Which equation shows that the Pythagorean identity is true for 0 = 27? Select
the equation that is in the form sin?(27) + cos2(27) = 1.
A. 02 + (-1)2 = 1
B. 02 + 12 = 1
C. (-1)² + 02 = 1
D. 12 + 02 = 1

9514 1404 393

Answer:

  a.  x = 60

  b.  y = 93

Step-by-step explanation:

The relevant relations are ...

__

Using these relations, we have ...

  A = (BC -x°)/2

  x° = BC -2A = 114° -2(27°)

  x° = 60°

__

  y° = CD/2 = (360° -BC -BD)/2 = (360° -114° -60°)/2

  y° = 93°

Answer:

Step-by-step explanation:

There are two possible equations, but neither matches the the choices you listed. The choices seem to have several typographical errors.

Point-slope form of an equation of the line through the points (-4, 7) and (5,-3) is y - 7 =(-10/9)(x + 4).

Slope

[tex]$= \frac{y_{2} -y_{1}}{x_{2} -x_{1}}[/tex]

= (-3 - 7) / (5 - (-4))

= -10/9

The point-slope equation for the line of slope -(10/9) that passes through the point (5, -3).

y + 3 = (-10/9)(x - 5)

Point slope equation for the line of slope -(10/9) that passes through the point (-4, 7)

Point-slope form of an equation of the line through the points (-4, 7) and (5,-3) is y - 7 = (-10/9)(x + 4).

Therefore, the correct answer is y - 7 = (-10/9)(x + 4).

To learn more about the equation of a line refer to:

https://brainly.com/question/11751737

#SPJ2

Answer:

75.03

Step-by-step explanation:

14×11×sin(77)

= 75.02649499..

≈ 75.03 (rounded to nearest hundredth)

Answered by GAUTHMATH

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

[tex]x^2-2x + y^2 - 6y = 26[/tex]

Typically, the equation of a circle would be in the form [tex](x-h)^2+(y-k)^2=r^2[/tex] where [tex](h,k)[/tex] is the center and [tex]r[/tex] is the radius.

To get the given equation [tex]x^2-2x + y^2 - 6y = 26[/tex] into this form, we must complete the square for both x and y.

1) Complete the square for x

Let's take a look at this part of the equation:

[tex]x^2-2x[/tex]

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

[tex]x^2-2x+1[/tex]

Great! Now, let's add this to our original equation:

[tex]x^2-2x+1+y^2-6y = 26[/tex]

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

[tex]x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27[/tex]

Complete the square:

[tex](x-1)^2+y^2-6y = 27[/tex]

2) Complete the square for y

Let's take a look at this part of the equation [tex](x-1)^2+y^2-6y = 27[/tex]:

[tex]y^2-6y[/tex]

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

[tex]y^2-6y+9[/tex]

Great! Now, back to our original equation:

[tex](x-1)^2+y^2-6y+9= 27[/tex]

Remember to add 9 on the other side as well:

[tex](x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36[/tex]

Complete the square:

[tex](x-1)^2+(y-3)^2= 36[/tex]

3) Determine the center and the radius

[tex](x-1)^2+(y-3)^2= 36[/tex]

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

Answer:

[tex]\sqrt{g^2+f^2-c}[/tex]

[tex]g=-1,f=-3,c=-26[/tex]

so, the Center of the equation is [tex](1,3)[/tex]

[tex]\sqrt{(-1)^2+(-3)^2-(-26})[/tex]

[tex]=\sqrt{1+9+26}[/tex]

[tex]=\sqrt{36}[/tex]

[tex]=6[/tex]

OAmalOHopeO

Answer:

[tex]y=-5x-3[/tex]

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0).

To solve for the equation of the line, we would need to:

1) Find the point of intersection between the two given lines

[tex]2x - 3y + 11 = 0[/tex]

[tex]5x + y + 3 = 0[/tex]

Isolate y in the second equation:

[tex]y=-5x-3[/tex]

Plug y into the first equation:

[tex]2x - 3(-5x-3) + 11 = 0\\2x +15x+9 + 11 = 0\\17x+20 = 0\\17x =-20\\\\x=\displaystyle-\frac{20}{17}[/tex]

Plug x into the second equation to solve for y:

[tex]5x + y + 3 = 0\\\\5(\displaystyle-\frac{20}{17}) + y + 3 = 0\\\\\displaystyle-\frac{100}{17} + y + 3 = 0[/tex]

Isolate y:

[tex]y = -3+\displaystyle\frac{100}{17}\\y = \frac{49}{17}[/tex]

Therefore, the point of intersection between the two given lines is [tex](\displaystyle-\frac{20}{17},\frac{49}{17})[/tex].

