why meter cube is called derived unit

Answers

Answer 1

Answer:

Because it is the result of two more fundamental units, a derived unit is termed that. For volume, the cubic meter (m³) is the fundamental unit of area. Any number that cannot be measured directly with any equipment is referred to as a derived unit. For example, we can't quantify a substance's density using a rule, scale, or bucket.

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Answer 2
The quantities that are expressed in terms of base quantities are called derived quantities
And Meter cube is derived from base quantity so it’s called a derived quantity
Hope it helps❤️⭐️

Related Questions

A 21 newton force keeps a 3 kg object in uniform circular motion. The speed of the object is 9 m/s. The magnitude of the centripetal acceleration is


3 m/s^2
7 m/s^2
27 m/s^2
30 m/s^2

Answers

Answer:

Explanation:

F = ma

a = F/m = 21/3 = 7 m/s²

What is the difference between speed and velocity?

Answers

Speed is the rate of change of distance with time while velocity is the rate of change of displacement with time.Speed is a scalar quantity while velocity is a vector quantity.Speed cannot be negative but velocity can be negative.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Calculate the net force acting on a body of mass 20 kg moving with a
uniform velocity of 4 ms-1.

Answers

Answer:

0 N

Explanation:

Uniform velocity means no acceleration and therefore no net force.


BECAUSE OF THEIR A PAIR OF SUNGLEASSES ON THE DASHBOARD WILL CONTINUE MOVING FORWARD WHEN THE CAR TURNS SHARPLY

a. Acceleration
b. inertia
c. velocity
d. weight

Answers

Answer:

b. inertia

Explanation:

BECAUSE OF THEIR inertia A PAIR OF SUNGLEASSES ON THE DASHBOARD WILL CONTINUE MOVING FORWARD WHEN THE CAR TURNS SHARPLY.

Use the circuit diagram to decide if the lightbulb will
light. Justify your answer.

Answers

Answer:

The light bulb will NOT light because the lower switch being closed makes a short circuit. The light will have a high resistance and the electricity will choose to flow the easiest way possible through the low resistance wires.

Explanation:

What is the object' velocity between O s and 2 s?

Answers

Answer:

Explanation:

Acceleration b/c 0m/s/2s =0m/s²

Car 1 of mass m1 is waiting at a traffic light.
Car 1 is struck from behind by Car 2 of mass m2.
The two cars stick together after the collision.
Car 2 was traveling at v2i = 30.0 m/s before the collision.

What is the kinetic, in [J], of the system after the collision if m1 = 2500 kg and m2 = 1000 kg?

Answers

Answer:

Explanation:

Conservation of momentum

2500(0) + 1000(30) = (2500 + 1000)v

v = 8.57 m/s

KE = ½(2500 + 1000)8.57² = 128,571.428... = 128 KJ

The kinetic energy of the system after the collision would be 128.5  KJ.

What is momentum?

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem Car 1 of mass m1 is waiting at a traffic light.

Car 1 is struck from behind by Car 2 of mass m2. The two cars stick together after the collision. Car 2 was traveling at v2i = 30.0 m/s before the collision.

By using the conservation of the momentum,

2500(0) + 1000(30) = (2500 + 1000)v

v = 8.57 m/s

The final velocity of the system comes out to be  8.57 m/s.

The kinetic energy of the system after the collision,

KE =1/2×(2500 + 1000)×8.57² = 128,571.4

    = 128.5  KJ

Thus, the kinetic energy of the system after the collision would be 128.5  KJ.

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Suppose a cannon is sitting on top of a 50.0 m high hill and a 5.00 kg cannon ball is fired with a velocity of 30.0 m/s at some unknown angle. What is the velocity of the cannon ball when it strikes the earth?

Answers

The final velocity of the cannon ball when it strikes the earth is 43.36 m/s.

The given parameters:

Height of the hill, h = 50 mMass of the cannon, m = 5 kgVelocity of the ball, v = 30 m/s

The final velocity of the cannon ball when it strikes the earth is calculated by applying the principle of conservation of energy as follows;

[tex]P.E_i + K.E_i = P.E_f + K.E_f\\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = g(0) + \frac{1}{2} v_f^2\\\\2gh_i + v_i^2 = v_f^2\\\\v_f = \sqrt{2gh_i + v_i^2 } \\\\v_f = \sqrt{(2 \times 9.8 \times 50) \ \ + \ \ 30^2} \\\\v_f = 43.36 \ m/s[/tex]

Thus, the final velocity of the cannon ball when it strikes the earth is 43.36 m/s.

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Kyle, a 23-year-old-male, feels as if he is always on the “edge of his seat,” as if something is going to happen. He also has problems sleeping. Kyle feels nervous continuously and cannot seem to relax. When asked if he is nervous about something in particular, he can’t pinpoint the source of his anxiety.

