what would the algebraic expression be for the product of 3 and x increased by 20

Answers

Answer 1

Answer:

3x + 20

Step-by-step explanation:

Product is for multiplication therefore, the product of 3 and x is 3x.

increased = addition

Overall, the product of 3 and x increased by 20 is 3x + 20.


Related Questions

Can anyone answer this for me?

Answers

Answer:

y = 2 - [tex]x^{2}[/tex]

Step-by-step explanation:

[tex]x^{2}[/tex] results in a parabola (U-shape). Adding a negative in front of it flips the parabola to look like an upside-down U.

The 2 makes it shift up two decimal spots to (0,2).

12.915 to 2 decimal places

Answers

Answer:

12.92

Step-by-step explanation:

rounding the 1 hundredth up to 2 because of the 5 thousandth

Answer:

12.915 to 2.d.p :12.92

Step-by-step explanation:

See explanation in attached image

Cos 600 degrees solved by double angle formula (20 points)
show work please :)))

Answers

Answer:

[tex] \rm\cos({600}^{ \circ} ) =-1/2 [/tex]

Step-by-step explanation:

we would like to solve the following using double-angle formula:

[tex] \displaystyle \cos( {600}^{ \circ} ) [/tex]

there're 4 double Angle formulas of cos function which are given by:

[tex] \displaystyle \cos(2 \theta) = \begin{cases} i)\cos^{2} ( \theta) - { \sin}^{2}( \theta) \\ii) 2 { \cos}^{2}( \theta) - 1 \\iii) 1 - { \sin}^{2} \theta \\ iv)\dfrac{1 - { \tan}^{2} \theta}{1 + { \tan}^{2} \theta } \end{cases}[/tex]

since the question doesn't allude which one we need to utilize utilize so I would like to apply the second one, therefore

step-1: assign variables

to do so rewrite the given function:

[tex] \displaystyle \cos( {2(300)}^{ \circ} ) [/tex]

so,

[tex] \theta = {300}^{ \circ} [/tex]

Step-2: substitute:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2 \cos ^{2} {300}^{ \circ} - 1[/tex]

recall unit circle thus cos300 is ½:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2 \left( \dfrac{1}{2} \right)^2 - 1[/tex]

simplify square:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2\cdot \dfrac{1}{4} - 1[/tex]

reduce fraction:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = \dfrac{1}{2} - 1[/tex]

simplify substraction and hence,

[tex] \rm\cos({600}^{ \circ} ) = \boxed{-\frac{1}{2}}[/tex]

please show work it’s for calc

Answers

Answer:

24

Step-by-step explanation:

The question is asking for the net area from x=3 to x=10.

It gives you the net area from x=3 to x=5 being -18.

It gives you the net area from x=5 to x=10, being 42.

Together those intervals make up the interval we want to find the net area for.

-18+42=42-18=24

Answer:

[tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt = 24[/tex]

General Formulas and Concepts:

Calculus

Integration

Integrals

Integration Property [Splitting Integral]:                                                               [tex]\displaystyle \int\limits^c_a {f(x)} \, dx = \int\limits^b_a {f(x)} \, dx + \int\limits^c_b {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^{5}_3 {f(t)} \, dt = -18[/tex]

[tex]\displaystyle \int\limits^{10}_5 {f(t)} \, dt = 42[/tex]

[tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt[/tex]

Step 2: Integrate

[Integral] Rewrite [Integration Property - Splitting Integral]:                      [tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt = 24 = \int\limits^5_3 {f(t)} \, dt + \int\limits^{10}_5 {f(t)} \, dt[/tex][Integrals] Substitute:                                                                                    [tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt = 24 = -18 + 42[/tex]Simplify:                                                                                                         [tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt = 24[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

a sum of money Doubles itself in 5 years what is rate of simple interest​

Answers

Step-by-step explanationIf you are reading this say

thank u

20) solve:
[tex] {8}^{2} + 2 = [/tex]
21) solve:
[tex]4(2x + 5y = [/tex]
22) simplify the expression
[tex]4( {2}^{2} + 30) - 4 = [/tex]

Answers

Ques20. 66
Ques21. 8x+20y
Ques22. 132

A particle moves along a line with a velocity v(t)=t2−t−6, measured in meters per second. Find the total distance the particle travels from t=0 seconds to t=4 seconds.