2) Determine the slope (m)

[tex]m=\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Plug in the two points [tex](\displaystyle-\frac{20}{17},\frac{49}{17})[/tex] and (-1,2):

[tex]m=\displaystyle \frac{\displaystyle\frac{49}{17}-2}{\displaystyle-\frac{20}{17}-(-1)}\\\\\\m=\displaystyle \frac{\displaystyle\frac{15}{17} }{\displaystyle-\frac{20}{17}+1}\\\\\\m=\displaystyle \frac{\displaystyle\frac{15}{17} }{\displaystyle-\frac{3}{17} }\\\\\\m=-5[/tex]

Therefore, the slope of the line is -5. Plug this into [tex]y=mx+b[/tex]:

[tex]y=-5x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=-5x+b[/tex]

Plug in the point (-1,2) and solve for b:

[tex]2=-5(-1)+b\\2=5+b\\-3=b[/tex]

Therefore, the y-intercept is -3. Plug this back into [tex]y=-5x+b[/tex]:

[tex]y=-5x+(-3)\\y=-5x-3[/tex]

I hope this helps!

Answer:

Hence the adjusted R-squared value for this model is 0.7205.

Step-by-step explanation:

Given n= sample size=20  

Total Sum of square (SST) =1000  

Model sum of square(SSR) =750  

Residual Sum of Square (SSE)=250  

The value of R ^2 for this model is,  

R^2 = \frac{SSR}{SST}  

R^2 = 750/1000 =0.75  

Adjusted [tex]R^2[/tex] :

[tex]Adjusted R^2 =1- \frac{(1-R^2)\times(n-1)}{(n-k-1)}[/tex]

Where k= number of regressors in the model.

[tex]Adjusted R^2 =1-(19\times 0.25/((20-2-1)) = 0.7205[/tex]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Each point moves to 3 times its original distance from P.

  A is 2 up and 1 left of P, so A' will be 6 up and 3 left of P.

  B is 1 down and 2 left of P, so B' will be 3 down and 6 left of P.

  C is 2 right of P, so C' will be 6 right of P.

Solution :

Let [tex]p_1[/tex] and [tex]p_2[/tex]  represents the proportions of the seeds which germinate among the seeds planted in the soil containing [tex]3\%[/tex] and [tex]5\%[/tex] mushroom compost by weight respectively.

To test the null hypothesis [tex]H_0: p_1=p_2[/tex] against the alternate hypothesis  [tex]H_1:p_1 \neq p_2[/tex] .

Let [tex]\hat p_1, \hat p_2[/tex] denotes the respective sample proportions and the [tex]n_1, n_2[/tex] represents the sample size respectively.

[tex]$\hat p_1 = \frac{74}{155} = 0.477419[/tex]

[tex]n_1=155[/tex]

[tex]$p_2=\frac{86}{155}=0.554839[/tex]

[tex]n_2=155[/tex]

The test statistic can be written as :

[tex]$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}[/tex]

which under [tex]H_0[/tex]  follows the standard normal distribution.

We reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance, if the P-value [tex]<0.05[/tex] or if [tex]|z_{obs}|>Z_{0.025}[/tex]

Now, the value of the test statistics = -1.368928

The critical value = [tex]\pm 1.959964[/tex]

P-value = [tex]$P(|z|> z_{obs})= 2 \times P(z< -1.367928)$[/tex]

                                     [tex]$=2 \times 0.085667$[/tex]

                                     = 0.171335

Since the p-value > 0.05 and [tex]$|z_{obs}| \ngtr z_{critical} = 1.959964$[/tex], so we fail to reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the [tex]\text{proportion}[/tex] of the seeds that [tex]\text{germinate differs}[/tex] with the percent of the [tex]\text{mushroom compost}[/tex] in the soil.

Answer:

the answer is b). z- score.

Answer:

b

Step-by-step explanation:

9514 1404 393

Answer:

  a) 16A -4B +C = 1

  b) 4A -2B +C = 0.94

  c) C = 1

Step-by-step explanation:

Substitute the x- and y-values into the general form equation.

a. A(-4)² +B(-4) +C = 1

  16A -4B +C = 1

__

b. A(-2)² +B(-2) +C = 0.94

  4A -2B +C = 0.94

__

c. A(0)² +B(0) +C = 1

  C = 1

_____

Additional comment

Solving these equations gives A=0.015, B=0.06, C=1. The quadratic is ...

  0.015x² +0.06x +1 = y

Answer:

if the zeros are x = -2, x = 0, and x = 1

then (x + 2), x and (x - 1) are factors of the polynomial

multiply these factors together

p(x) = x(x + 2)(x - 1)

p(x) = x(x2 + x - 2)

p(x) = x3 + x2 - 2x

this is a polynomial of degree 3 with the given roots

Answer:

P = 7.03 - 0.42T

Step-by-step explanation:

Let the price of a ticket be P.

Let the ticket be T.

A linear equation can be defined as an algebraic equation that's typically written for two (2) independent variables, in which each of them has an exponent of one (1) and they make a straight line when plotted on a graph.

Given the following data;

Tax = 0.42

Total bill = $7.03

Translating the word problem into an algebraic expression, we have;

0.42T + P = 7.03

P = 7.03 - 0.42T

Answer:

coefficient of determination

Step-by-step explanation:

The Coefficient of determination, R² which is the squared value of the correlation Coefficient is used to give Tha proportion of variation in the predicted / dependent variable that can be explained by the regression line. The coefficient of determination ranges from 0 to 1. Once the proportion of explained variation is obtained, the proportion of unexplained variation is ( 1 - proportion of explained variation).