Answers

Based on the information given, it can be posited that Kyle has a general anxiety disorder.

Generalized Anxiety Disorder is a disorder that is characterized by persistent and excessive worry about different things. People with the disorder may anticipate disaster and are concerned about money, health, family, or other issues.

Some of the effective ways of treatment are spending more time with family and friends, doing regular exercises , enough sleeping, etc.

Learn more about disorder on:

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Just like our bodies, Earth's cycles tend to maintain a balance or equilibrium .

Answers

The Correct answer is Equilibrium

the earth's cycle cycle tend to maintain the balance or equilibrium of the earth by maintaining the proper amount of water , nitrogen , carbon , phosphorous on earth . Each of the comonent of earth's cycle is equally important because they support life on earth. They are basis of life as carbon is found in abundant amount in all the life forms. Phosphorous, nitrogen and Water is equally important in the human beings as well as in plants and animals Hence , they maintain the equilibrium of earth

What initial speed v is required if the blocks m1 =2.5 kg and m2=1.5 kg are to travel a distance d =7.0cm before coming to rest? Assume the coefficient of kinetic friction between m1 and the tabletop is ųk=0.21

Answers

Answer:

OPTRIMUM PRIDE URGH URGH URGH

Explanation:

AHHAAHAHAHAHA

How much work does an elephant do while moving a circus wagon 60 meters with a pulling force of 240N

Answers

Answer:

14,400

Explanation:

You need to do 240x60 and you would get the answer as 14,000

Michelle recently started selling her invention: A bed that looks like it floats in mid-air. The bed is actually suspended by magnetic forces. Michelle is a(n)

Answers

Answer:

Explanation:

designer

illusionist

engineer

entrepreneur

salesperson

human

inventor

Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 1.60 cm from the axis to equal 300000 g (where g is the acceleration due to gravity).
Express your answer numerically in revolutions per minute.

Answers

Answer:

Explanation:

300000(9.8) = ω²(0.0160)

ω = 13555 rad/s

13555 rad/s (60 s/min/ 2π rad/rev) = 129,445 rev/min

K
Mission CG9: Weightlessness
Consider the several locations along a roller coaster
track. In which location(s) would the riders feel less
than their normal weight? Select all that apply.
Location A
Location B
Location C
a
=-10 m/s/s, dn
--2 m/s/s, up
a--6 m/s/s, dn
Location D
Location E
x=-12 m/s/s, dn
---6 m/s/s, up

Answers

The locations where the riders feel less than their normal weight are Location A, Location C and Location D.

The given parameters;

Location A, a = 10 m/s² downLocation B, a = 2 m/s² upLocation C, a = 6 m/s² downLocation D, a = 12 m/s² downLocation E, a = 6 m/s² up

The normal weight of the riders is calculated by applying Newton's second law of motion as follows;

W = mg

W = 9.8m

The apparent weight of the riders for the upward acceleration is calculated  as follows;

[tex]R = m(g + a)[/tex]

The apparent weight of the riders for the downward acceleration is calculated  as follows;

[tex]R = m(g - a)[/tex]

The apparent weight of the riders at location A is calculated as follows;

[tex]R_ A = m(9.8 - 10)\\\\R_ A = -0.2 m[/tex]

The apparent weight of the riders at location B is calculated as follows;

[tex]R_B = m(9.8 + 2)\\\\R_B = 11.8 m[/tex]

The apparent weight of the riders at location C is calculated as follows;

[tex]R_C = m(9.8 - 6)\\\\R_C = 3.8 m[/tex]

The apparent weight of the riders at location D is calculated as follows;

[tex]R_D = m(9.8 - 12)\\\\R_D = -2.2 m[/tex]

The apparent weight of the riders at location E is calculated as follows;

[tex]R_E = m(9.8 + 6)\\\\R_E = 15.8 m[/tex]

Thus, the locations where the riders feel less than their normal weight are;

Location ALocation CLocation D.

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Anyone know? plzz It's a grade.

Answers

Answer:

Gregor Mendal discovered the basic laws of inheritance he concluded that genes come in pairs and are are inherited from each parent. Rosalind Franklin discovered the structure of DNA(Deoxyribonucleic Acid), and RNA(Ribonucleic Acid). She also discovered about the double helix structure of DNA. She works on the composition of the human body and her discoveries were vast. Watson and Clark were one of the greatest genetic discoverers ever. They were the ones who rose modern molecular biology. In short terms, they were the ones concerned with how genes work and there role in DNA Replication.