Answers

The total distance the particle travels from t=0 seconds to t=4 seconds would be 11.33 meters.

Used the concept of integration that states,

In Maths, integration is a method of adding or summing up the parts to find the whole. It is a reverse process of differentiation, where we reduce the functions into parts.

Given that,

A particle moves along a line with a velocity v(t) = t² - t - 6, measured in meters per second.

Now the total distance the particle travels from t=0 seconds to t=4 seconds is,

D = ∫₀⁴ |(t² - t - 6)| dt

D =  ∫₀⁴ (t²) dt - ∫₀⁴ (t) dt -  ∫₀⁴ (6) dt

D = (t³/3)₀⁴ - (t²/2)₀⁴ - 6 (t)₀⁴

D =| (64/3) - (16/2) - 6 (4)|

D = | (64/3) - 8 - 24 |

D = | (64/3) - 32|

D = 11.33 meters

Therefore, the total distance is 11.33 meters.

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please help, is associated with angles. thank u :)

Answers

Answer:

Step-by-step explanation:

Because those lines are parallel, that means that the angle measuring 75 and the angle measuring 4x + 7 are alternate interior and by definition are congruent. Therefore,

75 = 4x + 7 and

68 = 4x so

x = 17

Find the value of m if x + m is a factor of x^2 - 5mx + 3​

Answers

Answer:

+or- sqrt(3/4)

Step-by-step explanation:

If x + m is a factor, that means that when x = -m the equation equals 0. Sub -m into x

0 = (-m)^2 - 5m(-m) + 3

0 = m^2 - 5m^2 + 3

0 = -4m^2 + 3

Factorise

0 = -4(m^2 - 3/4)

0 = -4(m + sqrt(3/4))(m - sqrt(3/4))

:. m = +or- sqrt(3/4)

If a sine curve has a vertical shift down 19 units with an amplitude of 21, what will the minimum and maximum values be? (i.e. how high and low will the graph go?)
Min Value:
Max Value:

Answers

Given:

Amplitude = 21

Vertical shift = 19 units down

To find:

The maximum and the minimum value.

Solution:

The general form of sine function is:

[tex]y=A\sin (Bx+C)+D[/tex]

Where, |A| is amplitude, [tex]\dfrac{2\pi}{B}[/tex] is period, [tex]-\dfrac{C}{B}[/tex] is phase shift and D is the vertical shift.

Here,

[tex]Maximum=D+A[/tex]

[tex]Minimum=D-A[/tex]

We have,

Amplitude: [tex]A = 21[/tex]

Vertical shift: [tex]D=-19[/tex]

Negative sign means shifts downwards.

Now,

[tex]Maximum=D+A[/tex]

[tex]Maximum=-19+21[/tex]

[tex]Maximum=2[/tex]

And,

[tex]Minimum=D-A[/tex]

[tex]Minimum=-19-21[/tex]

[tex]Minimum=-40[/tex]

Therefore, the minimum value is -40 and the maximum value is 2.

Please help explanation if possible

Answers

Answer: y = -3x + 5

Step-by-step explanation:

slope = m

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{2-(-4)}{1-3}=\frac{6}{-2}=-3[/tex]

y = mx + b, (3,-4), (1,2), m = -3

(both points work for the y = mx + b equation)

[tex]y=mx+b\\2=-3(1)+b\\2=-3+b\\b=5\\y=-3x+5[/tex]

1. 9+x-7
2. 8-2x+5x
3. -x-9+3x
4. 4x-6-4x

Answers

Answer:

1)9-7+x

2+x

2)8-2x+5x

8+3x

3)-x+3x-9

2x-9

4)4x-4x-6

-6

you have to group the like terms

I hope this helps and sorry if they are wrong

SOMEONE PLEASE HELP ME OUT ON THIS. PLEASE!
n= 1. then a1= 7+3(1)

How to solve it.

