In traveling a distance of 2.3 km between points A and D, a car is driven at 83 km/h from A to B for t seconds and 41 km/h from C to D also for t seconds. If the brakes are applied for 4.4 seconds between B and C to give the car a uniform deceleration, calculate t and the distance s between A and B.

Answer:

Please find attached pdf

Explanation:

Answer:

Explanation:

Radius of sphere R = .250 x 10⁻² m

Potential on the surface V = k Q / R , where Q is charge on the surface ,  R is radius of the surface and k = 9 x 10⁹

Q = 44  x 10⁻¹² C

V = 9 x 10⁹ x 44  x 10⁻¹² /  ( .25 x 10⁻²)

= 1584 x 10⁻¹ Volt .

= 158.4 Volt

Answer:

Only the car transforms electrical energy into more than one form of energy.

Explanation:

The motion of the car is mechanical energy but it can also transform into another energy witch is electrical energy

Answer:

Roro's total travel time = 6 seconds out of which he rested for 2 seconds

Distance covered by Roro = 8 meters

Explanation:

Given that :

Jojo:

Constant velocity, v = 3m/s

Travel time = h

Roro:

Constant velocity, v = 2m/s

Roro rest for 2 seconds

Travel time = h - 2

Recall:

Distance = speed * time

Distance covered by Jojo:

3 * h = 3h

At this distance ;

Roro's distance = 3h - 10

Using formula :

Roro's distance = 2 * (h - 2)

Hence,

2(h - 2) = 3h - 10

2h - 4 = 3h - 10

2h - 3h = - 10 + 4

-h = - 6

h = 6

Hence, Roro moved for :

h - 2 = 6 - 2 = 4seconds

Distance moved by Roro:

2(h - 2) = 2(6 - 2) = 2(4) = 8 meters

Answer:

(A)

A cup placed on a table won't float away

Answer:

E_total = 26.97 N/C

Electric field points towards the positive charge

Explanation:

We are given;

Charge 1; q1 = 6 nC = 6 × 10^(-9) C

Charge 2; q2 = 3 nC = 3 × 10^(-9) C

Distance between both charges; R_o = 2 m

Since we want to find electric field midway, the distance midway is r = 2/2 = 1 m

Using coulumbs law;

E = kq/r²

Where k is a constant with a value of 8.99 × 10^(9) N.m/C²

Thus;

E1 = kq1/r²

E1 = (8.99 × 10^(9) × 6 × 10^(-9))/1²

E1 = 53.94 N/C

Similarly;

E2 = kq2/r²

E2 = (8.99 × 10^(9) × 3 × 10^(-9))/1²

E2 = 26.97 N/C

Since both electric fields are positive, it means that they are both moving towards the midpoint of the distance between both charges.

This implies they will have opposite directions.

Thus, total electric field at the midway point is;

E_total = E1 - E2

E_total = 53.94 - 26.97

E_total = 26.97 N/C

Answer:

While working as a staff physicist at hughes Research Laboratories McNair learned that the National Aeronautics and Space Administration (NASA) was looking for scientist to join the shuttle program;)

Answer:

t = 5 s

Explanation:

Data:

Use formula:

Replace:

Solve the subtraction of the numerator:

It divides:

How much time did it take the car to reach this final velocity?

It took a time of 5 seconds.

yes

Explanation:

history is an important class and it helps to you understand what went on in the past so that we can learn from our mistakes and help us grow

Answer:

the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Explanation:

Given that;

mass of the object m = 1.20 kg

period of oscillation = 0.750 s

Amplitude ( A/x) = 15.0 cm = 0.15 m

now;

a) Determine the oscillation frequency;

oscillation frequency f = 1/T

we substitute

f = 1 / 0.750 s

f = 1.33 Hz

Therefore, the oscillation frequency is 1.33 Hz

b) Determine the spring constant;

we solve for spring constant from the following expression;

T = 2π√(m/k)

k = 4π²m / T²

so we substitute

k = (4π² × 1.20) / (0.750)²

k = 47.3741 / 0.5625

k =  84.22 N/m

Therefore, the spring constant is 84.22 N/m

c) determine the speed of the mass when it is halfway to the equilibrium position

So, at equilibrium, the energy is equal to K.E

such that;

1/2mv² = 1/2kx²

mv² = kx²

v² = kx² / m

v = √( kx²/m)

we substitute

v = √( 84.22×(0.15 m)²/ 1.2 )

v = √( 1.89495 / 1.2 )

v = √ 1.579125

v = 1.26 m/s  

Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Answer:

Explanation:

Q is larger than P . When two forces act in the same direction , Resultant force  

can be calculated by adding them up . When two forces act in the opposite  direction , Resultant force  can be calculated by subtracting  them .

Force = mass x acceleration .

In the first case

Resultant force = mass x acceleration

P + Q = 7 x 1.4 = 9.8 N

In the second case

Q - P = 7 x 0.7 = 4.9

Adding up these two equations

2 Q = 14.7

Q = 7.35 N

P = 9.8 - 7.35 = 2.45 N .

Answer:

Momentum, [tex]p=7.8\times 10^{-5}\ N-m[/tex]

Explanation:

Given that,

Mass of a mosquito, m = 0.000015 kg

Velocity of the mosquito, v = 5.2 m/s

We need to find the momentum of the mosquito. The momentum of an object is given by :

p = mv

Put all the values in the above formula.

[tex]p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m[/tex]

So, the momentum of the mosquito is [tex]7.8\times 10^{-5}\ N-m[/tex].

Answer:

Length, l = 0.126 meters.

