What is the decay constant for Oxygen-19 if it has a half-life of 26.5s?


A)0.0262/s

B)18.4

C)0.0377/s

C)38.2/s

Answers

Answer 1

Answer:

Option A.

Explanation:

We define the half time T as the time such that an initial quantity A reduces to its half.

So we can model the quantity as a function of time like:

P(t) = A*e^(-k*t)

Then for the half time, T, we will have:

P(T) = A/2 = A*e^(-k*T)

solving for k, we get:

A/2 = A*e^(-k*T)

1/2 = e^(-k*T)

ln(1/2) = ln( e^(-k*T)) = -k*T

-ln(1/2)/T = k

Here we know that the half time is T = 26.5s

if we input that in the above equation, we get:

-ln(1/2)/26.5s = k = 0.0262 s^-1

Then the correct option is A


Related Questions

Which shows the stars in the correct order, from smallest in size to largest?
white dwarf, Sun, red supergiant
Sun, red supergiant, white dwarf
white dwarf, red supergiant, Sun
Sun, white dwarf, red supergiant

Answers

Answer:

its A

Explanation:

White dwarf, Sun, red supergiant shows the stars in the correct order, from smallest in size to largest.

What is the size stars?

More than 1.4 million kilometers span our Sun. However, not every star is the same size. They range in size from that of a metropolis to that of our solar system's half!

The mass of neutron stars is concentrated into a very compact area. Even though they are frequently only 20 to 40 km in diameter, they may hold the mass of one or two Suns. White dwarf stars are a little larger and frequently resemble the size of the Earth.

Compared to our Sun, the greatest supergiant stars can be more than 1500 times bigger. They are now more than 2,000 million kilometres across. Supergiants don't, however, have thousands of times the mass of the Sun. The reason for this is that as supergiants become older, their interiors become considerably more dispersed. Betelgeuse, a red giant in Orion's constellation, is nearly 1000 times broader than the Sun yet only has around 15 times as much mass.

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A mass is pulled to the right while on a table.
A. Label the forces.
5 kg
B. Calculate the
object's weight.

Answers

Answer:

weight in 49N

I hope it's correct

11. A tennis ball is thrown straight up in the air, leaving the person's hand with an initial velocity of 3.0 m/s, as shown to the right. What is the displacement of the ball above the person's hand?​

Answers

Answer:

0.46m

Explanation:


A type of matter in which two or more elements are combined
chemically is called a _______

Answers

Answer:

COMPOUND

Explanation:

how many band is the parametric microphone equalizer?

Answers

Answer:

3 bands

Explanation:

Basically, the Parametric EQ divides the audio spectrum into three bands, allowing you to enhance (or suppress) the level in that range.

Lower chamber of Congress has how many members?

Answers

Answer:435 Representatives

Explanation:The lower chamber of Congress, in which the number of representatives per state is determined by the state's population, with 435 Representatives total. Members of the House of Representatives serve two-year terms, so they are up for reelection every two years.

what is a velocity of an object with a momentum of 300 kg m/s and the mass of 100 kg​

Answers

Answer:

v = 3 m/s

Explanation:

P is the momentum

m is the mass

v is the velocity

P = m•v

300 = 100•v Divide both sides per 100

300/100 = v

v = 3 m/s

[tex]\text{Given that,}\\\\\text{Momentum, p = 300 kg m s}^{-1}\\\\\text{Mass, m = 100 kg}\\\\\text{We know that,}\\\\p = mv\\\\\implies v = \dfrac pm = \dfrac{300}{100} = 3 ~ \text{m s}^{-1}[/tex]

an EM wave has a wave length of 956 m, What type of electromagnetic waves is this wave

Answers

The electromagnetic spectrum allows finding the result for the question of type of electromagnetic wave has a wavelength of 956 nm

The wave is in the near infrared range.

The electromagnetic wave is an oscillation of electric fields and magnets field that sustain each other, this wave time has the characteristics that it can travel without a material medium, for which they are of extreme importance.

