Using Java:
Background
Markdownis a formatting syntax used by many documents (these instructions, for example!) because of it's plain-text simplicity and it's ability to be translated directly into HTML.
Task
Let's write a simple markdown parser function that will take in a single line of markdown and be translated into the appropriate HTML. To keep it simple, we'll support only one feature of markdown in atx syntax: headers.
Headers are designated by (1-6) hashes followed by a space, followed by text. The number of hashes determines the header level of the HTML output.
Examples
# Header will become Header
## Header will become

Jhon must download third party pdf viewer softwares to open the .pdf file.

For example

Adobe Acrobat Reader

Must click thanks and mark brainliest

Answer:

The program in Python is as follows:

current_price = int(input("Current Price: "))

last_price = int(input("Last Month Price: "))

change = current_price - last_price

mortgage = (current_price * 0.051) / 12

print('Change: {:.2f} '.format(change))

print('Mortgage: {:.2f}'.format(mortgage))

Explanation:

This gets input for current price

current_price = int(input("Current Price: "))

This gets input for last month price

last_price = int(input("Last Month Price: "))

This calculates the price change

change = current_price - last_price

This calculates the mortgage

mortgage = (current_price * 0.051) / 12

This prints the calculated change

print('Change: {:.2f} '.format(change))

This prints the calculated monthly mortgage

print('Mortgage: {:.2f}'.format(mortgage))

Answer:

current_price = int(input())

last_months_price = int(input())

change = current_price - last_months_price

mortgage = current_price * 0.051 / 12

print('This house is $', end= '')

print(current_price, end= '. ')

print('The change is $', end= '')

print(change, end= ' ')

print('since last month.')

print('The estimated monthly mortgage is $', end= '')

print(mortgage, end='0.\n')

Answer:

With that in mind, let's take a look at five places where hard drives shine.

Backups and Archives. ...

Media Libraries. ...

Large Capacity Storage. ...

NAS Drives and Security. ...

RAID Arrays. ...

Other Uses.

int main {

//variables

unsigned long num = 0;

std::string phrase = " Please enter your name for confirmation: " ;

std::string name;

//codes

std::cout << phrase;

std::cin>> name;

while ( serial.available() == 0 ) {

num++;

};

if ( serial.avaliable() > 0 ) {

std::cout << " Thank you for your confirmation ";

};

};

Answer:

no

Explanation:

But you can't use this device alone to connect two microphones to your USB C port and expect it to have usable volume. So the description is somewhat misleading ...

Answer: True

Explanation:

Chassis intrusion detection is simply a vital security feature which is used typically by large corporate networks. It's simply an intrusion detection method which can be used in alerting a system administrator when there's a situation whereby a person opens a computer case which can then be investigated in order to know if the computer hardware has been tampered with.

It should also be noted that the chassis intrusion detection can then be either enabled or disabled in the BIOS setup utility if a BIOS comes equipped with this feature.

The correct option is True.

Answer:

C++

Explanation:

C++ is used in application development

Answer:

By using AI to collate data from multiple sources and assess existing automation to improve efficiency.

Artificial Intelligence is indeed a technique that allows machines to imitate the conduct of people. Machine Learning, even so, is an AI subset.

Therefore, By using AI, data from various sources is gathered and established automation is assessed to make it more efficient.

Learn more:

brainly.com/question/10054757

Answer:

Explanation:

The synchronized keyword needs to be active on the hit method at any point where 2 or more threads (users) exists at any given moment. This is in order to prevent two or more users from trying to perform a hammer hit at the same time. This is what the synchronized keyword is used for. It prevents the more than one thread from calling the specific method at the same time. Instead it adds the action to a sequence so that the second thread calls the hit method only after the first thread's hit method finishes.

Answer:

#include <iostream>

using namespace std;

struct entry

{

int number;

entry* next;

};

void orderedInsert(entry** head_ref,entry* new_node);

void init_node(entry *head,int n)

{

head->number = n;

head->next =NULL;

}

void insert(struct entry **head, int n)

{

entry *nNode = new entry;

nNode->number = n;

nNode->next = *head;

*head = nNode;

}

entry *searchNode(entry *head, int n)

{

entry *curr = head;

while(curr)

{

if(curr->number == n)

return curr;

curr = curr->next;

}

}

bool delNode(entry **head, entry *ptrDel)

{

entry *curr = *head;

if(ptrDel == *head)

{

*head = curr->next;

delete ptrDel;

return true;

}

while(curr)

{

if(curr->next == ptrDel)

{

curr->next = ptrDel->next;

delete ptrDel;

return true;

}

curr = curr->next;

}

return false;

}

void display(struct entry *head)

{

entry *list = head;

while(list!=NULL)

{

cout << list->number << " ";

list = list->next;

}

cout << endl;

cout << endl;

}

//Define the function to sort the list.

void insertionSort(struct entry **h_ref)

{

// Initialize the list

struct entry *ordered = NULL;

// Insert node to sorted list.

struct entry *current = *h_ref;

while (current != NULL)

{

struct entry *next = current->next;

// insert current in the ordered list

orderedInsert(&ordered, current);

// Update current

current = next;

}

// Update the list.