Explanation:

Given the following data;

Period = 6.98s

Acceleration due to gravity, g = 9.8m/s²

To find the length, l;

[tex] Period, T = 2 \pi \sqrt {lg} [/tex]

Substituting into the equation, we have;

[tex] 6.98 = 2*3.142 \sqrt {l*9.8} [/tex]

[tex] 6.98 = 6.284 \sqrt {9.8l} [/tex]

[tex] \frac {6.98}{6.284} = \sqrt {9.8l} [/tex]

[tex] 1.1108 = \sqrt {9.8l} [/tex]

Taking the square of both sides

[tex] 1.1108^{2} = 9.8l [/tex]

[tex] 1.2339 = 9.8l [/tex]

[tex] l = \frac {1.2339}{9.8} [/tex]

Length, l = 0.126m.

Answer:

θ = 225 rad

Explanation:

given data

angle = 25 rad

to find out

angular velocity after 3t?

solution

let angular acceleration α in t

θ = ω × t + 0.5 × α × t²        ........................1

here ω  = 0 (initial velocity )

so put this value here

25 = 0 + 0.5 × α × t²             ..........................2

α = 25 ÷ (0.5 t²)

α = 50 ÷ t²                            .........................3

now here we take in 3t

θ = ω × 3t + 0.5 × α × (3t)²

for ω  = 0

θ = 0 + 0.5 × α × 9t²

now put value in eq 2

so

θ = (0.5) ×  (50 ÷ t²) ×  (3t)²

θ = 25 × 9

θ = 225 rad

Answer:

heyy

Explanation:how r uuu

Answer:

This same Hawaii telescope, which would be 4 km across water level, can't provide an appropriate version of distanced planetary bodies. A further overview is provided below.

Explanation:

Answer:

230° C

Explanation:

A substance's specific heat tells you how much heat much either be added or removed from 1 g of that substance in order to cause a 1∘C

The car's rate of  acceleration : a = 2.04 m/s²

Given

speed = 110 km/hr

time = 15 s

Required

The acceleration

Solution

110 km/hr⇒30.56 m/s

Acceleration is the change in velocity over time

a = Δv : Δt

Input the value :

a = 30.56 m/s : 15 s

a = 2.04 m/s²

Answer:

yes

Explanation:

Answer:yeeeeeeeeeeeeeeeeeeeeeees

Explanation:

Explanation:

thermodynamics is the study of heat.

Answer The study of heat and its relationship to useful work is called thermodynamics and involves macroscopic quantities such as pressure, temperature, and volume without regard for the molecular basis of these quantitie

Explanation:

Answer:

By paying close attention to the formula for average kinetic energy, we can see that by increasing the mass by a proportional amount will lead to an increase in the total average kinetic energy. There is a direct relationship being observed between the values.

Answer:

here

Explanation:

Examples of insulators include plastics, Styrofoam, paper, rubber, glass and dry air.

Examples of conductors include metals, aqueous solutions of salts

Answer:

A thermometer is an instrument that measures temperature.

Explanation:

Answer:

Projectors do not project the color black. This makes sense since black is really the absence of light, and you can't project something that does not exist. When a projector sends a beam of light on to a wall or a projector screen so that an image is formed on the wall or screen, the parts of the image that look black are really a very dim white color (which we sometimes call gray).  - wtamu

Answer is:

Projectors do not project the color black.

Answer:

it will  decrease

Explanation:

According to the law of universal gravitation, the gravitational force exerted by the moon on the spacecraft is equal to the product of their masses and inversely proportional to the square of the distance that separates them. Therefore, as the spacecraft moves away, its distance increases and the force of attraction exerted by the moon decreases.

Answer:

A. It will increase

Explanation:

I took the quiz on K12 and this was the correct option.

Hope I helped

Answer:

 F = 120.25 10⁻⁹  N

Explanation:

In this exercise, the force between the closest neighbors is indicated by f = 481 10⁻⁹ N, in general between the one-dimensional solid the distances remain the same, if the distance between the first neighbor is d, the distance between the second neighbors is 2d.

For most solids the attractive forces are electrical, therefore force is proportional to the electrical charges and the inverse of the distance squared,

             F = [tex]k \frac{q_1 q_2}{r^2}[/tex]

if we call fo the force for the first neighbors

              F₀ = k \frac{q_1 q_2}{d^2}

the force for the second neighbors r= 2d  

              F = k \frac{q_1 q_2}{(2d)^2}

              F = F₀ / 4

let's calculate

              F = 481 10⁻⁹ / 4

              F = 120.25 10⁻⁹  N

Answer:

18 N/C

Explanation:

Given that:

Electric field constant, k = 9*10^9 N/c

Distance, r = 10^-8 m

Dipole moment, p = 10^-33

Using the relation for electric field due to dipole :

E = [2KP / r³]

E = (2 * (9*10^9) * 10^-33) ÷ (10^-8)^3

E = (18 * 10^9 * 10^-33) ÷ 10^-24

E = [18 * 10^(9-33)] ÷ 10^-24

E = (18 * 10^-24) / 10^-24

E = 18 * 10^-24+24

E = 18 * 10^0

E = 18 N/C

Answer:

Electrons

Explanation:

Only Protons and Neutrons are found in the nucleus

Answer:

Option B. 300 m/s².

Explanation:

From the question given above, the following data were obtained:

Mass (m) of student = 100 Kg

Mass (m) of ball = 1.5 Kg

Force (F) applied on the ball = 450 N

Acceleration (a) of ball =?

From Newton's 2nd law,

F = ma

Where

F => Force applied

m => mass of object

a => acceleration of object.

With the above formula, we can obtain the acceleration of the ball as follow:

Mass (m) of ball = 1.5 Kg

Force (F) applied on the ball = 450 N

Acceleration (a) of ball =?

F = ma

450 = 1.5 × a

Divide both side by 1.5

a = 450 / 1.5

a = 300 m/s²

Therefore, the acceleration of the ball is 300 m/s²