Answer:
I am almost positive that it is D. I might be incorrect do i appoligise if i am.
Explanation:
How many atoms are in 0.580 moles of CO2?
Answer:
[tex]1.05x10^{24}atoms[/tex]
Explanation:
Hello!
In this case, according to the definition of the Avogadro's number, it is possible to realize that one molecule of CO2 contains 3 moles of atoms, one of carbon and two of oxygen, thus, we have:
[tex]0.580molCO_2*\frac{3mol\ atoms}{1molCO_2} =1.74mol\ atoms[/tex]
Then, we use the Avogadro's number to obtain:
[tex]1.74mol\ atoms*\frac{6.022x10^{23}atoms}{1mol\ atoms} \\\\1.05x10^{24}atoms[/tex]
Best regards!
Hurry I need Now!!!In which biome would the climax species be reached most quickly following a fire?
A Taiga
B desert
C Grassland
D. deciduous forest
E tropical rain forest
Answer:
D. Deciduous Forest.
Explanation:
When determining the density of a grape, a student was not careful when putting the grape into the graduated cylinder, and some of the water got splashed out. How would that affect the determined density of the grape? In other words, is the calculated density be higher or lower than the actual density of the grape? Explain your answer (fill in the blanks below).
If some of the water got splashed out, the measured “grape + water” volume is incorrectly ______________________ (high or low?).
Then the calculated volume of the grape (“grape+water” – “water only” volume) is incorrectly _______________ (high or low?).
When calculating the density, the mass is divided by a (higher or lower?) ______________ value. As the result, the determined density is erroneously (high or low?) _____________ and therefore the determined density is (higher or lower?) ______________than the actual density of the grape.
Answer:
gtjgyjtjyjjjjk
Explanation:
what is 78%
of 100? help
Answer:
78
Explanation:
You have 100%, you take 22% and get 78%
What is the mass in grams of 2.5 mol of O2?
Answer:
80grams
Explanation:
RAM of O=16
molar mass of O2= 16×2=32g/mol
mass= mole × molar mass
= 2.5×32= 80g
What are the chemical symbols for the elements calcium carbon and chlorine respectivly
Answer:
Explanation:
Calcium is Ca
Carbon is C
Chlorine is Cl
Explain how the processes of photosynthesis and respiration are related to each other
Answer:
Explanation:
The end product of Photosynthesis is glucose that is used in cellular respiration to make ATP. The glucose is then turned back into carbon dioxide, which is used in photosynthesis. While water is broken down to form oxygen during photosynthesis, in cellular respiration oxygen is combined with hydrogen to form water.
Answer and I’ll give you brainliest!
What type of reaction is this *
N2 + H2 → NH3
O synthesis
O combustion
O decomp
O single
O double
In a laboratory experiment, students synthesized a new compound and found that when grams of the compound were dissolved to make mL of a diethyl ether solution, the osmotic pressure generated was atm at K. The compound was also found to be nonvolatile and a non-electrolyte. What is the molar mass they determined for this compound
The question is incomplete, the complete question is;
In a laboratory experiment, students synthesized a new compound and found that when 12.23 grams of the compound were dissolved to make 228.1 mL of a benzene solution, the osmotic pressure generated was 4.55 atm at 298 K. The compound was also found to be non-volatile and a non-electrolyte. What is the molecular weight they determined for this compound?
Answer:
287.76 g/mol
Explanation:
From;
π = M R T
M = molarity
R= gas constant
T = temperature
number of moles = π * volume/RT
number of moles = 4.55 * 228.1/1000/0.082 * 298
number of moles = 1.037855/24.436
number of moles = 0.0425 moles
Molar mass = mass/number of moles
Molar mass = 12.23 grams/0.0425 moles
Molar mass = 287.76 g/mol
The value of the rate constant for a gas phase reaction can be changed by increasing the A. temperature of the reaction vessel. B. volume of the reaction vessel. C. pressure of the reactant. D. amount of product.
