could NOT be a point on this table?
2, 130
8, 445
1, 65
11, 715

Answers

Y= 65+3 would not be a point on the current table

Answer:

y=65x      and      8455 there yall go

Step-by-step explanation:

A car covers a distance of 132 km. If each tire’s diameter is 42 cm, how many rotations does each tire make in covering this distance?

Answers

Answer:

Step-by-step explanation:

Diameter (D)= 42cm

Circumference = (pie)D= (22/7)*D=(22/7)*42 = 132cm

1 circumference = 1 revolution

1 revolution = 132cm = 1.32m

for covering 5.28km no. of revolution = 5.28*1000/1.32 = 4000

Hope this answer helps you :)

Have a great day

Mark brainliest

I need help on this A box contains 3 red, 4 green, and 3 yellow balls. If a ball is drawn at random, find the probability that the ball is red.

Answers

Answer:

3/10

Step-by-step explanation:

3 red, 4 green, and 3 yellow balls = 10 balls

P(red) = number of red balls / total balls

           = 3/10

What is the total surface area of a cuboid with length 16cm, width 8cm and height 6cm?

Answers

Answer:

Step-by-step explanation:

The dimensions as a pair, appear twice for each combination.

SA = 2* 16 * 8 + 2 * 16 * 6 + 2*8* 6

That's because when you look at the figure, there are 2 places each face is positioned.

SA = 256 + 192 + 96

SA = 544


Please help out explanation need it will

Answers

You just have to divide all of it and then round it to the nearest tenths if u need too .

Answer:

A=2(wl+hl+hw)

A=2(6ft×7ft+6ft×7ft+6ft×6ft)

A=2(42ft²+42ft²+36ft²)

A=2(120ft²)

A=240ft²

Step-by-step explanation:

If SP and CP of an article is Rs. x and Rs. y, write the formulae to find profit and loss percentage.​

Answers

Answer:

profit= sp-cp

loss %= loss ×100%/cp

=(cp-sp) ×100%/cp

= (1-sp)×100%/cp

A bag contains five white balls and four black balls. Your goal is to draw two black balls. You draw two balls at random. What is the probability that they are both black

Answers

Answer:

0.1667 = 16.67% probability that they are both black.

Step-by-step explanation:

The balls are drawn without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

5 + 4 = 9 balls, which means that [tex]N = 9[/tex]

4 are black, which means that [tex]k = 4[/tex]

2 are chosen, which means that [tex]n = 2[/tex]

What is the probability that they are both black?

This is P(X = 2). So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 2) = h(2,9,2,4) = \frac{C_{4,2}*C_{5,0}}{C_{9,2}} = 0.1667[/tex]

0.1667 = 16.67% probability that they are both black.

hi pls help. thank you sm:) have a good night/day!

Answers

Answer:

Step-by-step explanation:

a.)

[tex]14*2^x[/tex]

b.)

[tex]14*2^7=1792[/tex]

-3x(3x+5)(3x-4) help pls

Answers

Answer:

-3x(3x+5)(3x-4)

= -(9x²+15x)(3x-4)

= -27x³-9x²+60x

Answered by GAUTHMATH

plss help me with this :(​

Answers

Answer:

(k) cos(θ)·√(1 + cot²θ) = √(cosec²θ - 1)

From trigonometric identities, we have;

1 + cot²θ = cosec²θ

On the Left Hand Side of the equation, we get;

cos(θ)·√(1 + cot²θ) = cos(θ) × cosec(θ) = cot(θ)

On the Right Hand Side of the equation, we have;

√(cosec²(θ) - 1) = √(1 + cot²(θ) - 1) = √(cot²(θ)) = cot(θ)

∴ √(cosec²θ - 1) = cot(θ)

By transitive property of equality, therefore;

cos(θ)·√(1 + cot²θ) = √(cosec²θ - 1)

(l) sin⁶A + cos⁶A = 1 - 3·sin²A·cos²A

sin⁶A + cos⁶A = (sin²A)³ + (cos²A)³

(sin²A)³ + (cos²A)³ = ((sin²A) + (cos²A))³ - 3·((sin²A)·(cos²A))·((sin²A) + (cos²A))