Consequently the spectrum of electromagnetic waves to each part has been given a different name second to its use, for example

Range                        Name  

Ultraviolet light          200 to 400 nm

Visible light               400 to 700 nm

Infrared light (heat  ) 700 nm to 1 mm

The latter is subdivided into:

 Near infrared          700 nm to 1000 nm (1 μm)

 Medium infrared        1 μm  to 30 μm

 Far infrared             50 μm to 1000 μm

It indicates that the wavelength of the measured radiation is 956 nm, therefore it is in the near infrared range.

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the probe used in a medical ultrasound examination emits sound waves in air that have a wavelength of 0.12 mm.

Answers

Answer:

IF GOD IS TEIIING YOU SOMETHING JUST DO IT

Explanation:

What is the sum of 130+125+191? A. 335. B. 456. C. 446. D. 426.
If we minus 712 from 1500, how much do we get? A. 788. B. 778. C. 768. D. 758.
50 times of 8 is equal to: A. 80. B. 400. C. 800. D. 4000.
110 divided by 10 is: A. 11. B. 10. C. 5. D. None of these.
FRIEND ME!!!

Answers

1. C- 446
2. A- 778
3. B- 400
4. A- 11

Name the two sources of light.​

Answers

Answer:

Natural light (Sun, stars.etc.) and Artificial light (Lamposts, televisions.etc.)

Hope that helps. x

A position versus time graph is shown:
Position vs. Time
1 15
10
10
Time (seconds) ->
Which statement accurately describes the motion of the object in the graph above?
O It is at rest for 3 seconds before moving at constant speed for 10 seconds.
It is at rest for 3 seconds before moving at constant speed for 4 seconds.
Olt is moving from 0 cm to 5 cm at constant speed of 7 cm/s.
O it is moving from 0 cm to 3 cm at a constant speed of 3 cm/s.

Answers

Answer:    Answer: The object moves forward at 5 m/s, stops, and then changes velocity.

Explanation:

With the information given in the question we can graph the points (image attached).

As we can observe, in the first segment of the graph the velocity is increasing linearly (at a constant rate) and is 5 m/s, then in the second segment we can see the position of the object remains the same from second 2 to second 4, which means the object is stopped.

Finally, in the third and last segment, we can observe a change in velocity (at a negative constant rate, because is decreasing), which is decreasing until the object stops.

Explanation:

Part A
As an object moves around, on which quantities does the change in its gravitational potential energy depend? Choose all that
apply.

Answers

As expressed by the equation, potential energy depends upon the mass and the height of the object. Any increase in these two quantities will lead to an increase in the amount of potential energy possessed by the object.

You slide towards the window when a car makes a sudden turn

Answers

Answer:

thats ummm

Explanation:

law of inertia

Newton’s 1 law

What is the mass of a box if it accelerated 5 m/s from a force of 12 N?

Answers

Answer:

60

Explanation:

You multiply the acceleration and the force and you get your answer

On average, how many stars would we have to search before we would expect to hear a signal? assume there are 500 billion stars in the galaxy.

Answers

We would have to search at least 5,000,000,000 (5 billion) stars before we would expect to hear a signal.

To find out the number of stars that we will need to search to find a signal, we need to use the following formula:

total of stars/civilizations500,000,000,000 (500 billion) stars / 100 civilization = 5,000,000,000 (5 billion)

This shows it is expected to find a civilization every 5 billion stars, and therefore it is necessary to search at least 5 billion stars before hearing a signal from any civilization.

Note: This question is incomplete; here is the complete question.

On average, how many stars would we have to search before we would expect to hear a signal? Assume there are 500 billion stars in the galaxy.

Assuming 100 civilizations existed.

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Explain how the stars impact the shape of a galaxy.

Answers

Answer:

Galaxies are too far away for astronomers to take real 3D measurements, but we can infer their shape based on the movement of stars. ... This is also true of less common spiral galaxies like the Milky Way. The bulge near the center contains older stars, while the flattened arms are home to younger ones.

Explanation:

The orbits of stars can also affect the shape of a galaxy through a variety of density waves that are produced when material is compressed into something comparable to a traffic jam in galaxies.

What is Star?