*h_ref = ordered;

}

//Define the function to insert and traverse the ordered list

void orderedInsert(struct entry** h_ref, struct entry* n_node)

{

struct entry* current;

/* Check for the head end */

if (*h_ref == NULL || (*h_ref)->number >= n_node->number)

{

n_node->next = *h_ref;

*h_ref = n_node;

}

else

{

//search the node before insertion

current = *h_ref;

while (current->next!=NULL &&

current->next->number < n_node->number)

{

current = current->next;

}

//Adjust the next node.

n_node->next = current->next;

current->next = n_node;

}

}

int main()

{

//Define the structure and variables.

char ch;int i=0;

entry *newHead;

entry *head = new entry;

entry *ptr;

entry *ptrDelete;

//Use do while loop to countinue in program.

do

{

//Define the variables

int n;

int s;

int item;

char choice;

//Accept the user choice

cout<<"Enter your choice:"<<endl;

cout<<"a. Add a number"<<endl

<<"b. Delete a number"<<endl

<<"c. Search for a number"<<endl

<<"d. Display the whole list of numbers"<<endl;

cin>>choice;

//Check the choice.

switch(choice)

{

//Insert an item in the list.

case 'a' :

// cin>>item;

cout<<"Enter the element:"<<endl;

cin>>item;

//To insert the first element

if(i==0)

init_node(head,item);

//To insert remaining element.

else

{

ptr = searchNode(head,item);

//Check for Duplicate data item.

if(ptr==NULL)

{

insert(&head,item);

}

else

{

cout<<"Duplicate data items not allowed";

cout<<endl<<"EnterAgain"<<endl;

cin>>item;

insert(&head,item);

}

}

insertionSort(&head);

i=i+1;

break;

//Delete the item from the list

case 'b' :

int numDel;

cout<<"Enter the number to be deleted :"<<endl;

cin>>numDel;

//Locate the node.

ptrDelete = searchNode(head,numDel);

if(ptrDelete==NULL)

cout<<"Element not found";

else

{

if(delNode(&head,ptrDelete))

cout << "Node "<< numDel << " deleted!\n";

}

break;

//Serach the item in the list.

case 'c' :

cout<<"Enter the element to be searched :";

cout<<endl;

cin>>s;

ptr = searchNode(head,s);

if(ptr==NULL)

cout<<"Element not found";

else

cout<<"Element found";

break;

//Display the list.

case 'd' :

display(head);

break;

default :

cout << "Invalid choice" << endl;

break;

}

//Ask user to run the program again

cout<<endl<<"Enter y to countinue: ";

cin>>ch;

}while(ch=='y'||ch=='Y');

return 0;

}

output:

Answer:

A good identifier for a variable that will be used to hold an employee’s phone number is:

a. EmployeePhoneNumber

Explanation:

An identifier is a string that uniquely identifies or names the entity or an object.  The object or entity may be a constant, variable, structure, function, etc. Identifiers can be formed from uppercase and lowercase letters, digits, and underscores.  Meaningful identifiers mostly favor the use of long descriptive names like EmployeePhoneNumber.  However, the other options can still be used.

Answer:

a. 36, 55, 13, 9, 23, 2, 62, 86, 95, 65,74, 75, 100, 98, 89

b. 15

Explanation:

Answer:

The answer is D.

Explanation:

because the other answers doesn't make sense.

Answer:

d. All of the above

Explanation:

A software can be defined as a set of executable instructions (codes) or collection of data that is used typically to instruct a computer how to perform a specific task and to solve a particular problem.

A software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications.

In Computer science, management of software development consist of;

a. Process: it involves the stages through which a software application is analyzed, designed, developed, tested, etc.

b. People: it refers to the individuals involved in the software development process.

c. Project: it's the entirety of the stages a software goes through before it gets to the end user.