Answer:
temperature of the reaction vessel
Explanation:
temperature of the reaction vessel
The value of the rate constant for a gas phase chemical reaction can be changed by increasing the: A. temperature of the reaction vessel.
What is the rate constant?In Chemistry, rate constant is typically used with rate law to tell the reaction rate or rate of a chemical reaction that is affected by activation energy.
The rate law equation.Mathematically, the rate law is given by this formula:
[tex]R = k[A]^x[B]^y[/tex]
Where:
k is the rate constant.A is the concentration of reactant A.B is the concentration of reactant B.Generally, the value of the rate constant for a gas phase chemical reaction can be changed by increasing the temperature of the vessel (container) that is used in conducting the chemical reaction.
Read more on rate constant here: brainly.com/question/24749252
PLEASE HELP it’s due in 30 minutes
Answer:
1-6
3 1 3 3 2 2
Explanation:
What is the mass of 5 liters of fluorine (F2) gas at STP?
Answer:
The molar density of any ideal gas at STP is:
1 mol / 22.4 L = 0.04464 mol / L
The molar mass of F2 is: 2(19) = 38 g/mol
0.04464 mol / L * (38 g / mol) = 1.70 g/L
Explanation:
The image shown here is a good illustration of which law?
Answer:
3rd law
Explanation:
His third laws states that every action has an equal and opposite reaction. because you are putting force on your wall, the wall is giving the force of wall on your finger.
How many moles of
salt (NaCl) is 28.7
grams?
Answer:
0.491 mol NaCl
Explanation:
Convert from grams to moles using the molar mass of NaCl:
28.7 g NaCl x 1 mol NaCl/58.44 g NaCl = 0.491 mol NaCl
The molar mass (58.44 g) can be found from adding the molar masses of the individual elements (Na and Cl); the g NaCl will cancel out (dimensional analysis), leaving you with mol NaCl.
A student determines the chromium(III) content of a solution by first precipitating it as chromium(III) hydroxide, and then decomposing the hydroxide to chromium(III) oxide by heating. How many grams of chromium(III) oxide should the student obtain if her solution contains 56.0 mL of 0.600 M chromium(III) nitrate?
Answer:
Explanation:
Chromium nitrate Cr( NO₃ )₂
Chromium hydroxide Cr( OH)₃
Chromium oxide ( Cr₂O₃ )
1 mole of chromium nitrate will form 1 mole of chromium hydroxide
1 mole of chromium hydroxide will form one mole of chromium oxide .
Moles of chromium nitrate in 56 mL of .6 M solution
= .056 x .6 = .336 moles
.336 moles of chromium nitrate will produce .336 moles of chromium hydroxide and .336 moles of chromium hydroxide will produce .336 moles of chromium oxide .
So chromium oxide produced = .336 moles
Molecular weight of chromium oxide = 152
.336 moles of chromium oxide is equal to
.336 x 152 grams of chromium oxide
= 51.07 grams .
For the reaction of reducing benzil (MW 210.23 g/mol) with sodium borohydride (MW 37.83 g/mol), if 2.56 g of benzil and 0.38 g of sodium borohydride were used to make hydrobenzoin (MW 214.26 g/mol), and 2.22 g of hydrobenzoin was obtained, which chemical is limiting reagent
Answer:
NaBH₄
Explanation:
First, we need to write the chemical formula of all the compounds:
Benzil: C₁₄H₁₀O₂
Sodium Borhydride: C₁₄H₁₀O₂
Hydrobenzoin: C₁₄H₁₄O₂
Now, let's write the reaction that is taking place and write all the products:
C₁₄H₁₀O₂ + 2NaBH₄ + 2H₂O -----------> C₁₄H₁₄O₂ + 2BH₃ + 2NaOH
We can see that the reaction is already balanced, so we don't need to do anything else.
