Which process is represented by the picture below?

A. Vegetative Propagation
B. Meiosis
C. Fertilization
D. Binary Fission



HELPP MEEE

Answer:

mitosis is a process of cell division in which one cell is divided into two and the two cells produced are exacty similar to the parent cell. chromosome number cell size remains same.

mitosis plays an important role in growth of organisms.

Explanation:

Answer:

1

djdhdbbdbdbsbdbdbsb

Answer:

Mass of LiCi = 17.9352 gm

Explanation:

Given:

Volume of LiCi = 235 ml

Molarity = 1.80 M

Find:

Mass of LiCi

Computation:

Atomic mass of LiCi = 6.9 + 365.5 = 42.4 gm

Mole(n) = Weight / Atomic mass

1.80 = [W / (42.4 x 235)]1000

Mass of LiCi = 17.9352 gm

Answer:

C. The genetic code is not overlapping.

Explanation:

The genetic code is nonoverlapping because each nucleotide can be part of only one codon or 'codeword' during protein synthesis. Therefore, a particular point mutation in the nucleotide sequence can result in only one amino acid modification. A nonoverlapping genetic code indicates that the same letter (i.e., the same nucleotide) can not be used for two different codons. The non-overlapping nature of the genetic code was discovered by Tsugita and Fraenkel-Conrat (1960) by observing point mutations in the tobacco mosaic virus.

A change or modification in the single nucleotide base of the genetic material is called a point mutation. It can be either addition, deletion or inversion.

The correct answer is:

Option C. The genetic code is not overlapping.

This can be explained as:

Therefore, point mutation tells that the genetic code is non-overlapping.

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Answer:

Jesus made every one evalution is false

When Charles Darwin introduced the theory of evolution through natural selection 158 years ago, the scientists of the day argued over it fiercely, but the massing evidence from paleontology, genetics, zoology, molecular biology and other fields gradually established evolution's truth beyond reasonable doubt. Today that battle has been won everywhere—except in the public imagination. Embarrassingly, in the 21st century, in the most scientifically advanced nation the world has ever known, creationists can still persuade politicians, judges and ordinary citizens that evolution is a flawed, poorly supported fantasy. They lobby for creationist ideas such as “intelligent design” to be taught as alternatives to evolution in science classrooms. When this article first went to press in 2002, the Ohio Board of Education was debating whether to mandate such a change. Prominent antievolutionists of the day, such as Philip E. Johnson, a law professor at the University of California, Berkeley, and author of Darwin on Trial, admitted that they intended for intelligent-design theory to serve as a “wedge” for reopening science classrooms to discussions of God.

The good news is that in 2005 the landmark legal case Kitzmiller v. Dover in Harrisburg, Pa., set binding precedent that the teaching of intelligent design in U.S. public schools is unconstitutional because the idea is fundamentally religious, not scientific. The bad news is that in response, creationists have reinvented their movement and pressed on. When they lost the ability to claim that creationist ideas are valid science, they switched to arguing that they were only supporting “academic freedom.” Worse, to further obscure the religious roots of their resistance, they now push for “critical analysis” of climate change, cloning research and other scientific endeavors that they paint as culturally oppressive.Explanation:

The answer is True.

Answer:

D. Nerve tissue

Explanation:

Answer:

C. Nucleotide

Explanation:

There are four types of biological molecules existing in nature. These are: carbohydrates, proteins, lipids, and nucleic acids. Nucleic acids are biological polymers made up of monomeric units called NUCLEOTIDES.

A nucleotide as depicted in the attached image is a molecule made up of three components namely; Penrose sugar, phosphate group, and nitrogenous base (adenine, guanine, cytosine and thymine). Based on the image in this question;

A represents ADENINE

S represents SUGAR

P represents PHOSPHATE GROUP

Hence, the monomer is a NUCLEOTIDE.

Answer: i would say b!

Explanation:

hope i helped! :D

Recombination frequency determines if two genes are linked or if they segregate independently from each other. The recombination frequency between E and H is 8%

Linked genes are those that are too close to each other in the same chromosome and they do not segregate independently.

These are the linked genes that do not exhibit an independent distribution, and they are inherited together more frequently.  

Recombination frequency can be defined as the crossing over events  frequency occurring between two genes.

The value of recombination frequency indicates weather genes are linked or not. The maximum recombination frequency is always 50%.

When RF is 50% or more, we can assume that genes are not linked.

In the exposed example, we can recognize the parental gametes in the descendants because their phenotypes are the most frequent, while the double recombinants are the less frequent.

Parental)

400 ee Hh Bb

426 Ee hh bb

Double recombinant)

4 Ee Hh Bb

2 ee hh bb

Simple recombinant)

48 ee Hh bb

36 ee hh Bb

46 Ee hh Bb

38 Ee Hh bb

We will call Region I to the area between genes E and H and Region II to the area between genes H and B.

------------E------------H--------------B-----------

              /---RI------//------RII-----/

To calculate the recombination frequency between E and H we just need to consider region I. We will call P1 to the recombination frequency in this region.

P1 = (R + DR) / N

Where:

Now, let us analyze the information.