A star is defined as a celestial object consisting of a luminous sphere of plasma held together by self-gravity where the closest star to Earth is the Sun. While many other stars are visible to the uncovered eye at night, their extreme distance from Earth causes them to appear as fixed points of light.

Galaxies are too far away for astronomers to take true 3D measurements, through which we can estimate their size based on the motion of stars, which is also true for less common spiral galaxies like the Milky Way.

Thus, the orbits of stars can also affect the shape of a galaxy through a variety of density waves that are produced when material is compressed into something comparable to a traffic jam in galaxies.

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A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?

Answers

The ratio of time of flight for inelastic collision to elastic collision is 1:2

The given parameters;

mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂

Considering inelastic collision, the final velocity of the system is calculated as;

[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]

The time of motion of the system form top of the table is calculated as;

[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]

Considering elastic collision, the final velocity of the system is calculated as;

[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]

Apply one-directional velocity

[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]

Substitute the value of [tex]v_1[/tex] into the above equation;

[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]

where;

[tex]v_2[/tex] is the final velocity of the block after collision

Since the bullet bounces off, we assume that only the block fell to the ground from the table.

The time of motion of the block is calculated as follows;

[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]

The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;

[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]

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A ball is kicked at an angel of 37° to a goalkeeper who is 24m away. What was the initial velocity of the ball?

Answers

The initial velocity of the ball when it was projected is 15.64 m/s.

The given parameters:

Angle of the projection, θ = 37⁰The range of the projectile, R = 24 m

The initial velocity of the ball is calculated by applying formula for range of projectile as follows;

[tex]R = \frac{u^2 sin(2\theta)}{g} \\\\u^2 = \frac{Rg}{sin(2\theta)} \\\\u = \sqrt{\frac{Rg}{sin(2\theta)} } \\\\u =\sqrt{\frac{24 \times 9.8}{sin(2\times 37)} } \\\\u = 15.64 \ m/s[/tex]

Thus, the initial velocity of the ball when it was projected is 15.64 m/s.

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which term is equal to velocity change per second?

Answers

Answer:

Acceleration  is measured in meters per second squared (m/s²) change in velocity is measured in meters per second (m/s) time taken

‍12/3/21 A wave in the ocean has a wavelength of 24 m and a frequency of 8 Hz,What is the wave's speed?

Answers

Answer:

192 m/s

Explanation:

The speed of the wave given only it's frequency and wavelength can be found by using the formula

[tex]c = f \times \lambda[/tex]

where

c is the velocity of the wave in m/s

[tex] \lambda[/tex] is the wavelength in m

f is the frequency in Hz

From the question we have

c = 8 × 24 = 192

We have the final answer as

192 m/s

Hope this helps you

A 30.4-newton force is used to slide a 40.0-newton crate a distance of 6.00 meters at constant speed along an incline to a vertical height of 3.00 meters. Calculate the work done by a friction force on the crate as it slides 6.00 m along the incline.

Answers

Hi there!

Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:

Wsinθ = downward acceleration along incline due to gravity (N)

Fκ = kinetic friction force along incline (N)

A = applied force (N)

The acceleration due to gravity and friction force act in the same direction, so:

Wsinθ + Fκ = A

Solve for sinθ using right triangle trigonometry:

sinθ = O/H = 3/6 = 0.5

Rearrange the equation for the force of kinetic friction and solve:

Fκ = A - 0.5W

Fκ = 30.4 - 20 = 10.4 N

Now, recall that:

Work = Force × displacement (W = F × d)

Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:

W = Fdcosθ

Angle between displacement and friction force is 180°.

cos(180) = -1

Work done by friction = -Fd = -10.4(6) = -62.4 J

when is atmospheric pressure 1x10 to the power of 5 and when is it pgh

Answers

Answer:

1 atmospheris pressure is equal to10.33 meter under water

Explanation:

right ??

David delivers meals to elderly people once a week. He uses a cart to move the meals. The cart has four smooth wheels. Which type of friction acts between the cartwheels and the sidewalk?

Answers

Answer: rolling friction

Explanation: I think it is the answer

7. A drag car takes off at the green light heading in a straight line. The car goes
from a complete stop to 45m/s in 9 seconds. What is its acceleration?