Explanation:

The part of the circuit that converts electrical energy into other forms

Answers

Answer:

Load

Explanation:

The load in an electric circuit is any device that converts electrical energy into another form of energy.

what is the relationship between work and mechanical advantage

Answers

Answer:
Mechanical efficiency: the comparison of the machine's work output with it's work input
Mechanical advantage: the number of times that the machine multiplies the force


Explained:

A solid, uniform sphere with a mass of 2.5 kg rolls without slipping down an incline plane starting from rest at a vertical height of 19 m. If the sphere has a radius of 0.60 m, what is the angular speed of the sphere at the bottom of the incline plane

Answers

Answer:

1/2 m v^2 + 1/2 I ω^2 = m g h       conservation of energy

I = 2/5 m R^2     inertia of solid sphere

1/2 m v^2 + 1/5 m ω^2 R^2 = m g h

1/2 v^2 + 1/5 v^2 = g h

v^2 = 10 g h / 7 = 1.43 * 9.80 * 19 m^2/s^2 = 266 m^2/s^2

v = 16.3 m/s

v = R ω

ω = 16.3 / .6 = 27.2 / sec

As the amount of charge on either of two charged objects increases, the electric force between the objects decreases.

O True O False​

Answers

Answer:

False.

Explanation:

provided the distance between the forces remains the same, the force will increase with increased charge, whether attractive or repulsive.

3. A ball is dropped from the roof of a building 55 meters tall. What is the approximate time of fall?
(Neglect air resistance and round to 2 decimal places).

Answers

Answer:

3.35 seconds

Explanation:

Use one of the equations of accelerated motion:

Δd = v1Δt+1/2aΔt^2

and rearrange for Δt which is time

Δt = √(2Δd)/a

now we can substitute in the values

a= 9.8 (acceleration due to gravity) and Δd= 55 as that is the height of the building

Δt = √(2*55)/9.8

Δt = 3.3503s

Who won the noble prize for physics. He led a coalition of scientists who argued to control nucleus weapons

Answers

Answer:

Linus Pauling

Explanation:

Prize motivation: "for his fight against the nuclear arms race between East and West." Linus Pauling received his Nobel Prize one year later, in 1963.

Qué velocidad –en m/s– tiene un móvil, que recorre 15 km en 20 minutos
(es para hoy por faaaa)

Answers

Answer:

Explanation:

15 km(1000 m / km) / (20 min(60 s/min)) = 12.5 m/s

what is dispersion of light?​

Answers

Answer:

[tex] \huge \bold \blue{ \underline{ answer}}[/tex]

The splitting up of light into its constituent colours while passing from one medium to the other is called dispersion.

What are the two fundamental ways energy and momentum are moved from one place to another?​

Answers

The two fundamental ways energy and momentum are moved from one

place to another are through the mass and velocity.

The formula for momentum is mass multiplied with velocity.

Momentum= mass × velocity

The two factors in which momentum and energy is moved from one place to

another is however through how much and how fast the object is moving

which validates the answer.

Read more on https://brainly.com/question/1042017

An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?

Answers

Answer:

Explanation:

acceleration=  change in velocity/time taken

acceleration=  93/49

=2.02

Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula
KE = one half.mv2, where m is the mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of
0.8 m will be 4 m/s, and use this speed for each calculation.

Record your calculations in Table A of your Student Guide.

When the mass of the bottle is 0.125 kg, the KE is
✔ 1
kg m2/s2.

When the mass of the bottle is 0.250 kg, the KE is
✔ 2
kg m2/s2.

When the mass of the bottle is 0.375 kg, the KE is
✔ 3
kg m2/s2.

When the mass of the bottle is 0.500 kg, the KE is

✔ 4
kg m2/s2.

Answer included in Question

Answers

Answer:

kinetic energy is given as KE = (0.5) m v²given that : v = speed of the bottle in each case =  4 m/s when m = 0.125 kg KE = (0.5) m v² =  (0.5) (0.125) (4)²

Explanation:

Answer:

1. 0.5    2.  2    3. 3.75    4.  5

Explanation:

all pressure topics in physics​

Answers

Absolute, Atmospheric, Differential, and Gauge Pressure

Which kind of chemical reaction is best
represented by the following equation?
BaCl2 + Na2S04 --> 2NaCl + BaSO4
A. Synthesis
B. Single displacement
C. Decomposition
D. Double displacement

Answers

Answer:

Synthesis

Explanation:

[tex] \color{lime}{ \sf better \: luck \: on \: your \: exam \: lol}[/tex]

A container holds 192 g of oxygen gas at a pressure of 8.00 atm.
How much heat Q is required to increase the temperature by
145 °C at constant volume?

Answers

The quantity of heat (Q) that is required to increase the temperature at constant volume is 18,082.95 Joules.

Given the following data:

Mass of oxygen gas = 192 gPressure = 8.00 atmTemperature = 145°C

Scientific data:

Ideal gas constant, R = 8.314 J/molKMolar mass of oxygen gas = 32 g/mol.