∴ (sin²A)³ + (cos²A)³ = (1)³ - 3·((sin²A)·(cos²A))·(1) = 1 - 3·((sin²A)·(cos²A))

sin⁶A + cos⁶A = (sin²A)³ + (cos²A)³ = 1 - 3·((sin²A)·(cos²A))

sin⁶A + cos⁶A = 1 - 3·((sin²A)·(cos²A))

(m) (sinA - cosecA)² + (cosA - secA)² = cot²A + tan²A - 1

(sinA - cosecA)²  = sin²A - 2×sinA×cosecA + cosec²A = sin²A - 2 + cosec²A

(cosA - secA)² = cos²A - 2×cosA×secA + sec²A = cos²A - 2 + sec²A

∴ (sinA - cosecA)² + (cosA - secA)² = sin²A - 2 + cosec²A + cos²A - 2 + sec²A

Where;

sin²A - 2 + cosec²A + cos²A - 2 + sec²A = sin²A + cos²A  - 2  - 2 + cosec²A + sec²A

sin²A + cos²A  - 2  - 2 + cosec²A + sec²A = 1 - 4 + cosec²A + sec²A

1 - 4 + cosec²A + sec²A = cosec²A + sec²A - 3

Where;

cosec²A = cot²A + 1

sec²A = tan²A + 1

∴ cosec²A + sec²A - 3 = cot²A + 1 + tan²A + 1 - 3 = cot²A + tan²A - 1 = The Right Hand Side of the equation

∴ (sinA - cosecA)² + (cosA - secA)² = cot²A + tan²A - 1

(n) [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex] = sinA - cosA

Squaring the Right Hand Side of the equation, we get;

(sinA - cosA)² = sin²A -2·sinA·cosA + cos²A = sin²A + cos²A -2·sinA·cosA

sin²A + cos²A -2·sinA·cosA = 1 - 2·sinA·cosA

∴ (sinA - cosA)² =  1 - 2·sinA·cosA

Taking the square root of both sides gives;

√((sinA - cosA)²) = [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex]

∴ sinA - cosA = [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex]

By symmetric property of equality, we have;

[tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex] = sinA - cosA

Step-by-step explanation:

anyone know number 11 please

Answers

Step-by-step explanation:

1. 22/60

2. LCM..of 3,9 is 9

So, 3+2/9 ( made the denominators equal)

5/9 Answer

Answer:

which of these fraction is not equivalent to 2/5 is 22/60

b) work out 1/2 + 2/9 = 5/9

Find the volume of the prism. Round to the nearest tenth.

Answers

Answer:

829.6

Step-by-step explanation:

Volume = sh

= (5+12) x 6.1 / 2 x 16

= 12 x 6.1/2 x 16

= 17 x 6.1 x 8

= 829.6 mi^3

Answered by Gauthmath

what is value of y if 2x+3y=4​

Answers

Answer:

y=(4-2x)/3

Step-by-step explanation:

3y= 4-2x

y= (4-2x)/3

ANSWER QUICK! MANY POINTS! NO WRONG ANSWERS PLEASE!

1. Use the table and the graph to answer the questions.

Function 1
x: -1 -2 -3 2 3
y: 3 5 7 -3 -5

Function 2
(see picture below)

a) What is the rate of change for each function? Show your work.
b) Which function has the greater rate of change?

Answers

Answer:

see below

Step-by-step explanation:

Function 1

Find the slope

m = ( y2-y1)/ (x2-x1)

   = (-5 -3) /(3 - -1)

   = ( -5-3)/(3+1)

   = -8/4

   = -2

Function 2

Using the points (0,4) and (-1,0)

m = ( y2-y1)/ (x2-x1)

m = ( 0-4)/(-1-0)

   = -4/-1

    = 4

The function with the greater rate of change is function 2

#Function 1

(-1,3)(-2,5)

Slope=

m=5-3/-2+1m=2/-1m=-2

#Function 2

(-1,0)(0,4)

Slope

m=4/1m=4

Function 2 has greater rate of change

Helpp mee please i need help i am stuck

Which statements are true? Check all that apply.

-2.5 = -2 1/2
-1.5 > -0.5
-0.5 < 0
-2.5 < -2
- 1/2 > 1.5

Answers

First, third, and fourth are all true.

Which functions have a removeable discontinuity? Check all that apply.

Answers

Answer:

It already shows the answers.