The question of this exercise is to determine the limiting reagent of the reaction, in other words, the reagent that controls the reaction and produces the 2.22 g of the hydrobenzoin. And to know this we need to see the mole ratio in both reactants, and compare them to the given moles (That can be obtained with the given masses and MW)
According to the above reaction, we have a mole ratio of 1:2, so, let's calculate the moles of benzil and the borohydride, and see which of them is the limiting reactant:
moles C₁₄H₁₀O₂ = 2.56 / 210.23 = 0.0122 moles
moles NaBH₄ = 0.38 / 37.83 = 0.01 moles
moles C₁₄H₁₄O₂ = 2.22 / 214.26 = 0.0103 moles
We have the moles of every species, now, let's see the mole ratio
If 1 mole of C₁₄H₁₀O₂ -----------> 2 moles of NaBH₄
Then 0.0122 moles C₁₄H₁₀O₂ ----------> X moles of NaBH₄
Solving for X:
X = 0.0122 * 2 / 1 = 0.0244 moles of NaBH₄ are required.
However, we only have 0.01 moles of NaBH₄, and we need so much more of this to completely react with the moles of the benzil. Therefore we can safely assume that the limiting reagent is the NaBH₄
Another data that we can use for this, is the fact the produced moles were 0.0103, and this value is nearest to the moles of NaBH₄ rather than the moles of the benzil.
So, in conclusion, Limiting reagent NaBH₄Hope this helps
Carbon dioxide non examples? Please and catalyst non examples?
Answer:
I guess you mean by non element example. Non element examples have more than one elements. Carbon dioxide is a non element example since caebon dioxide has 2 oxygen atoms + 1 carbon atom = carbon dioxide.
I think catalyst is also a non element example because catalyst is inorganic which means that it is not a living thing. Since catalyst is in brass and brass is a non element example, I think catalyst is also a non element example.
Hope that helps, thank you !!
What is a personal factor of resilience?
A. Feeling of belonging
B. Family and friends
C. Genetics
D. Coping Mechanisms
Answer:
B
Explanation:
B is a personal factor of resilience
Why is HCI a strong acid and HCIO a weak acid?
Strong Acid: dissolves and dissociates 100% to produce protons (H+) 1. seven strong acids: HCl, HBr, HI, HNO3, H2SO4, HClO4, & HClO3 2. ... Weak Acid: dissolves but less than 100% dissociates to produce protons (H+) 1.
How many grams of moles are in 94.2 g of C02?
Answer:
Moles to grams carbon dioxide
1 mole is equal to 1 moles Carbon Dioxide, or 44.0095 grams.
Explanation:
Moles to grams carbon dioxide
1 mole is equal to 1 moles Carbon Dioxide, or 44.0095 grams.
A 8.15 g sample of hydrogen peroxide (H2O2) decomposes to form water and oxygen. The temperature and pressures conditions in the lab were 21.2oC and 761.4 torr, respectively. The oxygen gas is collected over a sample of water at 21.2oC; the vapor pressure of water at that temperature is 18.9 torr. When the water level inside and outside of the tube is equal the volume of gas is recorded as 176.23 mL. a) Write and balance the equation for the decomposition reaction
Answer: [tex]H_2O_2\rightarrow H_2+O_2[/tex]
Explanation:
Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.
According to law of conservation of mass, mass can neither be created nor be destroyed. Thus the number of atoms of each element must be same on reactant and product side. Thus chemical equations are balanced.
The balanced equation for the decomposition reaction of hydrogen peroxide is:
[tex]H_2O_2\rightarrow H_2+O_2[/tex]
Decomposition is a type of chemical reaction in which a chemical breaks into two or more molecules or atoms. One reactant breaks into two products which can be shown as:
XY----->X + Y
The decomposition reaction of hydrogen peroxide can be written as:
[tex]H_{2}O_{2} = H_{2} + O_{2}[/tex]
According to the mass conserving law the mass can neither be added nor deleted they can just get transferred. For a reaction to be stable the number of atoms on both sides of the reaction should be balanced.Therefore, the balanced chemical reaction of decomposition of hydrogen peroxide will be:
[tex]H_{2}O_{2} = H_{2} + O_{2}[/tex]
To learn more about decomposition reaction follow the given link:
https://brainly.com/question/8009068
in what way are these flowers similar from one another?
