What logarithmic function represents the data in the table?


x f(x)
216 3
1296 4
7776 5

Answer:

=35

Step-by-step explanation:

3(3) ^2 + 2(4)

= 3(9) + 8

= 35

Where you see a, substitute with 3 and where you see b, substitute with 4

Just follow the steps above.

[tex]\\ \sf\Rrightarrow 3a^2+2b[/tex]

[tex]\\ \sf\Rrightarrow 3(3)^2+2(4)[/tex]

[tex]\\ \sf\Rrightarrow 3(9)+8[/tex]

[tex]\\ \sf\Rrightarrow 27+8[/tex]

[tex]\\ \sf\Rrightarrow 35[/tex]

Answer:

264 cm³

Step-by-step explanation:

Answer:

1,015

Step-by-step explanation:

7 pounds of honey equals 1 pound of wax

So if we have 145 pounds of was, we multiply 145 by 7

145x7= 1,015

Answer: -1/6

You can multiply 2/6 by 2 to get 4/12 which you can subtract from 6/12.

4/12 - 6/12 = -2/12 which you can simplify further to get -1/6

Answer:

the answer would be 3 bags of 6

f(x+3)

[tex]\\ \sf\Rrightarrow 2(x+3-1)^2+3[/tex]

[tex]\\ \sf\Rrightarrow 2(x+2)^2+3[/tex]

[tex]\\ \sf\Rrightarrow 2(x^2+4x+4)+3[/tex]

[tex]\\ \sf\Rrightarrow 4x^2+8x+8+3[/tex]

[tex]\\ \sf\Rrightarrow 4x^2+8x+11[/tex]

Now

[tex]\\ \sf\Rrightarrow h(x)[/tex]

[tex]\\ \sf\Rrightarrow -f(x+3)-1[/tex]

[tex]\\ \sf\Rrightarrow -4x^2-8x-11-1[/tex]

[tex]\\ \sf\Rrightarrow -4x^2-8x-12[/tex]

[tex]\\ \sf\Rrightarrow 4(-x^2-2x-3)[/tex]

Answer:

$7.01

Step-by-step explanation:

Answer:

$7.01

Step-by-step explanation:

You have seven whole dollars, which goes before the decimal point, then your cents go behind the decimal point.

Answer:

3x5=15

5x3=15

Step-by-step explanation:

Answer:

a=19

Step-by-step explanation:

In this equation you want to solve for a

In this case you simply add 6 to 13 because -6 is attached to the a on the left side and you want a on it's own.

a - 6 = 13  

+6       +6       (-6+6 = 0) (6+13=19)

a = 19

Answer:

B

Step-by-step explanation:

Each tick = + or - 2 depending on which quadrant and axis

So the first line (the slanted one) intersects the y axis at (0,5) and continues until (2,5)

Then the line becomes straight (the y remains constant) from (2,5) (the points x value is 2) to (2,10) (the points x value is now 10)

Answer:

EI = FI and EG is twice the length of EI. Try setting up algebraic equations 3x + 8 = 6x -4 to find the value of x. Then substitute it back into the equation to find the length.

Step-by-step explanation:

Answer:

Step-by-step explanation:

The area of each trapezoid can be found using the relevant formula:

  A = 1/2(b1 +b2)h . . . . b1, b2 are the base lengths; h is the height

For the top trapezoid, the height is 13 m-7 m = 6 m, so the area is ...

  A = 1/2(8 m +5 m)(6 m) = 39 m²

The area of the bottom trapezoid is ...

  A = 1/2(10 m +17 m)(7 m) = 94.5 m²

The area of the shape is the sum of the areas of the two trapezoids.

  area = 39 m² +94.5 m² = 133.5 m² . . . . area of the figure

__

The horizontal lengths are all marked, but the slant lengths are not. There are no angles or other information given that can help determine the slant lengths. In order to answer the question, we can assume that the trapezoids are isosceles. Then the base of the right triangle shown in the top trapezoid is (8 -5)/2 = 1.5 m. The height is 6 m. The Pythagorean theorem tells us the slant length is ...

  s1 = √(1.5² +6²) ≈ 6.1847 . . . . meters

Similarly, the base length of the right triangle shown next to the bottom trapezoid is (17 -10)/2 = 3.5 m. The height is 7 m. The slant length of that one is ...

  s2 = √(3.5² +7²) ≈ 7.8262 . . . . meters

__

The perimeter is the sum of the lengths of the sides. Note that the 17 m dimension includes 8 m that are not part of the boundary of the figure. The sum of lengths of the horizontal edges is ...