Step-by-step explanation:

I'm pretty sure you already submitted. The ones with check marks are correct and the ones with x marks are incorrect.

P =5000 T =2year R =7%find simple intreset ​

Answers

Answer:

5070

Step-by-step explanation:

Total = P(1+rt) =5000(1+0.007*2) =5070

If the question is asking about the amount of interest earnt, its 70

See screenshot below​

Answers

Answer:

cos theta = -1/ 2

Step-by-step explanation:

sin theta = -sqrt(3)/2

Drawing a triangle

We know sin theta = opp/hyp

We can determine the adj side using the Pythagorean theorem

a^2 + b^2 = c^2

adj^2 + (-sqrt(3))^2 = 2^2

adj^2 +3 = 4

adj^2 = 4-3

adj ^2 =1

Taking the square root of each side

adj = 1

We know that since it is in the third quadrant the adj side is negative

adj = -1

cos theta = adj / hyp

cos theta = -1/ 2

Answer:

Solution given:

Sin[tex]\theta_{1}=\frac{-\sqrt{3}}{2}[/tex]

[tex]\frac{opposite}{hypotenuse}=\frac{-\sqrt{3}}{2}[/tex]

equating corresponding value

opposite=-[tex]\sqrt{3}[/tex]

hypoyenuse=2

adjacent=x

By using Pythagoras law

hypotenuse²=opposite²+adjacent²

2²=-[tex]\sqrt{3²}[/tex]+x²

4=3+x²

x²=4-3

x=[tex]\sqrt{1}=1[/tex]

x=-1

In third quadrant

Cos angle is negative

Cos[tex]\theta_{1}=\frac{-adjacent}{hypotenuse}[/tex]

Cos[tex]\theta_{1}=\frac{-1}{2}[/tex]

Divide Rs.45000 among 2 students Mina and Rita in the ratio of marks they got 40 and 50 respectively

Answers

Let

Money share of Mina=40xMoney shae of Rita=50x

ATQ

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 40x+50x=45000[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 90x=45000[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow x=\dfrac{45000}{90}[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow x=500[/tex]

Now

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow Rita=50x=50(500)=25000[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow Mina=40x=40(500)=20000[/tex]

What is the length of AC

Answers

Answer:

x=9 ⇒AC=24

Step-by-step explanation:

vì DE//B C⇒ΔABC  Tương ung ti tỉ lệ vớiv  ΔADE

⇒DB/AB=EC/AC

⇒AC=(EC.AB)/DB

⇒AC=24

The foot of a ladder is placed 10 feet from a wall. If the top of the ladder rests 13 feet up on the wall, find the length of the ladder.

Answers

10 squared + 13 squared = your answer squared.
So do that then take the square root of whatever you get.

The cube with side 2 is cut from the corner of rectangular prism with dimensions 4×3×5. Find the volume and total surface area of the new object.

Answers

Answer:

Volume: 52 Units Squared

Surface Area: 94 units.

Step-by-step explanation:

The volume is relatively simple to find. Just subtract the original volume by the 2x2x2 cube's volume. The original volume is 60. The cube's volume is 2x2x2 which is 8. 60-8=52.

The surface area is harder to find. Try to envision the corner of the rectangle being cut out. We see that each side of the cube has a surface area of 2x2 which is 4. In the picture, we see that three sides of the rectangle has been partially removed. But since each side of the cube has an equal surface area, it is safe to minus 3 of the sides that has been partially removed by 3. However, since that it is the corner, the "dent" that the cube made in the rectangle also needed to be counted. As we said, each of the sides of a cube has a surface area of 4, so since that the dent has 3 sides, we see that the surface area of the dent is 4x3 which is 12. Now we need to count the unaffected sides of the rectangle. There are three of them. Just multiply the edges to find the surface area of each side. Add all of the values up: 11+16+12+8+15+12+20=94 units.

What is the constant of proportionality y/x?

Answers

Answer:

0.5

Step-by-step explanation:

k = y/x

k = 0.5/1

k = 0.5

which is greaterr 0.5 or 0.14

Answers

Answer:

To determine which number is greater, 0.5 or 0.14, you must determine which of the two has a higher ratio with respect to a whole number. Thus, since 0.5 is equal to 1/2 and 0.14 is equal to 7/50, 0.5 is the greater number.

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