Answer:
do you have names or pictures?
Explanation:
Which of the following notations represents an alpha particle?
A. 2 He
C.B+
В. В
D. Y
Answer:
A. 2 He
Explanation:
The notation of an alpha particle is depicted as:
₂He
An alpha particles is a nucleus of 2 protons and 2 neutrons. So it is actually a Helium cation.
Alpha particles are monoenergetic and they mostly have discrete energy.
So, the mass number of the particle is 4 and atomic number is 2
Question 7 (1 point)
Order the levels of organization from smallest to largest.
11. Organism
1 2. Cell
13. Organ System
1 4. Organ
1 5. Tissue
A sample of compound A (a clear, colorless gas) is analyzed and found to contain 4.27g carbon and 5.69g oxygen. A sample of compound B (also a clear, colorless gas) is analyzed and found to contain 5.19g carbon and 13.84g oxygen. Are these data an example of the law of definite proportions, the law of multiple proportions, or neither? What do these data tell you about substances A and B?
Answer:
law of multiple proportions
Explanation:
The law of multiple proportions states that, if two elements A and B, combine to form more than one chemical compound. Then the various masses of one element A, which combine separately with a fixed mass of element B are in simple multiple ratio.
We can see that the ratio of oxygen that combines with carbon in the two compounds( A and B) is 1:2. This demonstrates the law of multiple proportions.
The substances A and B must be CO and CO2 respectively.
what the the noble gas configuration for Boron
Answer:
[He]2[tex]s^{2}[/tex]3[tex]p^{1}[/tex]
Explanation:
The electron configuration for Boron is 1[tex]s^{2}[/tex]2[tex]s^{2}[/tex]3[tex]p^{1}[/tex], but you can also write it as the noble gas configuration, which is [He]2[tex]s^{2}[/tex]3[tex]p^{1}[/tex]
Note that helium has the configuration of 1[tex]s^{2}[/tex], so we instead of writing it, we write [He]. This can be useful when writing the configurations of elements from the later periods as it saves space.
Help pls!!!!!!!!!!!!!!!!!!!!!!!
Answer:
D a compound
Explanation:
Helppp plssss pls help it’s Science I will give Brainlyist no cap I will just plssss help
Answer:
I cant see it that well but id be happy to help if u post a clearer picture!
Explanation:
50 points Two waves combine with constructive interference. What must be true of the
combined wave that forms?
A. It has a lower frequency than that of the original waves.
B. It has a higher amplitude than that of the original waves.
C. It has a higher frequency than that of the original waves.
D. It has a lower amplitude than that of the original waves.
Answer:B
Explanation:
Maybe
Answer:B is correct
Explanation:
Consider a disubstituted aromatic compound. The parent name is benzene and there is a chloro and bromo substituent. Disubstituted benzenes can be described using the terms ortho, meta and para, depending on their relative distance from each other. The terms are often just abbreviated as o, m and p. In addition, the IUPAC name can use locant numbers instead of the descriptor. Br
Select the correct names for the structure.
1. 1-bromo-3-chlorobenzene
2. 3-bromo-1-chlorobenzene
3. meta-bromochlorobenzene
4. o-bromochlorobenzene
5. ortho-bromochlorobenzene
6. m-bromochlorobenzene
Answer:The correct names for the structure are:
--> 1. 1-bromo-3-chlorobenzene.
--> 3. meta-bromochlorobenzene.
--> 6. m-bromochlorobenzene.
Explanation:
Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.
Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.
The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:
--> the functional group is benzene
--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)
--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.
The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.
--> ortho or O : this is used when the substituents are close to each other in the benzene ring.
--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.
--> para or (p): This is used when the substituents are across each other in the benzene ring
From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.