Answers

Answer:

405

Explanation:

If the car stops at 45m/s in 9 seconds then it took the car 405 meters to stop

the acceleration of a train moving from rest and its speed reaches 36m/sec in 9 sec​

Answers

Answer:

4 m/s^2

Explanation:

The acceleration is defined as: Δv/Δt (the difference of the velocity over a time period in which happens that difference).

Remember that a difference is calculated by subtracting the initial value of a physical quantity from its final value.

In our case:

Δv = Vfinal - Vinitial = 36m/s - 0 m/s = 36m/s

Δt = 9s

a = Δv/Δt = 36m/s / 9s = 4m/s^2

To overcome an object's inertia, it must be acted upon by __________. A. Gravity B. Energy C. Force D. Acceleration Please select the best answer from the choices provided. A B C D.

Answers

Taking into account the Newton's first Law, the correct answer is option C. To overcome an object's inertia, it must be acted upon by a force.

Newton's First Law, also called the Law of inertia, indicates that "Every body perseveres in its state of rest or of uniform rectilinear motion unless it is forced to change its state by forces impressed on it." This means that for a body to come out of its state of rest or of uniform rectilinear motion, it is necessary for a force to act on it.

In other words, it is not possible for a body to change its initial state (be it rest or motion) unless one or more forces intervene.

Finally, the correct answer is option C. To overcome an object's inertia, it must be acted upon by a force.

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Answer:

C) Force

Explanation:

A swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.


Hint: 1 m^3 of water has a mass of 1000 kg.

Answers

With the use of the formula, the pressure on the bottom of the pool due to the water is 29400 Pascal

Given that a swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m.

Volume = Length x Width x Height

Volume = 9 x 12 x 3

Volume = 324 [tex]m^{3}[/tex]

Since 1 m^3 of water has a mass of 1000 kg,

Mass = 324 x 1000

mass = 324000 kg

To calculate the pressure on the bottom of the pool due to the water, let us use the pressure formula below

P = δgh

where

P = pressure

δ = density of the water = 1000 kg/[tex]m^{3}[/tex]

g = Acceleration due to gravity = 9.8 m/[tex]s^{2}[/tex]

h = height = 3m

Substitute all the parameters into the formula

P = 1000 x 9.8 x 3

P = 29400 Pascal

Therefore, the pressure on the bottom of the pool due to the water is 29400 Pascal

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A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) 28 kg⋅m/s 28 kilograms times meters per second 280 kg⋅m/s 280 kilograms times meters per second 70,000 kg⋅m/s 70,000 kilograms times meters per second 7,000 kg⋅m/s

Answers

The impulse of the boxers punch is 28 kgm/s.

The given parameters;

applied force by the boxer, F = 1400 Ntime of force action, t = 0.02 s

The impulse of the boxers punch is calculated as follows;

[tex]J = Ft[/tex]

where;

F is the applied force (N)t is the time of force action (s)

The magnitude of the impulse is calculated as follows;

[tex]J = 1400 \times 0.02 \\\\J = 28 \ kg m/s[/tex]

Thus, the impulse of the boxers punch is 28 kgm/s.

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In which scenario is work being done on an object?

a) A force is applied to an object to hold it at rest on an inclined plane.
b) Sitting on a box.
c) An upward force is applied to an object to move it upward at a constant speed.
d) An upward force is applied to an object to suspend it motionless in mid-air.

Answers

Answer:c

Explanation:

To solve this, we must know each and every concept related to work. Therefore, the correct option is option C that is "an upward force is applied to an object to move it upward at a constant speed."

What is work?

Work in physics is the energy delivered to or out of an item by applying force across a displacement. It is frequently expressed in its most basic form as the combination of displacement and force.

When a force is applied, it is said to produce positive work if it has a portion in the directions of the movement of the site of application. Work is done on a body is equivalent to an increase in the body's energy, because work transmits energy to the body. If, on the other hand, the force acting is in the opposite direction as the item's motion, the work is regarded negative, suggesting that energy is withdrawn from the object.

Therefore,  the correct option is option C that is "an upward force is applied to an object to move it upward at a constant speed."

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