Answers

Answer:

I think this is right for the 2nd problem

Step-by-step explanation:

a1=7+(3)(1)

Step 1: Simplify both sides of the equation.

a1=7+(3)(1)

a=7+3

a=(7+3)(Combine Like Terms)

a=10

a=10

Answer:

a=10

please help have a lot of math to do today

Answers

Answer:

115 in.^2

Step-by-step explanation:

The total surface area is the sum of the areas of the square base and the 4 congruent triangular faces.

SA = b^2 + 4 * bh/2

SA = (5 in.)^2 + 4 * (5 in.)(9 in.)/2

SA = 25 in.^2 + 2 * 45 in.^2

SA = 115 in.^2


Name the property shown by the statement a + b + 2 = 2 + a + b

Answers

This property is known as COMMUTATIVE PROPERTY

The population, P, of six towns with time t in years are given by the following exponential equations:
(i) P = 1000 (1.08) Superscript t (ii) P = 600 (1.12) Superscript t
(iii) P = 2500 (0.9) Superscript t (iv) P = 1200 (1.185) Superscript t
(v) P = 800 (0.78) Superscript t (vi) 2000 (0.99) Superscript t
Which town decreasing the fastest?
a.
ii
c.
iii
b.
v
d.
vi



Please select the best answer from the choices provided


A
B
C
D

Answers

Given:

The population, P, of six towns with time t in years are given by the following exponential equations:

(i) [tex]P=1000(1.08)^t[/tex]

(ii) [tex]P = 600 (1.12)^2[/tex]

(iii) [tex]P =2500 (0.9)^t[/tex]

(iv) [tex]P=1200 (1.185)^t[/tex]

(v) [tex]P=800 (0.78)^t[/tex]

(vi) [tex]P=2000 (0.99)^t[/tex]

To find:

The town whose population is decreasing the fastest.

Solution:

The general form of an exponential function is:

[tex]P(t)=ab^t[/tex]

Where, a is the initial value, b is the growth or decay factor.

If b>1, then the function is increasing and if 0<b<1, then the function is decreasing.

The values of b for six towns are 1.08, 1.12, 0.9, 1.185, 0.78, 0.99 respectively. The minimum value of b is 0.78, so the population of (v) town  [tex]P=800 (0.78)^t[/tex] is decreasing the fastest.

Therefore, the correct option is b.

What is the measure of m?
6
24
n
m
m =
[?]
Enter

Answers

the measure of m is24 according to the questions

The graph below could be the graph of which exponential function?

Answers

Answer:

B

Step-by-step explanation:

Which statement is true about this quadratic equation?
y = 12 – 11x + 7
A.
There is one real solution.
B.
There are two complex solutions.
C.
There are two real solutions.
D.
There is one complex solution,

Answers

The statement that is true about the quadratic equation is (b) There are two complex solutions.

Identifying the statement that is true about the quadratic equation

From the question, we have the following parameters that can be used in our computation:

y = 12 – 11x + 7

Express properly

So, we have

y = 12x² – 11x + 7

Next, we calculate the discriminant using

d = b² - 4ac

Where

a = 12

b = -11

c = 7

Substitute the known values in the above equation, so, we have the following representation

d = (-11)² - 4 * 12 * 7

Evaluate

d = -215

This value is less than 0

This means that it has complex solutions

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if 20,x,y,z,25 are in AP .find the value of X,y,z.​

Answers

Answers:

x = 21.25y = 22.5z = 23.75

=============================================================

Work Shown:

AP = arithmetic progression, which is the same as arithmetic sequence

d = common difference

x = 20+dy = 20+2dz = 20+3d

Notice how we scale up the d terms d, 2d, 3d, counting up by 1 each time.

So that must mean 25 is the same as 20+4d

20+4d = 25

4d = 25-20

4d = 5

d = 5/4

d = 1.25

and therefore,

x = 20+d = 20+1.25 = 21.25y = 20+2d = 20+2*1.25 = 22.5z = 20+3d = 20+3*1.25 = 23.75

We could convert these to fraction form, but I find decimal form is easier in this case.