  10 m +(17 -8 m) +5 m = 24 m

The sum of the lengths of the slant edges is ...

  2·s1 +2·s2 = 2(6.1847 +7.8262) ≈ 28.02 . . . . meters

The perimeter of the figure is the sum of horizontal lengths and slant lengths:

  24 m + 28.02 m = 52.02 m . . . . perimeter of the figure

The speed of this car is equal to 1.6 km/min.

Given the following data:

To calculate the speed of this car:

Speed can be defined as the distance travelled by an object per unit time and it is usually measured in meter per seconds (m/s). Also, speed has magnitude but no direction and as such it is a scalar quantity.

Mathematically, speed is given by the formula;

[tex]Speed = \frac{distance}{time}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Speed = \frac{50}{30}[/tex]

Speed = 1.6 km/min.

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Its 1/-2, or in other words it is -(1/2), so it would be the third option you have there.

Your welcome! :D

Answer:

EFGH, HFGE, EGFH, HGFE

Step-by-step explanation:

Answer:

30/6 is correct

Step-by-step explanation:

Work Shown:

(3 mm)/(17 m) = (x mm)/(55 m)

3/17 = x/55

3*55 = 17*x

165 = 17x

17x = 165

x = 165/17

x = 9.706 approximately

Side note: I used the cross multiplication rule for the third step.

Answer:

  2 13/14 feet

Step-by-step explanation:

The remaining length is the difference between the starting length and the amount cut off:

  5 3/7 - 2 1/2 = (5 -2) +(3/7 -1/2) = 3 +((3·2-7·1)/(7·2)) = 3 -1/14

  = 2 13/14 . . . feet remaining

_____

Additional comment

Addition and subtraction of fractions can be accomplished using a formula that does not rely on finding a least common denominator. In this case, the denominators have no common factors, so their product is, in fact, the least common denominator.

  [tex]\dfrac{a}{b}-\dfrac{c}{d}=\dfrac{ad-bc}{bd}[/tex]

Answer:

3 and five fifthteenths or  3 and 4/9

Step-by-step explanation:

i think so.........

Answer:

if im correct the answer is 63 + 36 = 9 (7 + 4)

Step-by-step explanation:

Answer:

The guy above was correct! I hope people see this so that they can trust the provided answer above.

Step-by-step explanation:

The answer is in the image attached. I hope it is helpful.

The least common denominator of two given rational expression are   4x, (x-3) and (x+3).

The factored denominator of two rational terms are called least common denominator of two rational numbers.

To find the least common denominator of two rational terms, we factor the expression and multiply all the distinct factors.

According to the given question

We have two rational expressions

[tex]\frac{9}{4x^{2} -12x}[/tex] and [tex]\frac{7x}{x^{2} -9}[/tex]

Now let's factorize the denominators

[tex]4x^{2} -12x =4x(x-3)[/tex]

and, [tex]x^{2} -9=(x+3)(x-3)[/tex]

Therefore,

[tex]\frac{9}{4x^{2} -12x}+\frac{7x}{x^{2} -9}[/tex]

⇒[tex]\frac{9}{4x(x-3)} +\frac{7x}{(x-3)(x+3)}[/tex]

⇒[tex]\frac{9(x+3)+7x(4x)}{4x(x-3)(x+3)}[/tex]

Therefore, the least common denominator of two given rational expression are   4x, (x-3) and (x+3).

Learn more about least common denominator of two rational expression here:

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Answer:

the Domain would be represented by Time in this problem, since time can only be positive, the domain would start at zero seconds and end at 5 seconds when the soccer ball hits the ground.

Step-by-step explanation:

Answer:

p = (-15)/14

Step-by-step explanation:

Solve for p:

5 + 1/28 = p/2 + 4/7 + 5

Put 5 + 1/28 over the common denominator 28. 5 + 1/28 = (28×5)/28 + 1/28:

((28×5)/28 + 1/28) = p/2 + 4/7 + 5

28×5 = 140:

140/28 + 1/28 = p/2 + 4/7 + 5

140/28 + 1/28 = (140 + 1)/28:

((140 + 1)/28) = p/2 + 4/7 + 5

140 + 1 = 141:

141/28 = p/2 + 4/7 + 5

Put each term in p/2 + 4/7 + 5 over the common denominator 14: p/2 + 4/7 + 5 = (7 p)/14 + 8/14 + 70/14:

141/28 = ((7 p)/14 + 8/14 + 70/14)

(7 p)/14 + 8/14 + 70/14 = (7 p + 8 + 70)/14:

141/28 = ((7 p + 8 + 70)/14)

Grouping like terms, 7 p + 8 + 70 = 7 p + (70 + 8):

141/28 = (7 p + (70 + 8))/14

70 + 8 = 78:

141/28 = (7 p + 78)/14

141/28 = (7 p + 78)/14 is equivalent to (7 p + 78)/14 = 141/28:

(7 p + 78)/14 = 141/28

Multiply both sides of (7 p + 78)/14 = 141/28 by 14:

(14 (7 p + 78))/14 = (14×141)/28

(14 (7 p + 78))/14 = 14/14×(7 p + 78) = 7 p + 78:

(7 p + 78) = (14×141)/28

14/28 = 14/(14×2) = 1/2:

7 p + 78 = 141/2

Subtract 78 from both sides:

7 p + (78 - 78) = 141/2 - 78

78 - 78 = 0:

7 p = 141/2 - 78

Put 141/2 - 78 over the common denominator 2. 141/2 - 78 = 141/2 + (2 (-78))/2:

7 p = (141/2 - (78×2)/2)

2 (-78) = -156:

7 p = 141/2 + (-156)/2

141/2 - 156/2 = (141 - 156)/2:

7 p = ((141 - 156)/2)

141 - 156 = -15:

7 p = (-15)/2

Divide both sides by 7:

p = ((-15)/7)/2

2×7 = 14:

Answer: p = (-15)/14

The solutions to the equation [tex]3-k=\sqrt{3k+1}[/tex] are k = 1 and 8

The given equation is:

[tex]3-k=\sqrt{3k+1}[/tex]

Square both sides of the equation

[tex](3-k)^2=3k+1[/tex]

Expand the left side of the equation above

[tex](3-k)^2=3k+1\\\\(3-k)(3-k)=3k+1\\\\3^2-3k-3k+k^2=3k+1\\\\9-6k+k^2=3k+1[/tex]

Write the quadratic equation in standard form

[tex]k^2-6k-3k+9-1=0\\\\k^2-9k+8=0\\\\[/tex]

Factor the quadratic equation

[tex](k-8)(k-1)=0[/tex]

Use the zero product property

k - 8 = 0

k = 8

k - 1 = 0

k = 1

The solutions to the equation [tex]3-k=\sqrt{3k+1}[/tex] are k = 1 and 8

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answer

first one: 8 and 1

second one: is 1

Step-by-step explanation:

slay

Step-by-step explanation:

The first inequality has solution

 4p > -8 . . . . . . subtract 1

 p > -2 . . . . . . . divide by 4

This is graphed as an open dot at -2, with shading to the right.

Neither inequality symbol includes "or equal to", so both dots are open dots. The appropriate choice is the first one:

 a number line with open circles at negative 2 and 5 with shading in between

hope that help mark me brinilylist

Applying the required rule or theorem, it can be concluded that the second biker is farther from the parking lot. The distance of the bikers to the parking lot are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The path of travel of both bikers would form a triangle. Applying the Pythagoras theorem to the path of the first biker would give his distance from the starting point. While applying the cosine rule to the path of second rider would gives his distance to the starting point.

Thus,

a. To determine the distance of the first biker from the parking lot.

Let the required distance be represented by x. Applying the Pythagoras theorem, we have:

[tex]hyp^{2}[/tex] = [tex]adj 1^{2}[/tex] + [tex]adj 2^{2}[/tex]

[tex]x^{2}[/tex] = [tex]8^{2}[/tex] + [tex]15^{2}[/tex]

   = 64 + 225

   = 289

x = [tex]\sqrt{289}[/tex]

  = 17

x = 17 km

Thus, the first biker is 17.0 km from the starting point.

b. To determine the distance of the second biker from the parking lot.

Let the required distance be represented by x. So that applying the cosine rule, we have:

[tex]c^{2}[/tex] = [tex]a^{2}[/tex] + [tex]b^{2}[/tex] - 2ab Cos θ

[tex]x^{2}[/tex] = [tex]8^{2}[/tex] + [tex]15^{2}[/tex] - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

[tex]x^{2}[/tex] = 289 + 120

   = 409

x = [tex]\sqrt{409}[/tex]

 = 20.2237

x = 20.22 km

Thus, the second biker is 20.22 km from the starting point.

Therefore, the second biker is farther from the parking lot.

A sketch of the path of travel for the two bikers is attached for more clarifications.

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b. gh is a perp. bisector .

Answer:

option c.)

Step-by-step explanation:

m∠1 + m∠3 = 180°