Answer:

for the 5 segments, the utilization is 3.8%

Explanation:

Given the data in the question;

segment size = 1090 bytes

Receiver window size = 5,718 bytes

Link transmission rate or Bandwidth = 26 Mbps = 26 × 10⁶ bps

propagation delay = 22.1 ms

so,

Round trip time = 2 × propagation delay = 2 × 22.1 ms = 44.2 ms

we determine the total segments;

Total segments = Receiver window size / sender segment or segment size

we substitute

Total segments = 5718 bytes / 1090 bytes

Total segments = 5.24587 ≈ 5

Next is the throughput

Throughput = Segment / Round trip

Throughput = 1090 bytes / 44.2 ms

1byte = 8 bits and 1ms = 10⁻³ s

Throughput = ( 1090 × 8 )bits / ( 44.2 × 10⁻³ )s

Throughput = 8720 bits / ( 44.2 × 10⁻³ s )

Throughput = 197.285 × 10³ bps

Now Utilization will be;

Utilization = Throughput / Bandwidth

we substitute

Utilization = ( 197.285 × 10³ bps ) / ( 26 × 10⁶ bps )

Utilization = 0.0076

Utilization is percentage will be ( 0.0076 × 100)% = 0.76%

∴ Over all utilization for the 5 segments will be;

⇒ 5 × 0.76% = 3.8%

Therefore, for the 5 segments, the utilization is 3.8%

Answer:

it should be the welcome screen I will hope so lol

Answer:

welcomeyou don't know that much also

Answer:

The function is as follows:

def square_list(myList):

   for i in range(len(myList)):

       myList[i] = myList[i]**2

   print(myList)

Explanation:

This defines the function

def square_list(myList):

This iterates through the list elements

   for i in range(len(myList)):

This squares each list element

       myList[i] = myList[i]**2

This prints the mutated list

   print(myList)

Answer:

They have different words

Explanation:

I hope it helps choose me the brainest

Answer:

the smallest number start with the first number of the alphabet

Answer:

C – continue statement with example. The continue statement is used inside loops. When a continue statement is encountered inside a loop, control jumps to the beginning of the loop for next iteration, skipping the execution of statements inside the body of loop for the current iteration.

Explanation:

PLS mark brainliest

hope it helped u

Answer and Explanation:

var gettext= prompt("please enter text");

function strtok(gettext){

var splitString = gettext.split("");

if(splitString.length<=80){

var reverseArray = splitString.reverse();

var joinArray = reverseArray.join("");

return joinArray;}

else{

Alert("too many characters");

}

}

/* we first ask for user input using the prompt function. We save this in a variable gettext which we pass to the strtok function. This function first splits the text and makes it an array so we are able to count how many characters the user enters and set an if..else condition to handle characters that may be more than 80. The reverse and join functions are then used respectively to reverse and return the string.*/

Answer:

It is a method of developing architecture in various stages

Explanation:

Answer:

error: incompatible types

Explanation:

Given

The attached code

Required

The output

Variable "a" is declared as float

While p is declared as a pointer to an integer variable

An error of incompatible types will be returned on line 3, int *p = a;

Because the variables are not the same.

To assign a to p*, we have to use type casting.

Hence, (b) is correct

Answer:

The program is as follows:

num = int(input("Number: "))

fact = 1

for i in range(1,num+1):

   fact*=i

print(fact)

Explanation:

This gets integer input from the user

num = int(input("Number: "))

This initializes factorial to 1

fact = 1

The following iteration calculates the factorial of the integer input

for i in range(1,num+1):

   fact*=i

This prints the calculated factorial

print(fact)

Answer:

Code:-  

# function to print the pattern

def draw_triangle(n, num):

   # base case

   if (n == 0):

       return;

   print_space(n - 1);

   print_asterisk(num - n + 1);

   print("");

   # recursively calling pattern()

   pattern(n - 1, num);

# function to print spaces

def print_space(space):

   # base case

   if (space == 0):

       return;

   print(" ", end = "");

   # recursively calling print_space()

   print_space(space - 1);

# function to print asterisks

def print_asterisk(asterisk):

   # base case

   if(asterisk == 0):

       return;

   print("* ", end = "");

   # recursively calling asterisk()

   print_asterisk(asterisk - 1);

# Driver Code

n = 19;

draw_triangle(n, n);

Output:-  

# Driver Code n = 19;| draw_triangle(n, n);

Answer:yes

Explanation:

Yup

Answer:

Explanation:

The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int count = 0;

       int highest, lowest;

       ArrayList<Integer> myArr = new ArrayList<>();

       while (true) {

           System.out.println("Enter a number [0-10] or -1 to exit");

           int num = in.nextInt();

           if (num != -1) {

               if ((num >= 0) && (num <= 10)) {

                   count+= 1;

                   myArr.add(num);

               } else {

                   System.out.println("Wrong Value");

               }

           } else {

               break;

           }

       }

       if (myArr.size() > 3) {

           highest = myArr.get(0);

           lowest = myArr.get(0);

           for (int x: myArr) {

               if (x > highest) {

                   highest = x;

               }

               if (x < lowest) {

                   lowest = x;

               }

           }

           System.out.println("Number of Elements: " + count);

           System.out.println("Highest: " + highest);

           System.out.println("Lowest : " + lowest);

       } else {

           System.out.println("Number of Elements: " + count);

           System.out.println("No Highest or Lowest Elements");

       }

   }

}