(2/1.3)+(2/3.5)+(2/5.7)+ ... + (2/97.99) > 98%

Answers

Step-by-step explanation:

gxhkmnjggggffffffcccccccccccc

Read is solving the quadratic equation 0 equals X over two minus 2X -3 using the quadratic formula which shows the correct substitution of the values ABC into the quadratic formula quadratic formula X equals negative B+

Answers

Answer:

[tex]x = \frac{-(-2) \± \sqrt{(-2)^2 - 4*1*-3}}{2*1}[/tex]

Step-by-step explanation:

Given

[tex]0 = x^2 - 2x -3[/tex]

Required

The correct quadratic formula for the above

A quadratic equation is represented as:

[tex]ax^2 + bx + c = 0[/tex]

And the formula is:

[tex]x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]

So, we have:

[tex]0 = x^2 - 2x -3[/tex]

Rewrite as:

[tex]x^2 - 2x - 3 = 0[/tex]

By comparison:

[tex]a= 1; b = -2; c = -3[/tex]

So, we have:

[tex]x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]x = \frac{-(-2) \± \sqrt{(-2)^2 - 4*1*-3}}{2*1}[/tex]

Can somebody help me with this question

Answers

Answer:

900°

Step-by-step explanation:

The interior angles sum = 180° ( n - 2 )

~~~~~~~~

n = 7

180° ( 7 - 2 ) = 900°

Answer:

900 degrees

Step-by-step explanation:

just apply the formulas discussed in class !

The sum of interior angles in a triangle is 180°. To find the sum of interior angles of a polygon, multiply the number of triangles in the polygon by 180°.

The number of triangles in each polygon is two less than the number of sides.

The formula for calculating the sum of interior angles is:

(n−2)×180∘ (where n is the number of sides)

in our case we have 7 sides.

so, we could split this polygon into 5 triangles.

each of these triangles would have an angle sum of 180°.

so, the angle sum of the polygon is

5×180 = 900°

Find the missing side. Round your answer to the nearest tenth. 19, 36

Answers

Answer:

x=110.6

Step-by-step explanation:

sin(19)=36/x. x=36/sin(19)=110.6

The diameter of a $1 coin is 26.5 mm. Find the area of one side of the coin. Round to the nearest hundredth.

Answers

The area of one side of the coin is 41.605 mm².

Given that, the diameter of a $1 coin is 26.5 mm.

We need to find the area of one side of the coin.

What is the area of a circle formula?

The area of a circle formula is A=πr².

Now, radius=26.5/2=13.25 mm.

Area of a coin=3.14×13.25=41.605 mm².

Therefore, the area of one side of the coin is 41.605 mm².

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Solve.
Sy= 2x - 6
4x – 2y = 14
Use the substitution method

Answers

Answer:

14.4 i hope it helped you

Complete the statements.
f(4) is
f(x) = 4 when x is

Answers

F(4)=1/2
F(x)=4 when x is 8


Hope this helps:)

The answer X is 8
Hope I helped

Wilma worked 38 hours 52 minutes last week. She earns $25.15 per hour. What is wilma's pay for this work period? Round your answer to the nearest hundredth

Answers

Answer:

$968.78

Step-by-step explanation:

multiply worked hours by her pay per hour

38.52×$25.15=

38.52×$25.15=$968.778

then you round it to the nearest hundredth

since the thousandth is greater than 5 the 8 will round the 7 to an 8

giving you $968.78

Answer: $977.50

Step-by-step explanation:

(38)(25.15)=955.70

(52)(25.15)/60=21.80

955.70 + 21.80 = 977.50

SEE QUESTION IN IMAGE

Answers

Answer:

c) 11.5

Step-by-step explanation:

Total frequencies:

6 + 15 + 20 + 7 + 2 = 50

Median group is the containing the middle - 25th and 26th frequencies. This is the 11-15 interval.

Estimated median formula:

Estimated Median = L +  ((n/2) − B)/G* w, whereL -  lower class boundary of the group containing the median = 10.5 n -  total number of values = 50 B - cumulative frequency of the groups before the median group = 6 + 15 = 21 G -  frequency of the median group = 20 w -  group width = 5

Substitute values and work out the number:

Estimated Median = 10.5 + (50/2 - 21)/20*5 = 11.5

Find x.

A. 6√6
B. 18
C. 9√2
D. 24√3

Answers

Answer:

C  

Step-by-step explanation:

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