We know that individuals carrying double recombinant gametes are

We know that the recessive parent from the testcross could only provide the following gametes ⇒ ehb

This leads us to assume that the followings are the double recombinant gametes from the trihybrid parent,

Since these gametes are the product of a double recombination event in region I and II, we can assume that the parental gametes of the trihybrid individual are

Hence the simple recombinant gametes in region I are

Now, according to this analysis, we know that

Simple recombinants in region I

36 ee hh Bb

38 Ee Hh bb

Double recombinants

4 Ee Hh Bb

2 ee hh bb

Total number of individuals

N = 1000

Recombination frequency in Region I

P1 = (R + DR) / N

P1 = (38 + 36 + 4 + 2) / 1000

P1 = 80 / 1000

P1 = 0.08 = 8%

The recombination frequency between genes E and H is P1 = 8%

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Answer:

The probability of exactly 3 heads in 10 tosses is 1201024.

The probability that result will be head in the next toss is 1/2.

This is a mathematical term which is used to describe how likely an event is to occur or how true a proposition is. In this scenario, we have two variables which are head and tail.

The probability probability of tossing heads in your next toss is therefore

1/2 = 50% chance.

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DNA contains the instructions for an needed for an organism to develop, survive, and reproduce.

Answer: it would be b!

Explanation:

Answer:

the answer is two for this question

Answer:

The size of the brain cavity increased.

Explanation:

Over the years the brain cavity got bigger  and so did our brain and that is why humans are smarter

The evolution of hominid structure over time involved the increase in the size of the brain cavity.

Evolution refers to the gradual and cumulative changes that occurred in organisms over a long period of time which made them more complex and which they were able to transmit to their offspring.

The hominids were the ancestors of the modern day humans.

Through the process of evolution, the size of the brain cavity increased in hominids resulting in larger brains and more complexity as seen in modern humans today.

Therefore, the increase in the brain cavity of hominids occurred through the process of evolution.

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The most likely to happen to the cell is ; ( C ) It will expand as water moves into it

The movement of water in and out of a cell is based on osmosis .The cell membrane of the cell will regulate the movement of water molecules in and out of the cell. based on the solute concentration inside the cell and outside the cell.

When a cell is placed in a hypotonic solution ( i.e. a solution with a lower solute concentration as seen in the 2% salt solution ) the water molecules from the hypotonic solution will move into the cell which will cause the cell to be Turgid/expand over time.  

Hence we can conclude that the most likely thing to happen to the cell is ;  It will expand as water moves into it

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Answer:

facilitated diffusion

Explanation:

Answer:

I think 3 because I had the same thing but eah

Answer:

an idea that can be used to talk about the world

Explanation:

Answer:

aa

Explanation:

A widow's peak is the dominant genotype so one must not have that trait. If it was presented then the woman would have the genotype.

A widow's peak is dominant so the man would be either AA or Aa. Since it stated that his is heterozygous (Hetero meaning two different), his genotype would be Aa (again since a widow's peak is the dominant, it only needs one dominant genotype)

Answer:

you're correct

Explanation:

Answer:

楽しい時間楽しい時間楽しい時間

Explanation:

The given statemnet is false because  Free or low-cost apps can provide many of the same benefits as fitness trackers, albeit with some limitations.Option B

Fitness trackers are dedicated devices designed specifically for monitoring physical activity and collecting data related to fitness goals. They often include features like step counting, heart rate monitoring, sleep tracking, and GPS tracking. These devices may offer a more seamless and integrated user experience, with optimized hardware and software for tracking and analyzing fitness data.

However, free or low-cost apps can offer similar benefits and functionalities, albeit with some trade-offs. Many smartphone apps are available that can track steps, monitor heart rate, record workouts, and provide guidance for various exercises. These apps can be downloaded and installed on smartphones, making them accessible and convenient for users.

While some features might be more accurate or reliable in dedicated fitness trackers due to specialized sensors, smartphone apps can still provide valuable data and insights for tracking fitness progress. They can offer personalized workout plans, track progress over time, provide reminders and notifications, and offer social features for sharing achievements and connecting with others.

Moreover, free or low-cost apps often come with the advantage of being customizable, allowing users to choose the features and functionalities that are most relevant to their specific fitness goals and preferences. They can be easily updated and expanded with new features as technology advances.

In conclusion, while dedicated fitness trackers may offer a more comprehensive and optimized experience, free or low-cost apps can still provide many of the same benefits, making them a viable alternative for individuals seeking fitness tracking capabilities.

Option B

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Answer:

Diagram A

Explanation:

This is because binary fission is asexual reproduction by a separation of the body into two new bodies. In the process of binary fission, an organism duplicates its genetic material, or deoxyribonucleic acid (DNA), and then divides into two parts (cytokinesis), with each new organism receiving one copy of DNA.

Answer:

Location 4

Explanation:

The closest you are to a tectonic plate, the most likely is to expect an earthquake. Note how Location 3 is over California. So, location 4 is away from the tectonic plates.

Answer:    The answer is B.  prophase, metaphase, anaphase, telophase

Explanation:    

Answer:

The correct answer is -3/16

Explanation:

The cross between BBss and bbSS In cocker spaniels will form gametes that are - Bs and bS. As it is given that  black coat color ( B) is dominant over red ( b), and solid color ( S) is dominant over spotted ( s) then f1 gen would be :

      Bs      Bs

bS BbSs  BbSs

bS  BbSs  BbSs

Now F2 generation;

       BS        Bs        bS        bs

BS   BBSS   BBSs   BbSS   BbSs

Bs   BBSs    BBss   BbSs   Bbss

bS   BbSS   BbSs   bbSS    bbSs

bs   BbSs   Bbss   bbSs     bbss

Here black-spotted that is possible only in two cases, BBss or Bbss, are 3/16