To determine the quantity of heat (Q) that is required to increase the temperature at constant volume:

First of all, we would find the number of moles of oxygen gas.

[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{192}{32}[/tex]

Number of moles = 6 moles.

At constant volume, the heat capacity for a diatomic gas is given by:

[tex]C_v = \frac{5}{2} R\\\\C_v =\frac{5}{2} \times 8.314[/tex]

Heat capacity = 20.785 J/molK.

At constant volume, the quantity of heat (Q) is given by this formula:

[tex]Q = nC_v \Delta T\\\\Q=6 \times 20.785 \times 145[/tex]

Quantity of heat (Q) = 18,082.95 Joules

Note: [tex]\Delta T[/tex] = 145°C = 145 K (since the difference is the same).

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What is the equation of the following line? Be sure to scroll down first to see all answer options. A. y = 18x B. y = 9x C. y = -9x D. y = - x E. y = -18x F. y = x a. Download the attached Greetings.java file.b. Implement the getGreetings method, so that the code prompts the user to enter the first name, the last name, and year of birth, then it returns a greetings message in proper format (see the example below). The main method will then print it out. Here is an example dialogue with the user:Please enter your first name: tomPlease enter your last name: cruisePlease enter your year of birth: 1962Greetings, T. Cruise! You are about 50 years old.Note that the greetings message need to be in the exact format as shown above (for example, use the initial of the first name and the first letter of the last name with capitalization).c. Submit the final Greetings.java file (DO NOT change the file name) online. Answer problem below A place where animals are protected in their natural habitat is called ------------------ find the value of trigonometric ratio HURRY! HELP PLSJanelle is conducting an experiment to determine whether a new medication is effective in reducing sneezing she finds 1000 volunteers with sneezing issues and divides them into two groups the control group does not receive any medication the treatment group received the medication the patients in the treatment group show reduced signs of sneezing what can genetic include from this experiment? Give four examples illustrating each of the following terms. a. homogeneous mixture b. heterogeneous mixture c. compound e. physical change d. element f. chemical change what is the meaning of "under a lot of pressure" slang expression gdp bnh qun l g ? In ________ organizational cultures, more individuality is shown through the organizations rules being less strictly applied. 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(In other words, cost of goods sold is 60% of sales.)e. Monthly expenses are budgeted as follows: salaries and wages, $27,000 per month: advertising, $70,000 per month; shipping, 5% of sales; other expenses, 3% of sales. Depreciation, including depreciation on new assets acquired during the quarter, will be $42,000 for the quarter.f. Each months ending inventory should equal 25% of the following months cost of goods sold.g. One-half of a months inventory purchases is paid for in the month of purchase; the other half is paid in the following month.h. During February, the company will purchase a new copy machine for $1,700 cash. During March, other equipment will be purchased for cash at a cost of $84,500.i. During January, the company will declare and pay $45,000 in cash dividends.j. Management wants to maintain a minimum cash balance of $30,000. The company has an agreement with a local bank that allows the company to borrow in increments of $1,000 at the beginning of each month. The interest rate on these loans is 1% per month and for simplicity we will assume that interest is not compounded. The company would, as far as it is able, repay the loan plus accumulated interest at the end of the quarter.Required:Using the data above, complete the following statements and schedules for the first quarter:1. Schedule of expected cash collections:JanuaryFebruaryMarchQuarterCash sales $ 80,000Credit sales 224,000Total cash collections $304,0002. a. Merchandise purchases budget:JanuaryFebruaryMarchQuarterBudgeted cost of goods sold $240,000*$360,000Add desired ending inventory90,000fTotal needs 330,000Less beginning inventory60,000Required purchases $270,000 ___________*$400,000 sales X 60% cost ratio =$240,000.$360,000 X 25% = $90,000.b. Schedule of expected cash disbursements for merchandise purchases:JanuaryFebruaryMarchQuarterDecember purchases $ 93,000$ 93,000January purchases 135,000135,000270,000February purchases March purchases Total cash disbursements for purchases $228,0003. Schedule of expected cash disbursements for selling and administrative expenses:JanuaryFebruaryMarch QuarterSalaries and wages $ 27,000 Advertising 70,000 Shipping 20,000 Other expenses 12,000Total cash disbursements forselling and administrative expenses$129,0004. Cash budget:JanuaryFebruaryMarch QuarterCash balance, beginning $ 48,000Add cash collections 304,000Total cash available 352,000Less cash disbursements:Purchases of i nventory 228,000Selling and administrativeexpenses129,000 Purchases of equipment _____ Cash dividends 45,000Total cash disbursements 402,000Excess (deficiency) of cash Financing: Etc.(50,000)5. Prepare an absorption costing income statement for the quarter ending March 31 as shown in Schedule 9 in the chapter.6. Prepare a balance sheet as of March 31. which one of the following favourite the fastest transpiration rate