Answer:

See pic below.

Answer: C. 380°

Step-by-step explanation:

We know that [tex]\log_a(bc)=\log_a(b)+\log_a(c)[/tex].

Using this rule,

[tex]\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3)[/tex].

We also know that [tex]\log_c(a^b)=b\log_c(a)[/tex].

Using this rule,

[tex]\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)[/tex]

Now we know that [tex]\log_c(A)=2,\log_c(B)=5[/tex] so,

[tex]5\cdot2+3\cdot5=10+15=\boxed{25}[/tex].

Hope this helps :)

Answer:

Step-by-step explanation:

Answer:

The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is 0.4137.

Step-by-step explanation:

The point estimate is the sample proportion.

Sample proportion:

103 out of 249, so:

[tex]p = \frac{103}{249} = 0.4137[/tex]

The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is 0.4137.

Answer:

18c^3d^9

Step-by-step explanation:

2c^3 d^2 * 9d^7

We know that  we add the exponents when the base is the same

2*9  c^3 d^(2+7)

18c^3d^9

Answer:

Feet to Miles

Step-by-step explanation:

Answer:

Feet to Miles

Step-by-step explanation:

Both units must measure the same quantity.

Answer:

r + s - 19

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

r - 7 + s - 12

Step 2: Simplify

Answer:

[tex]{ \sf{ {x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy }}[/tex]

Step-by-step explanation:

[tex]{ \tt{ {(x + y)}^{2} = (x + y)(x + y) }} \\ { \tt{ {(x + y)}^{2} = ( {x}^{2} + 2xy + {y}^{2}) }} \\ { \tt{( {x}^{2} + {y}^{2} ) = {(x + y)}^{2} - 2xy}}[/tex]

Answer: 17 feet

Step-by-step explanation:

51/48 = x/16

(51)(16)/48

The statute is 17 feet tall.

Similar triangles are the triangles that have the same shape, but different sizes. The corresponding angles are congruent and the sides are in proportion.

The ratio of any corresponding sides in two equiangular triangles is always the same.

Let's visualize the situation according to the given question.

AB is the building ,whose height is 51f

BC is the shadow of the building AB, whose length is 48ft.

QR is the shadow of the tower statue, whose length is 16feet.

Let the height of the statue PR be h feet.

In triangle ACB and triangle PRQ

∠ACB = ∠PRQ = 90 degrees  

( the objects and shadows are perpendicular to each other)

∠BAC = ∠QPR

( sunray falls on the pole and tower at the same angle, at the same time )

⇒ΔACB similar to ΔPRQ   ( AA criterion)

Therefore, the ratio of any two corresponding sides in equiangular triangles is always same.

⇒ AC/CB = PR/RQ

⇒[tex]\frac{51}{48} =\frac{h}{16}[/tex]

⇒ h = [tex]\frac{(51)(16)}{48}[/tex]

⇒ h = 17 feet.

Hence, the statute is 17 feet tall.    

Learn more about the similar triangle here:

brainly.com/question/25882965

#SPJ2

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

Answer:

"D"

if you multiply by Conjugate

the denominator would end up A^2 - b^2

the answer has 25 - 10x

that is D

Step-by-step explanation:

Answer:

D)

Step-by-step explanation: Im not so sure ok i sorry if Im wrong

9514 1404 393

Answer:

  (a) The blue line ... solution ... (-6, -2)..

Step-by-step explanation:

The second equation describes a line with negative slope and a y-intercept of -4. This is clearly the red line on the graph.

The blue line represents the equation 2x -3y = -6.

The point of intersection of the two lines is (-6, -2), so that is the solution to the system of equations. This, by itself, is sufficient for you to choose the correct answer.

(D)

Step-by-step explanation:

Multiply and divide the fraction by the conjugate:

[tex]\dfrac{2}{\sqrt{13}+\sqrt{11}}×\dfrac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}[/tex]

[tex]= \dfrac{2(\sqrt{13} - \sqrt{11})}{(\sqrt{13})^2 - (\sqrt{11})^2}[/tex]

[tex]=\dfrac{2(\sqrt{13} - \sqrt{11})}{2}[/tex]

[tex]=\sqrt{13} - \sqrt{11}[/tex]

Answer:

Step-by-step explanation:

Here's how you convert:

[tex]\sqrt[n]{x^m}=x^{\frac{m}{n}[/tex]  The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.

A couple of examples:

[tex]\sqrt[3]{x^4}=x^{\frac{4}{3}[/tex]

[tex]\sqrt[5]{x^7}=x^{\frac{7}{5}[/tex]

It's that simple. For your problem in particular:

[tex]\sqrt[3]{7}[/tex] is the exact same thing as [tex]\sqrt[3]{7^1}=7^{\frac{1}{3}[/tex]